Is there any way to select the multiples shape from slide with the same shape name.
For e.g., I have 5 shapes with the name "Textbox 60". And I want run a macro which select all the shapes from a slide named "Textbox 60". Have used the below code.
ActiveWindow.View.Slide.Shapes.Range("Textbox 60").Select
Here's one approach:
Sub Tester()
SelectByName ActivePresentation.Slides(1), "Textbox1"
End Sub
Sub SelectByName(sld As Slide, nm As String)
Dim s As Shape, first As Boolean
first = True
For Each s In sld.Shapes
If s.Name = nm Then
s.Select first 'Argument determines whether to add to
first = False ' existing selection, or replace it
End If
Next s
End Sub
You should try following #TinMan's suggestion though - that is the "better" way to go.
Activating and Selecting Objects should be avoided whenever possible. You are better of working with the Shapes using a ShapeRange.
Sub Main()
Dim ShapeRange As ShapeRange
Set ShapeRange = FindShapes(ActiveWindow.View.Slide, "Textbox 60")
If Not ShapeRange Is Nothing Then
End If
End Sub
Function FindShapes(Slide As Slide, Pattern As String) As ShapeRange
Dim Results() As Long
ReDim Results(1 To Slide.Shapes.Count)
Dim n As Long
Dim Index As Long
For Index = 1 To Slide.Shapes.Count
With Slide.Shapes(Index)
.Name = "Textbox 60"
If .Name Like Pattern Then
n = n + 1
Results(n) = Index
End If
End With
Next
If n > 0 Then
ReDim Preserve Results(1 To n)
Set FindShapes = Slide.Shapes.Range(Results)
End If
End Function
Note: I rewrote the code to handle multiple shapes with the same name.
Related
I need to generate a random number between 1 and 30 and display it on every slide. I found the following code online:
Sub UpdateRandomNumber(oSh As Shape)
Dim X As Long
'Make the shape’s text a random number
'X or less
'Change 12 below to any number you’d like:
X = 30
oSh.TextFrame.TextRange.Text = CStr(Random(X))
End Sub
Function Random(High As Long) As Long
'Generates a random number less than or equal to
'the value passed in High
Randomize
Random = Int((High * Rnd) + 1)
End Function
Sub RandomNumber()
End Sub
I need the code to do one thing differently:
The object prompting the action is in the same spot on all slides. When generating and displaying a random number, all slides should be changed accordingly.
When I leave the slide, the previously generated number should be shown instead of the one that was previously generated on this slide.
This creates a random number between 1 and 30. Change the shape name to the actual shape used in your file:
Sub ShapeNumber()
Dim X As Long
Dim ShapeNumber As String
Dim oSlide As Slide
Dim oShape As Shape
X = 30
Randomize
ShapeNumber = Int((X * Rnd) + 1)
For Each oSlide In ActivePresentation.Slides
For Each oShape In oSlide.Shapes
If oShape.Name = "Rectangle 3" Then
oShape.TextFrame.TextRange.Text = ShapeNumber
End If
Next oShape
Next oSlide
End Sub
I have used VBA in the past mostly with excel, but I am not very experienced.
I want to cycle through multiple boxes and make each of them have coincident edges. Like they are sitting on top of each other. I am having trouble identifying the position of the first shape in my selection. I've tried a number of different objects including selection.shaperange.
Dim shp As Visio.Shape
Dim shp1 As Visio.Shape
Dim Pos As Double
Set shp1 = ActiveWindow.Selection.ShapeRange.Item
Pos = shp1.Cells("PinY")
For Each shp In Application.ActiveWindow.Selection
'Change the cell name to the one you want
If shp <> ActiveWindow.Selection.Item(1) Then
Pos = Pos + 6
End If
shp.CellsSRC(visSectionControls, visRowXFormOut, visXFormPinY).FormulaU = Pos & "mm"
Pos = shp.Cells("PinY")
Next shp
End Sub
Can you help me get the position of the first selected item and then I may be able to figure out the rest.
