Date automatically where clause - SQL - sql

I have on my DB the dates that I can filter like this:
select *
where
a.y=2021 and a.m=2 and a.d=7
However if I run this query tomorrow I'll have to go there and change manually.
Is there a way to do this automatically as in if I run the query tomorrow I'll get d=8 and the day after d=9 and so on?
I tried to use get date but I get the following error:
SQL Error [6]: Query failed (#20210207_153809_06316_2g4as): line 2:7: Function 'getdate' not registered
I also don't know if that is the right solution. Does anybody know how to fix that?

you can use NOW to get the current date, and use YEAR , MONTH , DAY to get parts of the date
SELECT *
FROM [TABLE]
WHERE a.y=YEAR(NOW()) and a.m=MONTH(NOW()) and a.d=DAY(NOW())

The best solution is to have a date column in your data. Then you can just use:
where datecol = current_date
Or whatever your particular database uses for the current date.
Absent that, you have to split the current date into parts. In Standard SQL, this looks like:
where y = extract(year from current_date) and
m = extract(month from current_date) and
d = extract(day from current_date)
That said, date functions notoriously vary among databases, so the exact syntax depends on your database.
For instance, a common way to write this in SQL Server would be:
where y = year(getdate()) and
m = month(getdate()) and
d = day(getdate())

Related

SQL Query to Retrieve Monthly Data

I'm working with the following SQL Query in Redash, the query retrieves monthly data from table.
SELECT *
FROM Table
WHERE
"Date" between '2021-04-01T00:00:00.669976+00:00' and '2021-04-30T23:59:59.669976+00:00'
I'd like to know if there's a workaround to updating the WHERE clause in an efficient manner rather than manually typing it out at the end of each month.
This worked well for me:
WHERE
EXTRACT(MONTH FROM "Date") = EXTRACT(MONTH FROM CURRENT_DATE) AND EXTRACT(YEAR FROM "Date") = EXTRACT(YEAR FROM CURRENT_DATE)
In your case, I suggest you avoid any solution that involves doing a convert or other type of conversion with the GRP_Date field. By doing that, you do not allow SQL Server to be able to use an index if there is one for the GRP_Date field and this can affect your performance in a very obvious way.
And of course between is not ideal in this specific case for the reasons already mentioned in your question.
I suggest the following condition for the best performance (good use of the indexes) and to avoid problems with the hours
where GRP.GRP_date >= #since
and GRP.GRP_date < dateadd(day, 1, #until) -- #until + 1 day
In the case where:
#since = 2016-11-01
#until = 2016-11-14
where GRP.GRP_Fecha >= '2016-11-01'
and GRP.GRP_Fecha < '2016-11-15'
When ordering dates before 2016-11-15, this includes all dates from 2016-11-14 regardless of time.

How to get the third month of a query without using variables?

I have a query in which I need to get the third month of the given reporting date using SQL and then use it as part of the query. I am able to get all the months but I specifically need to get the third month how would I go about doing that? I know this is fairly easy to do in other languages but is it possible in SQL?
SELECT REPORTING_MONTH, COUNT(*)
FROM database1 AS fb
JOIN (
--derrived core set
SELECT service_no, subscription_id
FROM database2
WHERE REPORTING_MONTH = '2015-04-01' <-- this is the reporting month
) AS c
ON fb.SERVICE_NO = c.service_no
AND fb.subscription_id = c.subscription_id
AND fb.REPORTING_MONTH = '2015-07-01' <-- THIS SHOULD BE THE THIRD MONTH
AND fb.ACTIVE_BASE_IND_NEW = 1
GROUP BY 1
ORDER BY 1
For example if the reporting month is '2015-04-01 I need the variable month to then be '2015-07-01' to be used as part of the query
You don't specify the database you are using. A typical approach would be:
SELECT REPORTING_MONTH, COUNT(*)
FROM database1 fb JOIN
database2 c
ON fb.SERVICE_NO = c.service_no AND
c.REPORTING_MONTH = '2015-04-01' AND
fb.subscription_id = c.subscription_id AND
fb.REPORTING_MONTH = c.reporting_month + interval '3 month' AND
fb.ACTIVE_BASE_IND_NEW = 1
GROUP BY 1
ORDER BY 1;
The exact syntax for + interval '3 month' varies by database.
If the field REPORTING_MONTH is text then you might have to use SUBSTRING (SQL Server) or MID (Others).
If it's a proper date field then perhaps DATEPART(month, fb.REPORTING_MONTH) = 3 will work?
My SQL is a bit rusty but try those functions.

