SELECT
tblEmployeeMaster.TeamName, SUM(tblData.Quantity) AS 'TotalQuantity'
FROM
tblData
INNER JOIN
tblEmployeeMaster ON tblData.EntryByHQCode = tblEmployeeMaster.E_HQCode
INNER JOIN
tblPhotos ON tblEmployeeMaster.TeamNo = tblPhotos.TeamNo
WHERE
IsPSR = 'Y'
GROUP BY
tblPhotos.TeamSort, tblPhotos.TeamNo, tblPhotos.Data,
tblEmployeeMaster.TeamName
ORDER BY
tblPhotos.TeamSort DESC, TotalQuantity DESC
This returns
Using this statement
select TeamName, count(TeamName) AS 'Head Count'
from dbo.tblEmployeeMaster
where IsPSR = 'Y'
group by teamname
Which returns
I would like to combine these 2 queries in 1 to get the below result.
Tried union / union all but no success :(
Any help will be very much helpful.
You can simply use the sub-query as follows:
SELECT tblEmployeeMaster.TeamName, SUM(tblData.Quantity) AS 'TotalQuantity',
MAX(HEAD_COUNT) AS HEAD_COUNT, -- USE THIS VALUE FROM SUB-QUERY
CASE WHEN MAX(HEAD_COUNT) <> 0
THEN SUM(tblData.Quantity)/MAX(HEAD_COUNT)
END AS PER_MAN_CONTRIBUTION -- column asked in comment
FROM tblData INNER JOIN
tblEmployeeMaster ON tblData.EntryByHQCode = tblEmployeeMaster.E_HQCode INNER JOIN
tblPhotos ON tblEmployeeMaster.TeamNo = tblPhotos.TeamNo
-- FOLLOWING SUB-QUERY CAN BE USED
LEFT JOIN (select TeamName, count(TeamName) AS HEAD_COUNT
from dbo.tblEmployeeMaster
where IsPSR = 'Y' group by teamname) AS HC
ON HC.TeamName = tblEmployeeMaster.TeamName
where IsPSR = 'Y'
GROUP BY tblPhotos.TeamSort, tblPhotos.TeamNo, tblPhotos.Data,tblEmployeeMaster.TeamName
order by tblPhotos.TeamSort desc, TotalQuantity desc
Related
I have my initial statement which is :
SELECT TEAM.ID PKEY_SRC_OBJECT,
TEAM.MODF_DAT UPDATE_DATE,
TEAM.MODF_USR UPDATED_BY,
PERSO.FIRST_NAM FISRT_NAME
FROM TEAM
LEFT OUTER JOIN PERSO ON (TEAM.ID=PERSO.TEAM_ID)
I want to calculate some "flags" and return them in my initial statement.
There are 3 flags which can be calculated like this :
1) Flag ISMASTER:
SELECT Count(*)
FROM TEAM_TEAM_REL A, TEAM B
WHERE B.PARTY_PTY_ID = A.RLTD_TEAM_ID
AND CODE = 'Double';
2) Flag ISAGENT:
SELECT Count(*)
FROM TEAM_ROL_REL A, TEAM B
WHERE B.PARTY_PTY_ID = A.TEAM_ID;
3) Flag NUMPACTS:
SELECT Count(*)
FROM TEAM_ROL_REL A,
TEAM_ROL_POL_REL B,
PERSO_POL_STA_REL C,
TEAM D
WHERE A.ROL_CD IN ('1','2')
AND A.T_ROL_REL_ID = B.P_ROL_REL_ID
AND B.P_POL_ID = C.P_POL_ID
AND C.STA_CD = 'A'
AND D.PARTY_PTY_ID = A.TEAM_ID;
To try to achieve this, I've updated my initial statement like this :
WITH ABC AS (
SELECT TEAM.ID PKEY_SRC_OBJECT,
TEAM.MODF_DAT UPDATE_DATE,
TEAM.MODF_USR UPDATED_BY,
