can not make a select with the desired values in SQL Server - sql

Question

Creating the table
CREATE TABLE dbo.factura
(
customer_code varchar(20),
invoice_number char(4),
line_number char(2),
data date
);
DROP TABLE dbo.factura;
SELECT * FROM dbo.factura;
Populating the table:
INSERT INTO dbo.factura VALUES ('ABC', '0012', '01', '2020-10-01');
INSERT INTO dbo.factura VALUES ('ABC', '0012', '02', '2020-11-01');
INSERT INTO dbo.factura VALUES ('ABC', '0012', '03', '2020-11-01');
INSERT INTO dbo.factura VALUES ('ABC', '0013', '08', '2021-01-21');
INSERT INTO dbo.factura VALUES ('ABC', '0013', '09', '2020-09-01');
INSERT INTO dbo.factura VALUES ('SLIK', '0001', '01', '2021-01-01');
INSERT INTO dbo.factura VALUES ('SLIK', '0001', '02', '2020-02-01');
Write a SQL statement to return the recordset:
CUSTOMER_CODE, INVOICE_NR, LINE_NR
where NR_LINE is the line number with the most recent value in the DATA column for each invoice of each customer in the table.
I tried to do with a self join, but it doesn't work.
Do you have any ideas how to write this query?

Answer 1

If you want the rows by sorted by line_number in descending order then the query will be:
with cte as (
select CUSTOMER_CODE, INVOICE_number, LINE_number , row_number()over(partition by customer_code,invoice_number order by LINE_number desc) rn
from factura
)
select CUSTOMER_CODE, INVOICE_number, LINE_number from cte where rn=1
Output:
If you want the result in descending order of data field then the query will be:
with cte as (
select CUSTOMER_CODE, INVOICE_number, LINE_number , row_number()over(partition by customer_code,invoice_number order by data desc) rn
from factura
)
select CUSTOMER_CODE, INVOICE_number, LINE_number from cte where rn=1
Output: