I want to test how my app reacts to numpad keys. I found in https://www.w3.org/TR/webdriver/ specs that for example for Numpad Home (with location = DOM_KEY_LOCATION_NUMPAD = 3) a symbol \uE057 should be used. However, it doesn't work for me: I get Home with default location (0), moreover, event.code is empty. It gives me a different result when I physically press NUMPAD7 button with Num Lock off: it that case, I get correct location 3 and event.code is Numpad7.
var options = FirefoxOptions();
options.setLogLevel(FirefoxDriverLogLevel.TRACE);
var driver = FirefoxDriver(options);
driver.navigate().to("https://keycode.info/");
driver.findElementByTagName("body").sendKeys("\uE057");
So how can I send such a key? I'm now thinking of manual recording of generated events when I physically press a key, and then sending these events via Selenium's execution of JS script. However, I haven't tried it yet; maybe there is a better way to do it in Selenium; maybe there is another framework that allows it better.
By the way, I've filed a similar ticket in geckodriver because it looks like a bug of webdriver to me...
\ue01d is the unicode for NUmberpad3
python code:
from selenium import webdriver
from selenium import webdriver
options = webdriver.ChromeOptions()
driver = webdriver.Chrome()
driver.get("https://keycode.info/")
driver.find_element_by_tag_name("body").send_keys("\ue01d")
input()
you can use https://www.javadoc.io/doc/org.seleniumhq.selenium/selenium-api/latest/org/openqa/selenium/Keys.html to send keys instead of sending unicode directly
In firefox this is will work if you use action chain:
ActionChains.send_keys("\ue01d").perform()
Related
I'm attempting to replicate this code:
from selenium import webdriver
browser = webdriver.Firefox()
browser.get('https://inventwithpython.com')
try:
elem = browser.find_element_by_class_name(' cover-thumb')
print('Found <%s> element with that class name!' % (elem.tag_name))
except:
print('Was not able to find an element with that name.')
But it keeps returning the exception. I'm running this on mac w. vscode and there are few things off.
find_element_by_class_name method doesn't seem to register as a method.
Everytime I run this Intellicode prompts get disabled
I can't run this at all on Chrome as it crashes the chrome browsers
I've also searched online for driver issues and have done webdriver with the chrome driver path. Didn't work either
This is the error I'm getting if run it without try and except.
elem = browser.find_element_by_class_name(' cover-thumb') ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ AttributeError: 'WebDriver' object has no attribute 'find_element_by_class_name'
Selenium removed that method in version 4.3.0. See the CHANGES: https://github.com/SeleniumHQ/selenium/blob/a4995e2c096239b42c373f26498a6c9bb4f2b3e7/py/CHANGES
Selenium 4.3.0
* Deprecated find_element_by_* and find_elements_by_* are now removed (#10712)
* ...
You now need to use:
driver.find_element("class name", "VALUE_OF_CLASS_NAME")
Eg:
driver.find_element("class name", "cover-thumb")
But if a class name has multiple segments, use the dot notation from a CSS Selector:
driver.find_element("css selector", "img.cover-thumb")
I'm trying to write this code using Selenium and Python:
from selenium import webdriver
browser = webdriver.Firefox()
browser.get('http://demo.guru99.com/test/login.html')
from selenium.webdriver.common.keys import Keys
email = firefox.find_element_by_xpath('//*[#id="email"]')
email.send_keys('user#gmail.com')
passwd = firefox.find_element_by_xpath('//*[#id="passwd"]')
passwd.send_keys('123456')
But I don't understand why this error occured, please help me
In your code, you are making a an instance of the webdriver.Firefox() object and calling it browser
browser = webdriver.Firefox()
Later on in your code, you try to find an element by xpath using a varible called firefox
email = firefox.find_element_by_xpath('//*[#id="email"]')
The problem is that that firefox was never actually created, I think what you meant to do is
email = browser.find_element_by_xpath('//*[#id="email"]')
You are defining the variable browser as a webdriver object. You then attempt to use firefox as a webdriver object, but you never defined the variable firefox. This is one way to solve your problem. You're better off calling the variable browser, rather than firefox, because then you can just change the browser type in your first line of code and the code will not be confusing.
browser = webdriver.Firefox()
browser.get('http://demo.guru99.com/test/login.html')
from selenium.webdriver.common.keys import Keys
email = browser.find_element_by_xpath('//*[#id="email"]')
email.send_keys('user#gmail.com')
passwd = browser.find_element_by_xpath('//*[#id="passwd"]')
passwd.send_keys('123456')
The next command is failed on Safari browser during automation testing:
ActionChains(driver).move_to_element(searchInput).perform()
Exception:
InvalidArgumentException: Message: Encountered key input source with
invalid 'value' in payload: {actions = ({duration = 0;type =
pause;});
id = key;
type = key;}
The whole refined test example:
def test_safari2(self):
driver = webdriver.Safari()
driver.get('https://www.wikipedia.org')
locator = (By.ID, 'searchInput')
# 1. the line below is passed
searchInput = WebDriverWait(driver, timeout=30).until(expected_conditions.visibility_of_element_located(locator))
# 2. the line below is failed in Safari, but passed in Chrome, FF
ActionChains(driver).move_to_element(searchInput).perform()
However! If self.w3c_actions.key_action.pause() is commented inside action move_to_element(), then the whole Action chains works!
def move_to_element(self, to_element):
"""
Moving the mouse to the middle of an element.
