SQL FOR JSON: Create line for each object - sql

Question

I'm currently working on a JSON creation on a SQL Server 2016. For this, I use the FOR JSON function.
SELECT TOP 2
'12.00' AS [time]
,GUID AS [ID]
,'action value' AS [EVENT.ACTION]
,'category value' AS [EVENT.CATEGORY]
,'username' AS [user.name]
FROM TABLE_NAME
FOR JSON PATH, WITHOUT_ARRAY_WRAPPER
This piece of code creates me this:
{"time":"12.00","ID":"16AE8C15-084C-4C84-8F5D-0000193F8E74","EVENT":{"ACTION":"action value","CATEGORY":"category value"},"user":{"name":"username"}},{"time":"12.00","ID":"D5667AF4-5922-4D30-9C8A-00001AB928F6","EVENT":{"ACTION":"action value","CATEGORY":"category value"},"user":{"name":"username"}}
The problem is, every object gets displayed on line 1, but I would like to have one line per object.
This would look like this:
{"time":"12.00","ID":"16AE8C15-084C-4C84-8F5D-0000193F8E74","EVENT":{"ACTION":"action value","CATEGORY":"category value"},"user":{"name":"username"}},
{"time":"12.00","ID":"D5667AF4-5922-4D30-9C8A-00001AB928F6","EVENT":{"ACTION":"action value","CATEGORY":"category value"},"user":{"name":"username"}}
I have not found any snippets to do this. How can I create such a

Answer 1

If you need to build a separate JSON object for each row, you may try the following statement:
SELECT TOP 2
(
SELECT
'12.00' AS [time]
,GUID AS [ID]
,'action value' AS [EVENT.ACTION]
,'category value' AS [EVENT.CATEGORY]
,'username' AS [user.name]
FOR JSON PATH, WITHOUT_ARRAY_WRAPPER
) AS JsonData
FROM TABLE_NAME
But, if the expected ouput is one JSON array (with or without array wrapper) for the entire table, the format of this output is controlled by FOR JSON AUTO. The visual representation of this output (one line per each JSON object) should be made in the presentation layer. Of course, as an additional option using T-SQL, a small string manipulation is a possible solution:
SELECT REPLACE (
(
SELECT TOP 2
'12.00' AS [time]
,GUID AS [ID]
,'action value' AS [EVENT.ACTION]
,'category value' AS [EVENT.CATEGORY]
,'username' AS [user.name]
FROM TABLE_NAME
FOR JSON PATH, WITHOUT_ARRAY_WRAPPER
),
'},{',
'},' + CHAR(10) + '{'
)