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I'm new to numpy, and I have an interesting observation on the broadcasting. When I'm adding a 3x5 array directly to a 3x1 array, and update the original 3x1 array with the result, there is no broadcasting issue.
import numpy as np
total = np.random.uniform(-1,1, size=(3))[:,np.newaxis]
print(f'init = \n {total}')
for i in range(3):
total = total + np.ones(shape=(3,5))
print(f'total_{i} = \n {total}')
However, if i'm using '+=' operator to increment the 3x1 array with the value of 3x5 array, there is a broadcasting issue. May I know which rule of numpy broadcasting did I violate in the latter case?
total = np.random.uniform(-1,1, size=(3))[:,np.newaxis]
print(f'init = \n {total}')
for i in range(3):
total += np.ones(shape=(3,5))
print(f'total_{i} = \n {total}')
Thank you!
hawkoli1987
according to add function overridden in numpy array,
def add(x1, x2, *args, **kwargs): # real signature unknown; NOTE: unreliably restored from __doc__
"""
add(x1, x2, /, out=None, *, where=True, casting='same_kind', order='K', dtype=None, subok=True[, signature, extobj])
Add arguments element-wise.
Parameters
----------
x1, x2 : array_like
The arrays to be added.
If ``x1.shape != x2.shape``, they must be broadcastable to a common
shape (which becomes the shape of the output).
out : ndarray, None, or tuple of ndarray and None, optional
A location into which the result is stored. If provided, it must have
a shape that the inputs broadcast to. If not provided or None,
a freshly-allocated array is returned. A tuple (possible only as a
keyword argument) must have length equal to the number of outputs.
add function returns a freshly-allocated array when dimensions of arrays are different.
In python, a=a+b and a+=b aren't absolutly same. + calls __add__ function and += calls __iadd__.
a = np.array([1, 2])
b = np.array([3, 4])
first_id = id(a)
a = a + b
second_id = id(a)
assert first_id == second_id # False
a = np.array([1, 2])
b = np.array([3, 4])
first_id = id(a)
a += b
second_id = id(a)
assert first_id == second_id # True
+= function does not create new objects and updates the value to the same address.
numpy add function updates an existing instance when adding an array of the same dimensions, but returns a new object when adding arrays of different dimensions. So when use += functions, the two functions must have the same dimension because the results of the add function must be updated on the same object.
For example,
a = np.array()
total = np.random.uniform(-1,1, size=(3))[:,np.newaxis]
print(id(total))
for i in range(3):
total += np.ones(shape=(3,1))
print(id(total))
id(total) are all same because add function just updates the instance in same address because dimmension of two arrays are same.
In [29]: arr = np.zeros((1,3))
The actual error message is:
In [30]: arr += np.ones((2,3))
Traceback (most recent call last):
Input In [30] in <cell line: 1>
arr += np.ones((2,3))
ValueError: non-broadcastable output operand with shape (1,3) doesn't match the broadcast shape (2,3)
I read that as say that arr on the left is "non-broadcastable", where as arr+np.ones((2,3)) is the result of broadcasting. The wording may be awkward; it's probably produced in some deep compiled function where it makes more sense.
We get a variant on this when we try to assign an array to a slice of an array:
In [31]: temp = arr + np.ones((2,3))
In [32]: temp.shape
Out[32]: (2, 3)
In [33]: arr[:] = temp
Traceback (most recent call last):
Input In [33] in <cell line: 1>
arr[:] = temp
ValueError: could not broadcast input array from shape (2,3) into shape (1,3)
This is clearer, saying that the RHS (2,3) cannot be put into the LHS (1,3) slot.
Or trying to put the (2,3) into one "row" of arr:
In [35]: arr[0] = temp
Traceback (most recent call last):
Input In [35] in <cell line: 1>
arr[0] = temp
ValueError: could not broadcast input array from shape (2,3) into shape (3,)
arr[0] = arr works because it tries to put a (1,3) into a (3,) shape - that's a workable broadcasting combination.
arr[0] = arr.T tries to put a (3,1) into a (3,), and fails.
