I would like to get for each contract the record with the highest serial for the highest dates
ID CONTRCT C_DATE SERIAL
--------------------------------
1 ABC 20201201 1
2 ABC 20201201 2
3 ABC 20201201 3
4 DEF 20201201 3
4 DEF 20201210 1
5 DEF 20201210 2
Required results:
ID CONTRCT C_DATE SER
3 ABC 20201201 3
6 DEF 20201210 2
I achieved the results with two layers of self joins but may table is quite big and it takes a long time.
Is there a more efficient way?
My Query:
SELECT t3.ID
,t3.CONTRCT
,t3.C_DATE
,t3.SER
FROM (
SELECT ID
,tbl.CONTRCT
,tbl.C_DATE
,tbl.SER
FROM (
SELECT CONTRCT
,C_DATE
,max(SER) mx
FROM tbl
GROUP BY CONTRCT
,C_DATE
) t1
JOIN tbl ON t1.C_DATE = tbl.C_DATE
AND t1.mx = tbl.SER
AND t1.CONTRCT = tbl.CONTRCT
) t3
JOIN (
SELECT CONTRCT
,MAX(C_DATE) MAX_DATE
FROM (
SELECT ID
,tbl.CONTRCT
,tbl.C_DATE
,tbl.SER
FROM (
SELECT CONTRCT
,C_DATE
,max(SER) mx
FROM tbl
GROUP BY CONTRCT
,C_DATE
) t1
JOIN tbl ON t1.C_DATE = tbl.C_DATE
AND t1.mx = tbl.SER
AND t1.CONTRCT = tbl.CONTRCT
) t2
GROUP BY CONTRCT
) t4 ON t4.CONTRCT = t3.CONTRCT
AND t4.MAX_DATE = t3.C_DATE
I would suggest window functions:
select t.*
from (select t.*,
row_number() over (partition by contract order by date desc, ser desc) as seqnum
from tbl t
) t
where seqnum = 1;
It should works for you:
SELECT
t.contact,
MAX(t.C_DATE) C_DATE2,
(SELECT MAX(SERIAL) FROM test t2 WHERE t2.contact = t.contact AND t2.C_DATE=MAX(t.C_DATE) LIMIT 1) SERIAL
FROM test t
GROUP BY
t.contact;
If I was you, definitely will define an index of contact, date, serial on my table as well.
Related
I've a table that stores the historical data, what i'm trying to do is trying to capture the max seq record. i can do that, but i need to include the tr_type, then i'll use the outupt to join with another table. below is ex of my data
CLM_NO SEQ SUB TR_TYPE
12345 1 1 50
12345 1 2 50
12345 2 1 60
12345 2 2 60
i want to return only the last row
You can try to use exists and correlated subquery
SELECT *
FROM T t1
WHERE exists(
SELECT 1
FROM T tt
GROUP BY tt.CLM_NO
HAVING MAX(tt.SEQ) = t1.SEQ AND MAX(tt.SUB) = t1.SUB
)
EDIT
You can try to use ROW_NUMBER window function.