PERSO.FIRST_NAM FISRT_NAME
FROM TEAM
LEFT OUTER JOIN PERSO ON (TEAM.ID=PERSO.TEAM_ID)
)
SELECT ABC.*, MAST.ISMASTER, AGENT.ISAGENT, PACTS.NUMPACTS FROM ABC
LEFT OUTER JOIN (
select
RLTD_TEAM_ID,
Count(RLTD_TEAM_ID) OVER (PARTITION BY RLTD_TEAM_ID) as ISMASTER
FROM TEAM_TEAM_REL
WHERE CODE = 'Double'
) MAST
ON ABC.PKEY_SRC_OBJECT = MAST.RLTD_TEAM_ID
LEFT OUTER JOIN (
select
TEAM_ID,
Count(TEAM_ID) OVER (PARTITION BY TEAM_ID) as ISAGENT
FROM TEAM_ROL_REL
) AGENT
ON ABC.PKEY_SRC_OBJECT = AGENT.TEAM_ID
LEFT OUTER JOIN (
select
TEAM_ID,
Count(TEAM_ID) OVER (PARTITION BY TEAM_ID) as NUMPACTS
FROM TEAM_ROL_REL, TEAM_ROL_POL_REL, PERSO_POL_STA_REL
WHERE TEAM_ROL_REL.ROL_CD IN ('1','2')
AND TEAM_ROL_REL.T_ROL_REL_ID = TEAM_ROL_POL_REL.P_ROL_REL_ID
AND TEAM_ROL_POL_REL.P_POL_ID = PERSO_POL_STA_REL.P_POL_ID
AND PERSO_POL_STA_REL.STA_CD = 'A'
) PACTS
ON ABC.PKEY_SRC_OBJECT = PACTS.TEAM_ID;
For the two first flags (ISMASTER and ISAGENT) I get the result in less than 1min, but for the last flag (NUMPACTS) it runs few minutes without provide any result.
I think my statement is too heavy, maybe I should do it in a totally different way.
I think you have perhaps over complicated things.
You could do this (assuming I have understood your requirements correctly) like so:
WITH ttr AS (SELECT rltd_team_id,
COUNT(*) is_master
FROM team_team_rel
AND CODE = 'Double'
GROUP BY rltd_team_id),
trr AS (SELECT team_id,
COUNT(*) is_agent
FROM team_rol_rel
GROUP BY team_id)
pacts AS (SELECT trr1.team_id,
COUNT(*) num_pacts
FROM team_rol_rel trr1
INNER JOIN team_rol_pol_rel trpr ON (trr1.t_rol_rel_id = trpr.p_rol_rel_id)
INNER JOIN perso_pol_sta_rel ppsr ON (trpr.p_pol_id = ppsr.p_pol_id
WHERE trr1.rol_cd IN ('1', '2')
AND ppsr.st_cd = 'A'
GROUP BY trr1.team_id)
SELECT t.id pkey_src_object,
t.modf_dat update_date,
t.modf_usr updated_by,
p.first_nam first_name,
ttr.is_master,
trr.is_agent,
pacts.num_pacts
FROM team t
LEFT OUTER JOIN perso p ON t.id = p.team_id
LEFT OUTER JOIN ttr ON t.party_pty_id = ttr.rltd_team_id
LEFT OUTER JOIN trr ON t.party_pty_id = trr.team_id
LEFT OUTER JOIN pacts ON t.pkey_src_object = pacts.team_id;
N.B. untested, since you didn't provide any test data.
I have code to select some applications but LEFT JOIN is creating duplicates.
Question: How to get rid of duplicates generated by
LEFT JOIN
attachments as att
ON
(a.ssn = att.ssn AND att.doc_type = 'id_copy' AND att.source = 'cpt3')
My Work:
I am considering SELECT DISTINCT or GROUP BY but, can't figure out where to put them.
