I have a table ORDERS with a column named cache_total_price, spent by each client.
+----+-----------+------------+-----------+------------------+
| id | client_id | date | reference | cache_total_price|
+----+-----------+------------+-----------+------------------+
| 1 | 20 | 2019-01-01 | 004214 | 0 |
| 2 | 3 | 2019-01-03 | 007120 | 0 |
| 3 | 11 | 2019-01-04 | 002957 | 0 |
| 4 | 6 | 2019-01-07 | 003425 | 0 |
I have another table ORDERS_REFS where there is the price total spent for each orders id
+-----+-------------+------------+----------+---------------+------------+
| id | order_id | name | quantity | unit_price | total_price|
+-----+-------------+------------+----------+---------------+------------+
| 1 | 1 | Produit 19 | 3 | 49.57 | 148.71 |
| 2 | 1 | Produit 92 | 4 | 81.24 | 324.96 |
| 3 | 1 | Produit 68 | 2 | 17.48 | 34.96 |
| 4 | 2 | Produit 53 | 4 | 83.69 | 334.76 |
| 5 | 2 | Produit 78 | 6 | 5.99 | 35.94 |
I want to had to column cache_total_price the result of my query :
select sum(total_price) from orders_refs group by order_id;
result :
+--------------------+
| sum(total_price) |
+--------------------+
| 508.6299819946289 |
| 370.700008392334 |
| 132.3699951171875 |
| 2090.1800079345703 |
I've tried some queries with Insert into select or update set, but didn't worked :(
If you're wanting to update all the orders at once, in MySQL a subquery like this should do the trick. You could always add a WHERE clause to do one at a time.
UPDATE ORDERS
SET cache_total_price = (
SELECT sum(total_price) from ORDERS_REF where order_id = ORDERS.id
)
update t
set t.cache_total_price=x.sum_total_price
from ORDERS as t
join
(
select order_id,sum(total_price)as sum_total_price
from orders_refs group by order_id
)x on t.id=x.order_id
In SQL Server you can try this one.
Related
the supply table:
supply_id | title | author | price | amount |
+-----------+----------------+------------------+--------+--------+
| 1 | Лирика | Пастернак Б.Л. | 518.99 | 2 |
| 2 | Черный человек | Есенин С.А. | 570.20 | 6 |
| 3 | Белая гвардия | Булгаков М.А. | 540.50 | 7 |
| 4 | Идиот | Достоевский Ф.М. | 360.80 | 3
I am trying to insert into book , all the values from supply:
+---------+-----------------------+------------------+--------+--------+
| book_id | title | author | price | amount |
+---------+-----------------------+------------------+--------+--------+
| 1 | Мастер и Маргарита | Булгаков М.А. | 670.99 | 3 |
| 2 | Белая гвардия | Булгаков М.А. | 540.50 | 5 |
| 3 | Идиот | Достоевский Ф.М. | 460.00 | 10 |
| 4 | Братья Карамазовы | Достоевский Ф.М. | 799.01 | 2 |
| 5 | Стихотворения и поэмы | Есенин С.А. | 650.00 | 15 |
+---------+-----------------------+------------------+--------+--------+
insert into book(title,author,price,amount)
select * from supply;
the primary ids conflict with each other - both tables start with id '1'
ERROR 1136: Column count doesn't match value count at row 1
Your columns in insert and select mismatches. You need to give explicit names of the columns instead of * in SELECT clause.
Try this:
insert into book(title,author,price,amount)
select title,author,price,amount from supply;
I have two tables 'Product' and 'product_Desc'
+-----------+-------------+
| ProductID | ProductName |
+-----------+-------------+
| 1 | A |
| 2 | B |
+-----------+-------------+
+----+-----------+-------------+-----------+
| Id | ProductID | ProductDec | SortOrder |
+----+-----------+-------------+-----------+
| 1 | 1 | Aero-pink | |
| 2 | 1 | Aero-white | |
| 3 | 1 | Aero-green | |
| 4 | 1 | Aero-Orange | |
| 5 | 2 | Baloon-1 | |
| 6 | 2 | Baloon-2 | |
| 7 | 2 | Baloon-3 | |
+----+-----------+-------------+-----------+
Now, what is the Sql code that can update 'sortOrder' column sequentially for each group of ProductID as shown below:
+----+-----------+-------------+-----------+
| Id | ProductID | ProductDec | SortOrder |
+----+-----------+-------------+-----------+
| 1 | 1 | Aero-pink | 1 |
| 2 | 1 | Aero-white | 2 |
| 3 | 1 | Aero-green | 3 |
| 4 | 1 | Aero-Orange | 4 |
| 5 | 2 | Baloon-1 | 1 |
| 6 | 2 | Baloon-2 | 2 |
| 7 | 2 | Baloon-3 | 3 |
+----+-----------+-------------+-----------+
Please note that these are sample tables, actual tables have thousands of records.
