Dynamic Queue Based on Key - rabbitmq

I have a system with many users.
Every user is allowed to do 1 action at a time.
I want to create a "different" queue for every user.
So let's say I push
{user: 1, todo: 'Get Money'}
{user: 1, todo: 'Get Pizza'}
{user: 1, todo: 'Get a car'}
{user: 2, todo: 'Get Money'}
{user: 2, todo: 'Get a car'}
I have basically created two queues.
Let's assume I have 2 or more workers. Only one worker will work per queue.
I am trying to find a queue system that can do it without using an external database.
Which queue system could handle it the best?

mongo queue will do the job
http://learnmongodbthehardway.com/schema/queues/
https://dltlabs.medium.com/mongodb-queue-and-processing-in-distributed-systems-a805b32f6e76
http://mongodb.github.io/node-mongodb-native/schema/chapter7/
https://github.com/chilts/mongodb-queue

Related

Is there a bounded variant of UnicastProcessor?

The UnicastProcessor requests Long.MAX_VALUE elements on subscription and there is no way to set this while creating the processor.
I want to limit the number of requested items (to say 1) and only request next item once the previous items have been replayed to the subscriber. Also, the processor should only keep 1 subscriber and disconnect on second subscription, just like UnicastProcessor.

ActiveMQ Durable Subscriber with jmsMessageId

I'm new to ActiveMQ and trying to find anything that explicitly outlines how JMSMessageID behaves with durable subscribers and selectors, however, I am struggling to find much.
As an example: JMSType = 'car' AND color = 'blue' AND weight > 2500 as a selector. Each subscriber will only receive messages from the topic where the criteria match. When each receives said messages are the JSMMessageID unique for each subscriber or are they unique for the entire topic before it was filtered by the selector for the subscriber.
If not is there a way that I can get the JSMessageID to be unique for each subscriber so that it can be used as a form of sequence number using custom messageID layout: 1, 2, 3... ad infinitum.
The Message ID is set by the producer at the time of send, the broker passes along a copy of the message to each Topic subscription (durable or not) with the message ID that it was sent with. You cannot alter the ID the broker uses that value to track the message and ensure that it is preserved until each subscription that it was dispatched to or stored for has acknowledged it.

Can a telegram bot block a specific user?

I have a telegram bot that for any received message runs a program in the server and sends its result back. But there is a problem! If a user sends too many messages to my bot(spamming), it will make server so busy!
Is there any way to block the people whom send more than 5 messages in a second and don't receive their messages anymore? (using telegram api!!)
Firstly I have to say that Telegram Bot API does not have such a capability itself, Therefore you will need to implement it on your own and all you need to do is:
Count the number of the messages that a user sends within a second which won't be so easy without having a database. But if you have a database with a table called Black_List and save all the messages with their sent-time in another table, you'll be able to count the number of messages sent via one specific ChatID in a pre-defined time period(In your case; 1 second) and check if the count is bigger than 5 or not, if the answer was YES you can insert that ChatID to the Black_List table.
Every time the bot receives a message it must run a database query to see that the sender's chatID exists in the Black_List table or not. If it exists it should continue its own job and ignore the message(Or even it can send an alert to the user saying: "You're blocked." which I think can be time consuming).
Note that as I know the current telegram bot API doesn't have the feature to stop receiving messages but as I mentioned above you can ignore the messages from spammers.
In order to save time, You should avoid making a database connection
every time the bot receives an update(message), instead you can load
the ChatIDs that exist in the Black_List to a DataSet and update the
DataSet right after the insertion of a new spammer ChatID to the
Black_List table. This way the number of the queries will reduce
noticeably.
I have achieved it by this mean:
# Using the ttlcache to set a time-limited dict. you can adjust the ttl.
ttl_cache = cachetools.TTLCache(maxsize=128, ttl=60)
def check_user_msg_frequency(message):
print(ttl_cache)
msg_cnt = ttl_cache[message.from_user.id]
if msg_cnt > 3:
now = datetime.now()
until = now + timedelta(seconds=60*10)
bot.restrict_chat_member(message.chat.id, message.from_user.id, until_date=until)
def set_user_msg_frequency(message):
if not ttl_cache.get(message.from_user.id):
ttl_cache[message.from_user.id] = 1
else:
ttl_cache[message.from_user.id] += 1
With these to functions above, you can record how many messages sent by any user in the period. If a user's messages sent more than expected, he would be restricted.
Then, every handler you called should call these two functions:
#bot.message_handler(commands=['start', 'help'])
def handle_start_help(message):
set_user_msg_frequency(message)
check_user_msg_frequency(message)
I'm using pyTelegramBotAPI this module to handle.
I know I'm late to the party, but here is another simple solution that doesn't use a Db:
Create a ConversationState class to attach to each telegram Id when they start to chat with the bot
Then add a LastMessage DateTime variable to the ConversationState class
Now every time you receive a message check if enought time has passed from the LasteMessage DateTime, if not enought time has passed answer with a warning message.
You can also implement a timer that deletes the conversation state class if you are worried about performance.

