I have string column that looks usually approximately like this:
https://mapy.cz/zakladni?x=16.3360208&y=49.6718038&z=8&source=firm&id=13123554
https://mapy.cz/turisticka?x=15.9380354&y=50.1990211&z=11&source=base&id=2197
https://mapy.cz/turisticka?x=12.8611357&y=49.8051338&z=16&source=base&id=1703157
I would like to group data by source which is part of the string - four letters behind "source=" (in the case above: firm) and then simply count them. Is there a way to achieve this directly in SQL code? I am using hadoop.
Data is a set of strings that look like above. My expected result is summary table with two columns: 1) Each type of the source (there is about 20 possible and their length is different so I cannot use sipmle substring). Ideally I am looking for solution that says: For the grouping use four letters that come after "source=" 2) Count of their occurences in all the strings.
There is just one source type in each string.
You can use regexp_extract():
select substr(regexp_extract(url, 'source[^&]+'), 8)
You can use charindex in MSSQL to get position of string and extract record
;with cte as (
SELECT SUBSTRING('https://mapy.cz/zakladni?x=16.3360208&y=49.6718038&z=8&source=firm&id=13123554',
charindex('&source=','https://mapy.cz/zakladni?x=16.3360208&y=49.6718038&z=8&source=firm&id=13123554')
+8,4) AS ExtractString )
select ExtractString,count(ExtractString) as count from cte group by ExtractString;
There is equivalent function LOCATE in hiveql for charindex.
Related
I would like to convert this table
to something like this
the long string can be dynamic so it's important to me that it's not a fixed solution for these values specifically
Please help, i'm using big query
You could start by using SPLIT SPLIT(value[, delimiter]) to convert your long string into separate key-value pairs in an array.
This will be sensitive to you having commas as part of your values.
SPLIT(session_experiments, ',')
Then you could either FLATTEN that array or access each element, and then use some REGEXs to separate the key and the value.
If you share more context on your restrictions and intended result I could try and put together a query for you that does exactly what you want.
It's not possible what you want, however, there is a better practice for BigQuery.
You can use arrays of structs to store that information in a table.
Let's say you have a table like that
You can use that sample query to understand how to use it.
with rawdata AS
(
SELECT 1 as id, 'test1-val1,test2-val2,test3-val3' as experiments union all
SELECT 1 as id, 'test1-val1,test3-val3,test5-val5' as experiments
)
select
id,
(select array_agg(struct(split(param, '-')[offset(0)] as experiment, split(param, '-')[offset(1)] as value)) from unnest(split(experiments)) as param ) as experiments
from rawdata
The output will look like that:
After having that output, it's more convenient to manipulate the data
I want to find how many times "fizz" appears in "fizzbuzzfizz" string in bigquery or sql.
here output should be 2.
You can use REGEXP_EXTRACT_ALL and ARRAY_LENGTH, See this sql:
WITH data AS(
SELECT 'fizzbuzzfizz' as string
)
SELECT
ARRAY_LENGTH(REGEXP_EXTRACT_ALL(string, "fiz")) AS size FROM data;
Which produces this:
I have a table with about 200 million records. One of the columns is defined as varchar(100) and it's included in a full text index. Most of the values are numeric. Only few are not numeric.
The problem is that it's not working well. For example if a row contains the value '123456789' and i look for '567', it's not returning this row. It will only return rows where the value is exactly '567'.
What am I doing wrong?
sql server 2012.
Thanks.
Full text search doesn't support leading wildcards
In my setup, these return the same
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'28400')
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'"2840*"')
This gives zero rows
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'"*840*"')
You'll have to use LIKE or some fancy trigram approach
The problem is probably that you are using a wrong tool since Full-text queries perform linguistic searches and it seems like you want to use simple "like" condition.
If you want to get a solution to your needs then you can post DDL+DML+'desired result'
You can do this:
....your_query.... LIKE '567%' ;
This will return all the rows that have a number 567 in the beginning, end or in between somewhere.
99% You're missing % after and before the string you search in the LIKE clause.
es:
SELECT * FROM t WHERE att LIKE '66'
is the same as as using WHERE att = '66'
if you write:
SELECT * FROM t WHERE att LIKE '%66%'
will return you all the lines containing 2 'sixes' one after other
I have a table which has a column with doc locations, such as AA/BB/CC/EE
I am trying to get only one of these parts, lets say just the CC part (which has variable length). Until now I've tried as follows:
SELECT RIGHT(doclocation,CHARINDEX('/',REVERSE(doclocation),0)-1)
FROM Table
WHERE doclocation LIKE '%CC %'
But I'm not getting the expected result
Use PARSENAME function like this,
DECLARE #s VARCHAR(100) = 'AA/BB/CC/EE'
SELECT PARSENAME(replace(#s, '/', '.'), 2)
This is painful to do in SQL Server. One method is a series of string operations. I find this simplest using outer apply (unless I need subqueries for a different reason):
select *
from t outer apply
(select stuff(t.doclocation, 1, patindex('%/%/%', t.doclocation), '') as doclocation2) t2 outer apply
(select left(tt.doclocation2), charindex('/', tt.doclocation2) as cc
) t3;
The PARSENAME function is used to get the specified part of an object name, and should not used for this purpose, as it will only parse strings with max 4 objects (see SQL Server PARSENAME documentation at MSDN)
SQL Server 2016 has a new function STRING_SPLIT, but if you don't use SQL Server 2016 you have to fallback on the solutions described here: How do I split a string so I can access item x?
The question is not clear I guess. Can you please specify which value you need? If you need the values after CC, then you can do the CHARINDEX on "CC". Also the query does not seem correct as the string you provided is "AA/BB/CC/EE" which does not have a space between it, but in the query you are searching for space WHERE doclocation LIKE '%CC %'
SELECT SUBSTRING(doclocation,CHARINDEX('CC',doclocation)+2,LEN(doclocation))
FROM Table
WHERE doclocation LIKE '%CC %'
I have a report (built using SSRS) that uses a multi-value parameter.
I want to add a Filter onto my SQL Query WHERE FieldA is LIKE any of the values stored in the parameter.
So FieldA might have the following values:
BOBJAMESLOUISE
MARYBOB
JENNY
JOHNLOUISEJAMES
BOB
JENNYJAMESMIKE
And #ParamA might have the following values:
Bob, Louise
Therefore in this example only records 1, 3, 4 and 5 should be returned
Thanks to any help in advance :)
P.S I'm using SQL Server 2008
You will want to implement a function like the split function. This can take a comma separated value list and separate it into rows like you want.
Below is a link for a couple of different versions, any of them will work for you. It also tells you how to use it.
Split Function
I am guessing its not the spiting sting part that is the issue since just googling for SQL split string you can find a lot of example. In your case what you would want after the split string is something like this. Assuming that the split string function you end up using returns a table of values Here is what your comparison query for with field A would look like.
SELECT * FROM YourTableWithFieldA WHERE (#ParamA IS NULL OR EXISTS ( SELECT * FROM YourSplitFunctionThatReturnsATableOfValues(#ParamA) SplitTable WHERE (FieldA Like '%'+SplitTable.Value+'%')))