:Args:
- to_element: The WebElement to move to.
"""
if self._driver.w3c:
self.w3c_actions.pointer_action.move_to(to_element)
# self.w3c_actions.key_action.pause()
else:
self._actions.append(lambda: self._driver.execute(
Command.MOVE_TO, {'element': to_element.id}))
return self
The similar situation with other actions.
My question is:
Is it is known limitation of Safari? And therefore ActionChais command could not be use for Selenium + Safari? Or there is some configuration pecularity?
My test runner configuration:
OS: Mac HighSierra 10.13.6
Safari 12.0 (13606.2.11)
Selenium: 3.14.1
Python: 2.7.14
Safari is started with w3c capabilities and protocol (i.e. driver.w3c=True)
Issue background:
I have an enough developed framework with a lot of actions and tests that work Ok for Chrome and Firefox. Now I'm trying to extend coverage for Safari browser also. So, that is why I'm searching for solution for not working ActionChains
Workaround by wrapping ActionChains class so that key_action.pause is not used (which does not seem to serve any important purpose):
import selenium.webdriver
class ActionChains(selenium.webdriver.ActionChains):
def __init__(self, driver):
super(ActionChains, self).__init__(driver)
if driver.name in ('Safari', 'Safari Technology Preview'):
self.w3c_actions.key_action.pause = lambda *a, **k: None
I'm trying to make multiple tabs in Selenium and open a page on each tab simultaneously. Here is the code.
CHROME_DRIVER_PATH = "C:/chromedriver.exe"
from selenium import webdriver
import threading
driver = webdriver.Chrome(CHROME_DRIVER_PATH)
links = ["https://www.google.com/",
"https://stackoverflow.com/",
"https://www.reddit.com/",
"https://edition.cnn.com/"]
def open_page(url, tab_index):
driver.switch_to_window(handles[tab_index])
driver.get(url)
return
# open a blank tab for every link in the list
for link in range(len(links)-1 ): # 1 less because first tab is already opened
driver.execute_script("window.open();")
handles = driver.window_handles # get handles
all_threads = []
for i in range(0, len(links)):
current_thread = threading.Thread(target=open_page, args=(links[i], i,))
all_threads.append(current_thread)
current_thread.start()
for thr in all_threads:
thr.join()
Execution goes without errors, and from what I understand this should logically work correctly. But, the effect of the program is not as I imagined. It only opens one page at a time, sometimes it doesn't even switch the tab... Is there a problem that I'm not aware of in my code or threading doesn't work with Selenium?
There is no need in switching to new window to get URL, you can try below to open each URL in new tab one by one:
links = ["https://www.google.com/",
"https://stackoverflow.com/",
"https://www.reddit.com/",
"https://edition.cnn.com/"]
# Open all URLs in new tabs
for link in links:
driver.execute_script("window.open('{}');".format(link))
# Closing main (empty) tab
driver.close()
Now you can handle (if you want) all the windows from driver.window_handles as usual
My program is having trouble getting an existing class from a webpage using Selenium. It seems that my WebDriver.execute_script function is not working.
import urllib
from selenium import webdriver
#Path to the chromedriver is definitely working fine.
path_to_chromedriver = 'C:\Users\Ben\Desktop\Coding\FreeFoodFinder\chromedriver.exe'
browser = webdriver.Chrome(executable_path = path_to_chromedriver)
url = 'http://www.maidservicetexas.com/'
browser.implicitly_wait(30)
browser.get(url)
content = browser.execute_script("document.getElementsByClassName('content')");
#Just printing the first character of the returned content's toString for now. Don't want the whole thing yet.
#Only ever prints 'N', the first letter of 'None'...so obviously it isn't finding the jsgenerated content even after waiting.
print content
My program returns 'None,' which tells me that the javascript function is not returning a value/being executed. Chrome's web dev tools tell me that 'content' is certainly a valid class name. The webpage isn't even dynamically generated (my eventual goal is to scrape dynamic content, which is why I make my WebDriver wait for 30 seconds before running the script.)
Return the value:
content = browser.execute_script("return document.getElementsByClassName('content');");