How can i merge the values without including '0' values.
SELECT DATE_PART('YEAR', BIRTHDATE), SUM(CASE WHEN GENDER = 'M' THEN 1 ELSE 0 END) MAN,
SUM(CASE WHEN GENDER = 'F' THEN 1 ELSE 0 END) as FEMALE FROM TABLE
GROUP BY 1
My output
YEAR MAN FEMALE
1970 2 0
1970 0 5
1971 3 0
1971 0 2
Desired output
YEAR MAN FEMALE
1970 2 5
1971 3 2
I have tried it with another counting from MAN and FEMALE, but that doesnt work.
Your query should work, although I would recommend writing it as:
SELECT DATE_PART('YEAR', BIRTHDATE) as year,
COUNT(*) FILTER (WHERE GENDER = 'M') as MAN,
COUNT(*) FILTER (WHERE GENDER = 'F') as FEMALE
FROM TABLE
GROUP BY year;
Your results suggest that you are really using something like:
GROUP BY 1, gender
simply you need to correct your Group By syntaxe,
Group By DATE_PART('YEAR', BIRTHDATE)
Related
I'm trying to create a query which allows to categorize the average percentage for specific data per month.
Here's how my dataset presents itself:
Date
Name
Group
Percent
2022-01-21
name1
gr1
5.2
2022-01-22
name1
gr1
6.1
2022-01-26
name1
gr1
4.9
2022-02-01
name1
gr1
3.2
2022-02-03
name1
gr1
8.1
2022-01-22
name2
gr1
36.1
2022-01-25
name2
gr1
32.1
2022-02-10
name2
gr1
35.8
...
...
...
...
And here's what I want to obtain with my query (based on what I showed of the table):
Month
<=25%
25<_<=50%
50<_<=75%
75<_<=100%
01
1
1
0
0
02
1
1
0
0
...
...
...
...
...
The result needs to:
Be ordered by month
Have the average use for each name counted and categorized
So far I know how to get the average of the Percent value per Name:
SELECT Name,
AVG(Percent)
from `table`
where Group = 'gr1'
group by Name
and how to count iterations of Percent in the categories created for the query:
SELECT EXTRACT(MONTH FROM Date) as Month,
COUNT(CASE WHEN Percent <= 25 AND Group = 'gr1' THEN Name END) `_25`,
COUNT(CASE WHEN Percent > 25 AND Percent <= 50 AND Group = 'gr1' THEN Name END) `_50`,
COUNT(CASE WHEN Percent > 50 AND Percent <= 75 AND Group = 'gr1' THEN Name END) `_75`,
COUNT(CASE WHEN Percent > 75 AND Percent <= 100 AND Group = 'gr1' THEN Name END) `_100`,
FROM `table`
GROUP BY Month
ORDER BY Month
but this counts all iterations of every name where I want the average of those values.
I've been struggling to figure out how to combine the two queries or to create a new one that answers my need.
