Creating 2 "cartridges" of cumulative sum with conditions using SQL - sql

I need to create 2 cumulative sums based on the value type, for example:
I have values of incoming stock units from 2 types: A and B. and I also have records of outgoing stock units.
If we have enough stock of type "A" it should taken out of type A, if not- it should be taken out of type B. so basically I need to crate the columns "A stock" and "B stock" below, representing the current balance of each type.
I tried using cumulative sum but I'm having trouble with the condition... is there a way to write this query without using a loop ? ( Vertica DB)
In table below A_stock and B_stock are the final result I need to create
ID Type In OUT A stock B stock Order_id
1 A 100 0 100 0 1
1 B 50 0 100 50 2
1 A 100 0 200 50 3
1 - 0 -200 0 50 4
1 - 0 -10 0 40 5
1 B 50 0 0 90 6
1 A 40 0 40 90 7
1 - 0 -20 20 90 8
2 A 30 0 30 0 1
2 B 20 0 30 20 2
2 A 10 0 40 20 3
2 - 0 -20 20 20 4

You can use window functions - but you need a column that defines the ordering of the rows, I assumed ordering_id:
select t.*,
sum(case when type = 'A' then in + out else 0 end) over(partition by id order by ordering_id) a_stock,
sum(case when type = 'B' then in + out else 0 end) over(partition by id order by ordering_id) b_stock
from mytable t
This assumes that you want the stock on a per-id basis; if that's not the case, just remove the partition clause from the over() clause.

Related

Pandas DataFrame subtract values

Im new to python
I have a data frame (df) which has the following structure:
ID
rate
Sequential number
a
150
1
a
150
1
a
50
2
b
250
1
c
25
1
d
25
1
d
40
2
d
25
3
The ID are customers, the value are monthly rates and Sequential number is a number that always increases by 1, if the customer changes the monthly rate
I want to do the following:
for every ID find the maximum value in the column Sequential number, take the associated value in the column rate, find the minimum value in the column Sequential number and take associated value in the column rate and subtracting the rates.
At the end I want to have a additional column to my data frame with the difference of the rates. Maybe the loop could do the following:
for id in df()
find max() in column Sequential number and get value in rates -
min () in column Sequential number and get value in rates
return difference
The new df_new should be this
ID
rate
Sequential number
rate_diff
a
150
1
0
a
150
1
0
a
50
2
-100
b
250
1
0
c
25
1
0
d
25
1
0
d
40
2
0
d
30
3
5
If an ID has only one entry, the rate_diff should be 0
I tried already the lambda Function:
df['diff_rate'] = df.groupby('ID')['rate'].transform(lambda x : x-x.min())
but this returns
ID
rate
Sequential number
rate_diff
a
150
1
100
a
150
1
100
a
50
2
0
b
250
1
0
c
25
1
0
d
25
1
0
d
40
2
15
d
30
3
10
Maybe someone of you have a small workaround for this! :-)
One approach with indexing:
g = df.groupby('ID')['Sequential number']
IMAX = g.idxmax()
IMIN = g.idxmin()
df['rate_diff'] = 0
df.loc[IMAX, 'rate_diff'] = (df.loc[IMAX, 'rate'].to_numpy()
-df.loc[IMIN, 'rate'].to_numpy()
)
Another with groupby.transform+where:
g = df.sort_values(by=['ID', 'Sequential number']).groupby('ID')
m = g['Sequential number'].idxmax()
df['rate_diff'] = (g['rate'].transform(lambda x: x.iloc[-1]-x.iloc[0])
.where(df.index.isin(m), 0)
)
output:
ID rate Sequential number rate_diff
0 a 150 1 0
1 a 150 1 0
2 a 50 2 -100
3 b 250 1 0
4 c 25 1 0
5 d 25 1 0
6 d 40 2 0
7 d 30 3 5

Check if condition is true and if so add value to another column in sql

I have a postgres table that looks like this:
A B
5 4
10 10
13 15
100 250
20 Null
Using SQL, I would like to check whether the value in column A is larger than the value in column B and if so, then add a 1 to the column True. If the value in column A is smaller or equal to the value in column B or if column B contains a [NULL] value, I would like to add a 1 to the column False, like so:
A B True False
5 4 1 0
10 10 0 1
13 15 0 1
100 25 1 0
20 [NULL] 0 1
What is the best way to achieve this?
You can use case logic:
select t.*,
(case when A > B then 1 else 0 end) as true_col,
(case when A > B then 0 else 1 end) as false_col
from t;