I have some discrete data in an array, such that:
arr = np.array([[1,1,1],[2,2,2],[3,3,3],[2,2,2],[1,1,1]])
whose plot looks like:
I also have an index array, such that each unique value in arr is associated with a unique index value, like:
ind = np.array([[1,1,1],[2,2,2],[3,3,3],[4,4,4],[5,5,5]])
What is the most pythonic way of converting arr from discrete values to continuous values, so that the array would look like this when plotted?:
therefore, interpolating between the discrete points to make continuous data
I found a solution to this if anyone has a similar issue. It is maybe not the most elegant so modifications are welcome:
def ref_linear_interp(x, y):
arr = []
ux=np.unique(x) #unique x values
for u in ux:
idx = y[x==u]
try:
min = y[x==u-1][0]
max = y[x==u][0]
except:
min = y[x==u][0]
max = y[x==u][0]
try:
min = y[x==u][0]
max = y[x==u+1][0]
except:
min = y[x==u][0]
max = y[x==u][0]
if min==max:
sub = np.full((len(idx)), min)
arr.append(sub)
else:
sub = np.linspace(min, max, len(idx))
arr.append(sub)
return np.concatenate(arr, axis=None).ravel()
y = np.array([[1,1,1],[2,2,2],[3,3,3],[2,2,2],[1,1,1]])
x = np.array([[1,1,1],[2,2,2],[3,3,3],[4,4,4],[5,5,5]])
z = np.arange(1, 16, 1)
Here is an answer for the symmetric solution that I would expect when reading the question:
import matplotlib.pyplot as plt
import pandas as pd
import numpy as np
# create the data as described
numbers = [1,2,3,2,1]
nblock = 3
df = pd.DataFrame({
"x": np.arange(nblock*len(numbers)),
"y": np.repeat(numbers, nblock),
"label": np.repeat(np.arange(len(numbers)), nblock)
})
Expecting a constant block size of 3, we could use a rolling window:
df['y-smooth'] = df['y'].rolling(nblock, center=True).mean()
# fill NaNs
df['y-smooth'].bfill(inplace=True)
df['y-smooth'].ffill(inplace=True)
plt.plot(df['x'], df['y-smooth'], marker='*')
If the block size is allowed to vary, we could determine the block centers and interpolate piecewise.
centers = df[['x', 'y', 'label']].groupby('label').mean()
df['y-interp'] = np.interp(df['x'], centers['x'], centers['y'])
plt.plot(df['x'], df['y-interp'], marker='*')
Note: You may also try
centers = df[['x', 'y', 'label']].groupby('label').min() to select the left corner of the labelled blocks.
How to get data by querying radius from ball tree? For example
from sklearn.neighbors import BallTree
import pandas as pd
bt = BallTree(df[['lat','lng']], metric="haversine")
for idx, row in df.iterrow():
res = df[bt.query_radius(row[['lat','lng']],r=1)]
I want to get those rows in df that are in radius r=1. But it throws type error
TypeError: unhashable type: 'numpy.ndarray'
Following the first answer I got index out of range when iterating over the rows
5183
(5219, 25)
5205
(5219, 25)
5205
(5219, 25)
5221
(5219, 25)
Traceback (most recent call last):
File "/Users/Chu/Documents/dssg2018/sa4.py", line 45, in <module>
df.loc[idx,word]=len(df.iloc[indices[idx]][df[word]==1])/\
IndexError: index 5221 is out of bounds for axis 0 with size 5219
And the code is
bag_of_words = ['beautiful','love','fun','sunrise','sunset','waterfall','relax']
for idx,row in df.iterrows():
for word in bag_of_words:
if word in row['caption']:
df.loc[idx, word] = 1
else:
df.loc[idx, word] = 0
bt = BallTree(df[['lat','lng']], metric="haversine")
indices = bt.query_radius(df[['lat','lng']],r=(float(10)/40000)*360)
for idx,row in df.iterrows():
for word in bag_of_words:
if word in row['caption']:
print(idx)
print(df.shape)
df.loc[idx,word]=len(df.iloc[indices[idx]][df[word]==1])/\
np.max([1,len(df.iloc[indices[idx]][df[word]!=1])])
The error is not in the BallTree, but the indices returned by it are not used properly for putting it into index.
