SQL - Using Count with WHERE clause - sql

Question

I'm trying to do a simple, at first sight, SQL query, but I can't wrap my head around what I'm doing wrong.
Problem
Imagine these are my tables:
TableUsers
UserID FirstName LastName
1 Bill Johnson
2 Alex Agnew
3 Mike Owen
4 Kate Ryan
TableArticles
ArticleID Description
1 Bananas
2 Eggs
3 Milk
TableOrders
OrderID UserID ArticleID
1 1 1
2 1 2
3 2 3
4 2 2
5 3 3
I want to list all users who have at least one order linked to their name, count how many orders and count how many of a specific article they ordered:
Desired result
UserID FirstName # Orders # Banana orders # Egg orders
1 Bill 2 1 1
2 Alex 2 0 1
3 Mike 1 0 0
I have tried:
SELECT
UserID,
FirstName,
COUNT(*) AS '# Orders',
(SELECT COUNT(*) FROM TableOrders O WHERE O.UserID = TableOrders.UserID AND O.ArticleID = 1) AS '# Banana orders',
(SELECT COUNT(*) FROM TableOrders O WHERE O.UserID = TableOrders.UserID AND O.ArticleID = 2) AS '# Egg orders',
FROM TableUsers
LEFT JOIN TableOrders ON TableOrders.UserID = TableUsers.UserID
GROUP BY UserID, FirstName
HAVING Count(*) > 0;
But I'm getting an error saying the ArticleID needs to be in an aggregate function or group by clause. If I add the ArticleID to the group by clause, users with multiple orders are shown more than once...
Any help is appreciated!
Thank you!

Answer 1

Just use conditional aggregation:
SELECT o.UserID, o.FirstName, COUNT(*) AS num_orders,
SUM(CASE WHEN o.ArticleID = 1 THEN 1 ELSE 0 END) as num_bananas,
SUM(CASE WHEN o.ArticleID = 2 THEN 1 ELSE 0 END) as num_eggs
FROM TableUsers u JOIN
TableOrders o
ON o.UserID = u.UserID
GROUP BY UserID, FirstName;
Notes:
You want users with orders, so just use an inner join, not an outer join.
The HAVING clause is then not necessary.
Table aliases make the query easier to read and write.
Don't use single quotes for column aliases. It is better to name the columns so they don't need to be escaped.