I Want to extract data from a table for monthwise in oracle sql.
I tried it as follow,
SELECT * From customer ct
Where ct. Application_signed _date in (Date '31-12-2020, Date '01-10-2020')
But i am unable to Fetch the data for this range, whereas data is available for this months.
The correct format for a date in Oracle -- and almost everywhere else -- is YYYY-MM-DD:
select *
From customer ct
where ct.Application_signed_date in (Date '2020-12-31, Date '2020-10-01')
Note that Oracle dates can have time components. If that is possible in your data, then one fix is:
where trunc(ct.Application_signed_date) in (Date '2020-12-31, Date '2020-10-01')
Related
I have a table called Transactions that has a column called trans_date. I am just trying to do a simple query in the SQL*Plus command window
The query is
SELECT * FROM transactions WHERE
trans_date BETWEEN to_date('09/11/2021','mm/dd/yyyy') AND to_date('09/12/2021','mm/dd/yyyy');
When I run this query I get not valid month and there is a little * under trans_date. Most of what I have read suggests the query is right but I am not sure what the problem is. The data type is varchar2(20).
Since trans_date is a varchar and you're trying to query whether it's between two dates, you need to convert it to a date too. Assuming it has the same format as the literals in your query:
SELECT *
FROM transactions
WHERE to_date(trans_date, 'mm/dd/yyy') BETWEEN
to_date('09/11/2021','mm/dd/yyyy') AND to_date('09/12/2021','mm/dd/yyyy');
Seems like problem is columns data type, Try convert it to date,
SELECT * FROM transactions
WHERE to_date(trans_date,'mm/dd/yyyy') BETWEEN to_date('09/11/2021','mm/dd/yyyy') AND to_date('09/12/2021','mm/dd/yyyy');
You need to convert trans_date to a date. However, you can use date constants for the comparisons:
SELECT *
FROM transactions
WHERE to_date(trans_date, 'mm/dd/yyyy') BETWEEN DATE '2021-09-11' AND DATE '2021-09-12';
You should fix your data model so the dates are stored correctly, using Oracle's built-in data type.
I have a query as below,
SELECT column
FROM table
WHERE day IN date ('2019-06-27','2019-07-08', '2019-07-10')
the values in the column day are formatted as 2019-07-07 12:30:15.744
Currently doesn't let me filter for dates using the date syntax prior to that list of specific dates.
How can I properly code this query to retrieve data for only that list of dates? Thanks!
date is a keyword that introduces a date literal, not a list of dates. Just use it for each value:
SELECT column
FROM table
WHERE day IN (date '2019-06-27', date '2019-07-08', date '2019-07-10')
I have a problem with converting a varchar2 fields into a date format.
I got 2 columns with the datatyp varchar2, one is called qtime the other is called ztime. Both fields contain strings in this format (f.e. 152015 -> would be a timestamp 15:20:15).
For reporting reasons I need to convert this fields into a date format, afterwards I want to substract (qtime-ztime) the fields an convert them into the format [hh] (f.e. after the operation 01:20:00 would be -> 01). Is it possible to to this within Oracle SQL 12c? The biggest problem for me right now is that I don't get those Strings converted into a date format.
select TO_DATE(qtime,'MM/DD/YYYY hh24:mi:ss') just gives me
ORA-01861:"literal does not match format string"
select TO_DATE(qtime,'hh24mmss') gives me a wrong Date
01.03.2018
select TO_TIMESTAMP(qtime,'hh24mmss') gives me a wrong Date
01.03.2018 BUT the correct time with f.e. 15:20:15,0000000
Thank you in advance, any help is appreciated
Note: I only have reading rights on the database Oracle 12c, so I need to to this within Statements
"The Database contains another column with the correct date for each time"
The missing piece of the puzzle! Concatenate the two columns to get something which can be converted to an Oracle DATE:
select to_date(qdate||qtime, 'yyyymmddhh24miss') as qdatetime
, to_date(zdate||ztime, 'yyyymmddhh24miss') as zdatetime
from your_table
Once you have done that you can perform arithmetic of the dates e.g.
select id
, zdatetime - qdatetime as time_diff
from ( select id
, to_date(qdate||qtime, 'yyyymmddhh24miss') as qdatetime
, to_date(zdate||ztime, 'yyyymmddhh24miss') as zdatetime
from your_table
)
If you want the number of hours in the difference you can include this expression in the projection of the outer query:
, extract( hour from (zdatetime - qdatetime) day to second) as hrs_ela
First off, if you are trying to convert a varchar2 into a date without specifying neither day nor month, it will default to the first day of the current month:
If you specify a date value without a date, then the default date is the first day of the current month.
