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SELECT *
FROM Products
WHERE Industry IN (SELECT *
FROM STRING_SPLIT('Logistics;Retail;Agriculture', ';'))
Can I use LIKE instead of IN in my WHERE clause?
You could use LIKE as follows:
SELECT *
FROM Products
WHERE ';Logistics;Retail;Agriculture;' LIKE '%;' + Industry + ';%';
But it would be better to see if you can use a WHERE IN (...) construct, which would be sargable, easier to handle, and probably more performant than the above.
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How can I find data that dont end with letter 'g' without using NOT LIKE function, please help
select * from table where right(column, 1) != 'g'
Since you asked how to do it using "not like," I'll answer that. The function version provided by #Zoories would be more efficient.
This works at w3schools.com
SELECT * FROM Customers where CustomerName not like '%g';
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I want to find if the difference between 2 columns. How do I achieve that?
For example,
select(col1-col2) output is 1
select(col2-col1) output is -1
Is there a way to get just the difference as 1 without the negative (-) sign?
use abs() function
select abs(col2-col1) as diff
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π LOC, DEPTNO(DEPT) – πDEPTNO (σLOC-‘DALLAS’(DEPT))
The schemata of the left and right arguments of operator – (set difference) do not match: {LOC, DEPTNO} ≠ {DEPTNO}.
As is, this relational algebra query could not be evaluated.
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Team,
I need a sql query or function which will create the mirror image of string.
Thanks
Rajeev
If "mirror" is reversed text use:
SELECT REVERSE('my_text') FROM dual;
EDIT:
SqlFiddleDemo
SELECT t
,REVERSE(t) AS Mirror1
,TRANSLATE(t, 'abcdefghijklmnopqrstuvwxyz',N'ɐqɔpǝɟbɥıظʞןɯuodbɹsʇnʌʍxʎz') AS Mirror2
,TRANSLATE(REVERSE(t), 'abcdefghijklmnopqrstuvwxyz',N'ɐqɔpǝɟbɥıظʞןɯuodbɹsʇnʌʍxʎz') AS Mirror3
FROM tab;
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I am using Oracle SQL developer 2012. My data looks like 'valueA-valueB'. I want to strip the content after - and populate with rest.
You can use a combination of substr and instr:
SELECT SUBSTR(my_column, 1, INSTR(my_column, '-') - 1)
FROM my_table