Would you, pleace, help me, to count cummulative sum in sql server 2017. Condition is: 1) partition by client 2) order by date_tm. Desirable result is in the table below.
create table #clients (client nvarchar(1)
, date_tm datetime
,sum_pay int
, desirable_result int)
insert into #clients
(client, date_tm, sum_pay, desirable_result)
select '1', '2020-01-01', 10, 10 union all
select '1', '2020-01-02', 20, 30 union all
select '2', '2020-01-03', 20, 60 union all
select '2', '2020-01-01', 20, 20 union all
select '2', '2020-01-02', 20, 40 union all
select '3', '2020-01-01', 20, 20 union all
select '3', '2020-01-04', 20, 70 union all
select '3', '2020-01-02', 30, 50
select * from #clients
drop table if exists #clients
Thank you very much.
are finding below
select c.*,sum(sum_pay) over(partition by client order by date_tm)
from #clients c
You can use sum()over() window function as below:
select * ,SUM (sum_pay) OVER (partition by client order by date_tm) AS cummulativesum from #clients
SELECT * ,
CASE WHEN desirable_result = cum_sum THEN 'OK' ELSE 'NO' END AS Status
FROM
(
select
*,
SUM (sum_pay) OVER (partition by client order by date_tm) AS cum_sum
from #clients as tbl
) as a
with this code you can compare, desirable_result and cummilative sum
Related
I have a transaction table that stores amount paid(+amount) and corrected (-ve amount). I am looking for a query that would ignore a positive and a negative matching value of the amount for a date and post the sum of remaining number of transactions ignoring the 2 .
Id Dept Date Amount
1 A 21-Apr-21 1100
1 A 21-Apr-21 1100
1 A 21-Apr-21 -1100
1 A 07-Apr-21 1100
1 A 03-Feb-21 100
1 A 12-Jan-21 500
The sql query should ignore Rows 2 and 3 as the amount was corrected and should not be counted as a transaction.
o/p should be
Id Dept sum(Amount) count(transaction)
1 A 2800 4
If I got you well, you can use below solution for that purpose.
I first ranked all the occurrences of the same amount value, before I grouped them in order to make oracle ignore all matching positive and negative values.
with YourSample (Id, Dept, Date#, Amount) as (
select 1, 'A', to_date('21-Apr-21', 'dd-Mon-RR', 'nls_date_language=english'), 1100 from dual union all
select 1, 'A', to_date('21-Apr-21', 'dd-Mon-RR', 'nls_date_language=english'), 1100 from dual union all
select 1, 'A', to_date('21-Apr-21', 'dd-Mon-RR', 'nls_date_language=english'), -1100 from dual union all
select 1, 'A', to_date('07-Apr-21', 'dd-Mon-RR', 'nls_date_language=english'), 1100 from dual union all
select 1, 'A', to_date('03-Feb-21', 'dd-Mon-RR', 'nls_date_language=english'), 100 from dual union all
select 1, 'A', to_date('12-Jan-21', 'dd-Mon-RR', 'nls_date_language=english'), 500 from dual
)
, ranked_rws as (
select Id, Dept, Date#
, abs(Amount)Amount
, sign(AMOUNT) row_sign
, row_number() OVER (PARTITION BY Id, Dept, Amount order by date#, rownum) rn
from YourSample t
)
, ingored_matched_pos_neg_values as (
select ID, DEPT, sum(row_sign) * AMOUNT AMOUNT/*, sum(row_sign)*/
from ranked_rws
group by ID, DEPT, AMOUNT, RN
having sum(row_sign) != 0 /* this line filters out all matching positive
and negatives values (equality in terms of occurrences)*/
)
select ID, DEPT, sum(AMOUNT) sum, count(*) transactions
from ingored_matched_pos_neg_values
group by ID, DEPT
;
demo
Maybe some idea like this could work.
