I can't figure out how to get the largest element in loop - kotlin

Question

I don't understand the loop in the following content.
There is a sequence of integer numbers (which ends with the number 0). Find the largest element of this sequence.
The number 0 itself is not included in the sequence. It serves only as a sign that there are no more numbers.
I tried various methods, but they did not solve the problem.
The way to exit the loop at 0 is to use
While(i ! = 0){}
Here is the code we created.
fun main(args: Array<String>) {
val scanner = Scanner(System.`in`)
var count = scanner.nextInt()
do {
var input = scanner.nextInt()
while(input != 0 || count != 0) {
if (count < input){
count = input
}
}
}while(input != 0 || count != 0)
println(count)
}

Answer 1

You can use maxOf() for example:
fun readLn() = readLine()!!
fun readIntOrStopLoopWithZero() = readLn().toIntOrNull() ?: 0
fun readMaxInteger() {
var maxInput: Int = 0
//getting first user input
var userInput = readIntOrStopLoopWithZero()
while (userInput!= 0) {
//calc max
maxInput = maxOf(userInput, maxInput)
//getting user input again.
userInput= readIntOrStopLoopWithZero()
}
if (maxInput == 0)
//In case we get 0 as first input.
print("max value not found")
else
print("Max input is : $maxInput")
}
readMaxInteger()
Input:
1
2
0
output:
Max input is 2
Input:
1
0
output:
Max input is 1
Input:
0
output:
max value not found
Input:
1
2
3
Word
output:
Max input is : 3

Answer 2

Problems:
You've over-complicated it by creating a nested loop.
You're checking input != 0 to exit either of the loops, so it will exit immediately on the first element.
So fixing these problems, you have:
fun main(args: Array<String>) {
val scanner = Scanner(System.`in`)
var count = 0 // start with 0 for simplicity
do {
val input = scanner.nextInt()
if (count < input) {
count = input
}
} while (input != 0)
println(count)
}
And here's an alternate solution. Make a Sequence so it becomes an Iterable and you can use maxOrNull() on it:
fun main(args: Array<String>) {
val sequence = sequence {
val scanner = Scanner(System.`in`)
do {
val input = scanner.nextInt()
yield(input)
} while (input != 0)
}
println(sequence.maxOrNull() ?: 0)
}

Answer 3

I wanted to finish within a single function, so I chose the following.
fun main(args: Array<String>) {
val scanner = Scanner(System.`in`)
var count = 0 // start with 0 for simplicity
do {
val input = scanner.nextInt()
if (count < input) {
count = input
}
} while (input != 0)
println(count)
}
Thanks to everyone who responded!