SELECT * FROM (
SELECT *,ROW_NUMBER() OVER(PARTITION BY CLM_NO ORDER BY TRAN_SEQ DESC,TRAN_SUB DESC) rn
FROM TBL t1
)t1
where rn = 1
Example:
id Pricemoney time/date
1 100 01/20/2017
1 10 01/21/2017
1 1000 01/21/20147
2 10 01/23/2017
2 100 01/24/2017
3 1000 01/19/2017
3 100 01/22/2017
3 10 01/24/2017
I want to run a SQL query where I can display all the Id and it's pricemoney BUT NOT include the first record (based on time/date) per unique
Just to clarify what I do not want to be displayed
userid Pricemoney issuedate
1 100 01/20/2017 -- not included
1 10 01/21/2017
1 1000 01/21/20147
2 10 01/23/2017 --- not inlcuded
2 100 01/24/2017
3 1000 01/19/2017 -- not included
3 100 01/22/2017
3 10 01/24/2017
Expected result:
id Pricemoney time/date
1 10 01/21/2017
1 1000 01/21/20147
2 100 01/24/2017
3 100 01/22/2017
3 10 01/24/2017
You can use row_number():
select t.*
from (select t.*,
row_number() over (partition by id order by time_date asc) as seqnum
from <tablename> t
) t
where seqnum > 1;
If you want to keep single rows, you can do:
select t.*
from (select t.*,
row_number() over (partition by id order by time_date asc) as seqnum,
count(*) over (partition by id) as cnt
from <tablename> t
) t
where seqnum > 1 and cnt > 1;
You may use EXISTS
select t1.*
from data t1
where exists (
select 1
from data t2
where t1.id = t2.id and t2.time_date < t1.time_date
)
you can try this :
select data1.id,data1.Date,data1.Pricemoney from data1
left join (
select id ,min(Date) date from data1
group by id
) as t
on data1.date= t.date and t.id = data1.id
where t.id is null
group by data1.id,data1.Date,data1.Pricemoney
above query not duplicated records also ignore, if want
not duplicated records then use having count(id) > 1 in left query e,g.
select data1.id,data1.Date,data1.Pricemoney from data1
left join (
select id ,min(Date) date from data1
group by id
having COUNT(id) > 1
) as t
on data1.date= t.date and t.id = data1.id
where t.id is null
group by data1.id,data1.Date,data1.Pricemoney
Can't see the wood for the trees on this and I'm sure it's simple.
I'm trying to return the max ID for a related record in a joined table
Table1
NiD
Name
1
Peter
2
John
3
Arthur
Table2
ID
NiD
Value
1
1
5
2
2
10
3
3
10
4
1
20
5
2
15
Max Results
NiD
ID
Value
1
4
20
2
5
15
3
3
10
You can use row_number() for this:
select NiD, ID, Value
from (select t2.*,
row_number() over (partition by NiD order by ID desc) as seqnum
from table2 t2
) t2
where seqnum = 1;
As the question is stated, you do not need table1, because table2 has all the ids.
This is how I'd do it, I think ID and Value will be NULL when Table2 does not have a corresponding entry for a Table1 record:
SELECT NiD, ID, [Value]
FROM Table1
OUTER APPLY (
SELECT TOP 1 ID, [Value]
FROM Table2
WHERE Table1.NiD = Table2.NiD
ORDER BY [Value] DESC
) AS Top_Table2
CREATE TABLE Names
(
NID INT,
[Name] VARCHAR(MAX)
)
CREATE TABLE Results
(
ID INT,
NID INT,
VALUE INT
)
INSERT INTO Names VALUES (1,'Peter'),(2,'John'),(3,'Arthur')
INSERT INTO Results VALUES (1,1,5),(2,2,10),(3,3,10),(4,1,20),(5,2,15)
SELECT a.NID,
r.ID,
a.MaxVal
FROM (
SELECT NID,
MAX(VALUE) as MaxVal
FROM Results r
GROUP BY NID
) a
JOIN Results r
ON a.NID = r.NID AND a.MaxVal = r.VALUE
ORDER BY NID
Here's what I have used in similar situations, performance was fine, provided that the data set wasn't too large (under 1M rows).
SELECT
table1.nid
,table2.id
,table2.value
FROM table1
INNER JOIN table2 ON table1.nid = table2.nid
WHERE table2.value = (
SELECT MAX(value)
FROM table2
WHERE nid = table1.nid)
ORDER BY 1
I need to select data base upon three conditions
Find the latest date (StorageDate Column) from the table for each record
See if there is more then one entry for date (StorageDate Column) found in first step for same ID (ID Column)
and then see if DuplicateID is = 2
So if table has following data:
ID |StorageDate | DuplicateTypeID
1 |2014-10-22 | 1
1 |2014-10-22 | 2
1 |2014-10-18 | 1
2 |2014-10-12 | 1
3 |2014-10-11 | 1
4 |2014-09-02 | 1
4 |2014-09-02 | 2
Then I should get following results
ID
1
4
I have written following query but it is really slow, I was wondering if anyone has better way to write it.
