Launch url in default video player on android with react native - react-native

Question

I found this native android code for what I am trying to achieve
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setDataAndType(Uri.parse(newVideoPath), "video/mp4");
startActivity(intent);
(Android intent for playing video?)
But I can't figure out how to use apply it in react native with the Linking.sendIntent api, or if that api is even capable of doing it.
I also tried this module, but it failed to build the project with the error method does not override or implement a method from a supertype
I don't want to write a native module for this.

Answer 1

Turns out you can't send data with an intent with the built in sendIntent api, however there's a handy library that's capable of doing that (react-native-send-intent).
So now I am able to achieve what I wanted like so:
import { Linking, Platform } from "react-native";
import SendIntentAndroid from "react-native-send-intent";
export function playVideo(url){
var fn = Platform.select({
android(){
SendIntentAndroid.openAppWithData(
/* "org.videolan.vlc" */null,
"https://www.w3schools.com/html/mov_bbb.mp4",
"video/*"
).then(wasOpened => {});
},
default(){
Linking.openURL(url).catch(err => {});
}
});
fn();
}
Despite the library not offering a function for launching the default app for a url, you can achieve it by passing in null as the packagename, since the function it uses under the hood Intent.setPackage(String packageName), accepts null as a value.