I'm working with the BigQuery service from Google Cloud
This query produces the needed result, based on your example. So basically this combines your 2 queries using subquery, where the subquery is responsible to calculate AVG grouped by Name, Month and Group, and the outer query is for COUNT and "categorization"
SELECT
Month,
COUNT(CASE
WHEN avg <= 25 THEN Name
END) AS _25,
COUNT(CASE
WHEN avg > 25
AND avg <= 50 THEN Name
END) AS _50,
COUNT(CASE
WHEN avg > 50
AND avg <= 75 THEN Name
END) AS _75,
COUNT(CASE
WHEN avg > 75
AND avg <= 100 THEN Name
END) AS _100
FROM
(
SELECT
EXTRACT(MONTH from Date) AS Month,
Name,
AVG(Percent) AS avg
FROM
table1
GROUP BY Month, Name, Group
HAVING Group = 'gr1'
) AS namegr
GROUP BY Month
This is the result:
Month
_25
_50
_75
_100
1
1
1
0
0
2
1
1
0
0
See also Fiddle (BUT on MySql) - http://sqlfiddle.com/#!9/16c5882/9
You can use this query to Group By Month and each Name
SELECT CONCAT(EXTRACT(MONTH FROM Date), ', ', Name) AS DateAndName,
CASE
WHEN AVG(Percent) <= 25 THEN '1'
ELSE '0'
END AS '<=25%',
CASE
WHEN AVG(Percent) > 25 AND AVG(Percent) <= 50 THEN '1'
ELSE '0'
END AS '25<_<=50%',
CASE
WHEN AVG(Percent) > 50 AND AVG(Percent) <= 75 THEN '1'
ELSE '0'
END AS '50<_<=75%',
CASE
WHEN AVG(Percent) > 75 AND AVG(Percent) <= 100 THEN '1'
ELSE '0'
END AS '75<_<=100%'
from DataTable /*change to your table name*/
group by EXTRACT(MONTH FROM Date), Name
order by DateAndName
It gives the following result:
DateAndName
<=25%
25<_<=50%
50<_<=75%
75<_<=100%
1, name1
1
0
0
0
1, name2
0
1
0
0
2, name1
1
0
0
0
2, name2
0
1
0
0
Someone knows how i can group ages witch the CASE statement?
I got the ages 14,15,16,17,18,19,20,21,22,23,24,25. I want groups like <18,19,20,>21
I started like:
Case age when BETWEEN 14 AND 18 THEN sum(age)
when >=21 THEN sum(age)
ELSE age END as age_groups
But i think aggregate functions don't work in CASE statements, at least it brings up an error.
CASE statement would work, you have a syntax error, your query would be:
SELECT Case when age BETWEEN 14 AND 18 THEN '14 - 18'
when age >=21 THEN '>=21'
ELSE age END as age_groups, SUM(age)
FROM YOUR_TABLE
GROUP BY Case when age BETWEEN 14 AND 18 THEN '14 - 18'
when age >=21 THEN '>=21'
ELSE age END
Use a CTE to calculate the age_groups, and then you can normally sum the ages for each group.
WITH age_groups AS (
SELECT Age,
Case when age BETWEEN 14 AND 18 THEN '14 - 18'
when age >=21 THEN '>=21'
ELSE age END as age_group
FROM YOUR_TABLE
)
SELECT age_group, sum(Age)
FROM age_groups
GROUP BY age_group
Another neat alternative is to place the CASE inside a CROSS APPLY (VALUES so you can then refer to it in other parts of the query without repetition:
SELECT
v.age_group,
SUM(Age)
FROM age_groups ag
CROSS APPLY (VALUES (
CASE WHEN ag.age BETWEEN 14 AND 18 THEN '14 - 18'
WHEN ag.age >= 21 THEN '>=21'
ELSE CAST(ag.age AS varchar(10)) END
) ) v(age_group)
GROUP BY v.age_group
You can use Case inside Sum():
select
Sum(Case when age < 18 then 1 end) '<18',
Sum(Case when age = 19 then 1 end) '19',
Sum(Case when age = 20 then 1 end) '20',
Sum(Case when age > 20 then 1 end) '>20'
from myTable;
DBFiddle demo is here
EDIT: If you meant to get the results vertically, still keep it simple:
select '<18' as ageGroup, Sum(Case when age < 18 then 1 end) total from myTable
union
select '19', Sum(Case when age = 19 then 1 end) from myTable
union
select '20', Sum(Case when age = 20 then 1 end) from myTable
union
select '20>', Sum(Case when age > 20 then 1 end) from myTable;
I am trying to calculate the average number of times apple with an increment of 3 are shown per day in the years of both 2018 and 2017. To do this I am trying to use setNum and exNum that has a difference of 3.
