I have these tables,
CREATE TABLE Book
(
ISBN CHAR(05)NOT NULL,
BKName VARCHAR(20)NOT NULL,
Author VARCHAR(20)NOT NULL,
Price NUMERIC(02)NOT NULL,
CONSTRAINT Book_PK PRIMARY KEY (ISBN)
);
CREATE TABLE Location
(
LoID CHAR(05)NOT NULL,
CityName VARCHAR(15)NOT NULL,
Stoke CHAR(05)NOT NULL,
CONSTRAINT Location_PK PRIMARY KEY (LoID)
);
CREATE TABLE Customer
(
CuID CHAR(05)NOT NULL,
CusName VARCHAR(20)NOT NULL,
RegiDate DATE NOT NULL,
Gender VARCHAR(06)NOT NULL,
TeleNum CHAR(12)NOT NULL,
Address VARCHAR(30)NOT NULL,
CONSTRAINT Customer_PK PRIMARY KEY (CuID)
);
CREATE TABLE BookCopy
(
CopyID CHAR(05)NOT NULL,
ISBN CHAR(05)NOT NULL,
LoID CHAR(05)NOT NULL,
CONSTRAINT pk_BookCopy PRIMARY KEY (CopyID),
CONSTRAINT fk_BookCopy_ISBN_FK FOREIGN KEY (ISBN) REFERENCES Book(ISBN),
CONSTRAINT fk_BookCopy_LoID_FK FOREIGN KEY (LoID) REFERENCES Location(LoID)
);
CREATE TABLE BorrowRecord
(
BrrDate DATE NOT NULL,
RetDate DATE NOT NULL,
BrFee NUMBER(05) NOT NULL,
Cus_Review NUMERIC(02)NOT NULL,
CopyID CHAR(05)NOT NULL,
CuID CHAR(05) NOT NULL,
CONSTRAINT pk_BorrowRecord PRIMARY KEY (CopyID, CuID),
CONSTRAINT fk_BorrowRecord_CopyID_FK FOREIGN KEY (CopyID) REFERENCES BookCopy(CopyID) ,
CONSTRAINT fk_BorrowRecord_CuID_FK FOREIGN KEY (CuID) REFERENCES Customer(CuID) );
This is the task: "write and test a query to list the customer ID and name of every Customer along with the books that they have hired within the past 200 days. Include starting date, ending date, and location name for those hirings. All customer details (ID and name) should be included in the output, whether or not they have actually borrowed any books."
I write a query to list the customer ID and name of every Customer along with the books that they have borrowed within the past 200 days. Include starting date, ending date, and location name for those hirings. This the query for it.
SELECT
BorrowRecord.CuID, Customer.CusName, Book.ISBN, Book.BkName,
BorrowRecord.BrrDate, BorrowRecord.RetDate, Location.CityName
FROM
Book
LEFT JOIN
BookCopy ON Book.ISBN = BookCopy.ISBN
LEFT JOIN
BorrowRecord ON BookCopy.CopyID = BorrowRecord.CopyID
LEFT JOIN
Customer ON BorrowRecord.CuID = Customer.CuID
LEFT JOIN
Location ON Location.LoID = BookCopy.LoID
WHERE
BorrowRecord.BrrDate >= sysdate - 200 ;
But I also need to get all customer details (ID and name) that should be included in the output, whether or not they have actually borrowed any books. How can I do it?
If You want to see all customers independently whether they have borrowed a book or not, it's important that the first LEFT JOIN is based on customers table. In Your script, You start with Book, then join to BorrowRecord and only then have The Customer on the right side of the join. Another point is the WHERE -Condition that excludes all entries of Customer that borrowed a book outside of the 200-days-range. This meand that all records of BorrowRecord are shown (that match to the previous join) but only the customers that are found in a link to BorrowRecords from the past 200 days.
Try the following:
SELECT BorrowRecord.CuID, Customer.CusName, Book.ISBN, Book.BkName,
BorrowRecord.BrrDate,BorrowRecord.RetDate, Location.CityName
FROM Customer
LEFT JOIN BorrowRecord ON BorrowRecord.CuID = Customer.CuID
LEFT JOIN BookCopy ON BorrowRecord.CopyID = BookCopy.CopyID
LEFT JOIN Book ON BookCopy.ISBN= Book.ISBN
LEFT JOIN Location ON Location.LoID = BookCopy.LoID
WHERE ISNULL(BorrowRecord.BrrDate,'') >=sysdate-200 ;
Related
so basicly what i need is to get two tables at the same time and then use a condition that reside in the first table and i want to apply it to the second one
if it not possible do i need to call SELECT Twice ?
is this code right ?