SELECT Id, Dept, Date, Amount, COUNT(*) AS RecordCount
INTO #temptable
FROM table GROUP BY ...
SELECT
t1.Id
,t1.Dept
,t1.Date
,(t1.RecordCount - COALESCE(t2.RecordCount, 0)) * t1.Amount
,t1.RecordCount - COALESCE(t2.RecordCount, 0)
FROM #temptable t1
LEFT JOIN #temptable t2 ON
t1.Id = t2.Id
AND t1.Dept = t2.Dept
AND t1.Date = t2.Date
AND (t1.Amount * -1) = t2.Amount
I have created a Transaction table with columns card_id, amount, created_at. There may be more than 1 row of one user so I want to return the value card_id, sum(amount), first created_at date of all users.
CREATE TABLE Transactions(card_id int, amount money, created_at date)
INSERT INTO Transactions(card_id, amount, created_at)
SELECT 1, 500, '2016-01-01' union all
SELECT 1, 100, '2016-01-01' union all
SELECT 1, 100, '2016-01-01' union all
SELECT 1, 200, '2016-01-02' union all
SELECT 1, 300, '2016-01-03' union all
SELECT 2, 100, '2016-01-04' union all
SELECT 2, 200, '2016-01-05' union all
SELECT 3, 700, '2016-01-06' union all
SELECT 1, 100, '2016-01-07' union all
SELECT 2, 100, '2016-01-07' union all
SELECT 3, 100, '2016-01-07'
I have created function for that but one of my client says I need query not function. Can anyone here suggest what query to use?
CREATE FUNCTION [dbo].[card_id_data]()
RETURNS #t TABLE
(
card_id text,
amount money,
dateOfFirstTransaction date
)
AS
BEGIN
INSERT INTO #t(card_id)
SELECT DISTINCT(card_id) FROM Transactions;
UPDATE #t
SET dateOfFirstTransaction = b.createdat
FROM
(SELECT DISTINCT(card_id) cardid,
MIN(created_at) createdat
FROM Transactions
WHERE amount < 0
GROUP BY card_id) b
WHERE card_id = b.cardid;
UPDATE #t
SET amount = T.AMOUNT
FROM
(SELECT
card_id AS cardid, SUM(MIN(AMOUNT)) AMOUNT, created_at
FROM Transactions
WHERE amount < 0
GROUP BY card_id, created_at) T
WHERE card_id = cardid
AND dateOfFirstTransaction = created_at;
RETURN
END
I want a result as shown in this screenshot:
You can use DENSE_RANK for this. It will number the rows, taking into account tied places (same dates)
SELECT
t.card_id,
SumAmount = SUM(amount),
FirstDate = MIN(t.created_at)
FROM (
SELECT *,
rn = DENSE_RANK() OVER (PARTITION BY t.card_id ORDER BY t.created_at)
FROM dbo.Transactions t
) t
WHERE t.rn = 1
GROUP BY t.card_id;
If the dates are actually dates and times, and you want to sum the whole day, change t.created_at to CAST(t.created_at AS date)
Try this:
/*
CREATE TABLE dbo.Transactions
(
card_id INT,
amount MONEY,
created_at DATE
);
INSERT INTO dbo.Transactions (card_id, amount, created_at)
VALUES (1, 500, '2016-01-01'),
(1, 100, '2016-01-01'),
(1, 100, '2016-01-01'),
(1, 200, '2016-01-02'),
(1, 300, '2016-01-03'),
(2, 100, '2016-01-04'),
(2, 200, '2016-01-05'),
(3, 700, '2016-01-06'),
(1, 100, '2016-01-07'),
(2, 100, '2016-01-07'),
(3, 100, '2016-01-07');
*/
WITH FirstDatePerCard AS
(
SELECT
card_id,
FirstDate = MIN(created_at)
FROM
dbo.Transactions
GROUP BY
card_id
)
SELECT DISTINCT
t.card_id,
SumAmount = SUM(amount) OVER (PARTITION BY t.card_id),
FirstDate = f.FirstDate
FROM
FirstDatePerCard f
INNER JOIN
dbo.Transactions t ON f.card_id = t.card_id AND f.FirstDate = t.created_at
You'll get an output something like this:
card_id SumAmount FirstDate
--------------------------------
1 700.00 2016-01-01
2 100.00 2016-01-04
3 700.00 2016-01-06
Is that what you're looking for??
