Ramda.js - How to make R.merge point free - 2 functions with same dataset - ramda.js

Question

Given the below code snippet that uses Ramda.js, are there multiple ways of making parseDetails point free? If so, is there an "ideal" way of doing it?
const someData = {
products: [{
stockId: 123,
name: "chocolate",
translatedTags: {
wasPrice: "Was 10"
}
}]
}
const getProductData = R.pipe(
R.pathOr([], ['products', 0]),
R.pick([
'stockId',
'name']
)
);
const getProductTags = R.pipe(
R.pathOr([], ['products', 0, 'translatedTags'])
);
const parseDetails = (data) => R.merge(
getProductData(data),
getProductTags(data)
);
parseDetails(someData);

Answer 1

There are several ways I can think of, but by far the best is to use lift. The way I think of using lift is that it takes a function which works on values and returns an equivalent function which works on containers of those values.
And functions that return those values can be thought of as containers. So we can do it like this:
const getProductData = pipe (
pathOr ([], ['products', 0]),
pick ([
'stockId',
'name']
)
)
// `pipe` not necessary here
const getProductTags = pathOr ([], ['products', 0, 'translatedTags'])
const parseDetails = lift (merge) (getProductData, getProductTags)
const someData = {products: [{stockId: 123, name: "chocolate", translatedTags: {wasPrice: "Was 10"}}]}
console .log (parseDetails (someData))
<script src="//cdnjs.cloudflare.com/ajax/libs/ramda/0.27.1/ramda.min.js"></script>
<script> const {pipe, pathOr, pick, lift, merge} = R </script>
And if you have no other need for getProductData or getProductTag, you can inline them in the function:
const parseDetails = lift (merge) (
pipe (pathOr ([], ['products', 0]), pick (['stockId', 'name'])),
pathOr ([], ['products', 0, 'translatedTags'])
)