insert missing row in table oracle - sql

Question

I have data in table like below:
Primary_id Serial_ID PRIMARY_ID SECONDARY_ID queue_ID
1 100 58 89 Q1428291
2 100 58 89 Q1428281
3 100 58 89 Q1428293
4 100 89 58 Q1428293
5 100 89 58 Q1428291
6 100 89 58 Q1428000281
7 200 16 28 Q1433144
8 200 16 28 Q1431953
9 200 16 28 Q1432397
10 200 16 28 Q1431921
11 200 28 16 Q1433144
12 200 28 16 Q1432397
13 200 28 16 Q1431921
We have primary_ID and Secondary_ID column. for serial_ID 100 we have 3 primary and 3 secondary records ..If you see the data Primary_ID become secondary and secondary become primary(3 each).but for serial_id 200 we have 4 primary records but 3 secondry records..
I want to insert missing record in the table.For ex serial_id 200 has missing data for primary ID 28 so insert this into table.Please assist

Answer 1

You can use something like this. In the temp_table, I put rows into two different types ('P' or 'S').
I assume that the queue_id = 'Q1428000281' (from row 6) is a mistake, and It should be 'Q1428281'.
drop table table_test ;
create table table_test (id, serial_id, primary_id, secondary_id, queue_id) as (
select 1 , 100, 58, 89, 'Q1428291' from dual union all
select 2 , 100, 58, 89, 'Q1428281' from dual union all
select 3 , 100, 58, 89, 'Q1428293' from dual union all
select 4 , 100, 89, 58, 'Q1428293' from dual union all
select 5 , 100, 89, 58, 'Q1428291' from dual union all
select 6 , 100, 89, 58, 'Q1428000281' from dual union all
select 7 , 200, 16, 28, 'Q1433144' from dual union all
select 8 , 200, 16, 28, 'Q1431953' from dual union all
select 9 , 200, 16, 28, 'Q1432397' from dual union all
select 10, 200, 16, 28, 'Q1431921' from dual union all
select 11, 200, 28, 16, 'Q1433144' from dual union all
select 12, 200, 28, 16, 'Q1432397' from dual union all
select 13, 200, 28, 16, 'Q1431921' from dual
)
;
insert into table_test (id, serial_id, primary_id, secondary_id, queue_id)
with temp_table as (
select t.*
, case when primary_id < secondary_id then 'P' else 'S' end type_t
from table_test t
)
select v_max.id_max + rownum ID, SERIAL_ID, PRIMARY_ID, SECONDARY_ID, queue_id
from (
select SERIAL_ID
, max(SECONDARY_ID) PRIMARY_ID
, min(PRIMARY_ID) SECONDARY_ID
, max(queue_id)queue_id
, count(TYPE_T) cnt
from temp_table tp
group by SERIAL_ID
, least(PRIMARY_ID, SECONDARY_ID)
, greatest(PRIMARY_ID, SECONDARY_ID)
, QUEUE_ID
having count(TYPE_T) != 2
)t
cross join (select max(id) id_max from table_test) v_max
;

Answer 2

Hmmm . . . You can generate the missing rows using cross join and then something like left join or not exists:
select sp.serial_id, sp.primary_id, sp.secondary_id
from (select d.serial_id, d.primary_id
from data d
) sp join
(select d.serial_id, d.secondary_id
from data d
) ss
on sp.serial_id = ss.serial_id left join
data d
on d.serial_id = sp.serial_id and
d.primary_id = sp.primary_id and
d.secondary_id = sp.secondary_id
where d.serial_id is null;
You can then insert the results of this query into your table.
Your question doesn't specify what value of queue_id should be used. NULL seems like a very reasonable value under these circumstances.