UPDATE: OK, so you want to sum the amount only for the first_date, for every card_id - is that correct? (wasn't clear from the original question)
Updated my solution accordingly
I need to write a query that gives me the count with the following logic. The example below shows that ACCOUNT_ID 123 signup in 2020-02-21 so M0 is 1 and then the same ACCOUNT_ID had an event in the consecutive month so M1 is 1.
M0 is a the signup date
M1 is signup date + 1 month
M2 is signup date + 2 consecutive months
M3 is signup date + 3 consecutive months
WITH M_O AS (
SELECT
parsed_data."ACCOUNT_ID" AS "parsed_data.account_id",
MIN(TO_CHAR(TO_DATE(parsed_data."TIMESTAMP"::timestamp_ntz ), 'YYYY-MM-DD')) AS "SIGNUP",
COUNT(DISTINCT (parsed_data."ACCOUNT_ID") ) AS "COUNT_USERS_O"
FROM "PUBLIC"."PARSED_DATA"
AS parsed_data
WHERE (parsed_data."ACCOUNT_ID") IS NOT NULL
AND (((parsed_data."EVENT") = 'Started'))
AND (
((TO_CHAR(TO_DATE(parsed_data."TIMESTAMP"::timestamp_ntz ), 'YYYY-MM-DD')) >= '2020-02-21')
AND ((parsed_data."TIMESTAMP"::timestamp_ntz ) < CURRENT_DATE())
)
GROUP BY 1),
M_1 AS (
SELECT
parsed_data."ACCOUNT_ID" AS "parsed_data.account_id",
TO_CHAR(TO_DATE(parsed_data."TIMESTAMP"::timestamp_ntz ), 'YYYY-MM-DD') AS "parsed_data.timestamp_date",
COUNT(DISTINCT (parsed_data."ACCOUNT_ID") ) AS "COUNT_USERS_1"
FROM "PUBLIC"."PARSED_DATA"
AS parsed_data INNER JOIN M_O ON parsed_data.account_id = M_O."parsed_data.account_id"
WHERE
(parsed_data."ACCOUNT_ID") IS NOT NULL
AND (((parsed_data."EVENT") = 'Started'))
AND (
(TO_CHAR(TO_DATE(parsed_data."TIMESTAMP"::timestamp_ntz ), 'YYYY-MM-DD')) >= DATEADD('MONTH', 1, SIGNUP)
AND ((parsed_data."TIMESTAMP"::timestamp_ntz ) < CURRENT_DATE())
)
GROUP BY 1,2
)
It looks like you want to create cohorts? As in "establish the creation date for each id, and then look how they changed their behavior every month thereafter".
This code should work:
with events as (
select 1 id, '2020-01-01'::date e_date
union all select 1, '2020-02-03'
union all select 2, '2020-03-01'
union all select 2, '2020-05-08'
union all select 3, '2020-08-01'
union all select 3, '2020-09-02'
union all select 3, '2020-09-22'
union all select 3, '2020-09-30'
union all select 3, '2020-10-10'
),
first_per_id as (
select id, min(e_date) first_date
from events
group by id
)
select a.id
, count_if(e_date>=dateadd(month, 0, first_date) and e_date<dateadd(month, 1, first_date)) m0
, count_if(e_date>=dateadd(month, 1, first_date) and e_date<dateadd(month, 2, first_date)) m1
, count_if(e_date>=dateadd(month, 2, first_date) and e_date<dateadd(month, 3, first_date)) m2
from events a
join first_per_id b
where a.id=b.id
group by 1
I have table with following structure:
And I'm trying to get grouped values between two dates, problem is, that i would like to have also retuned rows for dates which are not in select, for example i have range for
WHERE m.date BETWEEN "2014-09-02" AND "2014-09-10"
But for example in date 2014-09-06 is no related row in table, so in result should be
2014-09-06| 0 | 0 | 0 | 0
How can i do it please? (if is it possible with SQLLite database).