ID Year Text setNum ExNum
-------------------------------------------------
1 2018-01-21 apple 1 3
2 2017-08-03 apple 2 5
3 2018-03-02 banana 1 3
4 2018-05-22 apple 1 3
5 2018-12-12 apple 3 6
6 2017-04-13 apple 3 6
My current query to obtain this is:
SELECT
2017 = avg(case when Year BETWEEN '2017-01-01' AND '2017-12-31' then 1 else 0 end),
2018 = avg(case when Year BETWEEN '2018-01-01' AND '2018-12-31' then 1 else 0 end)
FROM
exampleTable
WHERE
Text LIKE '%apple%'
This currently outputs:
2017 2018
0 0
Note: The original table had a single text column Increment, which had values like 1-3. That is, the 1-3 represented a setNum of 1 and an ExNum of 3.
Your decision to store a numerical increment range as text is not a good one, and ideally you should be storing the two points of the increment in separate columns. That being said, we can do some string olympics to work around this:
SELECT
YEAR(Year) AS Year,
COUNT(CASE WHEN 3 BETWEEN CAST(LEFT(Increment, CHARINDEX('-', Increment)-1) AS int) AND
CAST(RIGHT(Increment, LEN(Increment) - CHARINDEX('-', Increment)) AS int)
THEN 1 END) AS apple_3_cnt
FROM exampleTable
WHERE
TEXT LIKE '%apple%'
GROUP BY
YEAR(year);
Demo
Here I am aggregating by year, and then taking a conditional count of record, for each year, where the apple increment range contains 3. To do this, I separate out the two ends of the increment range, and then convert them to integers.
Edit:
Based on your updated table, we can try a simpler query:
SELECT
YEAR(Year) AS Year,
COUNT(CASE WHEN 3 BETWEEN setNum AND ExNum THEN 1 END) AS apple_3_cnt
FROM exampleTable
WHERE
TEXT LIKE '%apple%'
GROUP BY
YEAR(year);
Try below
SELECT
avg(case when Year BETWEEN '2017-01-01' AND '2017-12-31' then setNum+ExNum end) as 2017
avg(case when Year BETWEEN '2018-01-01' AND '2018-12-31' then setNum+ExNum end) as 2018
FROM
exampleTable
WHERE
Text LIKE '%apple%'
Your query is fine. The only problem is how and to where you assign the results.
Use this syntax instead
SELECT
avg(case when Year BETWEEN '2017-01-01' AND '2017-12-31' then 1 else 0 end) as A2017,
avg(case when Year BETWEEN '2018-01-01' AND '2018-12-31' then 1 else 0 end) as A2018
FROM
exampleTable
WHERE
Text LIKE '%apple%'
Note that you can't use numbers as variable names.
I want to get statistics with sql query. My table is like this:
ID MATERIAL CREATEDATE DEPARTMENT
1 M1 10.10.1980 D1
2 M2 11.02.1970 D2
2 M3 18.04.1971 D3
.....................
.....................
.....................
How can I get a range of data count like this
DEPARTMENT AGE<10 10<AGE<20 20<AGE
D1 24 123 324
D2 24 123 324
Assuming that CREATEDATE is a date column, in PostgreSQL you can use the AGE function:
select DEPARTMENT, age(CREATEDATE) as AGE
from Materials
and with date_part you can get the age in years. To show the data in the format that you want, you could use this GROUP BY query:
select
DEPARTMENT,
sum(case when date_part('year', age(CREATEDATE))<10 then 1 end) as "age<10",
sum(case when date_part('year', age(CREATEDATE))>=10 and date_part('year', age(CREATEDATE))<20 then 1 end) as "10<age<20",
sum(case when date_part('year', age(CREATEDATE))>=20 then 1 end) as "20<age"
from
Materials
group by
DEPARTMENT
which can be simplified as:
with mat_age as (
select DEPARTMENT, date_part('year', age(CREATEDATE)) as mage
from Materials
)
select
DEPARTMENT,
sum(case when mage<10 then 1 end) as "age<10",
sum(case when mage>=10 and mage<20 then 1 end) as "10<age<20",
sum(case when mage>=20 then 1 end) as "20<age"
from
mat_age
group by
DEPARTMENT;
if you are using PostgreSQL 9.4 you can use FILTER:
with mat_age as (
select DEPARTMENT, date_part('year', age(CREATEDATE)) as mage
from Materials
)
select
DEPARTMENT,
count(*) filter (where mage<10) as "age<10",
count(*) filter (where mage>=10 and mage<20) as "10<age<20",
count(*) filter (where mage>=20) as "20<age"
from
mat_age
group by
DEPARTMENT;
The following solution assumes that your CREATEDATE column exists as some sort of valid Postgres date type. If this be not the case, and it is being stored as text, you will first have to convert it to date in order for the query to work.
