This is the input table (tbl_statuslog):
User_id
isactive
date
1
1
1 Feb 2021
2
1
1 Feb 2021
3
1
2 Feb 2021
2
0
5 Feb 2021
4
1
10 Feb 2021
4
0
10 Feb 2021
3
0
12 Feb 2021
create table tbl_statuslog
(
[user_id] int,
[isactive] bit,
[date] datetime
);
insert into tbl_statuslog (user_id, isactive, date) values
(1, 1, ' 1 Feb 2021'),
(2, 1, ' 1 Feb 2021'),
(3, 1, ' 2 Feb 2021'),
(2, 0, ' 5 Feb 2021'),
(4, 1, '10 Feb 2021'),
(4, 0, '10 Feb 2021'),
(3, 0, '12 Feb 2021');
I want to return output, given today is 16 Feb:
User_id
isactive
date
1
1
1 Feb 2021
.
.
.
1
1
16 Feb 2021
2
1
1 Feb 2021
.
.
2
1
4 Feb 2021
2
0
5 Feb 2021
.
.
2
0
16 Feb 2021
3
1
2 Feb 2021
.
.
3
1
11 Feb 2021
3
0
12 Feb 2021
.
.
3
0
16 Feb 2021
4
0
10 Feb 2021
.
.
4
0
16 Feb 2021
I have used following SQL to get the list of all dates.
DECLARE #StartDateTime DATETIME
DECLARE #EndDateTime DATETIME
SET #StartDateTime = '2021-02-01'
SET #EndDateTime = GETDATE();
WITH DateRange(DateData) AS
(
SELECT #StartDateTime as Date
UNION ALL
SELECT DATEADD(d,1,DateData)
FROM DateRange
WHERE DateData < #EndDateTime
)
SELECT DateData
FROM DateRange
OPTION (MAXRECURSION 0)
GO
Now I am thinking of doing a left join of this table with tbl_statuslog table. Thus I have a date irrespective of whether date exists in tbl_statuslog or not.
Then I want to backfill the isactive value for the date and user_id based on the previous value.
Can I use window function- example partition by user_id, order by date to achieve the result?
I'm blocked here because when evaluating the isactive value for a date and userid, how can I get access to prior 1 day value, or value of 2 days prior (and so on) when the previous day doesn't have value?
This answers the original version of the question.
I would suggest using recursion but only for each row:
with ts as (
select ts.*,
lead(date) over (partition by user_id order by date) as next_date
from tbl_statuslog ts
),
cte as (
select user_id, date, isactive,
coalesce(dateadd(day, -1, next_date), convert(date, getdate())) as end_date
from ts
union all
select user_id, dateadd(day, 1, date), isactive, end_date
from cte
where date < end_date
)
select user_id, date, isactive
from cte;
Here is a db<>fiddle.
Related
I have a table with this kind of structure (Sample only)
ID | STATUS | DATE |
--- -------- ------
1 OPEN 31-01-2022
2 CLOSE 15-11-2021
3 CLOSE 21-10-2021
4 OPEN 11-10-2021
5 OPEN 28-09-2021
I would like to know the counts of close vs open records by week. So it will be count(close)/count(open) where close.week = open.week
If there are no matching values, need to return 0 of course.
I got to this query below
SELECT *
FROM
(SELECT COUNT(*) AS 'CLOSE', DATEPART(WEEK, DATE) AS 'WEEKSA', DATEPART(YEAR, DATE) AS 'YEARA' FROM TABLE
WHERE STATUS IN ('CLOSE')
GROUP BY DATEPART(WEEK, DATE),DATEPART(YEAR, DATE)) TMPA
FULL OUTER JOIN
(SELECT COUNT(*) AS 'OPEN', DATEPART(WEEK, DATE) AS 'WEEKSB', DATEPART(YEAR, DATE) AS 'YEARB' FROM TABLE
WHERE STATUS IN ('OPEN')
GROUP BY DATEPART(WEEK, DATE),DATEPART(YEAR, DATE)) TMPB
ON TMPA.WEEKSA = TMPB.WEEKSB AND TMPA.YEARA = TMPB.YEARB
My results are as below (sample only)
close | weeksa | yeara | open | weeksb | yearb |
------ -------- ------ ------- ------- ------
3 2 2021
1 3 2021
1 4 2021
2 20 2021 2 20 2021
7 22 2021
2 23 2021
7 26 2021
7 27 2021
2 28 2021 14 28 2021
2 29 2021
10 30
24 31 2021
2 32 2021 5 32
4 33 2021
1 34 2021 13 34 2021
6 35 2021
1 36 2021
1 38 2021
1 39 2021
2 41 2021
4 43 2021
1 45 2021
2 46 2021 25 46 2021
1 47 2021 5 47 2021
4 48 2021
1 49 2021 20 49 2021
1 50 2021 17 50 2021
1 51 2021
How do I do the math now?