How to show the closest date to the selected one

I'm trying to extract the stock in an specific date. To do so, I'm doing a cumulative of stock movements by date, product and warehouse.
select m.codart AS REF,
m.descart AS 'DESCRIPTION',
m.codalm AS WAREHOUSE,
m.descalm AS WAREHOUSEDESCRIP,
m.unidades AS UNITS,
m.entran AS 'IN',
m.salen AS 'OUT',
m.entran*1 + m.salen*-1 as MOVEMENT,
(select sum(m1.entran*1 + m1.salen*-1)
from MOVSTOCKS m1
where m1.codart = m.codart and m1.codalm = m.codalm and m.fecdoc >= m1.fecdoc) as 'CUMULATIVE',
m.PRCMEDIO as 'VALUE',
m.FECDOC as 'DATE',
m.REFERENCIA as 'REF',
m.tipdoc as 'DOCUMENT'
from MOVSTOCKS m
where (m.entran <> 0 or m.salen <> 0)
and (select max(m2.fecdoc) from MOVSTOCKS m2) < '2020-11-30T00:00:00.000'
order by m.fecdoc
Without the and (select max(m2.fecdoc) from MOVSTOCKS m2) < '2020-11-30T00:00:00.000' it shows data like this, which is ok.
REF WAREHOUSE UNITS IN OUT MOVEMENT CUMULATIVE DATE
1 0 2 0 2 -2 -7 2020-11-25
1 1 3 0 3 -3 -3 2020-11-25
1 0 5 0 5 -5 -7 2020-11-25
1 0 9 9 0 9 2 2020-11-26
2 0 2 2 0 2 2 2020-11-26
1 0 1 1 0 1 3 2020-12-01
The problem is, with the subselect in the where clause it returns no results (I think it is because it just looks for the max date and says it is bigger than 2020-11-30). I would like it to show the closest dates (all of them, for each product and warehouse) to the selected one, in this case 2020-11-30.
It should look slike this:
REF WAREHOUSE UNITS IN OUT MOVEMENT CUMULATIVE DATE
1 1 3 0 3 -3 -3 2020-11-25
1 0 9 9 0 9 2 2020-11-26
2 0 2 2 0 2 2 2020-11-26
Sorry if I'm not clear. Ask me if I have to clarify anything
Thank you
I am guessing that you want something like this:
select t.*
from (select m.*,
sum(m.entran - m1.salen) over (partition by m.codart, m.codalm order by fecdoc) as cumulative,
max(fecdoc) over (partition by m.codart, m.codalm) as max_fecdoc
from MOVSTOCKS m
where fecdoc < '2020-11-30'
) m
where fecdoc = max_fecdoc;
The subquery calculates the cumulative amount of stock using window functions and filters for records before the cutoff date. The outer query selects the most recent record from the combination of codeart/codalm, which seems to be how you are identifying a product.

