I'm attempting to get the difference of time in seconds between two timestamps on an sqlite db (running sqlite 3.12.1) I've tried several things I have found here on stack overflow but nothing seems to be working as expected.
for reference I've tried creating the datetime field as both an integer and a text field and I get the same results. Below is the query I'm running and the results set that it produces.
essentially I'm attempting to replicate the datediff() function in SQL Server
select cast(JulianDay('now') - JulianDay(last_upd_dt) * 24 * 60 * 60 As Integer) "gives me null value",
last_upd_dt as "from date",
datetime('now') as "To date this will be another field in the future",
(datetime('now') - last_upd_dt ) as "Gives me 2012 on all records"
from sqlite_db
Your date value should be stored as a TEXT datatype, in one of the formats supported by SQLite, such as YYYY-MM-DD HH:MI:SS.
Then, you can do
select (julianday('now') - julianday(last_upd_dt)) * 24 * 60 * 60 as date_diff_seconds
from mytable
The problem with your code is that you should use parentheses around the difference of the dates and then multiply by 24 * 60 * 60.
But there is a much simpler way to get the difference between 2 dates in seconds:
select strftime('%s', 'now') - strftime('%s', last_upd_dt)
from sqlite_db
The function strftime() with the '%s' modifier returns the unix timestamp (the number of seconds since '1970-01-01') of a date (provided it is formatted as YYYY-MM-DD hh:mm:ss).
Related
I have two timestamp columns: arrTime and depTime.
I need to find the number of munites the bus is late.
I tried the following:
SELECT RouteDate, round((arrTime-depTime)*1440,2) time_difference
FROM ...
I get the following error: inconsistent datatype . expected number but got interval day to second
How can i parse the nuber of minutes?
If i simply subtract: SELECT RouteDate, arrTime-depTime)*1440 time_difference
The result is correct but not well formatted:
time_difference
+00000000 00:01:00 0000000
The result of timestamp arithmetic is an INTERVAL datatype. You have an INTERVAL DAY TO SECOND there...
If you want the number of minutes one way would be to use EXTRACT(), for instance:
select extract( minute from interval_difference )
+ extract( hour from interval_difference ) * 60
+ extract( day from interval_difference ) * 60 * 24
from ( select systimestamp - (systimestamp - 1) as interval_difference
from dual )
Alternatively you can use a trick with dates:
select sysdate + (interval_difference * 1440) - sysdate
from (select systimestamp - (systimestamp - 1) as interval_difference
from dual )
The "trick" version works because of the operator order of precedence and the differences between date and timestamp arithmetic.
Initially the operation looks like this:
date + ( interval * number ) - date
As mentioned in the documentation:
Oracle evaluates expressions inside parentheses before evaluating those outside.
So, the first operation performed it to multiply the interval by 1,440. An interval, i.e. a discrete period of time, multiplied by a number is another discrete period of time, see the documentation on datetime and interval arithmetic. So, the result of this operation is an interval, leaving us with:
date + interval - date
The plus operator takes precedence over the minus here. The reason for this could be that an interval minus a date is an invalid operation, but the documentation also implies that this is the case (doesn't come out and say it). So, the first operation performed is date + interval. A date plus an interval is a date. Leaving just
date - date
As per the documentation, this results in an integer representing the number of days. However, you multiplied the original interval by 1,440, so this now represented 1,440 times the amount of days it otherwise would have. You're then left with the number of seconds.
It's worth noting that:
When interval calculations return a datetime value, the result must be an actual datetime value or the database returns an error. For example, the next two statements return errors:
The "trick" method will fail, rarely but it will still fail. As ever it's best to do it properly.
SELECT (arrTime - depTime) * 1440 time_difference
FROM Schedule
WHERE ...
That will get you the time difference in minutes. Of course, you can do any rounding that you might need to to get whole minutes....
Casting to DATE first returns the difference as a number, at least with the version of Oracle I tried.
round((cast(arrTime as date) - cast(depTime as date))*1440)
You could use TO_CHAR then convert back to a number. I have never tested the performance compared to EXTRACT, but the statement works with two dates instead of an interval which fit my needs.
Seconds:
(to_char(arrTime,'J')-to_char(depTime,'J'))*86400+(to_char(arrTime,'SSSSS')-to_char(depTime,'SSSSS'))
Minutes:
round((to_char(arrTime,'J')-to_char(depTime,'J'))*1440+(to_char(arrTime,'SSSSS')-to_char(depTime,'SSSSS'))/60)
J is julian day and SSSSS is seconds in day. Together they give an absolute time in seconds.