to determine the average rating of all movies released in 2012
SELECT AVG(rating),year FROM ratings , movies
WHERE year = 2012;
//these are the tables that i have
CREATE TABLE movies (
id INTEGER,
title TEXT NOT NULL,
year NUMERIC,
PRIMARY KEY(id)
);
CREATE TABLE stars (
movie_id INTEGER NOT NULL,
person_id INTEGER NOT NULL,
FOREIGN KEY(movie_id) REFERENCES movies(id),
FOREIGN KEY(person_id) REFERENCES people(id)
);
CREATE TABLE directors (
movie_id INTEGER NOT NULL,
person_id INTEGER NOT NULL,
FOREIGN KEY(movie_id) REFERENCES movies(id),
FOREIGN KEY(person_id) REFERENCES people(id)
);
CREATE TABLE ratings (
movie_id INTEGER NOT NULL,
rating REAL NOT NULL,
votes INTEGER NOT NULL,
FOREIGN KEY(movie_id) REFERENCES movies(id)
);
CREATE TABLE people (
id INTEGER,
name TEXT NOT NULL,
birth NUMERIC,
PRIMARY KEY(id)
);
I think you want a JOIN and an aggregate function:
SELECT AVG(r.rating) avg_rating_2012
FROM ratings r
INNER JOIN movies m on m.id = r.movie_id
WHERE m.year = 2012;
If you want this for all years at once, then use GROUP BY:
SELECT m.year, AVG(r.rating) avg_rating
FROM ratings r
INNER JOIN movies m on m.id = r.movie_id
GROUP BY m.year;
Hello my question is simple for some of yours ^^
I've a table product, reference, and intervention. When there is an intervention the table reference make the link between products that we need for the interventions and the intervention.
I would like to know how to do to search products that have made part of all interventions.
This are my tables :
--TABLE products
create table products (
reference char(5) not null check ( reference like 'DT___'),
designation char(50) not null,
price numeric (9,2) not null,
primary key(reference) );
-- TABLE interventions
create table interventions (
nointerv integer not null ,
dateinterv date not null,
nameresponsable char(30) not null,
nameinterv char(30) not null,
time float not null check ( temps !=0 AND temps between 0 and 8),
nocustomers integer not null ,
nofact integer not null ,
primary key( nointerv),
foreign key( noclient) references customers,
foreign key (nofacture) references facts
);
-- TABLE replacements
create table replacements (
reference char(5) not null check ( reference like 'DT%'),
nointerv integer not null,
qtereplaced smallint,
primary key ( reference, nointerv ),
foreign key (reference) references products,
foreign key(nointerv) references interventions(nointerv)
);
--EDIT :
This is a select from my replacement table
We can see in this picture that the product DT802 is used in every interventions
Thanks ;)
This will show 1 line intervention - products. Is this you are expecting for?
select interventions.nointerv, products.reference
from interventions
inner join replacements on interventions.nointerv = replacements.nointerv
inner join products on replacements.reference = products.reference;
This one?
select products.reference, products.designation
from interventions
inner join replacements on interventions.nointerv = replacements.nointerv
inner join products on replacements.reference = products.reference
group by products.reference, products.designation
having count(*) = (select count(*) from interventions);
Your question is hard to follow. If I interpret it as all nointerv in replacements whose reference contains all products, then:
select nointerv
from replacements r
group by nointerv
having count(distinct reference) = (select count(*) from products);
I am taking my first database class and need some info on what I need to change for my script to process. Currently I have 2 tables, an "orders" table and a "customers" table and this is how they are coded.
CREATE TABLE customers (
customer_id INT ,
customer_first_name VARCHAR(20),
customer_last_name VARCHAR(20) NOT NULL,
customer_address VARCHAR(50) NOT NULL,
customer_city VARCHAR(20) NOT NULL,
customer_state CHAR(2) NOT NULL,
customer_zip CHAR(5) NOT NULL,
customer_phone CHAR(10) NOT NULL,
customer_fax CHAR(10),
CONSTRAINT customers_pk
PRIMARY KEY (customer_id)
);
CREATE TABLE order (
order_id INT NOT NULL,
customer_id INT NOT NULL,
order_date DATE NOT NULL,
shipped_date DATE,
employee_id INT,
CONSTRAINT orders_pk
PRIMARY KEY (order_id),
CONSTRAINT orders_fk_customers
FOREIGN KEY (customer_id) REFERENCES customers (customer_id),
CONSTRAINT orders_fk_employees
FOREIGN KEY (employee_id) REFERENCES employees (employee_id)
);
My script to join these two tables together is as follows:
SELECT or.order_id, or.order_date, or.customer_city,
cu.customer_first_name, cu.customer_last_name
FROM orders or INNER JOIN customers cu
ON or.customer_first_name = cu.customer_first_name
AND or.customer_last_name = cu.customer_last_name;
Now obviously, I know it is incorrect and may have multiple errors, so be gentle. I would love to know what I can do to make it work. Please advise.
Two things:
Don't use or as an alias. That's a reserved word.
Join by the foreign key.
The query should look like:
SELECT o.order_id, o.order_date, cu.customer_city,
cu.customer_first_name, cu.customer_last_name
FROM orders o
INNER JOIN customers cu
on o.customer_id = cu.customer_id
You can join your tables on the ID numbers, and you won't have to worry about what happens when multiple people have the same name.
Use this instead:
FROM orders ord INNER JOIN customers cu
ON ord.order_id = cu.customer_id
Your select statement can remain as it is. I also re-aliased according to the comment from Error_2646.
