PLSQL - REGEXP_SUBSTR Remove XML Tags - sql

Question

I currently have a payload that was generated by oracle xml gateway that I need to pull some exact information out. The payload information is store within a db table meaning that I am attempting to us regexp_substr to accomplish this task.
This is the tag that is in the middle of the XML document
<IDCODE>S2200</IDCODE>
"<?xml version="1.0" encoding="UTF-8" standalone='no'?>
<!DOCTYPE PROCESS_INVOICE_002 SYSTEM "asfasdf.dtd">
<!-- Oracle eXtensible Markup Language Gateway Server -->
<PROCESS_INVOICE_002>
<CNTROLAREA>
<BSR>
<VERB value="PROCESS"/>
<NOUN value="INVOICE"/>
<REVISION value="002"/>
</BSR>
<SENDER>
<LOGICALID/>
<COMPONENT/>
<TASK/>
<REFERENCEID/>
<CONFIRMATION/>
<LANGUAGE/>
<CODEPAGE/>
<AUTHID/>
</SENDER>
<DATETIME qualifier="CREATION">
<YEAR/>
<MONTH/>
<DAY/>
<HOUR/>
<MINUTE/>
<SECOND/>
<SUBSECOND/>
<TIMEZONE/>
</DATETIME>
</CNTROLAREA>
<DATAAREA>
<PROCESS_INVOICE>
<INVHEADER>
<AMOUNT qualifier="DOCUMENT" type="T" index="1">
<VALUE>78538</VALUE>
<NUMOFDEC>8</NUMOFDEC>
<SIGN>+</SIGN>
<CURRENCY>USD</CURRENCY>
<DRCR>D</DRCR>
</AMOUNT>
<DATETIME qualifier="DOCUMENT" index="1">
<YEAR>2020</YEAR>
<MONTH>11</MONTH>
<DAY>28</DAY>
<HOUR>00</HOUR>
<MINUTE>00</MINUTE>
<SECOND>00</SECOND>
<SUBSECOND>0000</SUBSECOND>
<TIMEZONE>+0000</TIMEZONE>
</DATETIME>
<DOCUMENTID>81989184</DOCUMENTID>
<DESCRIPTN/>
<DOCTYPE>INV</DOCTYPE>
<PAYMETHOD/>
<REASONCODE/>
<USERAREA>
<NOTEREFCODE/>
<NOTESREF/>
<VENDNUMQUAL>IA</VENDNUMQUAL>
<VENDNUM>98181</VENDNUM>
<DEPTNUMQUAL>DP</DEPTNUMQUAL>
<DEPTNUM>85</DEPTNUM>
<ORDNUMQUAL/>
<ORDNUM>0</ORDNUM>
<CUSTCODEQUAL/>
<CUSTCODE/>
<NETDAYS/>
<DATETIMEQUAL/>
<FOBCODE/>
<UOM/>
<TOTALQUANTITY/>
</USERAREA>
<PARTNER>
<NAME index="1">COMPANY NAME</NAME>
<ONETIME/>
<PARTNRID/>
<PARTNRTYPE>Supplier</PARTNRTYPE>
<SYNCIND/>
<ACTIVE/>
<CURRENCY/>
<DESCRIPTN/>
<DUNSNUMBER/>
<GLENTITYS/>
<PARENTID/>
<PARTNRIDX/>
<PARTNRRATG/>
<PARTNRROLE/>
<PAYMETHOD/>
<TAXEXEMPT/>
<TAXID/>
<TERMID/>
<USERAREA>
<IDQUAL/>
<IDCODE/>
</USERAREA>
<CONTACT>
<NAME index="1">PROFILE</NAME>
<CONTCTTYPE/>
<DESCRIPTN/>
<EMAIL/>
<FAX index="1"/>
<TELEPHONE index="1"/>
<USERAREA/>
</CONTACT>
</PARTNER>
<PARTNER>
<NAME index="1">CUSTOMER NAME</NAME>
<ONETIME/>
<PARTNRID>981698198</PARTNRID>
<PARTNRTYPE>ShipTo</PARTNRTYPE>
<SYNCIND/>
<ACTIVE/>
<CURRENCY/>
<DESCRIPTN/>
<DUNSNUMBER/>
<GLENTITYS/>
<PARENTID/>
<PARTNRIDX/>
<PARTNRRATG/>
<PARTNRROLE/>
<PAYMETHOD/>
<TAXEXEMPT/>
<TAXID/>
<TERMID/>
<USERAREA>
<IDQUAL>ZZ</IDQUAL>
<IDCODE>S2200</IDCODE>
</USERAREA>
<ADDRESS>
<ADDRLINE index="1">123 MAIN STREET</ADDRLINE>
<ADDRTYPE/>
<CITY>HAM CITY</CITY>
<COUNTRY>United States</COUNTRY>
<COUNTY>NEW YORK</COUNTY>
<DESCRIPTN/>
<FAX index="1"/>
<POSTALCODE>18080</POSTALCODE>
<REGION/>
<STATEPROVN>NY</STATEPROVN>
<TAXJRSDCTN/>
<TELEPHONE index="1"/>
<URL/>
<USERAREA/>
</ADDRESS>
REGEX that I am using in the query
TRIM(regexp_substr(ed.payload, '?.+(</IDCODE>)')) Store_NUM,
TRIM(regexp_substr(ed.payload, '(^IDCODE)?.+(</IDCODE>)')) Store_Number
The Outcome that I am receiving from the above SQL regexp_substr. The issue is that I have made it to the correct tab but I can't figure out how to strip the \<IDCODE> and the \</IDCODE> for the output
-Field can have 4 or 5 chars
-letters or numbers
<IDCODE>S2200</IDCODE> Store_NUM
<IDCODE>S2200</IDCODE> Store_Number

Answer 1

I believe you are looking for this if I am understanding you correctly. Return everything in the group between the tags.
SELECT REGEXP_SUBSTR('<IDCODE>S2200</IDCODE>', '<IDCODE>(.*)</IDCODE>', 1, 1, NULL, 1) Store_Number
from dual;
STORE_NUMBER
------------
S2200
1 row selected.