This is the query:
SELECT
a.*, c.code, l.who, l.locked_time, att.id AS attnew,
( SELECT
COUNT(*)
FROM
applications as a2
WHERE
a2.approved = 'Y'
AND
a2.paid = 'Y'
AND
a2.paid_back = 'Y'
AND
a2.ssn = a.ssn
) AS previous_apps
FROM
applications as a
LEFT JOIN
locked_by as l
USING(id)
LEFT JOIN
campaign_codes as c
ON
c.id = a.campaign
LEFT JOIN
attachments as att
ON
(a.ssn = att.ssn AND att.doc_type = 'id_copy' AND att.source = 'cpt3')
WHERE
a.closed='N'
AND
a.paid = 'N'
ORDER BY
a.arrived_date
DESC
Use GROUP BY
to avoid duplicates. In your case:
...
WHERE
a.closed='N'
AND
a.paid = 'N'
GROUP BY
a.id
ORDER BY
a.arrived_date
DESC
If you want to make an one to one relation to avoid duplicates and att.id is the same for each att.ssn or you need only one (MAX,MIN,..ANY?) att.id. Try this:
LEFT JOIN
(SELECT ssn,
MAX(id) as id,
FROM attachments
WHERE doc_type = 'id_copy' AND source = 'cpt3'
GROUP BY ssn
)as att
ON
(a.ssn = att.ssn)
Sigh ... can anyone help? In the SQL query below, the results I get are incorrect. There are three (3) labor records in [LaborDetail]
Hours / Cost
2.75 / 50.88
2.00 / 74.00
1.25 / 34.69
There are two (2) material records in [WorkOrderInventory]
Material Cost
42.75
35.94
The issue is that the query incorrectly returns the following:
sFunction cntWO sumLaborHours sumLaborCost sumMaterialCost
ROBOT HARNESS 1 12 319.14 236.07
What am I doing wrong in the query that is causing the sums to be multiplied? The correct values are sumLaborHours = 6, sumLaborCost = 159.57, and sumMaterialCost = 78.69. Thank you for your help.
SELECT CASE WHEN COALESCE(work_orders.location, Work_Orders_Archived.location) IS NULL
THEN '' ELSE COALESCE(work_orders.location, Work_Orders_Archived.location) END AS sFunction,
(SELECT COUNT(*)
FROM work_orders
FULL OUTER JOIN Work_Orders_Archived
ON work_orders.order_number = Work_Orders_Archived.order_number
WHERE COALESCE(work_orders.order_number, Work_Orders_Archived.order_number) = '919630') AS cntWO,
SUM(Laborhours) AS sumLaborHours,
SUM(LaborCost) AS sumLaborCost,
SUM(MaterialCost*MaterialQuanity) AS sumMaterialCost
FROM work_orders
FULL OUTER JOIN Work_Orders_Archived
ON work_orders.order_number = Work_Orders_Archived.order_number
LEFT OUTER JOIN
(SELECT HoursWorked AS Laborhours, TotalDollars AS LaborCost, WorkOrderNo
FROM LaborDetail) AS LD
ON COALESCE(work_orders.order_number, Work_Orders_Archived.order_number) = LD.WorkOrderNo
LEFT OUTER JOIN
(SELECT UnitCost AS MaterialCost, Qty AS MaterialQuanity, OrderNumber
FROM WorkOrderInventory) AS WOI
ON COALESCE(work_orders.order_number, Work_Orders_Archived.order_number) = WOI.OrderNumber
WHERE COALESCE(work_orders.order_number, Work_Orders_Archived.order_number) = '919630'
GROUP BY CASE WHEN COALESCE(work_orders.location, Work_Orders_Archived.location) IS NULL
THEN '' ELSE COALESCE(work_orders.location, Work_Orders_Archived.location) END
ORDER BY sFunction
Try using the SUM function inside a derived table subquery when doing the full join to "WorkOrderInventory" like so...
select
...