Using a field that is a primary key in one of your tables is also better practice than using non-key fields, when possible.
I have 4 tables.
create table LOCATION(
loccode Number(2) NOT NULL,
locname Varchar2 (30),
state Varchar2 (10),
population Number(7),
travelcode Number(1),
CONSTRAINT PK_LOCATION PRIMARY KEY (loccode)
);
create table DEPOT(
depid Number(4) NOT NULL,
audit_year Number(4),
address Varchar2 (30),
mgrname Varchar2 (30),
capacity Number(7),
capacity_used Number(7),
mgrgender Varchar2(10),
loccode Number(2) NOT NULL,
CONSTRAINT PK_DEPOT PRIMARY KEY (depid),
CONSTRAINT FK_LOCATION FOREIGN KEY (loccode) REFERENCES LOCATION
create table MANUFACTURER(
manid Number (2) NOT NULL,
manname Varchar2(30),
loccode Number(2) NOT NULL,
CONSTRAINT PK_MANUFACTURER PRIMARY KEY (manid),
CONSTRAINT FK_LOC FOREIGN KEY (loccode) REFERENCES LOCATION
);
create table STOCKITEM(
stkid Number(2) NOT NULL,
stkname Varchar2(30),
sellingprice Number(6,2),
purchaseprice Number(6,2),
depid Number(4) NOT NULL,
manid Number(2) NOT NULL,
CONSTRAINT PK_STOCKITEM PRIMARY KEY (stkid),
CONSTRAINT FK_DEP FOREIGN KEY (depid) REFERENCES DEPOT,
CONSTRAINT FK_MANUFACTURER FOREIGN KEY (manid) REFERENCES MANUFACTURER
);
I am trying to generate a query that lets me see the stock id, stock name, manufacturer location and department location.
This requires 4 inner join clauses.
1 to link stockitem to depot, one to link stockitem to manufacturer, and two unique ones linking location to both depot and manufacturer.
Im using this at the moment;
select
stockitem.stkid as "STOCK ID",
stockitem.stkname as "STOCK NAME",
manloc.locname as "MANUFACTURER LOCATION",
deploc.locname as "DEPOT LOCATION"
from stockitem
inner join depot on stockitem.depid = depot.depid
inner join manufacturer on stockitem.manid = manufacturer.manid
inner join location on location.locid = deploc.locid as deploc
inner join location on location.locid = manloc.locid as manloc
order by stockitem.stkid asc;
however it is spitting back that the string is not properly terminated. Am I missing something here?
If I put the alias's before the 'on' (the deploc and manloc), then I get an error saying that its missing an expected operator...i.e....'on'.
Where am I going wrong with this?
The location table alias's should be after the table name and there should be no AS when aliasing tables (that's an Oracle quirk):
select
stockitem.stkid as "STOCK ID",
stockitem.stkname as "STOCK NAME",
manloc.locname as "MANUFACTURER LOCATION",
deploc.locname as "DEPOT LOCATION"
from stockitem
inner join depot on stockitem.depid = depot.depid
inner join manufacturer on stockitem.manid = manufacturer.manid
inner join location deploc on depot.loccode = deploc.loccode
inner join location manloc on manufacturer.loccode = manloc.loccode
order by stockitem.stkid asc;
You don't actually need the AS when aliasing columns but it makes it read easier.
Note the correct column reference in the location inner joins
CREATE TABLE CUSTOMER (
CUSID VARCHAR(25) NOT NULL,
CNAME VARCHAR(50),
CONSTRAINT CUSTOMER_PKEY PRIMARY KEY (CUSID),
);
CREATE TABLE SHOP (
SHOPID VARCHAR(10) NOT NULL,
ADDRESS VARCHAR(25),
CONSTRAINT SHOP_PKEY PRIMARY KEY (SHOPID),
);
CREATE TABLE VISIT (
CUSID VARCHAR(25) NOT NULL,
SHOPID VARCHAR(10) NOT NULL,
VDATE DATE NOT NULL,
CONSTRAINT VISIT_PKEY PRIMARY KEY (CUSID, SHOPID, VDATE),
CONSTRAINT VISIT_FKEY1 FOREIGN KEY (CUSID) REFERENCES CUSTOMER(CUSID),
CONSTRAINT VISIT_FKEY2 FOREIGN KEY (SHOPID) REFERENCES SHOP(SHOPID)
);
how to find the address of shops that have been visited at least 2 times by customer with name 'john'??
SELECT ADDRESS FROM SHOP NATURAL JOIN VISIT WHERE CUSID IN (SELECT CUSID FROM CUSTOMER WHERE CNAME = 'john' GROUP BY CUSID HAVING COUNT(CUSID) > 2);
i have tried many kinds of joins, it seems that after i put count and equal condition in together,my results will be 0 rows.
SELECT DISTINCT s.address
FROM shop s
JOIN visit v ON s.shopid = v.shopid
JOIN customer c ON v.customerid = c.customerid
WHERE c.cname = 'John'
GROUP BY
s.address
, c.customerid
HAVING COUNT(*) > 1