Would appreciate your help on this. Thank you
with cte
as
(
select SortOrder, row_number() over(partition by ProductID order by Id) as newPerProductOrder
from product_Desc
)
update cte
set SortOrder = newPerProductOrder
where (SortOrder <> newPerProductOrder or SortOrder is null)
I have a data orders that looks like this:
| Order | Step | Step Complete Date |
|:-----:|:----:|:------------------:|
| A | 1 | 11/1/2019 |
| | 2 | 11/1/2019 |
| | 3 | 11/1/2019 |
| | 4 | 11/3/2019 |
| | 5 | 11/3/2019 |
| | 6 | 11/5/2019 |
| | 7 | 11/5/2019 |
| B | 1 | 12/1/2019 |
| | 2 | 12/2/2019 |
| | 3 | |
| C | 1 | 10/21/2019 |
| | 2 | 10/23/2019 |
| | 3 | 10/25/2019 |
| | 4 | 10/25/2019 |
| | 5 | 10/25/2019 |
| | 6 | |
| | 7 | 10/27/2019 |
| | 8 | 10/28/2019 |
| | 9 | 10/29/2019 |
| | 10 | 10/30/2019 |
| D | 1 | 10/30/2019 |
| | 2 | 11/1/2019 |
| | 3 | 11/1/2019 |
| | 4 | 11/2/2019 |
| | 5 | 11/2/2019 |
What I need to accomplish is the following:
For each order, assign the 'Order_Completion_Date' field as the most recent 'Step_Complete_Date'. If ANY 'Step_Complete_Date' is NULL, then the value for 'Order_Completion_Date' should be NULL.
I set up a SQL FIDDLE with this data and my attempt, below:
SELECT
OrderNum,
MAX(Step_Complete_Date)
FROM
OrderNums
WHERE
Step_Complete_Date IS NOT NULL
GROUP BY
OrderNum
This is yielding:
ORDERNUM MAX(STEP_COMPLETE_DATE)
D 11/2/2019
A 11/5/2019
B 12/2/2019
C 10/30/2019
How can I achieve:
| OrderNum | Order_Completed_Date |
|:--------:|:--------------------:|
| A | 11/5/2019 |
| B | NULL |
| C | NULL |
| D | 11/2/2019 |
Aggregate function with KEEP can handle this
select ordernum,
max(step_complete_date)
keep (DENSE_RANK FIRST ORDER BY step_complete_date desc nulls first) res
FROM
OrderNums
GROUP BY
OrderNum
You can use a CASE expression to first count if there are any NULL values and if not then find the maximum value:
Query 1:
SELECT OrderNum,
CASE
WHEN COUNT( CASE WHEN Step_Complete_Date IS NULL THEN 1 END ) > 0
THEN NULL
ELSE MAX(Step_Complete_Date)
END AS Order_Completion_Date
FROM OrderNums
GROUP BY OrderNum
Results:
| ORDERNUM | ORDER_COMPLETION_DATE |
|----------|-----------------------|
| D | 11/2/2019 |
| A | 11/5/2019 |
| B | (null) |
| C | (null) |
First, you are representing dates as varchars in mm/dd/yyyy format (at least in fiddle). With max function it can produce incorrect result, try for example order with dates '11/10/2019' and '11/2/2019'.
Second, the most simple solution is IMHO to use fallback date for nulls and get null back when fallback date wins:
SELECT
OrderNum,
NULLIF(MAX(NVL(Step_Complete_Date,'~')),'~')
FROM
OrderNums
GROUP BY
OrderNum
(Example is still for varchars since tilde is greater than any digit. For dates, you could use 9999-12-31, for instance.)
i hope my description will be enough. i tried to remove all non-significant fields.
