I'm doing a sql query to extract orders from date to date.
I think I need to use LIKE because dates are strings and has days, but I have to consider only year and month, for example:
order date -> 2019-01-01
regex -> LIKE '%2019-01-%' (all orders in done in january)
and then I have to to the same thing for another date (let's say '%2019-03-%'). After that I use the two dates to extract time with BETWEEN.
The problem is that I don't know how to put these two things together.
You can use the substring and then do comparison as follows:
select * from orders
where substring(date, 1, 7) between '2019-01' and '2019-03'
Or you can convert your date column into date and then compare it with dates.
Related
I need to round up a month-date based on certain parameters. For example: If I have a parameter where if a day in a given month is between the 6th and the 4th of the next month, I need my query to return the next months date. Is there a way to round up the month given these parameters without hard coding case whens for every single month ever?
SELECT case when date_trunc('day',li.created_at between '2019-03-06 00:00:00' and '2019-04-06 00:00:00' then '2019-04-01' end)
FROM line_items li
If you want the beginning of the month, but offset by 4 days, you can use date_trunc() and subtract some number of days (or add some number of days). You seem to want something like this:
select dateadd(month, 1, date_trunc('month', li.created_at - interval '4 day'))
Another approach is to create a canonical "dates" table that precomputes the mapping from a given date to a new date using your rounding scheme. The mapping could be done outside of redshift in a script and the table loaded in (or within redshift using a user defined function).
I'm currently strugeling to get something done.
I needed only the rows where the date is between a certain date and month.
Example show only the rows where the date is between 01/05 (DD/MM) and 08/07 (DD/MM) the date can be found in the table tasks within the field information.
The year can't make any sense, but the results may only between those two dates in that year.
I've tried:
BETWEEN (TO_DATE ('01/05','DD/MM') AND (TO_DATE('08/07', 'DD/MM')
EXTRACT (DD/MM) from information.
none of those are working for me, I hope that someone of you can help me to figure this out!.
Thanks!
You seem to want to disregard the year. If so, then I would recommend:
TO_CHAR(datecol, 'MM/DD') BETWEEN '05/01' AND '07/08'
In order for BETWEEN to work in this case, you need the format in the order of MM-DD.
If you want this for a particular year, then use direct date comparisons:
datecol >= DATE '2018-05-01' AND
datecol < DATE '2018-07-09' -- note this is one day later
Oracle dates have a time component, so you need to be careful when making comparisons.
For example, if I have a data set including two columns, one which shows the month as a number and the other which shows the year (result of grouping my data using GROUP BY), I want to add another column called 'Days in the month' which will display the number of days in the respective month. Is there a way I can do this? Is there some function I can add in the SELECT clause?
I want to do this since there are further calculations I need to do with that number for each row.
In SQL Server 2012+, you can use:
select day(eomonth(datecol))
eomonth() gets the last day of the month. day() just returns the day of the month -- the number of days in the month, in this case.
For older SQL Server versions, I use the following:
DAY(DATEADD(MONTH, DATEDIFF(MONTH, -1, date_column)- 1, -1))
Much less elegant than the previous answer, but functional.
SELECT strftime('%W', 'Week'), sum(income) FROM tableOne GROUP BY Week;
Format for date is a simple date: YYYY-MM-DD
PROBLEM: When run no value for the Week column is provided. Any suggestions?
There is data in the table and when the query is run the income is summarized by the date in the week column. Thing is, this column contains a date that may be any day of the week and often multiple different days of the same week. I need to summarize the income by week.
In SQL, 'Week' is a string containing four characters.
To reference the value in a column named "Week", remove the quotes: Week.
I am trying to create a query to that can get some records in a table that is between a from and to date, with the dates being in month/year only. The problem that I am having is trying to get the records when the from and to dates are for the same month/year.
Here is a example of the issue that I am having:
select start_date
from job
where trunc(start_date) between to_date('05-2016','mm-yyyy') and to_date('05-2016','mm-yyyy')
In the job table, there are records with start_date in the month of May, but in order to see them I need to set the to date to '06-2016'. Is there way to get all of the records with a start_date in the month of May by just specifying that the from and to dates is 05-2016?
In your example you are selecting all start_date's between 5/1/2016 and 5/1/2016.
It seems like you want to capture everything in a month, but you are not specifying a format to truncate. Without specifying 'Month' in the Trunc() you are truncating to the day. When you truncate to Month you can now, actually just set it equal to the to_date() rather than between:
select start_date
from job
where trunc(start_date,'Month') = to_date('05-2016','mm-yyyy')
Here is some information on Trunc(date, [fmt]). when the fmt argument is left blank Trunc() defaults to 'round' to the nearest day but there are many other options.
If you want to specify ranges greater than a Month you can use between (but note, this is from the first day of the first to_date() to the first day of the second 'to_date()':
select start_date
from job
where trunc(start_date)
between to_date('06-2016','mm-yyyy')
and to_date('09-2016','mm-yyyy')
In this example all Start_dates would populate between 6/1/2016 and 9/1/2016.
I think the most accurate way to do this would be:
select start_date
from job
where trunc(start_date)
between to_date('06-01-2016','mm-dd-yyyy')
and to_date('09-30-2016','mm-dd-yyyy')
How about?
select start_date
from job
where trunc(start_date, 'mm') between
to_date('05-2016', 'mm-yyyy')
and to_date('05-2016', 'mm-yyyy')
Oracle has no way of interpolating the date on the right end of your between as falling at the end of the month. When to_date() is missing a day value in the format it simply supplies the 1st as the default value. Not sure if that's the behavior your were anticipating.
If instead you truncate dates by month (rather than day) then the comparisons will only involve dates falling on the first of the month. With the dates collapsed that way you can then treat a start and end of the two identical values as an inclusive range. Presumably you'll replace the hard-coded dates with parameters of some form and this works for wider ranges as well. Of course, the between can be just an equality test if you're always querying on a single month. And this isn't going to use an index on your column so it's not necessarily the most efficient.
I think this is what you're looking for. Is there a reason you need to supply the date value(s) in that format? Perhaps there's a better way to approach this using a little date math.
Try like this:
select start_date
from job
where trunc(start_date) between to_date('05-2016','mm-yyyy')
and dateadd('d', -1, dateadd('m', 1, to_date('05-2016','mm-yyyy')))
In order to see an entire month worth of dates, your date range in the between clause must be a full month long.