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I need to expected result from the attached screenshot
month empid emp_name p count wo count Totalhrs
----------------------------------------------------------------------------
FEB 00113 HUda salem al kaabi 25 4 1250
You can try a query like this :
Select
empid
max(emp_name) as emp_name,
count(*) as count,
sum(case when dstatus='wo' then 1 else 0 end) as wo_count,
sum(total_hrs) as totalhrs
from
<your_table>
where
p_date like '2020-10%'
group by
empid
Use conditional aggregation:
select empid, emp_name,
sum(case when dstatus = 'P' then 1 else 0 end) p_count,
sum(case when dstatus = 'WO' then 1 else 0 end) wo_count,
sum(total_hrs) total_hrs
from mytable
group by empid, emp_name
SELECT empid, emp_name, COUNT(*) 'p count', COUNT( IIF(DSTATUS = 'WO',1,0 )) 'wo count', COUNT(Total_Hrs) 'Total Hours'
FROM tb
GROUP BY empid, emp_name, p_count, wo_count, Total_Hrs
Related
Someone knows how i can group ages witch the CASE statement?
I got the ages 14,15,16,17,18,19,20,21,22,23,24,25. I want groups like <18,19,20,>21
I started like:
Case age when BETWEEN 14 AND 18 THEN sum(age)
when >=21 THEN sum(age)
ELSE age END as age_groups
But i think aggregate functions don't work in CASE statements, at least it brings up an error.
CASE statement would work, you have a syntax error, your query would be:
SELECT Case when age BETWEEN 14 AND 18 THEN '14 - 18'
when age >=21 THEN '>=21'
ELSE age END as age_groups, SUM(age)
FROM YOUR_TABLE
GROUP BY Case when age BETWEEN 14 AND 18 THEN '14 - 18'
when age >=21 THEN '>=21'
ELSE age END
Use a CTE to calculate the age_groups, and then you can normally sum the ages for each group.
WITH age_groups AS (
SELECT Age,
Case when age BETWEEN 14 AND 18 THEN '14 - 18'
when age >=21 THEN '>=21'
ELSE age END as age_group
FROM YOUR_TABLE
)
SELECT age_group, sum(Age)
FROM age_groups
GROUP BY age_group
Another neat alternative is to place the CASE inside a CROSS APPLY (VALUES so you can then refer to it in other parts of the query without repetition:
SELECT
v.age_group,
SUM(Age)
FROM age_groups ag
CROSS APPLY (VALUES (
CASE WHEN ag.age BETWEEN 14 AND 18 THEN '14 - 18'
WHEN ag.age >= 21 THEN '>=21'
ELSE CAST(ag.age AS varchar(10)) END
) ) v(age_group)
GROUP BY v.age_group
You can use Case inside Sum():
select
Sum(Case when age < 18 then 1 end) '<18',
Sum(Case when age = 19 then 1 end) '19',
Sum(Case when age = 20 then 1 end) '20',
Sum(Case when age > 20 then 1 end) '>20'
from myTable;
DBFiddle demo is here
EDIT: If you meant to get the results vertically, still keep it simple:
select '<18' as ageGroup, Sum(Case when age < 18 then 1 end) total from myTable
union
select '19', Sum(Case when age = 19 then 1 end) from myTable
union
select '20', Sum(Case when age = 20 then 1 end) from myTable
union
select '20>', Sum(Case when age > 20 then 1 end) from myTable;
I am writing a sql script in which I want to get total number of appointments per salesperson then also get how much he rank out of the rest salesperson. e.g Salesperson x has 5 appointment and he rate 4 out of 10 salespersons.