Here is the query which i'm using:
SELECT substr(m.date, 1, 10) as my_date, COUNT(m.ID) AS 'NUMBER_OF_ALL_CALLS',
(SELECT COUNT(*) FROM dialed_calls subq WHERE subq.call_result = 'DONE'
AND substr(m.date, 1, 10) = substr(subq.DATE, 1, 10)) as 'RESULT_DONE',
(SELECT COUNT(*) FROM dialed_calls subq WHERE subq.call_result = 'NOT_INTERESTED'
AND substr(m.date, 1, 10) = substr(subq.DATE, 1, 10)) as 'RESULT_NOT_INTERESTED',
(SELECT COUNT(*) FROM dialed_calls subq WHERE subq.call_result = 'NO_APPOINTMENT'
AND substr(m.date, 1, 10) = substr(subq.DATE, 1, 10)) as 'RESULT_NO_APP'
FROM dialed_calls m
WHERE m.date BETWEEN "2014-09-02" AND "2014-09-05"
GROUP BY my_date
Many thanks for any help.
Table structure:
BEGIN TRANSACTION;
CREATE TABLE dialed_calls(Id integer PRIMARY KEY,
'date' datetime,
'called_number' VARCHAR(45),
'call_result' VARCHAR(45),
'call_duration' INT,
'synced' BOOL);
/* Create few records in this table */
INSERT INTO dialed_calls VALUES(1,'2014-09-02 15:54:34+0200',
'800123456', 'NOT_INTERESTED', 10, 0);
INSERT INTO dialed_calls VALUES(2,'2014-09-02 15:56:30+0200',
'800123456', 'NO_APPOINTMENT', 10, 0);
INSERT INTO dialed_calls VALUES(3,'2014-09-02 16:01:49+0200',
'800123456', 'DONE', 9, 0);
INSERT INTO dialed_calls VALUES(4,'2014-09-02 16:03:03+0200',
'800123456', 'NO_APPOINTMENT', 69, 0);
INSERT INTO dialed_calls VALUES(5,'2014-09-02 18:09:34+0200',
'800123456', 'NO_APPOINTMENT', 3, 0);
INSERT INTO dialed_calls VALUES(6,'2014-09-02 18:54:02+0200',
'123456789', 'NO_APPOINTMENT', 89, 0);
INSERT INTO dialed_calls VALUES(7,'2014-09-02 18:55:25+0200',
'123456789', 'NOT_INTERESTED', 89, 0);
INSERT INTO dialed_calls VALUES(8,'2014-09-03 18:36:58+0200',
'123456789', 'DONE', 185, 0);
INSERT INTO dialed_calls VALUES(9,'2014-09-04 18:36:58+0200',
'123456789', 'DONE', 185, 0);
INSERT INTO dialed_calls VALUES(10,'2014-09-05 18:36:58+0200',
'123456789', 'DONE', 185, 0);
COMMIT;
Try this:
SELECT
d.date AS DATE,
IFNULL(NUMBER_OF_ALL_CALLS, 0) AS NUMBER_OF_ALL_CALLS,
IFNULL(RESULT_DONE, 0) AS RESULT_DONE,
IFNULL(RESULT_NOT_INTERESTED, 0) AS RESULT_NOT_INTERESTED,
IFNULL(RESULT_NO_APP, 0) AS RESULT_NO_APP
FROM
(SELECT DATE('1970-01-01', '+' || (t4.i*10000 + t3.i*1000 + t2.i*100 + t1.i*10 + t0.i) || ' days') date FROM
(SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t0,
(SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t1,
(SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t2,
(SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t3,
(SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t4) d
LEFT JOIN
(
SELECT substr(m.date, 1, 10) as my_date, COUNT(m.ID) AS 'NUMBER_OF_ALL_CALLS',
(SELECT COUNT(*) FROM dialed_calls subq WHERE subq.call_result = 'DONE'
AND substr(m.date, 1, 10) = substr(subq.DATE, 1, 10)) as 'RESULT_DONE',
