Select first occurrence of value after last occurrence of other value in SQL - sql

Question

I have a requirement to find the current operation of a part. The table I have to get this information from lists operation statuses of complete (1) or 0. So the table typically looks like:
ID Operation Status
1 100 1
2 200 1
3 250 1
4 300 0
5 350 0
So in this case Operation 300 is the current op which I get using MIN(Operation) WHERE Status = 0.
However, some cases have appeared where some operations are skipped which would look like:
ID Operation Status
1 100 1
2 200 0
3 250 1
4 300 0
5 350 0
So in this case the current operation is still Operation 300 but MIN(Operation) doesn't work. What I need is the first occurrence of the row where Status = 0 that follows the last occurrence of a Status = 1 row. How could I achieve this?
Edit: Also have to consider the case where all operations are Status 0, where the correct result would be the first row (Operation 100)

Answer 1

This will give you the entire row to work with:
DECLARE #MyTable TABLE (
ID INT,
Operation INT,
Status BIT
);
INSERT INTO #MyTable VALUES
(1, 100, 1)
,(2, 200, 0)
,(3, 250, 1)
,(4, 300, 0)
,(5, 350, 0)
;
WITH MaxOperation AS (
SELECT MAX(x.Operation) AS MaxOperation
FROM #MyTable x
WHERE x.Status = 1
)
SELECT TOP 1 t.*
FROM #MyTable t
CROSS APPLY (SELECT MaxOperation FROM MaxOperation) x
WHERE t.Operation > x.MaxOperation
OR x.MaxOperation IS NULL
ORDER BY t.Operation
This will result in:
ID Operation Status
----------- ----------- ------
4 300 0
It will also produce this if all the Status values are 0:
ID Operation Status
----------- ----------- ------
1 100 0

Answer 2

I'm sure there is a clever window function way to do it, but in vanilla sql this is the idea
SELECT MIN(Operation)
FROM SOME_TABLE
WHERE Operation >
( SELECT MAX(Operation)
FROM SOME_TABLE
WHERE status = 1
)

Answer 3

As indicated by user Error_2646, a good way would be something like
select
min(ID)
from
[YourTable]
where
ID > (select max(ID) from [YourTable] where Status = 1)

Answer 4

I hope this answer will give you the correct answer. If you can add the expected output in a image it is more easy to identify what you need. Please add schema and data when, so that it is easy for user to put their solutions.
Schema and data I used:
(
ID INT
,operation INT
,Status INT
)
insert into Occurances values(1,100,1)
insert into Occurances values(2,200,0)
insert into Occurances values(1,250,1)
insert into Occurances values(1,300,0)
insert into Occurances values(1,350,0)
SELECT *
FROM
(
SELECT
Rank() OVER ( ORDER BY operation) AS [rank]
,MIN([operation]) AS [min]
,id
,[status]
FROM Occurances
WHERE [Status]= 0
GROUP BY id
,[status]
,operation
UNION
SELECT
Rank() OVER ( ORDER BY operation DESC) AS [rank]
,MAX([operation]) AS [min]
,id
,[status]
FROM Occurances
WHERE [Status]= 1
GROUP BY id
,[status]
,operation
) AS A
WHERE A.[rank]= 1
This is the answer I am getting:

Answer 5

You can do this very efficiently with a window function:
SELECT TOP (1) *
FROM (
SELECT *, LEAD(Status) OVER (ORDER BY Operation DESC) AS PreviousStatus
FROM myTable
)
WHERE Status = 0 AND PreviousStatus = 1
ORDER BY Operation DESC

Answer 6

Try this:
DECLARE #Table TABLE
(
ID int
, Operation int
, [Status] bit
)
;
INSERT INTO #Table (ID, Operation, [Status])
VALUES
(1, 100, 1)
, (2, 200, 0)
, (3, 250, 1)
, (4, 300, 1)
, (5, 350, 0)
;
SELECT TOP 1 T.*
FROM #Table T
WHERE T.[Status] = 0
AND T.ID > (
SELECT TOP 1 T.ID
FROM #Table T
WHERE T.[Status] = 1
ORDER BY ID DESC
)
ORDER BY ID