LEFT JOIN & SUM GROUP BY - sql

Question

EDIT:
The result supposed to be like this:
desired result
I have this query:
SELECT DISTINCT mitarbeiter.mitarbnr, mitarbeiter.login, mitarbeiter.name1, mitarbeiter.name2
FROM vertragspos
left join vertrag_ek_vk_zuord ON vertragspos.id = vertrag_ek_vk_zuord.ek_vertragspos_id
left join mitarbeiter ON vertrag_ek_vk_zuord.anlage_mitarbnr = mitarbeiter.mitarbnr
left join vertragskopf ON vertragskopf.id = vertragspos.vertrag_id
left join
(
SELECT wkurse.*, fremdwaehrung.wsymbol
FROM wkurse
INNER join
(
SELECT lfdnr, Max(tag) AS maxTag
FROM wkurse
WHERE tag < SYSDATE
GROUP BY lfdnr
) t1
ON wkurse.lfdnr = t1.lfdnr AND wkurse.Tag = t1.maxTag
INNER JOIN fremdwaehrung ON wkurse.lfdnr = fremdwaehrung.lfdnr
) wkurse ON vertragskopf.blfdwaehrung = wkurse.lfdnr
left join
(
SELECT vertrag_ID, Sum (preis) preis, Sum (menge) menge, Sum (preis * menge / Decode (vertragskopf.zahlintervall, 1,1,2,2,3,3,4,6,5,12,1) / wkurse.kurs) vertragswert
FROM vertragspos
GROUP BY vertrag_ID
) s ON vertragskopf.id = s.vertrag_id
But I always get an error on line 21 Pos 145:
ORA-00904 WKURSE.KURS invalid identifier
The WKURSE table is supposed be joined already above, but why do I still get error?
How can I do join with all these tables?
I need to join all these tables:
Mitarbeiter, Vertragspos, vertrag_ek_vk_zuord, wkurse, fremdwaehrung, vertragskopf.
What is the right syntax? I'm using SQL Tool 1,8 b38
Thank you.

Answer 1

Because LEFT JOIN is executed on entire dataset, and not in row-by-row manner. So there's no wkurse.kurs available in the execution context of subquery. Since you join that tables, you can place the calculation in the top-most select statement.
EDIT:
After you edited the statement, it became clear where does vertragskopf.zahlintervall came from. But I don't know where are you going to use calculated vertragswert (now it is absent in the query), so I've put it in the result. As I'm not a SQL parser and have no idea of your tables, so I cannot check the code, but calculation now can be resolved (all the values are available in calculation context).
SELECT DISTINCT mitarbeiter.mitarbnr, mitarbeiter.login, mitarbeiter.name1, mitarbeiter.name2, s.amount / Decode (vertragskopf.zahlintervall, 1,1,2,2,3,3,4,6,5,12,1) / wkurse.kurs) vertragswert
FROM vertragspos
left join vertrag_ek_vk_zuord ON vertragspos.id = vertrag_ek_vk_zuord.ek_vertragspos_id
left join mitarbeiter ON vertrag_ek_vk_zuord.anlage_mitarbnr = mitarbeiter.mitarbnr
left join vertragskopf ON vertragskopf.id = vertragspos.vertrag_id
left join (
SELECT wkurse.*, fremdwaehrung.wsymbol
FROM wkurse
INNER join (
SELECT lfdnr, Max(tag) AS maxTag
FROM wkurse
WHERE tag < SYSDATE
GROUP BY lfdnr
) t1
ON wkurse.lfdnr = t1.lfdnr AND wkurse.Tag = t1.maxTag
INNER JOIN fremdwaehrung ON wkurse.lfdnr = fremdwaehrung.lfdnr
) wkurse ON vertragskopf.blfdwaehrung = wkurse.lfdnr
left join (
SELECT vertrag_ID, Sum (preis) preis, Sum (menge) menge, Sum (preis * menge) as amount
FROM vertragspos
GROUP BY vertrag_ID
) s ON vertragskopf.id = s.vertrag_id
Rewriting the code using WITH clause makes it much clearer than select from select.
Also get the rate on last day before today in oracle is as simple as
select wkurse.lfdnr
, max(wkurse.kurs) keep (dense_rank first order by wkurse.tag desc) as rate
from wkurse
where tag < sysdate
group by wkurse.lfdnr

Answer 2

One option is a lateral join:
left join lateral
(SELECT vertrag_ID, Sum(preis) as preis, Sum(menge) as menge,
Sum (preis * menge / Decode (vertragskopf.zahlintervall, 1,1,2,2,3,3,4,6,5,12,1) / wkurse.kurs) vertragswert
FROM vertragspos
GROUP BY vertrag_ID
) s
ON vertragskopf.id = s.vertrag_id