This code will abut the left sides of all but the first-selected shape with the right side of the first-selected shape:
Option Explicit
Public Sub AbutLeftsToPrimaryRight()
Dim sel As Visio.Selection
Set sel = Visio.ActiveWindow.Selection
If (sel.Count < 2) Then
Debug.Print "Select two or more shapes (Use Shift + Click)!"
GoTo Cleanup
End If
Dim shp0 As Visio.Shape
Dim shp As Visio.Shape
'// Get the selection and the primary selected shape,
'// which is item(1). See also: Selection.PrimaryItem
Set shp0 = sel(1)
'// Quick calculate the right side of shp0:
'// PinX - LocPinX + Width.
Dim dRight0 As Double
dRight0 = shp0.CellsU("PinX").ResultIU - shp0.CellsU("LocPinX").ResultIU + shp0.CellsU("Width").ResultIU
'// If shapes are rotated, flipped, or not rectangular,
'// then you'll need to use shp.BoundingBox, which
'// is more complicated
Dim dLeft As Double
Dim dx As Double, px As Double
Dim i As Integer
For i = 2 To sel.Count
'// Get the ith shape:
Set shp = sel(i)
'// Get its Pin:
px = shp.CellsU("PinX").ResultIU
'// Calculate the left side of the shape:
'// PinX - LocPinX:
dLeft = px - shp.CellsU("LocPinX").ResultIU
'// The offset:
dx = dLeft - dRight0
'// Set the new pin:
shp.CellsU("PinX").ResultIUForce = px - dx
Next i
Cleanup:
Set shp0 = Nothing
Set shp = Nothing
Set sel = Nothing
End Sub
Hope this helps!
I'm trying to explore how do I apply some formatting to only few selected words in a textbox but so far unable to accomplish this myself.
Somehow with the code I created below, I can only use it to select all the words in the textbox instead of just a few words I want.
It would be great if anyone can provide me a simpler/ existing codes that can help me solve this please ?
Thanks in advance
Sub ActiveTextRange()
Dim sld As slide
Dim sh As Shape
Dim wordcount As Long, j As Long, x As Long, y As Long, z As Long
wordcount = ActiveWindow.Selection.ShapeRange(1).textFrame.TextRange.Words.Count
With ActiveWindow.Selection.ShapeRange(1)
.textFrame.TextRange.Words(Start:=1, Length:=wordcount).Font.Color.RGB = RGB(230, 0, 0)
End With
End Sub
The following might help. Key to this is being able to track the location of the specific text you want to change in amongst larger chunks of text; my suggestion is to format each bit of text as you add it to the shape. Cheers.
Option Explicit
Sub ActiveTextRange()
Dim vPresentation As presentation
Dim vSlide As Slide
Dim vShape As Shape
Dim vAddThisText As String
' Create a new presentation, add a slide and a rectangle shape
Set vPresentation = Application.Presentations.Add
Set vSlide = vPresentation.Slides.Add(vPresentation.Slides.Count + 1, ppLayoutBlank)
Set vShape = vSlide.Shapes.AddShape(msoShapeRectangle, 10, 10, 600, 300)
' Make the shape white with a 3pt dark red border
vShape.Fill.ForeColor.RGB = rgbWhite
With vShape.Line
.ForeColor.RGB = rgbDarkRed
.Weight = 3
End With
' Setup the shape to be left aligned, font color, top anchored, etc
With vShape.TextFrame
.TextRange.Paragraphs.ParagraphFormat.Alignment = ppAlignCenter
.TextRange.Font.Color.RGB = rgbBlack
.VerticalAnchor = msoAnchorMiddle
.TextRange.ParagraphFormat.SpaceAfter = 6
.TextRange.ParagraphFormat.WordWrap = msoCTrue
End With
' And now format the word red, which is the 7th character and is 3 long
vAddThisText = "Hello Red World"
vShape.TextFrame.TextRange.InsertAfter vAddThisText
With vShape.TextFrame.TextRange.Characters(7, 3)
.Font.Color.RGB = rgbRed
' and change other attributes if needed etc
End With
End Sub
And the output is ...