You can read up more here
Also in 2nd and 3rd your example, you are using 'hh24mmss' for specifying hour, minute and second components, but do note that correct format for minutes is 'mi' and not 'mm', which is used for months.
So the solution is to concatenate both date and time component when creating the date as the other answer suggested, tho I would recommend using a single date field as it can store the information you need.
I want to compare the date in my sql query and get the records for a specific date, but it is stored in timestamp format in postgres.
What kind of query could compare only date parts, since I want and skip the time part.
This Query will give you date like '2012/11/22' which you can use for date comparison.
SELECT CONVERT(VARCHAR(10),GETDATE(),111)
//OR simply
select CAST(GETDATE() as DATE)
You can see more formats here :- CAST and CONVERT (Transact-SQL)
Try this:
SELECT *
FROM tab
where date_col::DATE BETWEEN '2012-01-01'::DATE AND '2012-01-05'::DATE
SQL Fiddle DEMO
I have a table student with the following columns:
no - integer
name - string
startdate - date
enddate - date.
Date format is MM/DD/YYYY.
I will give a date as input. Now I need a query the inputdate which found in between the start and end date.
For an example I will give 04/14/2012, then the query should return the 1st record as in the figure.
(because input date (04/14/2012) is found in between the 04/10/2012 to 04/20/2012)
Please help me.
The issue you are having is caused by your assumption that sqlite has a date/datetime type when in fact it doesn't.
I suggest you read the following http://www.sqlite.org/datatype3.html to have a better understanding of sqlite types.
The dates in the MM/DD/YYYY format are handled as TEXT by sqlite, and so those dates are compared as strings. For example, 02/01/2012 is considered bigger than 01/02/2012by sqlite if compared directly.
You will need to transform those dates to a format that can be string-compared. Here is an example:
sqlite> create table foo (d TEXT);
sqlite> insert into foo values ('02/01/2012');
sqlite> select substr(d, 7, 4) || substr(d, 1, 2) || substr(d, 4, 2) from foo;
20120201
You should post what you have tried so far.
There should be a between clause that you can use:
select * from table
where inputdate between startdate and enddate
Dates as a date type in SQLite don't exist. There are a number of approaches to dealing with dates - store them as integer seconds since 1 Jan 1970 (unixepoch) or store them as strings, but if you do, then you really need to store them in 'YYYY-MM-DD' format because that is what the date functions require as input.
Assuming you use the string format in the format I suggested then your query would look something like
SELECT * FROM Table WHERE Date(Inputdate) BETWEEEN Date(startDate) AND Date(EndDate);
(although you may want to format the output of the date columns to US date format with
SELECT Strftime("%m/%d/%Y",startDate) As StartDate ...
If you use seconds since 1970 its somewhat easier because the seconds just compare without needing the convert them to dates, although you still might want to output in US date format, so ...
SELECT Strftime("%m/%d/%Y",startDate) As StartDate ... FROM Table WHERE inputDate BETWEEN startDate and EndDate;
sqlite> select *from tbl_node where mydate between '2014-02-02' and '2014-02-06';
it show the output :-
1|1|123|456|12eb-ab|1|1|254|123|19|2014-02-03 16:00:44
2|1|123|456|12eb-ab|1|1|254|123|19|2014-02-03 16:01:03
3|1|123|456|12eb-ab|1|1|254|123|19|2014-02-03 16:00:57
4|1|123|456|12eb-ab|1|1|254|123|19|2014-02-03 16:00:34
Here mydate is column name in tbl_node;
we can also use from current time , using now.
sqlite> select *from tbl_node where mydate between '2014-02-02' and 'now';