**expected results**:
Salesperson x 5 4/10
Salesperson D 6 5/10
Salesperson s 8 7/10
Use rank()
with sales as
(
select Salesperson, count(appointment) appointments
from SalesTable
group by Salesperson
)
select sales.*, rank() over (order by appointments desc) as salesrank
from sales
Hi Thanks for your response. I tried it this way it works:
select id,sales_person,"Appointment/Day",rank_for_the_day,"Appointment/Week",rank_for_the_week,"Appointment/Month",
rank_for_the_month,"Appointment/year",rank_for_the_year
from(
select supplied_id,salesperson,sum(case when appointment_date::date=current_date then 1 else 0 end )"Appointment/Day",
rank() over (order by sum(case when appointment_date::date=current_date then 1 else 0 end ) desc )||'/'||
(select sum(case when appointment_date::date=current_date then 1 else 0 end ) from match where date_part( 'year', appointment_date)=2017
and appointment_date is not null and date_part('day',appointment_date)=date_part('day',current_date) ) rank_for_the_day,
sum(case when appointment_date::date between current_date-7 and current_date then 1 else 0 end )"Appointment/Week",
rank() over (order by sum(case when appointment_date::date between current_date-7 and current_date then 1 else 0 end ) desc)||'/'||
(select sum(case when appointment_date::date between current_date-7 and current_date then 1 else 0 end )
from match m where date_part( 'year', appointment_date)=2017 and appointment_date is not null
and date_part('week',appointment_date)=date_part('week',current_date) ) rank_for_the_week,
sum(case when date_part('month',appointment_date)=date_part('month',current_date) then 1 else 0 end )"Appointment/Month",
rank() over (order by sum(case when date_part('month',appointment_date)=date_part('month',current_date) then 1 else 0 end ) desc)||'/'||
(select sum(case when date_part('month',appointment_date)=date_part('month',current_date) then 1 else 0 end )
from match m where date_part( 'year', appointment_date)=2017 and appointment_date is not null
and date_part('month',appointment_date)=date_part('month',current_date) ) rank_for_the_month,
sum(case when date_part('year',appointment_date)=date_part('year',current_date) then 1 else 0 end )"Appointment/year",
rank() over (order by sum(case when date_part('year',appointment_date)=date_part('year',current_date) then 1 else 0 end ) desc)||'/'||
(select sum(case when date_part('year',appointment_date)=date_part('year',current_date) then 1 else 0 end )
from match m where date_part( 'year', appointment_date)=2017 and appointment_date is not null
and date_part('year',appointment_date)=date_part('year',current_date) ) rank_for_the_year
from salespersontable
where date_part( 'year', appointment_date)=2017 and appointment_date is not null
group by id,salesperson
)x order by 6 desc
However,I would appreciate an efficient way to write this query to minimize resource consumption.
I want to get statistics with sql query. My table is like this:
ID MATERIAL CREATEDATE DEPARTMENT
1 M1 10.10.1980 D1
2 M2 11.02.1970 D2
2 M3 18.04.1971 D3
.....................
.....................
.....................
How can I get a range of data count like this
DEPARTMENT AGE<10 10<AGE<20 20<AGE
D1 24 123 324
D2 24 123 324
Assuming that CREATEDATE is a date column, in PostgreSQL you can use the AGE function:
select DEPARTMENT, age(CREATEDATE) as AGE
from Materials
and with date_part you can get the age in years. To show the data in the format that you want, you could use this GROUP BY query:
select
DEPARTMENT,
sum(case when date_part('year', age(CREATEDATE))<10 then 1 end) as "age<10",
sum(case when date_part('year', age(CREATEDATE))>=10 and date_part('year', age(CREATEDATE))<20 then 1 end) as "10<age<20",
sum(case when date_part('year', age(CREATEDATE))>=20 then 1 end) as "20<age"
from
Materials
group by
DEPARTMENT
which can be simplified as:
with mat_age as (
select DEPARTMENT, date_part('year', age(CREATEDATE)) as mage
from Materials
)
select
DEPARTMENT,
sum(case when mage<10 then 1 end) as "age<10",
sum(case when mage>=10 and mage<20 then 1 end) as "10<age<20",
sum(case when mage>=20 then 1 end) as "20<age"
from
mat_age
group by
DEPARTMENT;
if you are using PostgreSQL 9.4 you can use FILTER:
with mat_age as (
select DEPARTMENT, date_part('year', age(CREATEDATE)) as mage
from Materials
)
select
DEPARTMENT,
count(*) filter (where mage<10) as "age<10",
count(*) filter (where mage>=10 and mage<20) as "10<age<20",
count(*) filter (where mage>=20) as "20<age"
from
mat_age
group by
DEPARTMENT;
The following solution assumes that your CREATEDATE column exists as some sort of valid Postgres date type. If this be not the case, and it is being stored as text, you will first have to convert it to date in order for the query to work.