This colors the second and third words red in a Title placeholder. After Words, the first number is the starting position and the second number is the length:
Sub ColorWords()
Dim objSlide As Slide
Dim objShape As Shape
For Each objSlide In ActivePresentation.Slides
For Each objShape In objSlide.Shapes
If objShape.Type = msoPlaceholder Then
If objShape.PlaceholderFormat.Type = ppPlaceholderTitle Or objShape.PlaceholderFormat.Type = ppPlaceholderCenterTitle Then
With objShape.TextFrame2.TextRange.Words(2, 2).Font.Fill
.Solid
.ForeColor.RGB = RGB(255, 0, 0)
End With
End If
End If
Next objShape
Next objSlide
End Sub
To color a word selection, use:
ActiveWindow.Selection.TextRange.Font.Color.RGB = RGB(Red:=255, Green:=0, Blue:=0)
OK. I think I better understand the ask ... but I'm assuming in this response you're selecting text ... rather than just a shape itself. So you're editing the powerpoint, select some text in a shape, and want to run a macro to format(?) It should be as simple as creating the following in a code module (and then I created a custom access toolbar link to run the macro at the top of PowerPoint to make it quick):
Option Explicit
Sub ActiveTextRange()
ActiveWindow.Selection.TextRange.Font.Color.RGB = rgbRed
End Sub
Before:
Select the text "Red" and run macro:
Btw ... if you want to select just the shape and have some logic choose the text, the concept is a mix of this and my first answer.
I have been working with VBA in excel and recently began working with the Scripting.Dictionary object. I hadn't run across any major problems until today.
Basically I am trying to populate a listbox with the Key values of a dictionary, then add one more value to the listbox. This results in the value not only being added to the listbox, but also to the dictionary as a key. I have attempted to copy the values from the dict.keys() array to a completely separate array, but still have the same issue. I assume this is a byref problem but have yet to figure out a solution. If anyone has any ideas that would be awesome.
Private Sub Setup_settingLst()
'Set Settings listbox items
'On Error GoTo ErrorExit
Dim list_ary() As Variant
Dim tmp As Variant
Dim i As Integer
settingLst.Clear
settingLst.Value = "-Select Setting-"
i = 0
tmp = tmp_dict.Keys()
If tmp_dict.Count > 1 Then
ReDim list_ary(0 To tmp_dict.Count)
For i = 0 To UBound(tmp)
list_ary(i) = tmp(i)
Next i
list_ary(tmp_dict.Count) = "Back"
Else
ReDim list_ary(0 To tmp_dict.Count - 1)
For i = 0 To UBound(tmp)
list_ary(i) = tmp(i)
Next i
End If
settingLst.List = list_ary
Erase list_ary
Exit Sub
ErrorExit:
End Sub
This seems to work
Private Sub UserForm_Click()
Dim dcValues As Scripting.Dictionary
Me.ListBox1.Clear
Set dcValues = FillDictionary
Me.ListBox1.List = dcValues.Keys
Me.ListBox1.AddItem "Back"
End Sub
Is there any way to get a shape's Id if you know it's Name?
For example, if I have this:
Dim myshape As Shape
myshape.Name
Can I get it's Id?
myshape.Id = getIdByName(myshape.Name)
Sure, it's pretty straigtforward:
Sub PrintShapeID()
Debug.Print getIDByName("My Shape", 1)
End Sub
Function getIDByName(shapeName As String, slide As Integer)
Dim ap As Presentation: Set ap = ActivePresentation
Dim sl As slide: Set sl = ap.Slides(slide)
Dim sh As Shape: Set sh = sl.Shapes(shapeName)
getIDByName = sh.Id
End Function
This works for the slide that you specify. You can also loop through all slides, but note that there may be more than one shape with the same name so you'd have to figure out which one you want.