Do it this way:
for idx, row in df.iterrows():
indices = bt.query_radius(row[['lat','lng']].values.reshape(1,-1), r=1)
res = df.iloc[[x for b in indices for x in b]]
# Do what you want to do with res
This will also do (since we are sending only a single point each time):
res = df.iloc[indices[0]]
Explanation:
I'm using scikit 0.20. So the code you wrote above:
df[bt.query_radius(row[['lat','lng']],r=1)]
did not work for me. I needed to make it a 2-d array by using reshape().
Now bt.query_radius() returns array of array of indices within the radius r specified as mentioned in the documentation:
ind : array of objects, shape = X.shape[:-1]
each element is a numpy integer array listing the indices of neighbors of the corresponding point. Note that unlike the results of
a k-neighbors query, the returned neighbors are not sorted by distance
by default.
So we needed to iterate two arrays to reach the actual indices of the data.
Now once we got the indices, in a pandas Dataframe, iloc is the way to access data with indices.
Update:
You dont need to query the bt each time for individual points. You can send all the df at once to return a 2-d array containing the indices of points within the radius to the point specified that index.
indices = bt.query_radius(df, r=1)
for idx, row in df.iterrows():
nearest_points_index = indices[idx]
res = df.iloc[nearest_points_index]
# Do what you want to do with res
I am drawing a histogram of a column from pandas data frame:
%matplotlib notebook
import matplotlib.pyplot as plt
import matplotlib
df.hist(column='column_A', bins = 100)
but got the following errors:
62 raise ValueError(
63 "num must be 1 <= num <= {maxn}, not {num}".format(
---> 64 maxn=rows*cols, num=num))
65 self._subplotspec = GridSpec(rows, cols)[int(num) - 1]
66 # num - 1 for converting from MATLAB to python indexing
ValueError: num must be 1 <= num <= 0, not 1
Does anyone know what this error mean? Thanks!
Problem
The problem you encounter arises when column_A does not contain numeric data. As you can see in the excerpt from pandas.plotting._core below, the numeric data is essential to make the function hist_frame (which you call by DataFrame.hist()) work correctly.
def hist_frame(data, column=None, by=None, grid=True, xlabelsize=None,
xrot=None, ylabelsize=None, yrot=None, ax=None, sharex=False,
sharey=False, figsize=None, layout=None, bins=10, **kwds):
# skipping part of the code
# ...
if column is not None:
if not isinstance(column, (list, np.ndarray, Index)):
column = [column]
data = data[column]
data = data._get_numeric_data() # there is no numeric data in the column
naxes = len(data.columns) # so the number of axes becomes 0
# naxes is passed to the subplot generating function as 0 and later determines the number of columns as 0
fig, axes = _subplots(naxes=naxes, ax=ax, squeeze=False,
sharex=sharex, sharey=sharey, figsize=figsize,
layout=layout)
# skipping the rest of the code
# ...
Solution
If your problem is to represent numeric data (but not of numeric dtype yet) with a histogram, you need to cast your data to numeric, either with pd.to_numeric or df.astype(a_selected_numeric_dtype), e.g. 'float64', and then proceed with your code.
If your problem is to represent non-numeric data in one column with a histogram, you can call the function hist_series with the following line: df['column_A'].hist(bins=100).
If your problem is to represent non-numeric data in many columns with a histogram, you may resort to a handful options:
Use matplotlib and create subplots and histograms directly
Update pandas at least to version 0.25
usually is 0
mta['penn'] = [mta_bystation[mta_bystation.STATION == "34 ST-PENN STA"], 'Penn Station']
mta['grdcntrl'] = [mta_bystation[mta_bystation.STATION == "GRD CNTRL-42 ST"], 'Grand Central']
mta['heraldsq'] = [mta_bystation[mta_bystation.STATION == "34 ST-HERALD SQ"], 'Herald Sq']
mta['23rd'] = [mta_bystation[mta_bystation.STATION == "23 ST"], '23rd St']
#mta['portauth'] = [mta_bystation[mta_bystation.STATION == "42 ST-PORT AUTH"], 'Port Auth']
#mta['unionsq'] = [mta_bystation[mta_bystation.STATION == "14 ST-UNION SQ"], 'Union Sq']
mta['timessq'] = [mta_bystation[mta_bystation.STATION == "TIMES SQ-42 ST"], 'Ti
Strange error from numpy via matplotlib when trying to get a histogram of a tiny toy dataset. I'm just not sure how to interpret the error, which makes it hard to see what to do next.
