Retrieve data between yesterday at 0700 and today at 0700 - sql

I am trying to come up with a SQL query that retrieves data starting from 0700 yesterday to 0700 today. I tried below, but I am not getting the correct values.
where datediff(hour, Incident_Call_Date_Time,getutcdate()) between 6 and 30
the data in the field is in the following format:
2020-10-28 22:16:30.000

Try this:
WHERE Incident_Call_Date_Time >= CONVERT(DATETIME, FORMAT(DATEADD(DAY, -1, GETDATE()), 'yyyy-MM-dd') + ' 07:00')
AND Incident_Call_Date_Time < CONVERT(DATETIME, FORMAT(GETDATE(), 'yyyy-MM-dd') + ' 07:00')
It gets yesterday and today's date as string (no time part), adds 07:00 to the dates as the new time part, and checks to see if your value is between those to new DATETIME values.

where Incident_Call_Date_Time
between dateadd(hh, 7, cast(cast(getutcdate() - 1 as date) as datetime))
and dateadd(hh, 7, cast(cast(getutcdate() as date) as datetime))

Related

SQL statement to select all rows from previous day with time

Need to select rows from the previous day but before 08:00 am.
(date >= dateadd(day,datediff(day,1,GETDATE()),0)
AND CONVERT(varchar, date,108) BETWEEN '00:00:00' AND '08:00:00')
return rows of from the previous day and before 08:00 am.
You can use:
where date >= dateadd(day, -1, convert(date, getdate())) and
date < dateadd(hour, -16, convert(date, getdate()))
This query is structured so it can make use of indexes.
You can also phrase this as:
where convert(date, [date]) = dateadd(day, -1, convert(date, getdate()) and
convert(time, [date]) <= '08:00:00'
This should also use indexes, because conversion to a date is perhaps the only function that does not prevent the use of an index.
You're on the right track. This does a BETWEEN check on the beginning of the day yesterday and the beginning of the day yesterday + 8 hours:
date BETWEEN dateadd(day,datediff(day,1,GETDATE()),0)
AND dateadd(hour, 8, dateadd(day,datediff(day,1,GETDATE()),0))

Getdate() functionality returns partial day in select query

I have a query -
SELECT * FROM TABLE WHERE Date >= DATEADD (day, -7, -getdate()) AND Date <= getdate();
This would return all records for each day except day 7. If I ran this query on a Sunday at 17:00 it would only produce results going back to Monday 17:00. How could I include results from Monday 08:00.
Try it like this:
SELECT *
FROM SomeWhere
WHERE [Date] > DATEADD(HOUR,8,DATEADD(DAY, -7, CAST(CAST(GETDATE() AS DATE) AS DATETIME))) --7 days back, 8 o'clock
AND [Date] <= GETDATE(); --now
That's because you are comparing date+time, not only date.
If you want to include all days, you can trunc the time-portion from getdate(): you can accomplish that with a conversion to date:
SELECT * FROM TABLE
WHERE Date >= DATEADD (day, -7, -convert(date, getdate())
AND Date <= convert(date, getdate());
If you want to start from 8 in the morning, the best is to add again 8 hours to getdate.
declare #t datetime = dateadd(HH, 8, convert(datetime, convert(date, getdate())))
SELECT * FROM TABLE
WHERE Date >= DATEADD (day, -7, -#t) AND Date <= #t;
NOTE: with the conversion convert(date, getdate()) you get a datatype date and you cannot add hours directly to it; you must re-convert it to datetime.
Sounds like you want to remove the time. Correct? If so then do the following.
SELECT * FROM TABLE WHERE Date >= (DATEADD (day, -7, -getdate()) AND Date DATEADD(dd, DATEDIFF(dd, 0, getdate()), 0))