i have 5 tables (Customer, Invoice, Items, Invoice_Item, Payment):
Customer fields and sample date are:
+----+------+
| ID | Name |
+----+------+
| 1 | John |
| 2 | Mary |
+----+------+
Invoice fields and sample date are:
+----+-----------+----------+------+
| ID | Date | Customer | Tax |
+----+-----------+----------+------+
| 1 | 1.1.2017 | 1 | 0.10 |
| 2 | 2.1.2017 | 2 | 0.10 |
| 3 | 3.1.2017 | 1 | 0.10 |
| 4 | 3.1.2017 | 2 | 0.10 |
| 5 | 8.1.2017 | 1 | 0.10 |
| 6 | 11.1.2017 | 1 | 0.10 |
| 7 | 12.1.2017 | 2 | 0.10 |
| 8 | 13.1.2017 | 1 | 0.10 |
+----+-----------+----------+------+
Item fields and sample data are:
+----+--------+
| ID | Name |
+----+--------+
| 1 | Door |
| 2 | Window |
| 3 | Table |
| 4 | Chair |
+----+--------+
Invoice_Item fields and sample data are:
+------------+---------+--------+------------+
| Invoice_ID | Item_ID | Amount | Unit_Price |
+------------+---------+--------+------------+
| 1 | 1 | 4 | 10 |
| 1 | 2 | 2 | 20 |
| 1 | 3 | 1 | 30 |
| 1 | 4 | 2 | 40 |
| 2 | 1 | 1 | 10 |
| 2 | 3 | 1 | 15 |
| 2 | 4 | 2 | 12 |
| 3 | 3 | 4 | 15 |
| 4 | 1 | 1 | 10 |
| 4 | 2 | 20 | 30 |
| 4 | 3 | 15 | 30 |
| 5 | 1 | 4 | 10 |
| 5 | 2 | 2 | 20 |
| 5 | 3 | 1 | 30 |
| 5 | 4 | 2 | 40 |
| 6 | 1 | 1 | 10 |
| 6 | 3 | 1 | 15 |
| 6 | 4 | 2 | 12 |
| 7 | 3 | 4 | 15 |
| 8 | 1 | 1 | 10 |
| 8 | 2 | 20 | 30 |
| 8 | 3 | 15 | 30 |
+------------+---------+--------+------------+
The reason the price is in this table not in the item table is because it is customer specific price.
Payment fields are:
+----------+--------+-----------+
| Customer | Amount | Date |
+----------+--------+-----------+
| 1 | 40 | 3.1.2017 |
| 2 | 10 | 7.1.2017 |
| 1 | 60 | 10.1.2017 |
+----------+--------+-----------+
so my report should be combine all tables and sort by DATE (either from Invoice or Payment) for a certain customer.
so for e.g. for customer John (1) it should be like:
+------------+----------------+---------+-----------+
| Invoice_ID | Invoice_Amount | Payment | Date |
+------------+----------------+---------+-----------+
| 1 | 171 | - | 1.1.2017 |
| 3 | 54 | - | 3.1.2017 |
| - | - | 40 | 3.1.2017 |
| 5 | 171 | - | 8.1.2017 |
| - | 10 | 60 | 10.1.2017 |
| 6 | 44.1 | - | 11.1.2017 |
| 8 | 954 | - | 13.1.2017 |
+------------+----------------+---------+-----------+
it is sorted by date, Invoice amount is (sum of (Amount* unit price)) * (1-tax)
i started with union but then got lost.
here is my try:
SELECT Inv_ID as Num, SUM(Invoice_Items.II_Price*Invoice_Items.II_Amount) AS Amount, Inv_Date as Created
FROM Invoice INNER JOIN Invoice_Items ON Invoice.Inv_ID = Invoice_Items.II_Inv_ID
UNION ALL
SELECT Null as Num, P_Value as Amount, P_Date as Created
FROM Payments
ORDER BY created ASC
Your help is appreciated!
Thanks
You can generate the report you requested using the following SQL script:
SELECT CustomerID,Invoice_ID,Invoice_Amount,Payment,Date
FROM (
SELECT c.ID AS CustomerID, i.ID AS Invoice_ID, SUM((t.Amount * t.UnitPrice)*(1-i.tax)) AS Invoice_Amount, NULL AS Payment,i.Date
FROM (Customer c
LEFT JOIN Invoice i
ON c.ID = i.Customer)
LEFT JOIN Invoice_Item t
ON i.ID = t.Invoice_ID
GROUP BY c.ID, i.ID,i.Date
UNION
SELECT c.ID AS CustomerID,NULL AS Invoice_ID, NULL AS Invoice_Amount, p.Amount AS Payment, p.Date
FROM Customer c
INNER JOIN Payment p
ON c.ID = p.Customer ) a
ORDER BY CustomerID, Date, Payment ASC
Note: I've added CustomerID to the output so you know what customer the data corresponds to.
here is the Answer which worked for me, a bit corrected from #Catzeye Answer , which didnt show the second part of the Union.