If I do another select the query fails. So I guess either syntax is bad or the whole concept is wrong.
The required result should look like this (Sample)
WEEK | YEAR | RATIO |
----- ------ -------
2 2021 0
3 2021 0
4 2021 0
5 2021 0.93
20 2021 0.1
22 2021 0
23 2021 0
26 2021 0
1 2022 0.75
2 2022 0.23
4 2022 0.07
Cheers!
I have added some test data to check the logic, adding the same in the code.
;with cte as(
select 1 ID, 'OPEN' as STATUS, cast('2021 -01-31' as DATE) DATE
union select 10 ID, 'CLOSE' as STATUS, cast('2021 -01-31' as DATE) DATE
union select 11 ID, 'CLOSE' as STATUS, cast('2021 -01-31' as DATE) DATE
union select 12 ID, 'CLOSE' as STATUS, cast('2021 -01-31' as DATE) DATE
union select 22 ID, 'CLOSE' as STATUS, cast('2021 -01-31' as DATE) DATE
union select 32 ID, 'CLOSE' as STATUS, cast('2021 -01-31' as DATE) DATE
union select 2,'CLOSE',cast('2021-11-28' as DATE)
union select 3,'CLOSE',cast('2021-10-21' as DATE)
union select 8,'CLOSE',cast('2021-10-21' as DATE)
union select 9,'CLOSE',cast('2021-10-21' as DATE)
union select 4,'OPEN', cast('2021-10-11' as DATE)
union select 5,'CLOSE', cast('2021-09-28' as DATE)
union select 6,'OPEN', cast('2021-09-27' as DATE)
union select 7,'CLOSE', cast('2021-09-26' as DATE) )
, cte2 as (
select DATEPART(WEEK,date) as week_number,* from cte)
,cte3 as(
select week_number,year(date) yr,count(case when status = 'open' then 1 end)open_count,count(case when status <> 'open' then 1 end) close_count from cte2 group by week_number,year(date))
select week_number as week,yr as year,
cast(case when open_count = 0 then 1.0 else open_count end /
case when close_count = 0 then 1.0 else close_count end as numeric(3,2)) as ratio
from cte3
How to add Non Null Values block by block without any grouping criteria :
Example input :
Machine Value DateTime
a null 1 Dec 2021 8:34AM
a 2 1 Dec 2021 8:35AM
a 1 1 Dec 2021 9:34AM
a 3 1 Dec 2021 10:11AM
a null 1 Dec 2021 11:14AM
a null 1 Dec 2021 11:16AM
a 5 1 Dec 2021 11:58AM
a 6 1 Dec 2021 11:59AM
Example output :
Machine Value DateTime SumValue
a null 1 Dec 2021 8:34AM
a 2 1 Dec 2021 8:35AM
a 1 1 Dec 2021 9:34AM
a 3 1 Dec 2021 10:11AM 6
a null 1 Dec 2021 11:14AM
a null 1 Dec 2021 11:16AM
a 5 1 Dec 2021 11:58AM
a 6 1 Dec 2021 11:59AM 11
I don't have any other grouping criteria other than device column , but I want sum block wise
You need to define the groups and use windowed SUM():
Table:
SELECT *
INTO Data
FROM (VALUES
('2021-12-12T09:00:01', 'a', null),
('2021-12-12T09:00:02', 'a', 2),
('2021-12-12T09:00:03', 'a', 1),
('2021-12-12T09:00:04', 'a', 3),
('2021-12-12T09:00:05', 'a', null),
('2021-12-12T09:00:06', 'a', null),
('2021-12-12T09:00:07', 'a', 5),
('2021-12-12T09:00:08', 'a', 6)
) v (Date, Machine, Value)
Statement:
SELECT
Date, Machine, Value,
CASE
WHEN ROW_NUMBER() OVER (PARTITION BY Machine, GroupNumber ORDER BY Date DESC) = 1
THEN SUM(Value) OVER (PARTITION BY Machine, GroupNumber ORDER BY (SELECT NULL))
END AS SumValue
FROM (
SELECT
*,
SUM(CASE WHEN Value IS NULL THEN 1 ELSE 0 END) OVER (PARTITION BY Machine ORDER BY Date) AS GroupNumber
FROM Data
) t
ORDER BY Machine, Date
Result:
Date Machine Value SumValue
2021-12-12T09:00:01 a
2021-12-12T09:00:02 a 2
2021-12-12T09:00:03 a 1
2021-12-12T09:00:04 a 3 6
2021-12-12T09:00:05 a
2021-12-12T09:00:06 a
2021-12-12T09:00:07 a 5
2021-12-12T09:00:08 a 6 11
I have table like below
Months cnt
Jan 2
Feb 3
Mar 5
I want output like below
Months cnt
Jan 2
Feb 2
Feb 3
Mar 2
Mar 3
Mar 5
I tried using below query but not getting the required output
Select distinct months, cnt, level
from (select months, cnt, rownum row_cnt
from tablename)
connect by level <= row_cnt
Order by months, cnt, level
Here's one option which converts month's names into their ordinal number (1 for Jan, 2 for Feb, etc.) and then - using self join - returns the result.
SQL> with test (months, cnt) as
2 (select 'jan', 2 from dual union all
3 select 'feb', 3 from dual union all
4 select 'mar', 5 from dual
5 ),
6 temp as
7 (select
8 months,
9 to_number(to_char(to_date(months, 'mon', 'nls_date_language=english'), 'mm')) mon,
10 cnt
11 from test
12 )
13 select a.months, b.cnt
14 from temp a join temp b on a.mon >= b.mon
15 order by a.mon, b.cnt;
MON CNT
--- ----------
jan 2
feb 2
feb 3
mar 2
mar 3
mar 5
6 rows selected.
SQL>
You need a self join:
select t.months, tt.cnt
from tablename t inner join tablename tt
on extract(month from to_date(t.Months,'MON')) >= extract(month from to_date(tt.Months,'MON'))
order by extract(month from to_date(t.Months,'MON')), tt.cnt
See the demo.
Results:
> MONTHS | CNT
> :----- | --:
> Jan | 2
> Feb | 2
> Feb | 3
> Mar | 2
> Mar | 3
> Mar | 5
Name Start_date end_date
aaa 01/02/2017 05/03/2017
bbb 03/05/2017 07/07/2017
ccc 02/01/2017 10/09/2017
I want to write a query that calculates the number of people who exist in the DB in a certain month/year.
Answer:
Jan 2017 1
Feb 2017 2
Mar 2017 3
Apr 2017 3
May 2017 2 (one person - aaa ,ended in May 2017)
Jun 2017 2
Jul 2017 1 (bbb ended in July 2017)
How do I write a PSQL query to get the desired output?
Thanks.
First, get the max and min dates in order to declare the dates range.
Second, with etc select all the month in the range.
Third, sum the number of the records in each dates.
Like:
declare #date date
declare #toDate date
select #date = min(Start_date),
#toDate = max(end_date)
from table_name
;With dt As
(
Select #date As [TheDate]
Union All
Select DateAdd(month, 1, TheDate) From dt Where [TheDate] < #toDate
)
select month(dt.TheDate),
year(dt.TheDate),
sum(case when table_name.Name is not null then 1 else 0 end)
from dt
left join table_name
on table_name.Start_date >= dt.TheDate
and table_name.end_date < dateadd(day,-1,dateAdd(month,1,dt.TheDate))
Anyone knows how to built temp table of week using T-SQL query?
I heard there has a lot of type of calculations for that, Gregorian or etc... My needs are ISO Week No and bind to temp table depends on week no.
The temp table has 2 columns : ISOWeekNo and WeekName
ISOWeekNo WeekName
1 01 Jan 2013 To 07 Jan 2013
2 08 Jan 2013 To 14 Jan 2013
How do I build programmatically in T-SQL Query based on ISO Week No?
Updated : I want to pass the parameter year only. e.g : 2013
EDIT: Added WHERE clause to terminate for sought year only.