I need to know a difference between start time and end time. Both are DATETIME fields, I tried to use "-" and DATADIFF.
I already tried using DATADIFF and simple subtraction converting the field to just time.
(to_date(Fim_Hora,'HH24:MI') - to_date(Inicio_Hora,'HH24:MI')) AS Diferenca
DATADIFF(MIN,Fim_Hora,Inicio_Hora)
I need to know the time in minutes for use as parameters.
Oracle does not have a time data type. Usually, subtraction works well enough:
select (end_time - start_time) as diff
You may need to convert to a string if you want it formatted in a particular way.
In Oracle, you can directly substract dates, it returns the difference between the dates in days. To get the difference in minutes, you can multiply the result by 24 (hours per days) and 60 (minutes per hour):
(Fim_Hora - Inicio_Hora) * 24 * 60 diff_minutes
This assumes that both Fim_Hora and Inicio_Hora are of datatype DATE.
I store date from Calendar.getTimeInMilliseconds() in SQLite DB.
I need to mark first rows by every month in SELECT statement, so I need convert time in milliseconds into any date format using SQLite function only. How can I avoid this?
One of SQLite's supported date/time formats is Unix timestamps, i.e., seconds since 1970.
To convert milliseconds to that, just divide by 1000.
Then use some date/time function to get the year and the month:
SELECT strftime('%Y-%m', MillisField / 1000, 'unixepoch') FROM MyTable
Datetime expects epochtime, which is in number of seconds while you are passing in milliseconds. Convert to seconds & apply.
SELECT datetime(1346142933585/1000, 'unixepoch');
Can verify this from this fiddle
http://sqlfiddle.com/#!5/d41d8/223
Do you need to avoid milliseconds to date conversion or function to convert milliseconds to date?
Since sqlite date functions work with seconds, then you can try to
convert milliseconds in your query, like this
select date(milliscolumn/1000,'unixepoch','localtime') from table1
convert millis to seconds before saving it to db, and then use date function in sql query
I have two fields dateTS and closingTime.
dateTS is a normal timestamp field (e.g. 2019-07-13 22:31:10.000000)
closingTime is a HH:MM format of when a store closes (e.g. 23:00)
I need a PostgreSQL query to subtract the two field and get the number of minutes difference between them.
Using the examples given above the difference between the two fields would be 28 minutes
So far I've tried different variations of the datediff function, but it won't work.
My guess is I either have to
a. generate a fake timestamp for closingTime which is the same day as the dateTs field and subtract the 2 timestamps.
or
b. convert the hour/minutes of both field to a float and subtract the two values to get the hours difference and convert that to minutes
You can just subtract them by converting the timestamp to a time:
select closingtime - datets::time
from your_table;
That will give you an interval as the result.
To convert that to minutes you can get the number of seconds and divide it by 60:
select (extract epoch from closingtime - datets::time) / 60
from your_table;
Cast your closing time to an interval and the timestamp to time and then subtract the two. By casting the timestamp to time you are effectively discarding the date part. You can the subtract one from the other to generate the difference as an interval.
select closingTime::interval - dateTS::time...
e.g.:
# select '23:00'::interval - now()::time;
?column?
-----------------
05:31:00.031141
(1 row)
If needed you can then convert the interval to minutes:
# select extract(epoch from ('23:00'::interval - now()::time)) / 60;
?column?
------------------
327.435313083333
(1 row)
I need to write a select query that gets data in between EPOCH(datetime)-3600 AND EPOCH(datetime).
select all incidents modified in specific date range between EPOCH(datetime)-3600 AND EPOCH(datetime)
So my query is:
SELECT *
FROM TABLENAME
WHERE COLUMN_NAME BETWEEN COLUMNNAME-3600 AND COLUMNNAME
Will this query get the data from 1 hour ago to the current time, in Unix TimeStamp format?
Given a column (COLUMN_NAME) where data is stored as a unix timestamp (eg number of seconds elapsed since January 1st, 1970), you are looking to filter records based on a DATE passed as parameter.
My understanding is that you need a way to convert a unix timestamp to a date. There is no such built-in function in Oracle, however you are allowed to add a number to a date, where the number represents the number of days to add.
Try :
SELECT *
FROM TABLENAME
WHERE
TO_DATE('01/01/1970', 'dd/mm/yyyy') + COLUMN_NAME/60/60/24 -- convert unix timestamp to date
BETWEEN :mydate - 3600 AND :mydate
;
Replace both :mydate with the actual DATE for which you want the search to be performed.