SELECT c.ID AS CustomerID,NULL AS Invoice_ID, NULL AS Invoice_Amount, p.Amount AS Payment, p.Date
FROM Customer c
INNER JOIN Payment p
ON c.ID = p.Customer
UNION ALL
SELECT c.ID AS CustomerID, i.ID AS Invoice_ID, SUM((t.Amount * t.Unit_Price)*(1-i.tax)) AS Invoice_Amount, NULL AS Payment,i.Date
FROM (Customer c
INNER JOIN Invoice i
ON c.ID = i.Customer)
INNER JOIN Invoice_Item t
ON i.ID = t.Invoice_ID
GROUP BY c.ID, i.ID,i.Date
ORDER BY CustomerID, Date, Payment;
Given the following tables, I am trying to set eventid to the highest value, incremented by one. So max(eventid) + 1. I cannot seem to get the right SQL syntax to accomplish this.
What I have right now that works, but does not give me what I need, is the following. How would I get the eventid to show, in this case, 96740?
INSERT INTO stock_history
(lastmodby,
event,
previous_stock,
new_stock,
lastmodified,
productid)
SELECT '160' AS lastmodby,
'SALE' AS event,
stockstatus AS previous_stock,
stockstatus + 1 AS new_stock,
Getdate() AS lastmodified,
products_joined.productid AS productid
FROM products_joined
WHERE productcode = 'abc'
stock_history table
+--------+-----------+----------------+-------+-----------+-------+---------+-----------------------+-----------+
| id | productid | previous_stock | count | new_stock | event | eventid | lastmodified | lastmodby |
+--------+-----------+----------------+-------+-----------+-------+---------+-----------------------+-----------+
| 105619 | 9282 | 9 | 1 | 10 | SALE | | 7/24/2015 5:29:00 PM | 160 |
| 105578 | 9282 | 8 | 1 | 9 | ORDER | 96739 | 7/23/2015 7:30:00 PM | 37655 |
| 89241 | 9282 | 7 | 1 | 8 | ORDER | 96738 | 6/1/2014 6:06:00 PM | 30761 |
| 86773 | 9282 | 6 | 1 | 7 | ORDER | 96737 | 4/12/2014 4:36:00 PM | 29745 |
| 70419 | 9282 | 5 | 1 | 6 | ORDER | 96736 | 5/21/2013 1:17:00 PM | 1754 |
| 69088 | 9200 | 19 | 1 | 20 | EDIT | 96735 | 4/28/2013 10:26:00 AM | 1754 |
| 69050 | 9200 | 18 | 1 | 19 | ORDER | 96734 | 4/27/2013 2:17:00 PM | 23001 |
| 68127 | 9200 | 17 | 1 | 18 | ORDER | 96733 | 4/13/2013 12:34:00 PM | 22674 |
| 67064 | 9200 | 16 | 1 | 17 | ORDER | 96732 | 3/30/2013 9:23:00 AM | 22327 |
+--------+-----------+----------------+-------+-----------+-------+---------+-----------------------+-----------+
products_joined table
+-------------+-----------+-------------+
| productcode | productid | stockstatus |
+-------------+-----------+-------------+
| abc | 9282 | 9 |
| xyz | 9200 | 19 |
+-------------+-----------+-------------+
You're better off using an IDENTITY column - SQL Server will take care of this much more efficiently than you can, both in terms of performance as in reliability. This question gives you some options on how to do that, e.g.
ALTER TABLE stock_history DROP COLUMN eventid
ALTER TABLE stock_history ADD eventid INT IDENTITY(1,1)
That said, it is technically possible to do this within the query. It might help to know this pattern for situations where an IDENTITY column is not an option.
INSERT INTO stock_history
(lastmodby,
event,
previous_stock,
new_stock,
lastmodified,
productid,
eventid)
SELECT '160' AS lastmodby,
'SALE' AS event,
stockstatus AS previous_stock,
stockstatus + 1 AS new_stock,
Getdate() AS lastmodified,
products_joined.productid AS productid,
(SELECT MAX(eventid) + 1 FROM stock_history) AS eventid
FROM products_joined
WHERE productcode = 'abc'
Note that this could lead to duplicate eventids if this query is executed multiple times at once.