SELECT DEPARTMENT,
SUM(CASE WHEN DATEDIFF(year, CREATEDATE, now()::date) < 10 THEN 1 ELSE 0 END) AS "AGE<10",
SUM(CASE WHEN DATEDIFF(year, CREATEDATE, now()::date) >= 10 AND
DATEDIFF(year, CREATEDATE, now()::date) < 20 THEN 1 ELSE 0 END) AS "10<AGE<20",
SUM(CASE WHEN DATEDIFF(year, CREATEDATE, now()::date) >= 20 THEN 1 ELSE 0 END) AS "20<AGE"
FROM Materials
GROUP BY DEPARTMENT
You can use extract(year FROM age(createdate)) to get the exact age
i.e
select extract(year FROM age(timestamp '01-01-1989')) age
will give you
Result:
age
---
27
so you can use following select statement to get your desired output:
SELECT dept
,sum(CASE WHEN age < 10THEN 1 END) "age<10"
,sum(CASE WHEN age >= 10 AND age < 20 THEN 1 END) "10<age<20"
,sum(CASE WHEN age >= 20 THEN 1 END) "20<age"
FROM (
SELECT dept,extract(year FROM age(crdate)) age
FROM dt
) t
GROUP BY dept
If you don't want to use a sub select use this.
SELECT dept
,sum(CASE WHEN extract(year FROM age(crdate)) < 10THEN 1 END) "age<10"
,sum(CASE WHEN extract(year FROM age(crdate)) >= 10 AND extract(year FROM age(crdate)) < 20 THEN 1 END) "10<age<20"
,sum(CASE WHEN extract(year FROM age(crdate)) >= 20 THEN 1 END) "20<age"
FROM dt
GROUP BY dept
I have table Sales in SQL Server 2012
Use tempdb
Go
CREATE TABLE Sales (EmpId INT, Yr INT, Sales MONEY)
INSERT Sales VALUES(1, 2005, 12000)
INSERT Sales VALUES(1, 2006, 18000)
INSERT Sales VALUES(1, 2007, 25000)
INSERT Sales VALUES(2, 2005, 15000)
INSERT Sales VALUES(2, 2006, 6000)
INSERT Sales VALUES(3, 2006, 20000)
INSERT Sales VALUES(3, 2007, 24000)
I want create a report with this results :
/*
EmpId------ Yr----- SUM(Sales) BY EmpId, Yr---------- SUM(Sales) BY EmpId ----------SUM(Sales)
1 2005 12000.00 12000.00 12000.00
1 2006 18000.00 30000.00 30000.00
1 2007 25000.00 55000.00 55000.00
1 NULL 55000.00 55000.00
2 2005 15000.00 15000.00 70000.00
2 2006 6000.00 21000.00 76000.00
2 NULL 21000.00 76000.00
3 2006 20000.00 20000.00 96000.00
3 2007 24000.00 44000.00 120000.00
3 NULL 44000.00 120000.00
NULL NULL 120000.00
*/
I write a query like this :
SELECT EmpId, Yr, SUM(Sales) AS Sales
FROM Sales
GROUP BY EmpId, Yr WITH ROLLUP
How can I change my query for get more columns like abauve.
