Query to calculate sum of time with above 24 hours interval - sql

Question

I have time like 25:00:00, 10:00:00, 30:00:00 and I want to calculate the sum of the values from database. How can I do that the current query for calculating sum is
SQL query:
SELECT
CAST(FORMAT((SUM((DATEPART("ss", Total_Time) +
DATEPART("mi", Total_Time) * 60 +
DATEPART("hh", Total_Time) * 3600)) / 3600), '00') AS varchar(max)) + ':' + CAST(FORMAT((SUM((DATEPART("ss", Total_Time) + DATEPART("mi", Total_Time) * 60 + DATEPART("hh", Total_Time) * 3600)) % 3600 / 60), '00') as varchar(max)) + ':' +CAST(FORMAT((SUM((DATEPART("ss", Total_Time) + DATEPART("mi", Total_Time) * 60 + DATEPART("hh", Total_Time) * 3600)) % 3600 % 60), '00') as varchar(max)) as WorkingTimeSum
FROM
tasker_usr.TaskTime
but I get an error
Cannot convert from datetime to character string

Answer 1

You cannot fit your values into a time datatype. It stores only value less than 23:59:59.9999999. Hence you cannot use DATEPART or DATEDIFF directly. One way is to split your values(as seconds) and do the sum. Something like
WITH CTE_SUM
AS (
SELECT SUM(LEFT(column_name, 2) * 3600
+ SUBSTRING(column_name, 4, 2) * 60
+ SUBSTRING(column_name, 7, 2)) AS SUM_AS_SECONDS
FROM YOUR_TABLE
)
SELECT CAST(SUM_AS_SECONDS / 3600 AS VARCHAR) + ':'
+ CAST(SUM_AS_SECONDS % 3600 / 60 AS VARCHAR) + ':'
+ CAST(((SUM_AS_SECONDS % 3600) % 60) AS VARCHAR) AS WorkingTimeSum
FROM CTE_SUM
Please note that this will work upto 99:99:99.If you have time values that are more than that, then you have to split based on : instead of hardcoding values in LEFT/Substring

Answer 2

Are you looking something like this ?
Declare #Hours Table(Hrs VARCHAR(20))
Declare #Hour TINYINT, #Minute INT,#Second INT, #InSeconds BIGINT, #Cdate DATETIME
INSERT #Hours
SELECT '25:00:00' Union All
SELECT '10:00:00' Union All
SELECT '30:00:00'
select #Hour = sum(cast(Left(Hrs,CharIndex(':',Hrs,1)-1) as int)) from #Hours
select #Minute = sum(cast(Substring(Hrs,CharIndex(':',Hrs,1)+1,2)as int)) from #Hours
select #Second = sum(cast(Substring(Hrs,CharIndex(':',Hrs,1)+4,2)as int)) from #Hours
Set #InSeconds = #Second + (#Minute * 60) + (#Hour *60 *60)
Set #Cdate = dateadd(second,#InSeconds,0)
select datediff(day,'1900-01-01',#Cdate) [Day(s)],
Format(#Cdate,'hh') [Hour(s)],
Format(#Cdate,'mm') [Minute(s)],
Format(#Cdate,'ss') [Second(s)]
Day(s)
Hour(s)
Minute(s)
Second(s)
2
05
00
00

Answer 3

Assuming that your format is HH(n):MM:SS (that is, hours can have 1 or more digits), you can decompose the value and reconstruct it. This requires string functions. You can get the total seconds as:
select sum(left(total_time, charindex(':', total_time) - 1) * 60 * 60 +
left(right(total_time, 5), 2) * 60 +
right(total_time, 2)
) as total_secs
from tasker_usr.TaskTime;
Note: This does implicit conversion from the string values to integers, but that should be okay if your values are consistent.
You can convert back to string:
select concat(format(total_secs / (60 * 60), '00:'),
format( (total_secs / 60) % 60, '00:'),
format(total_secs % 60, '00')
) as time_format
from (select sum(left(total_time, charindex(':', total_time) - 1) * 60 * 60 +
left(right(total_time, 5), 2) * 60 +
right(total_time, 2)
) as total_secs
from tasker_usr.TaskTime
) t