Today Production - SQL Date Calculation case when

I have an issue regarding date calculations.
I have a datetime column called CreatedLocalTime date with this format: 2015-11-15 19:48:50.000
I need to retrieve a new column called Prod_Date with:
if “CreatedLocalTime” between
(CreatedLocalTime 7 AM)
& (CreatedLocalTime+1 7 AM)
return CreatedLocalTime date with DD/MM/YYYY format
On other words, today production = sum of yesterday from 7 AM till today at 7 AM.
Any help using case?
For day 7AM to day+1 7AM, you can try:
SELECT CAST(CreatedLocalTime as date)
...
FROM ...
WHERE ...
CreatedLocalTime >= DATEADD(hour, 7, CAST(CAST(CreatedLocalTime as date) as datetime))
AND
CreatedLocalTime < DATEADD(hour, 31, CAST(CAST(CreatedLocalTime as date) as datetime))
...
For previous day 7AM to day 7AM, replace 7 by -14 and 31 by 7.
Another way..
SELECT CASE WHEN CreatedLocalTime BETWEEN DATEADD(HOUR, 7,
CAST(CAST (CreatedLocalTime AS DATE) AS DATETIME))
AND DATEADD(HOUR, 31,
CAST(CAST (CreatedLocalTime AS DATE) AS DATETIME))
THEN REPLACE(CONVERT(NVARCHAR, CreatedLocalTime, 103), ' ', '/')
END AS CreatedLocalTime
You can write the else part for this, if needed
It looks like you want somthing along the lines of
DECLARE #StartDateTime Datetime
DECLARE #EndDateTime Datetime
SET #EndDateTime = DATEADD(hour, 7,convert(datetime,convert(date,getdate())) )
SET #StartDateTime = DATEADD(day, -1, #EndDateTime )
--Print out the variables for demonstration purposes
PRINT '#StartDateTime = '+CONVERT(nchar(19), #StartDateTime,120)
PRINT '#EndDateTime = '+CONVERT(nchar(19), #EndDateTime,120)
SELECT SUM (Production) AS Prod_Date FROM YourSchema.YourTable WHERE CreatedLocalTime >= #StartDateTime AND CreatedLocalTime < #EndDateTime
But you could also look at it as all the times which after you remove 7 hours from them are yesterday
SELECT SUM (Production) AS Prod_Date
FROM YourSchema.YourTable
WHERE DATEDIFF(day,DATEADD(hour, -7, CreatedLocalTime ))) = 1
The First version will be more efficient as the query will only have to do the date arithmetic once at the start while the second involved executing DATEDIFF and DATEADD for every record. This will be slower on large amounts of data.
The Gold plated solution would be to add a computed column to your table
ALTER TABLE YourSchema.YourTable ADD EffectiveDate AS CONVERT(date, DATEDIFF(day,DATEADD(hour, -7, CreatedLocalTime ))))
And then an index on that column
CREATE INDEX IX_YourTable_EffectiveDate ON YourSchema.YourTable (EffectiveDate )
So you can write
DECLARE #YesterDay date = DATEADD(day,-1, getdate())
SELECT SUM (Production) AS Prod_Date
FROM YourSchema.YourTable
WHERE EffectiveDate = #YesterDay

Add time stamp to date in SQLserver

Below fetches the last monday from the current date.
SELECT cast (DATEADD(wk, DATEDIFF(wk, 6, GETDATE()), 0) as datetime)
but it displays date as timestamp all zeros like this
2014-05-26 00:00:00.000
I want the time stamp to be at 6 am like this
05-26-2014 06:00:00
or else its ok even if I get the the exact last monday date with the current GETDATE() timestamp.
Thank you for the help!
Adding 6 hours
SELECT cast (DATEADD(HH,6,DATEADD(wk, DATEDIFF(wk, 6, GETDATE()), 0)) as datetime)
You can convert it using one of the many built-in formats.
This will display it in the format:
MM-DD-YYYY 06:00:00
and still fetch the last Monday date you want.
SELECT CONVERT(VARCHAR, DATEADD(wk, DATEDIFF(wk, 6, GETDATE()), 0), 110) + ' 06:00:00'

how can I get last 7 days of data being my date field a number?

I need to get last 7 days data excluding Sunday being my date field a number. How can I do it? Field structure 20140425. For example is I run the statement today it should give me date range between 20140424 - 20140417 excluding 20140420.
The hitch is of course converting the number based date to a real date. This seems to work:
select convert(datetime, convert(char(10), 20140425))
To expand, your query would look like this:
select *
from [Table]
where convert(datetime, convert(char(10), [columnname])) between convert(varchar, getdate() - 8, 101) and convert(varchar, getdate() - 1, 101)
and datepart(DW, convert(datetime, convert(char(10), [columnname]))) <> 1
The convert(varchar, getdate - 1, 101) will return you 12:00am yesterday morning. My first pass didn't include that and would've only given a 6 day range.
SELECT *
FROM Table_Name
WHERE CAST(DateField AS DATE) >= DATEADD(DAY, -7, GETDATE())
AND CAST(DateField AS DATE) <= GETDATE()
AND DATEPART(DW,CAST(DateField AS DATE)) <> 1