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select * from TimeSheet
WeekID StudentID Hours
1 1 40
2 1 40
4 1 40
1 2 40
2 2 40
3 2 4
4 2 40
1 4 40
3 3 40
select * from Week
WeekID
1
2
3
4
select * from Student
StudentID StudentName
1 ABC
2 XYZ
3 ASD
4 QWE
After the join I have these results.
If have this data using three tables
select TS.WeekID
, TS.StudentID
, TS.[Hours]
, SS.StudentID
, WW.WeekID
FROM TimeSheet TS
left JOIN Student SS ON SS.StudentID = TS.StudentID
left JOIN [Week] WW ON WW.WeekID = TS.WeekID
WeekID StudentID Hours StudentID WeekID
1 1 40 1 1
2 1 40 1 2
4 1 40 1 4
1 2 40 2 1
2 2 40 2 2
3 2 4 2 3
4 2 40 2 4
3 3 40 3 3
1 4 40 4 1
Expectation Result is ...
WeekID StudentID Hours StudentID WeekID
3 1 40 1 2
1 3 40 3 3
2 3 40 3 3
4 3 40 3 3
2 4 40 4 1
3 4 40 4 1
4 4 40 4 1
I want to get for example:
student 1 and week 3 is missing
student 2 no week is missing
and student 3 1,2 and 4 week is missing
and student 4 2,3,4 week is missing.
Please help me out.
If you cross join your Week and Student tables to get all combinations, and then use not exists to determine where no TimeSheet record exists.
select W.WeekID, S.StudentID
from [Week] W
cross join Student S
where not exists (select 1 from TimeSheet T where T.StudentID = S.StudentID and T.WeekID = W.WeekID);
Related
I have two tables; one contains encounter dates and the other order dates. They look like this:
id enc_id enc_dt
1 5 06/11/20
1 6 07/21/21
1 7 09/15/21
2 2 04/21/20
2 5 05/05/20
id enc_id ord_dt
1 1 03/7/20
1 2 04/14/20
1 3 05/15/20
1 4 05/30/20
1 5 06/12/20
1 6 07/21/21
1 7 09/16/21
1 8 10/20/21
1 9 10/31/21
2 1 04/15/20
2 2 04/21/20
2 3 04/30/20
2 4 05/02/20
2 5 05/05/20
2 6 05/10/20
The order and encounter date can be the same, or differ slightly for the same encounter ID. I'm trying to get a table that contains all order dates before each encounter date. So the data would like this:
id enc_id enc_dt enc_key
1 1 03/7/20 5
1 2 04/14/20 5
1 3 05/15/20 5
1 4 05/30/20 5
1 5 06/11/20 5
1 1 03/7/20 6
1 2 04/14/20 6
1 3 05/15/20 6
1 4 05/30/20 6
1 5 06/12/20 6
1 6 07/21/21 6
1 1 03/7/20 7
1 2 04/14/20 7
1 3 05/15/20 7
1 4 05/30/20 7
1 5 06/12/20 7
1 6 07/21/21 7
1 7 09/15/21 7
2 1 04/15/20 2
2 2 04/21/20 2
2 1 04/15/20 5
2 2 04/21/20 5
2 3 04/30/20 5
2 4 05/02/20 5
2 5 05/05/20 5
Is there a way to do this? I am having trouble figuring out how to append the orders and encounter table for each encounter based on orders that occur before a certain date.
You may join the two tables as the following:
SELECT O.id, O.enc_id, O.ord_dt, E.enc_id
FROM
order_tbl O
JOIN encounter_tbl E
ON O.ord_dt <= E.enc_dt AND
O.id = E.id
See a demo from db<>fiddle.
This is the query:
SELECT WorkTypeId, WorktypeWorkID, LevelID
FROM Worktypes as w
LEFT JOIN WorktypesWorks as ww on w.ID = ww.WorktypeID
LEFT JOIN WorktypesWorksLevels as wwl on ww.ID = wwl.WorktypeWorkID
This is the result:
WorkTypeId WorktypeWorkID LevelID
1 1 1
1 1 2
1 1 3
1 2 1
1 2 2
1 2 3
1 3 1
1 4 1
1 4 2
1 5 1
NULL NULL NULL
3 19 2
4 6 1
4 7 1
4 7 2
4 7 3
4 17 1
4 17 2
4 18 1
4 18 2
NULL NULL NULL
I'd like to order the block of rows of each WorktypeWorkID, placing at the top the blocks which have the lower LevelID within the block.