Calculating Run Cost for lengths of Pipe & Pile

I work for a small company and we're trying to get away from Excel workbooks for Inventory control. I thought I had it figured out with help from (Nasser) but its beyond me. This is what I can get into a table, from there I need too get it to look like the table below.
My data
ID|GrpID|InOut| LoadFt | LoadCostft| LoadCost | RunFt | RunCost| AvgRunCostFt
1 1 1 4549.00 0.99 4503.51 4549.00 0 0
2 1 1 1523.22 1.29 1964.9538 6072.22 0 0
3 1 2 -2491.73 0 0 3580.49 0 0
4 1 2 -96.00 0 0 3484.49 0 0
5 1 1 8471.68 1.41 11945.0688 11956.17 0 0
6 1 2 -369.00 0 0 11468.0568 0 0
7 2 1 1030.89 5.07 5223.56 1030.89 0 0
8 2 1 314.17 5.75 1806.4775 1345.06 0 0
9 2 1 239.56 6.3 1508.24 1509.228 0 0
10 2 2 -554.46 0 0 954.768 0 0
11 2 1 826.24 5.884 4861.5961 1781.008 0 0
Expected output
ID|GrpID|InOut| LoadFt | LoadCostft| LoadCost | RunFt | RunCost| AvgRunCostFt
1 1 1 4549.00 0.99 4503.51 4549.00 4503.51 0.99
2 1 1 1523.22 1.29 1964.9538 6072.22 6468.4638 1.0653
3 1 2 -2491.73 1.0653 -2490.6647 3580.49 3977.7991 1.111
4 1 2 -96.00 1.111 -106.656 3484.49 3871.1431 1.111
5 1 1 8471.68 1.41 11945.0688 11956.17 15816.2119 1.3228
6 1 2 -369.00 1.3228 -488.1132 11468.0568 15328.0987 1.3366
7 2 1 1030.89 5.07 5223.56 1030.89 5223.56 5.067
8 2 1 314.17 5.75 1806.4775 1345.06 7030.0375 5.2266
9 2 1 239.56 6.3 1508.24 1509.228 8539.2655 5.658
10 2 2 -554.46 5.658 -3137.1346 954.768 5402.1309 5.658
11 2 1 826.24 5.884 4861.5961 1781.008 10263.727 5.7629
The first record of a group would be considered the opening balance. Inventory going into the yard have the ID of 1 and out of the yard are 2's. Load footage going into the yard always has a load cost per foot and I can calculate the the running total of footage. The first record of a group is easy to calculate the run cost and run cost per foot. The next record becomes a little more difficult to calculate. I need to move the average of run cost per foot forward to the load cost per foot when something is going out of the yard and then calculate the run cost and average run cost per foot again. Hopefully this makes sense to somebody and we can automate some of these calculations. Thanks for any help.
Here's an Oracle example I found;
SQL> select order_id
2 , volume
3 , price
4 , total_vol
5 , total_costs
6 , unit_costs
7 from ( select order_id
8 , volume
9 , price
10 , volume total_vol
11 , 0.0 total_costs
12 , 0.0 unit_costs
13 , row_number() over (order by order_id) rn
14 from costs
15 order by order_id
16 )
17 model
18 dimension by (order_id)
19 measures (volume, price, total_vol, total_costs, unit_costs)
20 rules iterate (4)
21 ( total_vol[any] = volume[cv()] + nvl(total_vol[cv()-1],0.0)
22 , total_costs[any]
23 = case SIGN(volume[cv()])
24 when -1 then total_vol[cv()] * nvl(unit_costs[cv()-1],0.0)
25 else volume[cv()] * price[cv()] + nvl(total_costs[cv()-1],0.0)
26 end
27 , unit_costs[any] = total_costs[cv()] / total_vol[cv()]
28 )
29 order by order_id
30 /
ORDER_ID VOLUME PRICE TOTAL_VOL TOTAL_COSTS UNIT_COSTS
---------- ---------- ---------- ---------- ----------- ----------
1 1000 100 1000 100000 100
2 -500 110 500 50000 100
3 1500 80 2000 170000 85
4 -100 150 1900 161500 85
5 -600 110 1300 110500 85
6 700 105 2000 184000 92
6 rows selected.
Let me say first off three things:
This is certainly not the best way to do it. There is a rule saying that if you need a while-loop, then you are most probably doing something wrong.
I suspect there is some calculation errors in your original "Expected output", please check the calculations since my calculated values are different according to your formulas.
This question could also be seen as a gimme teh codez type of question, but since you asked a decently formed question with some follow-up research, my answer is below. (So no upvoting since this is help for a specific case)
Now onto the solution:
I attempted to use my initial hint of the LAG statement in a nicely formed single update statement, but since you can only use a windowed function (aka LAG) inside a select or order by clause, that will not work.
What the code below does in short:
It calculates the various calculated fields for each record when they can be calculated and with the appropriate functions, updates the table and then moves onto the next record.
Please see comments in the code for additional information.
TempTable is a demo table (visible in the linked SQLFiddle).
Please read this answer for information about decimal(19, 4)
-- Our state and running variables
DECLARE #curId INT = 0,
#curGrpId INT,
#prevId INT = 0,
#prevGrpId INT = 0,
#LoadCostFt DECIMAL(19, 4),
#RunFt DECIMAL(19, 4),
#RunCost DECIMAL(19, 4)
WHILE EXISTS (SELECT 1
FROM TempTable
WHERE DoneFlag = 0) -- DoneFlag is a bit column I added to the table for calculation purposes, could also be called "IsCalced"
BEGIN
SELECT top 1 -- top 1 here to get the next row based on the ID column
#prevId = #curId,
#curId = tmp.ID,
#curGrpId = Grpid
FROM TempTable tmp
WHERE tmp.DoneFlag = 0
ORDER BY tmp.GrpID, tmp.ID -- order by to ensure that we get everything from one GrpID first
-- Calculate the LoadCostFt.
-- It is either predetermined (if InOut = 1) or derived from the previous record's AvgRunCostFt (if InOut = 2)
SELECT #LoadCostFt = CASE
WHEN tmp.INOUT = 2
THEN (lag(tmp.AvgRunCostFt, 1, 0.0) OVER (partition BY GrpId ORDER BY ID))
ELSE tmp.LoadCostFt
END
FROM TempTable tmp
WHERE tmp.ID IN (#curId, #prevId)
AND tmp.GrpID = #curGrpId
-- Calculate the LoadCost
UPDATE TempTable
SET LoadCost = LoadFt * #LoadCostFt
WHERE Id = #curId
-- Calculate the current RunFt and RunCost based on the current LoadFt and LoadCost plus the previous row's RunFt and RunCost
SELECT #RunFt = (LoadFt + (lag(RunFt, 1, 0) OVER (partition BY GrpId ORDER BY ID))),
#RunCost = (LoadCost + (lag(RunCost, 1, 0) OVER (partition BY GrpId ORDER BY ID)))
FROM TempTable tmp
WHERE tmp.ID IN (#curId, #prevId)
AND tmp.GrpID = #curGrpId
-- Set all our values, including the AvgRunCostFt calc
UPDATE TempTable
SET RunFt = #RunFt,
RunCost = #RunCost,
LoadCostFt = #LoadCostFt,
AvgRunCostFt = #RunCost / #RunFt,
doneflag = 1
WHERE ID = #curId
END
SELECT ID, GrpID, InOut, LoadFt, RunFt, LoadCost,
RunCost, LoadCostFt, AvgRunCostFt
FROM TempTable
ORDER BY GrpID, Id
The output with your sample data and a SQLFiddle demonstrating how it all works:
ID GrpID InOut LoadFt RunFt LoadCost RunCost LoadCostFt AvgRunCostFt
1 1 1 4549 4549 4503.51 4503.51 0.99 0.99
2 1 1 1523.22 6072.22 1964.9538 6468.4638 1.29 1.0653
3 1 2 -2491.73 3580.49 -2654.44 3814.0238 1.0653 1.0652
4 1 2 -96 3484.49 -102.2592 3711.7646 1.0652 1.0652
5 1 1 8471.68 11956.17 11945.0688 15656.8334 1.41 1.3095
6 1 2 -369 11587.17 -483.2055 15173.6279 1.3095 1.3095
7 2 1 1030.89 1030.89 5226.6123 5226.6123 5.07 5.07
8 2 1 314.17 1345.06 1806.4775 7033.0898 5.75 5.2288
9 2 1 239.56 1584.62 1509.228 8542.3178 6.3 5.3908
10 2 2 -554.46 1030.16 -2988.983 5553.3348 5.3908 5.3907
11 2 1 826.24 1856.4 4861.5962 10414.931 5.884 5.6103
If you are unclear about parts of the code, I can update with additional explanations.

Manipulating SQL query to create data categories that return maximum values

I have a table that looks like this at the moment:
Day Limit Price
1 52 0.3
1 4 70
1 44 200
1 9 0.01
1 0 0.03
1 0 0.03
2 52 0.4
2 10 70
2 44 200
2 5 0.01
2 0 0.55
2 2 50
Is there a way I can use SQL to manipulate the result into a table with different categories for price and selecting the maximum value for the limit respective to its price?
Day 0-10 10-100 100+
1 52 4 44
2 52 10 44
You can use CASE and MAX:
SELECT Day,
MAX(CASE WHEN Price BETWEEN 0 AND 10 THEN Limit ELSE 0 END) as ZeroToTen,
MAX(CASE WHEN Price BETWEEN 10 AND 100 THEN Limit ELSE 0 END) as TenToHundred,
MAX(CASE WHEN Price > 100 THEN Limit ELSE 0 END) as HundredPlus
FROM YourTable
GROUP BY Day
Here is the Fiddle.
BTW -- if you're using MySQL, add ticks around LIMIT since it's a keyword.
Good luck.