(SELECT COUNT(*) FROM dialed_calls subq WHERE subq.call_result = 'NOT_INTERESTED'
AND substr(m.date, 1, 10) = substr(subq.DATE, 1, 10)) as 'RESULT_NOT_INTERESTED',
(SELECT COUNT(*) FROM dialed_calls subq WHERE subq.call_result = 'NO_APPOINTMENT'
AND substr(m.date, 1, 10) = substr(subq.DATE, 1, 10)) as 'RESULT_NO_APP'
FROM dialed_calls m
GROUP BY my_date
) t
ON d.date = t.my_date
WHERE d.date BETWEEN '2014-09-02' AND '2014-09-10'
ORDER BY d.date;
Above query will first the retrieve the dates between the specified date range and later will join the retrieved values with your table.
This is a good case for joining to a Calendar table.
http://web.archive.org/web/20070611150639/http://sqlserver2000.databases.aspfaq.com/why-should-i-consider-using-an-auxiliary-calendar-table.html
Note this is a SQL server link, but you can adapt this to SQLlite.
You could do your calculations, and then right join the results to the calendar table, so that the dates appear with NULL values. Or you could COALESCE() the nulls to something that makes more sense, like 0.
to get intermediate dates as the query result you need a table with all the dates in the range.
in some rdbms you can populate a temporary table to join with.
you will have to compare the date part only (without time).
be careful with your between because the second date has time 00:00:00 and maybe it's not what you meant.
Scenario: Database for Biometric device. It inserts
EmpId, EmpName, DepName, RecTime, RecDate
It gets inserted when User Enters office and swipes finger and then 2nd time when he leaves office. RecTime saves Entry time then Exit time.
Problem:
I want to calculate total time a person has worked but finding difference between RecTime in first record being inserted and 2nd record being inserted, in minutes and hours.
I tried DateDiff function, DateSub etc but nothing worked
Not going to solve your problem as there is insufficient data to do so.
The approach pattern I would follow is;
CREATE TABLE #EmpLogging
(
LogID INT,
EmpId INT,
EmpName VARCHAR(50),
DepName VARCHAR(50),
RecTime TIME,
RecDate DATE
)
INSERT INTO #EmpLogging
SELECT 1, 1, 'Fred', 'Legal', '08:00:00', '2013-01-01' UNION ALL
SELECT 2, 2, 'Susan', 'Marketing', '08:03:00', '2013-01-01' UNION ALL
SELECT 3, 1, 'Fred', 'Legal', '17:00:00', '2013-01-01' UNION ALL
SELECT 4, 2, 'Susan', 'Marketing', '17:55:00', '2013-01-01'
;WITH EmpSequence AS
(
SELECT *
,EmpSeq = ROW_NUMBER() OVER (PARTITION BY EmpId ORDER BY RecDate, RecTime)
FROM #EmpLogging
)
,EndTime AS
(
SELECT E1.*
,OutTime = E2.RecTime
,OutDate = E2.RecDate
FROM EmpSequence E1
LEFT
JOIN EmpSequence E2 ON E1.EmpId = E2.EmpId
AND E1.EmpSeq = E2.EmpSeq - 1
)
SELECT *
,MINUTETimeFrame = DATEDIFF(MI, RecTime, OutTime)
FROM EndTime