In SQL Server 2012+, you can do cumulative sums using window functions. The following basically does what you want:
SELECT EmpId, Yr, SUM(Sales) AS Sales,
SUM(case when Yr is not null then SUM(Sales) end) OVER
(PARTITION BY EmpId
Order By (case when Yr is null then 0 else 1 end) desc, Yr
),
SUM(case when yr is not null then SUM(SALES) end) OVER
(Order by EmpId, (case when Yr is null then 0 else 1 end) desc, Yr)
FROM Sales
GROUP BY EmpId, Yr WITH ROLLUP
ORDER BY (case when EmpId is null then 0 else 1 end) desc, empid,
(case when Yr is null then 0 else 1 end) desc, yr;
This is tricky because the interplay between the rollup and the window functions requires care.
Here is the SQL Fiddle.
EDIT:
To fix the very last cell on the last row, you can add a case statement:
SELECT EmpId, Yr, SUM(Sales) AS Sales,
SUM(case when Yr is not null then SUM(Sales) end) OVER
(PARTITION BY EmpId
Order By (case when Yr is null then 0 else 1 end) desc, Yr
),
(case when yr is null and empid is null
then sum(case when yr is not null and empid is not null then sum(sales) end) over ()
else SUM(case when yr is not null then SUM(SALES) end) OVER
(Order by EmpId, (case when Yr is null then 0 else 1 end) desc, Yr)
end)
FROM Sales
GROUP BY EmpId, Yr WITH ROLLUP
ORDER BY (case when EmpId is null then 0 else 1 end) desc, empid,
(case when Yr is null then 0 else 1 end) desc, yr;
I have a full join sql query and i am retrieving the data from the same table.the problem is i am getting the null value where i am expecting the column name.
Example:
I am having a table where there are two columns typeOfPost,dob.
DOB TypeOfPost
--------- --------------
20/11/1998 Manager
1/1/2000 Sales
13/6/1999 Manager
20/1/1987 Manager
1/11/1985 Sales
Now when I am writing a join query like
select DATENAME(month,dob) as Red,count(TypeOfPost)
from tablename
where TypeOfPost='Manager'
group by DATENAME(month,dob) as A
full join
select DATENAME(month,dob) as Green,count(TypeOfPost)
from tablename
where TypeOfPost='Sales'
group by DATENAME(month,dob) as B on B.Green = A.Red
Output-- Expected Output--
--------------------- ---------------------
Month Man Sal Month Man Sal
-------- ----- ------ -------- ----- ------
January 1 1 January 1 1
NULL 1 NULL June 1 NULL
November 1 1 November 1 1
Now here the problem rise, I want 'June' in the column Month instead of NULL value.
So is there any way to get that??
Help me out.
Thanks.
One option is to
use a CASE statement in a subselect
Determine for given record if it is a manager or sales
substitute with 1 or 0 accordingly
SELECT and GROUP from this subselect the final results.
SQL Statement
SELECT Month
, SUM(Man) AS Man
, SUM(Sal) AS Sal
FROM (
SELECT DATENAME(MONTH, DOB) AS Month
, CASE WHEN TypeOfPost = 'Manager' THEN 1 ELSE 0 END AS Man
, CASE WHEN TypeOfPost = 'Sales' THEN 1 ELSE 0 END AS Sal
FROM tableName
) g
GROUP BY
Month
or
SELECT Month
, SUM(Man)
, SUM(Sal)
FROM (
SELECT DATENAME(MONTH, DOB) AS Month
, COUNT(TypeOfPost) AS Man
, 0 AS Sal
FROM tableName
WHERE TypeOfPost = 'Manager'
GROUP BY
DATENAME(MONTH, DOB)
UNION ALL
SELECT DATENAME(MONTH, DOB) AS Month
, 0 AS Man
, COUNT(TypeOfPost) AS Sal
FROM tableName
WHERE TypeOfPost = 'Sales'
GROUP BY
DATENAME(MONTH, DOB)
) g
GROUP BY
Month