Didn't find much related, though this nltk question and this gdsCAD question are superficially similar.
I intend the debugging info at bottom to be more helpful than the driver code, but if I've missed something, please ask. This is reproducible as part of an existing test suite.
if n > 1:
return diff(a[slice1]-a[slice2], n-1, axis=axis)
else:
> return a[slice1]-a[slice2]
E TypeError: ufunc 'subtract' did not contain a loop with signature matching types dtype('<U1') dtype('<U1') dtype('<U1')
../py2.7.11-venv/lib/python2.7/site-packages/numpy/lib/function_base.py:1567: TypeError
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> entering PDB >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
> py2.7.11-venv/lib/python2.7/site-packages/numpy/lib/function_base.py(1567)diff()
-> return a[slice1]-a[slice2]
(Pdb) bt
[...]
py2.7.11-venv/lib/python2.7/site-packages/matplotlib/axes/_axes.py(5678)hist()
-> m, bins = np.histogram(x[i], bins, weights=w[i], **hist_kwargs)
py2.7.11-venv/lib/python2.7/site-packages/numpy/lib/function_base.py(606)histogram()
-> if (np.diff(bins) < 0).any():
> py2.7.11-venv/lib/python2.7/site-packages/numpy/lib/function_base.py(1567)diff()
-> return a[slice1]-a[slice2]
(Pdb) p numpy.__version__
'1.11.0'
(Pdb) p matplotlib.__version__
'1.4.3'
(Pdb) a
a = [u'A' u'B' u'C' u'D' u'E']
n = 1
axis = -1
(Pdb) p slice1
(slice(1, None, None),)
(Pdb) p slice2
(slice(None, -1, None),)
(Pdb)
I got the same error, but in my case I am subtracting dict.key from dict.value. I have fixed this by subtracting dict.value for corresponding key from other dict.value.
cosine_sim = cosine_similarity(e_b-e_a, w-e_c)
here I got error because e_b, e_a and e_c are embedding vector for word a,b,c respectively. I didn't know that 'w' is string, when I sought out w is string then I fix this by following line:
cosine_sim = cosine_similarity(e_b-e_a, word_to_vec_map[w]-e_c)
Instead of subtracting dict.key, now I have subtracted corresponding value for key
I had a similar issue where an integer in a row of a DataFrame I was iterating over was of type numpy.int64. I got the
TypeError: ufunc 'subtract' did not contain a loop with signature matching types dtype('<U1') dtype('<U1') dtype('<U1')
error when trying to subtract a float from it.
The easiest fix for me was to convert the row using pd.to_numeric(row).
Why is it applying diff to an array of strings.
I get an error at the same point, though with a different message
In [23]: a=np.array([u'A' u'B' u'C' u'D' u'E'])
In [24]: np.diff(a)
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-24-9d5a62fc3ff0> in <module>()
----> 1 np.diff(a)
C:\Users\paul\AppData\Local\Enthought\Canopy\User\lib\site-packages\numpy\lib\function_base.pyc in diff(a, n, axis)
1112 return diff(a[slice1]-a[slice2], n-1, axis=axis)
1113 else:
-> 1114 return a[slice1]-a[slice2]
1115
1116
TypeError: unsupported operand type(s) for -: 'numpy.ndarray' and 'numpy.ndarray'
Is this a array the bins parameter? What does the docs say bins should be?
I am fairly new to this myself, but I had a similar error and found that it is due to a type casting issue. I was trying to concatenate rather than take the difference but I think the principle is the same here. I provided a similar answer on another question so I hope that is OK.