SELECT DEPARTMENT,
SUM(CASE WHEN DATEDIFF(year, CREATEDATE, now()::date) < 10 THEN 1 ELSE 0 END) AS "AGE<10",
SUM(CASE WHEN DATEDIFF(year, CREATEDATE, now()::date) >= 10 AND
DATEDIFF(year, CREATEDATE, now()::date) < 20 THEN 1 ELSE 0 END) AS "10<AGE<20",
SUM(CASE WHEN DATEDIFF(year, CREATEDATE, now()::date) >= 20 THEN 1 ELSE 0 END) AS "20<AGE"
FROM Materials
GROUP BY DEPARTMENT
You can use extract(year FROM age(createdate)) to get the exact age
i.e
select extract(year FROM age(timestamp '01-01-1989')) age
will give you
Result:
age
---
27
so you can use following select statement to get your desired output:
SELECT dept
,sum(CASE WHEN age < 10THEN 1 END) "age<10"
,sum(CASE WHEN age >= 10 AND age < 20 THEN 1 END) "10<age<20"
,sum(CASE WHEN age >= 20 THEN 1 END) "20<age"
FROM (
SELECT dept,extract(year FROM age(crdate)) age
FROM dt
) t
GROUP BY dept
If you don't want to use a sub select use this.
SELECT dept
,sum(CASE WHEN extract(year FROM age(crdate)) < 10THEN 1 END) "age<10"
,sum(CASE WHEN extract(year FROM age(crdate)) >= 10 AND extract(year FROM age(crdate)) < 20 THEN 1 END) "10<age<20"
,sum(CASE WHEN extract(year FROM age(crdate)) >= 20 THEN 1 END) "20<age"
FROM dt
GROUP BY dept
I have a passenger_information table where the columns are like booking_id, gender_id, passenger_name and passenger_age. I need to select the number of adults seats both male and female booked and also the child seats both male and female.
The gender_id table defines 24 as male and 25 as female. To differentiate between child and adults seats we use passenger_age where the age for the child should not exceed 11 years.
I am trying to write a query to get the details based on booking_id but failing miserably.
Can some one help me out with this?
Somnething like this:
select
booking_id
, sum(case when gender_id = 24 and passenger_age > 11 then 1 else 0 end) adult_male
, sum(case when gender_id = 25 and passenger_age > 11 then 1 else 0 end) adult_female
, sum(case when gender_id = 24 and passenger_age <= 11 then 1 else 0 end) child_male
, sum(case when gender_id = 24 and passenger_age <= 11 then 1 else 0 end) child_female
from passenger_information
group by booking_id
Try using Group by AND UNION.
Select
booking_id,
CASE gender_id WHEN 24 then 'Adult - Male'
ELSE 'Adult - Female' END as 'Gender',
count(booking_id)
FROM passenger_information
WHERE passenger_age>11
Group by booking_id,gender_id
UNION
Select
booking_id,
CASE gender_id WHEN 24 then 'Child - Male'
ELSE 'Child - Female' END as 'Gender',
count(booking_id)
FROM passenger_information
WHERE passenger_age<=11
Group by booking_id,gender_id