sum(hrs) as sumlaborhrs,
sum(cost) as sumlaborcost,
-- calculate material cost in subquery
summaterialcost
from labordetail a
full outer join
(select ordernumber, sum(materialcost) as summaterialcost
from WorkOrderInventory
group by ordernumber
) b on a.workorderno = b.ordernumber
i created a simple sql fiddle to demonstrate this (i simplified your query for examples sake)
Looks to me that work_orders and work_orders_archived contains the same thing and you need both tables as if they were one table. So you could instead of joining create a UNION and use it as if it was one table:
select location as sfunction
from
(select location
from work_orders
union location
from work_orders_archived)
Then you use it to join the rest. What DBMS are you on? You could use WITH. But this does not exist on MYSQL.
with wo as
(select location as sfunction, order_number
from work_orders
union location, order_number
from work_orders_archived)
select sfunction,
count(*)
SUM(Laborhours) AS sumLaborHours,
SUM(LaborCost) AS sumLaborCost,
SUM(MaterialCost*MaterialQuanity) AS sumMaterialCost
from wo
LEFT OUTER JOIN
(SELECT HoursWorked AS Laborhours, TotalDollars AS LaborCost, WorkOrderNo
FROM LaborDetail) AS LD
ON COALESCE(work_orders.order_number, Work_Orders_Archived.order_number) = LD.WorkOrderNo
LEFT OUTER JOIN
(SELECT UnitCost AS MaterialCost, Qty AS MaterialQuanity, OrderNumber
FROM WorkOrderInventory) AS WOI
ON COALESCE(work_orders.order_number, Work_Orders_Archived.order_number) = WOI.OrderNumber
where wo.order_number = '919630'
group by sfunction
order by sfunction
The best guess is that the work orders appear more than once in one of the tables. Try these queries to check for duplicates in the two most obvious candidate tables:
select cnt, COUNT(*), MIN(order_number), MAX(order_number)
from (select order_number, COUNT(*) as cnt
from work_orders
group by order_number
) t
group by cnt
order by 1;
select cnt, COUNT(*), MIN(order_number), MAX(order_number)
from (select order_number, COUNT(*) as cnt
from work_orders_archived
group by order_number
) t
group by cnt
order by 1;
If either returns a row where cnt is not 1, then you have duplicates in the tables.
I have to do an self join on a table. I am trying to return a list of several columns to see how many of each type of drug test was performed on same day (MM/DD/YYYY) in which there were at least two tests done and at least one of which resulted in a result code of 'UN'.
I am joining other tables to get the information as below. The problem is I do not quite understand how to exclude someone who has a single result row in which they did have a 'UN' result on a day but did not have any other tests that day.
Query Results (Columns)
County, DrugTestID, ID, Name, CollectionDate, DrugTestType, Results, Count(DrugTestType)
I have several rows for ID 12345 which are correct. But ID 12346 is a single row of which is showing they had a row result of count (1). They had a result of 'UN' on this day but they did not have any other tests that day. I want to exclude this.
I tried the following query
select
c.desc as 'County',
dt.pid as 'PID',
dt.id as 'DrugTestID',
p.id as 'ID',
bio.FullName as 'Participant',
CONVERT(varchar, dt.CollectionDate, 101) as 'CollectionDate',
dtt.desc as 'Drug Test Type',
dt.result as Result,
COUNT(dt.dru_drug_test_type) as 'Count Of Test Type'
from
dbo.Test as dt with (nolock)
join dbo.History as h on dt.pid = h.id
join dbo.Participant as p on h.pid = p.id
join BioData as bio on bio.id = p.id
join County as c with (nolock) on p.CountyCode = c.code
join DrugTestType as dtt with (nolock) on dt.DrugTestType = dtt.code
inner join
(
select distinct
dt2.pid,
CONVERT(varchar, dt2.CollectionDate, 101) as 'CollectionDate'
from
dbo.DrugTest as dt2 with (nolock)
join dbo.History as h2 on dt2.pid = h2.id
join dbo.Participant as p2 on h2.pid = p2.id
where
dt2.result = 'UN'
and dt2.CollectionDate between '11-01-2011' and '10-31-2012'
and p2.DrugCourtType = 'AD'
) as derived
on dt.pid = derived.pid
and convert(varchar, dt.CollectionDate, 101) = convert(varchar, derived.CollectionDate, 101)
group by
c.desc, dt.pid, p.id, dt.id, bio.fullname, dt.CollectionDate, dtt.desc, dt.result
order by
c.desc ASC, Participant ASC, dt.CollectionDate ASC
This is a little complicated because the your query has a separate row for each test. You need to use window/analytic functions to get the information you want. These allow you to do calculate aggregation functions, but to put the values on each line.