Invalid Operation On An ANSI DATETIME (Subtracting one timestamp from another in Teradata)

I would like to create a WHERE condition to return results where only 1 day has passed between two timestamps. I tried this:
SELECT * FROM RDMAVWSANDBOX.VwNIMEventFct
INNER JOIN VwNIMUserDim ON VwNIMUserDim.NIM_USER_ID = VwNIMEventFct.NIM_USER_ID
INNER JOIN rdmatblsandbox.TmpNIMSalesForceDB ON TmpNIMSalesForceDB.EMAIL = VwNIMUserDim.USER_EMAIL_ADDRESS
WHERE (CONTRACT_EFFECTIVE_DATE - EVENT_TIMESTAMP) =1
But the result was an error message "Invalid Operation On An ANSI DATETIME value".
I guess that, looking at the code now, Teradata has no way of knowing whether the "1" in "= 1" is a day, hour or year.
How would I select data where only 1 day has passed between CONTRACT_EFFECTIVE_DATE and EVENT_TIMESTAMP?
Same again for 2 days, and 3 days etc?
If both columns are DATEs you can use =1which means one day.
For Timestamps you need to tell what kind of interval you want:
WHERE (CONTRACT_EFFECTIVE_DATE - EVENT_TIMESTAMP) DAY = INTERVAL '1' DAY
But i'm not shure if this is what you really want, what's your definition of 1 day?
Edit:
Based on your comment the best way should be:
WHERE CAST(CONTRACT_EFFECTIVE_DATE AS DATE) - CAST(EVENT_TIMESTAMP AS DATE) = 1
This avoids dealing with INTERVAL arithmetic :-)
Not sure about Teradata, but I think most versions of SQL have built-in date math functions. In MSSQL for instance you could do this:
...
WHERE DATEDIFF(DAY, CONTRACT_EFFECTIVE_DATE, EVENT_TIMESTAMP) = 1
Or if you wanted to make sure 24 hours had passed you could do:
...
WHERE DATEDIFF(HOUR, CONTRACT_EFFECTIVE_DATE, EVENT_TIMESTAMP) = 1
Other SQL's have their own versions of this, and you may have to use 'D' or 'DD' instead of 'DAY' or something (and maybe 'HH' instead of 'HOUR' likewise).

SQL to filter for records more than 30 days old

Suppose I have the following query:
select customer_name, origination_date
where origination_date < '01-DEC-2013';
I would like to select all customers that have an origination date older than 30 days. Is there a way in SQL (oracle, if specifics needed) to specify it in a more dynamic approach than manually entering the date so that I don't need to update the query every time I run it?
Thanks!
Sure try something like this:
select customer_name, origination_date where
origination_date >= DATEADD(day, -30, GETUTCDATE());
This basically says where the origination_date is greater or equal to 30 days from now. This works in Microsoft SQL, not sure but there is probably a similar function on Oracle.
in Oracle, when you subtract dates, by default you get the difference in days, e.g.
select * from my_table where (date_1 - date_2) > 30
should return the records whose date difference is greater than 30 days.
To make your query dynamic, you parameterize it, so instead of using hard coded date values, you use:
select * from my_table where (:date_1 - :date_2) > :threshold
If you are using oracle sql developer to run such a query, it will pop up a window for you to specify the values for your paramteres; the ones preceded with colon.

mysql return rows matching year month

How would I go about doing a query that returns results of all rows that contain dates for current year and month at the time of query.
Timestamps for each row are formated as such: yyyy-mm-dd
I know it probably has something to do with the date function and that I must somehow set a special parameter to make it spit out like such: yyyy-mm-%%.
Setting days to be wild card character would do the trick but I can't seem to figure it out how to do it.
Here is a link to for quick reference to date-time functions in mysql:
http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html
Thanks
I think EXTRACT is the function you are looking for:
SELECT * FROM table
WHERE EXTRACT(YEAR_MONTH FROM timestamp_field) = EXTRACT(YEAR_MONTH FROM NOW())
you could extract the year and month using a function, but that will not be able to use an index.
if you want scalable performance, you need to do this:
SELECT *
FROM myTable
WHERE some_date_column BETWEEN '2009-01-01' AND '2009-01-31'
select * from someTable where year(myDt) = 2009 and month(myDt) = 9 and day(myDt) = 12