In essence you need to use a different data type cast, in my case I needed str not float, I suspect yours is the same so my suggested solution is. I am sorry I cannot test it before suggesting but I am unclear from your example what you were doing.
return diff(str(a[slice1])-str(a[slice2]), n-1, axis=axis)
Please see my example code below for the fix to my code, the change occurs on the third to last line. The code is to produce a basic random forest model.
import scipy
import math
import numpy as np
import pandas as pd
from sklearn.ensemble import RandomForestRegressor
from sklearn import preprocessing, metrics, cross_validation
Data = pd.read_csv("Free_Energy_exp.csv", sep=",")
Data = Data.fillna(Data.mean()) # replace the NA values with the mean of the descriptor
header = Data.columns.values # Ues the column headers as the descriptor labels
Data.head()
test_name = "Test.csv"
npArray = np.array(Data)
print header.shape
npheader = np.array(header[1:-1])
print("Array shape X = %d, Y = %d " % (npArray.shape))
datax, datay = npArray.shape
names = npArray[:,0]
X = npArray[:,1:-1].astype(float)
y = npArray[:,-1] .astype(float)
X = preprocessing.scale(X)
XTrain, XTest, yTrain, yTest = cross_validation.train_test_split(X,y, random_state=0)
# Predictions results initialised
RFpredictions = []
RF = RandomForestRegressor(n_estimators = 10, max_features = 5, max_depth = 5, random_state=0)
RF.fit(XTrain, yTrain) # Train the model
print("Training R2 = %5.2f" % RF.score(XTrain,yTrain))
RFpreds = RF.predict(XTest)
with open(test_name,'a') as fpred :
lenpredictions = len(RFpreds)
lentrue = yTest.shape[0]
if lenpredictions == lentrue :
fpred.write("Names/Label,, Prediction Random Forest,, True Value,\n")
for i in range(0,lenpredictions) :
fpred.write(RFpreds[i]+",,"+yTest[i]+",\n")
else :
print "ERROR - names, prediction and true value array size mismatch."
This leads to an error of;
Traceback (most recent call last):
File "min_example.py", line 40, in <module>
fpred.write(RFpreds[i]+",,"+yTest[i]+",\n")
TypeError: ufunc 'add' did not contain a loop with signature matching types dtype('S32') dtype('S32') dtype('S32')
The solution is to make each variable a str() type on the third to last line then write to file. No other changes to then code have been made from the above.
import scipy
import math
import numpy as np
import pandas as pd
from sklearn.ensemble import RandomForestRegressor
from sklearn import preprocessing, metrics, cross_validation
Data = pd.read_csv("Free_Energy_exp.csv", sep=",")
Data = Data.fillna(Data.mean()) # replace the NA values with the mean of the descriptor
header = Data.columns.values # Ues the column headers as the descriptor labels
Data.head()
test_name = "Test.csv"
npArray = np.array(Data)
print header.shape
npheader = np.array(header[1:-1])
print("Array shape X = %d, Y = %d " % (npArray.shape))
datax, datay = npArray.shape
names = npArray[:,0]
X = npArray[:,1:-1].astype(float)
y = npArray[:,-1] .astype(float)
X = preprocessing.scale(X)
XTrain, XTest, yTrain, yTest = cross_validation.train_test_split(X,y, random_state=0)
# Predictions results initialised
RFpredictions = []
RF = RandomForestRegressor(n_estimators = 10, max_features = 5, max_depth = 5, random_state=0)
RF.fit(XTrain, yTrain) # Train the model
print("Training R2 = %5.2f" % RF.score(XTrain,yTrain))
RFpreds = RF.predict(XTest)
with open(test_name,'a') as fpred :
lenpredictions = len(RFpreds)
lentrue = yTest.shape[0]
if lenpredictions == lentrue :
fpred.write("Names/Label,, Prediction Random Forest,, True Value,\n")
for i in range(0,lenpredictions) :
fpred.write(str(RFpreds[i])+",,"+str(yTest[i])+",\n")
else :
print "ERROR - names, prediction and true value array size mismatch."
These examples are from a larger code so I hope the examples are clear enough.
I think #James is right. I got stuck by same error while working on Polyval(). And yeah solution is to use the same type of variabes. You can use typecast to cast all variables in the same type.
BELOW IS A EXAMPLE CODE
import numpy
P = numpy.array(input().split(), float)
x = float(input())
print(numpy.polyval(P,x))
here I used float as an output type. so even the user inputs the INT value (whole number). the final answer will be typecasted to float.
I ran into the same issue, but in my case it was just a Python list instead of a Numpy array used. Using two Numpy arrays solved the issue for me.