This seems to match the Wikipedia description and I am sure there is room for optimisation.
Mikael, I copied your formatting code for the friendly column, thank you.
This code will work on SQL Server 2008 onwards because of the use of the ISOWEEK datepart.
use tempdb
go
DECLARE #Year SMALLINT = 2013
,#FirstISOWKDay DATETIME
;WITH FindISOWEEKFirstDay AS
(
SELECT DT = DATEADD(DAY, -7, DATEFROMPARTS(#Year, 1, 1))
UNION ALL
SELECT DATEADD(DAY, 1, DT)
FROM FindISOWEEKFirstDay
WHERE DATEADD(DAY, 1, DT) < DATEADD(DAY, 14, DATEFROMPARTS(#Year, 1, 1))
)
SELECT TOP 1 #FirstISOWKDay = DT
FROM FindISOWEEKFirstDay
WHERE DATEPART(ISO_WEEK, DT) = 1
ORDER BY DT ASC -- Eliminate probability of arb sorting (Thanks Mikael)
;WITH Base10 (n) AS
(
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1
)
,Base1000 (n) AS
(
SELECT ROW_NUMBER() OVER (ORDER BY (SELECT NULL))-1
FROM Base10 T1, Base10 T2, Base10 T3
)
SELECT Start = DATEADD(DAY, n*7, #FirstISOWKDay)
,[End] = DATEADD(DAY, n*7 + 6, #FirstISOWKDay)
,Friendly = CONVERT(VARCHAR(101), DATEADD(DAY, n*7, #FirstISOWKDay), 106)+' To '+CONVERT(VARCHAR(101), DATEADD(DAY, n*7 + 6, #FirstISOWKDay), 106)
,ISOWEEK = DATEPART(ISO_WEEK, DATEADD(DAY, n*7, #FirstISOWKDay))
FROM Base1000
-- Filter to terminate, resulting only in sought year's calendar
WHERE DATEPART(YEAR, DATEADD(DAY, n*7 + 6, #FirstISOWKDay)) = #Year
declare #Year int;
set #Year = 2016;
with C as
(
select datefromparts(#Year, 1, 1) as D
union all
select dateadd(day, 1, C.D)
from C
where C.D < datefromparts(#Year, 12, 31)
)
select datepart(iso_week, C.D) as ISOWeekNo,
convert(varchar(101), min(C.D), 106)+' To '+convert(varchar(101), max(C.D), 106) as WeekName
from C
group by datepart(iso_week, C.D),
case when datepart(month, C.D) = 12 and
datepart(iso_week, C.D) > 50
then 1
else 0
end
order by min(C.D)
option (maxrecursion 0);
Result:
ISOWeekNo WeekName
----------- --------------------------
53 01 Jan 2016 To 03 Jan 2016
1 04 Jan 2016 To 10 Jan 2016
2 11 Jan 2016 To 17 Jan 2016
3 18 Jan 2016 To 24 Jan 2016
4 25 Jan 2016 To 31 Jan 2016
5 01 Feb 2016 To 07 Feb 2016
6 08 Feb 2016 To 14 Feb 2016
7 15 Feb 2016 To 21 Feb 2016
.
.
.
47 21 Nov 2016 To 27 Nov 2016
48 28 Nov 2016 To 04 Dec 2016
49 05 Dec 2016 To 11 Dec 2016
50 12 Dec 2016 To 18 Dec 2016
51 19 Dec 2016 To 25 Dec 2016
52 26 Dec 2016 To 31 Dec 2016
This may help:
Select date '2012-12-31' + level*7 WK_STARTS_DT
, to_char(date '2012-12-31' + level*7, 'IW') ISO_WEEK
, to_char(date '2012-12-31' + level*7, 'WW') WEEK
From dual
Connect By Level <=
(
Select Round( (ADD_MONTHS(TRUNC(SYSDATE,'Y'),12)-TRUNC(SYSDATE,'Y') )/7, 0) From dual
) --365/7
/
WK_STARTS_DT ISO_WEEK WEEK
------------------------------------
1/7/2013 02 01
1/14/2013 03 02
1/21/2013 04 03
......
2/4/2013 06 05
2/11/2013 07 06
......
3/4/2013 10 09
To confirm week numbers:
http://www.epochconverter.com/date-and-time/weeknumbers-by-year.php?year=2013