SELECT DISTINCT(TD.RecordID)
FROM dbo.MyTable TD
JOIN (
SELECT T1.RecordID, T2.MaxDate,COUNT(*) AS RecordCount
FROM MyTable T1 WITH (nolock)
JOIN (
SELECT RecordID, MAX(StorageDate) AS MaxDate
FROM MyTable WITH (nolock)
GROUP BY RecordID)T2
ON T1.RecordID = T2.RecordID AND T1.StorageDate = T2.MaxDate
GROUP BY T1.RecordID, T2.MaxDate
HAVING COUNT(*) > 1
)PT ON TD.RecordID = PT.RecordID AND TD.StorageDate = PT.MaxDate
WHERE TD.DuplicateTypeID = 2
Try this and see how the performance goes:
;WITH
tmp AS
(
SELECT *,
RANK() OVER (PARTITION BY ID ORDER BY StorageDate DESC) AS StorageDateRank,
COUNT(ID) OVER (PARTITION BY ID, StorageDate) AS StorageDateCount
FROM MyTable
)
SELECT DISTINCT ID
FROM tmp
WHERE StorageDateRank = 1 -- latest date for each ID
AND StorageDateCount > 1 -- more than 1 entry for date
AND DuplicateTypeID = 2 -- DuplicateTypeID = 2
You can use analytic function rank , can you try this query ?
Select recordId from
(
select *, rank() over ( partition by recordId order by [StorageDate] desc) as rn
from mytable
) T
where rn =1
group by recordId
having count(*) >1
and sum( case when duplicatetypeid =2 then 1 else 0 end) >=1
I have a table_1:
id custno
1 1
2 2
3 3
and a table_2:
id custno qty descr
1 1 10 a
2 1 7 b
3 2 4 c
4 3 7 d
5 1 5 e
6 1 5 f
When I run this query to show the minimum order quantities from every customer:
SELECT DISTINCT table_1.custno,table_2.qty,table_2.descr
FROM table_1
LEFT OUTER JOIN table_2
ON table_1.custno = table_2.custno AND qty = (SELECT MIN(qty) FROM table_2
WHERE table_2.custno = table_1.custno )
Then I get this result:
custno qty descr
1 5 e
1 5 f
2 4 c
3 7 d
Customer 1 appears twice each time with the same minimum qty (& a different description) but I only want to see customer 1 appear once. I don't care if that is the record with 'e' as a description or 'f' as a description.
First of all... I'm not sure why you need to include table_1 in the queries to begin with:
select custno, min(qty) as min_qty
from table_2
group by custno;
But just in case there is other information that you need that wasn't included in the question:
select table_1.custno, ifnull(min(qty),0) as min_qty
from table_1
left outer join table_2
on table_1.custno = table_2.custno
group by table_1.custno;
"Generic" SQL way:
SELECT table_1.custno,table_2.qty,table_2.descr
FROM table_1, table_2
WHERE table_2.id = (SELECT TOP 1 id
FROM table_2
WHERE custno = table_1.custno
ORDER BY qty )
SQL 2008 way (probably faster):
SELECT custno, qty, descr
FROM
(SELECT
custno,
qty,
descr,
ROW_NUMBER() OVER (PARTITION BY custno ORDER BY qty) RowNum
FROM table_2
) A
WHERE RowNum = 1
If you use SQL-Server you could use ROW_NUMBER and a CTE:
WITH CTE AS
(
SELECT table_1.custno,table_2.qty,table_2.descr,
RN = ROW_NUMBER() OVER ( PARTITION BY table_1.custno
Order By table_2.qty ASC)
FROM table_1
LEFT OUTER JOIN table_2
ON table_1.custno = table_2.custno
)
SELECT custno, qty,descr
FROM CTE
WHERE RN = 1
Demolink