Here's the result that I'd like to get:
WorkTypeId WorktypeWorkID LevelID
NULL NULL NULL
NULL NULL NULL
1 3 1 // blocks which have MinLevel 1
1 5 1
4 6 1
1 4 1 // blocks which have MinLevel 2
1 4 2
3 19 2
4 17 1
4 17 2
4 18 1
4 18 2
1 1 1 // blocks which have MinLevel 3
1 1 2
1 1 3
1 2 1
1 2 2
1 2 3
4 7 1
4 7 2
4 7 3
I think this is what you are looking for:
SELECT WorkTypeId, WorktypeWorkID, LevelID, MAX(LevelID) OVER (PARTITION BY WorktypeWorkID) as maxLevelID
FROM Worktypes as w
LEFT JOIN WorktypesWorks as ww on w.ID = ww.WorktypeID
LEFT JOIN WorktypesWorksLevels as wwl on ww.ID = wwl.WorktypeWorkID
ORDER BY maxLevelID
I have the following REPORT table
m = month,
pid = product_id,
bid = branch_id,
s = sales
m pid bid s
--------------------------
1 1 1 20
1 3 1 11
1 2 1 14
1 4 1 16
1 5 1 31
1 1 2 30
1 3 2 10
1 2 2 24
1 4 2 17
1 5 2 41
2 3 1 43
2 5 1 21
2 4 1 10
2 1 1 5
2 2 1 12
2 3 2 22
2 5 2 10
2 4 2 5
2 1 2 4
2 2 2 10
3 3 1 21
3 5 1 10
3 4 1 44
3 1 1 4
3 2 1 14
3 3 2 10
3 5 2 5
3 4 2 6
3 1 2 7
3 2 2 10
I'd like to have a summary of this sales table
by showing the top 3 sales among the products across all branches.
something like this:
m pid total
---------------------
1 5 72
1 1 50
1 4 33
2 3 65
2 5 31
2 2 22
3 4 50
3 3 31
3 2 24
so on month 1, product #5 has the highest total sales with 72, followed by product #1 is 50.. and so on. if i could separate them into different table for each month would be better
so far what i can do is make a summary for 1 month and shows the entire thing and not top 3.
select pid, sum(s)
from report
where m = 1
group by pid
order by sum(s);
thanks a lot!
Most databases support the ANSI standard window functions. You can do what you want with row_number():
select m, pid, s
from (select r.m, r.pid, sum(s) as s,
row_number() over (partition by m order by sum(s) desc) as seqnum
from report r
group by r.m, r.pid
) r
where seqnum <= 3
order by m, s desc;
I want to know which seat was the most sold by individual halls?
TICKETS
IDTICKET MOVIE_IDMOVIE HALL_IDHALL PRICE SEAT ROW
1 10 2 4 10 6
2 5 2 4 10 5
3 5 2 4 10 4
4 8 5 4 3 1
5 7 5 4 4 15
6 10 7 4 7 9
7 6 2 4 14 3
HALLS
IDHALL PLACE_IDPLACE NAME NUMSEATS EQUIPMENT
1 5 A1 250 high
2 5 B1 200 medium
3 5 B2 200 medium
4 5 C2 180 medium
5 5 C2 180 medium
6 9 old hall 120 low
Display should look like
B1 10
C2 3
...
SELECT b.Name, a.Seat
FROM (SELECT Hall, Seat, COUNT(1) AS SeatCount, RANK() OVER (PARTITION BY Hall ORDER BY COUNT(1) DESC) AS SeatRank
FROM SEAT
GROUP BY Hall, Seat ) a
INNER JOIN
HALL b
ON a.HALL_IDHALL = b.IDHALL
WHERE a.SeatRank = 1
select h.name,t.hall_idhall,h.idhall, max(t.seat) from tickets t, hall h where t.hall_idhall=h.idhall
group by h.name,t.hall_idhall,h.idhall
Try the above query
hi i have a situation in sql as follows:
table name: case_details
caseid refno clientid report_date
1 1/1 1007 08-05-2013
2 1/2 1007 01-06-2013
3 1/3 1007 12-07-2013
4 1/4 1012 17-07-13
5 1/6 1009 08-07-13
table name: case_check_detail
caseid checkid alert_val
1 1 1
1 2 2
1 3 1
1 4 2
2 5 4
2 6 3
2 7 2
2 8 1
3 9 2
3 10 1
3 11 2
3 12 1
4 13 3
4 14 3
4 15 3
4 16 4
5 17 1
5 18 2
5 19 1
5 20 2
I want to count how many cases are there for clientid 1007 for whom the highest value of alert_val is 2 between 01-05-2013 to 18-07-2013
Like in this case its:
case id:1,caseid:3
Try
SELECT d.caseid
FROM case_details d JOIN case_check_detail c
ON d.caseid = c.caseid
WHERE d.clientid = 1007
AND d.report_date BETWEEN '20130501' AND '20130718'
GROUP BY d.caseid
HAVING MAX(c.alert_val) = 2
Output:
| CASEID |
----------
| 1 |
| 3 |
If you want to count them
SELECT COUNT(*) total
FROM
(
SELECT d.caseid
FROM case_details d JOIN case_check_detail c
ON d.caseid = c.caseid
WHERE d.clientid = 1007
AND d.report_date BETWEEN '20130501' AND '20130718'
GROUP BY d.caseid
HAVING MAX(c.alert_val) = 2
) q
Output:
| TOTAL |
---------
| 2 |
Here is SQLFiddle demo
SELECT COUNT(*)
FROM case_check_detail AS ccd
JOIN case_details AS cd ON cd.caseid=ccd.caseid
WHERE alert_val=2 AND report_date BETWEEN '2013-05-01' AND '2013-07-18'