Can I get the current queue in perform method of worker with sidekiq/redis?

I want to be able to delete all job in queue, but I don't know what queue is it. I'm in perform method of my worker and I need to get the "current queue", the queue where the current job is come from.
for this time I use :
require 'sidekiq/api'
queue = Sidekiq::Queue.new
queue.each do |job|
job.delete
end
because I just use "default queue", It's work.
But now I will use many queues and I can't specify only one queue for this worker because I need use a lots for a server load balancing.
So how I can get the queue where we are in perform method?
thx.
You can't by design, that's orthogonal context to the job. If your job needs to know a queue name, pass it explicitly as an argument.
This is much faster:
Sidekiq::Queue.new.clear
These docs show that you can access all running job information wwhich includes the jid (job ID) and queue name for each job
inside the perform method you have access to the jid with the jid accessor. From that you can find the current job and get the queue name
workers = Sidekiq::Workers.new
this_worker = workers.find { |_, _, work|
work['payload']['jid'] == jid
}
queue = this_worker[2]['queue']
however, the content of Sidekiq::Workers can be up to 5 seconds out of date, so you should only try this after your worker has been running at least 5 seconds, which may not be ideal

Camel-rabbitmq: Consuming from multiple rabbitmq queues in a single camel consumer

I have the following scenario:
There are 3 rabbitmq queues to which producers push their messages based on the priority of the message.(myqueue_high, myqueue_medium, myqueue_low)
I want to have a single consumer which can pull from these queues in order or priority i.e. it keeps pulling from high queue as long as messages are there. o/w it pulls from medium. If medium is also empty it pulls from low.
How do i achieve this? Do i need to write a custom component?
It would be easier to put all the messages to one queue but with different priorities. That way, the priority sorting would be done in the broker and the Camel consumer would get the messages already sorted by priority. However, RabbitMQ implements the FIFO principle and does not support priority handling (yet).
Solution 1
Camel allows you to reorganise messages based on some comparator using a Resequencer: https://camel.apache.org/resequencer.html:
from("rabbitmq://hostname[:port]/myqueue_high")
.setHeader("priority", constant(9))
.to("direct:messageProcessing");
from("rabbitmq://hostname[:port]/myqueue_medium")
.setHeader("priority", constant(5))
.to("direct:messageProcessing");
from("rabbitmq://hostname[:port]/myqueue_low")
.setHeader("priority", constant(1))
.to("direct:messageProcessing");
// sort by priority by allowing duplicates (message can have same priority)
// and use reverse ordering so 9 is first output (most important), and 0 is last
// (of course we could have set the priority the other way around, but this way
// we keep align with the JMS specification...)
// use batch mode and fire every 3th second
from("direct:messageProcessing")
.resequence(header("priority")).batch().timeout(3000).allowDuplicates().reverse()
.to("mock:result");
That way, all incoming messages are routed to the same sub route (direct:messageProcessing) where the messages are reordered according the priority header set by the incoming routes.
Solution 2
Use SEDA with a prioritization queue:
final PriorityBlockingQueueFactory<Exchange> priorityQueueFactory = new PriorityBlockingQueueFactory<Exchange>();
priorityQueueFactory.setComparator(new Comparator<Exchange>() {
#Override
public int compare(final Exchange exchange1, final Exchange exchange2) {
final Integer prio1 = (Integer) exchange1.getIn().getHeader("priority");
final Integer prio2 = (Integer) exchange2.getIn().getHeader("priority");
return -prio1.compareTo(prio2); // 9 has higher priority then 0
}
});
final SimpleRegistry registry = new SimpleRegistry();
registry.put("priorityQueueFactory", priorityQueueFactory);
final ModelCamelContext context = new DefaultCamelContext(registry);
// configure and start your context here...
The route definition:
from("rabbitmq://hostname[:port]/myqueue_high")
.setHeader("priority", constant(9))
.to("seda:priority?queueFactory=#priorityQueueFactory"); // reference queue in registry
from("rabbitmq://hostname[:port]/myqueue_medium")
.setHeader("priority", constant(5))
.to("seda:priority?queueFactory=#priorityQueueFactory");
from("rabbitmq://hostname[:port]/myqueue_low")
.setHeader("priority", constant(1))
.to("seda:priority?queueFactory=#priorityQueueFactory");
from("seda:priority")
.to("direct:messageProcessing");
Solution 3
Use JMS such as Camel's ActiveMQ component instead of SEDA if you need persistence in case of failures. Just forward the incoming messages from RabbitMQ to a JMS destination with setting the JMSPriority header.
Solution 4
Skip the RabbitMQ entirely and just use a JMS broker such as ActiveMQ that supports prioritization.