The following query starts with your query. It then calculates the number of UN results on each date for each participant and the total number of tests. It applies the appropriate filter to get what you want:
with base as (<your query here>)
select b.*
from (select b.*,
sum(isUN) over (partition by Participant, CollectionDate) as NumUNs,
count(*) over (partition by Partitipant, CollectionDate) as NumTests
from (select b.*,
(case when result = 'UN' then 1 else 0 end) as IsUN
from base
) b
) b
where NumUNs <> 1 or NumTests <> 1
Without the with clause or window functions, you can create a particularly ugly query to do the same thing:
select b.*
from (<your query>) b join
(select Participant, CollectionDate, count(*) as NumTests,
sum(case when result = 'UN' then 1 else 0 end) as NumUNs
from (<your query>) b
group by Participant, CollectionDate
) bsum
on b.Participant = bsum.Participant and
b.CollectionDate = bsum.CollectionDate
where NumUNs <> 1 or NumTests <> 1
If I understand the problem, the basic pattern for this sort of query is simply to include negating or exclusionary conditions in your join. I.E., self-join where columnA matches, but columns B and C do not:
select
[columns]
from
table t1
join table t2 on (
t1.NonPkId = t2.NonPkId
and t1.PkId != t2.PkId
and t1.category != t2.category
)
Put the conditions in the WHERE clause if it benchmarks better:
select
[columns]
from
table t1
join table t2 on (
t1.NonPkId = t2.NonPkId
)
where
t1.PkId != t2.PkId
and t1.category != t2.category
And it's often easiest to start with the self-join, treating it as a "base table" on which to join all related information:
select
[columns]
from
(select
[columns]
from
table t1
join table t2 on (
t1.NonPkId = t2.NonPkId
)
where
t1.PkId != t2.PkId
and t1.category != t2.category
) bt
join [othertable] on (<whatever>)
join [othertable] on (<whatever>)
join [othertable] on (<whatever>)
This can allow you to focus on getting that self-join right, without interference from other tables.
I have tried a lot to figure how to get the count from two tables with respect to master table
I have three tables
Using these table values I need to get this output..
Tried but could get the desired result
http://en.wikipedia.org/wiki/Join_(SQL)
SQL - LEFT OUTER JOIN and WHERE clause
http://forums.devshed.com/oracle-development-96/combination-of-left-outer-join-and-where-clause-383248.html
You have to first GROUP BY in subqueries, then JOIN to the main table:
SELECT
a.AttributeId
, COALECSE(cntE, 0) AS cntE
, COALECSE(cntM, 0) AS cntM
FROM
AttributeMaster AS a
LEFT JOIN
( SELECT
AttributeId
, COUNT(*) AS cntE
FROM
EmployeeMaster
GROUP BY
AttributeId
) em
ON em.AttributeId = a.AttributeId
LEFT JOIN
( SELECT
AttributeId
, COUNT(*) AS cntM
FROM
MonthlyDerivedMaster
GROUP BY
AttributeId
) mdm
ON mdm.AttributeId = a.AttributeId
SELECT AttributeId,
(SELECT COUNT(Eid) FROM EmployeeMaster WHERE AttributeMaster.AttributeId = EmployeeMaster.AttributeId) as master_eid,
(SELECT COUNT(Eid) FROM MonthnlyDerivedMaster WHERE AttributeMaster.AttributeId = MonthnlyDerivedMaster.AttributeId) as monthly_eid
FROM AttributeMaster