I have table like this:
Incident_id is foreign key. What I want to achieve it -> create one more column with named position (int). And populate it like this: find all rows for each incident_id and and update each row with index or list of rows I get by each incident_id. exapmple:
incident_id 5 matches with 4 note rows so updated for the position will be 0, 1, 2, 3 accordingly. Ty
I would not recomment storing such derived information. Instead, you can create a view that uses row_number() to enumerate the rows of each incident_id:
create view myview as
select t.*, row_number() over(partition by incident_id order by id) - 1 rn
from mytable t
To get a stable result, you need a column that can be used to consistently order the rows of each incident: I called it id in the query. You can change that to the relevant column name (or set of columns) for your use case; you would typically use the primary key column(s) of your table.
EDIT
If you really wanted to materialize that value in a new column, and considering that the primary key of your table, you would do:
alter table mytable add column position int;
update mytable t
set position = t1.position
from (
select incident_note_id,
row_number() over(partition by incident_id order by incident_note_id) - 1 position
from mytable
) t1
where t1.incident_note_id = t.incident_note_id;
Related
I already have a Hive partitioned table. I needed to add a new column to the table, so i used ALTER to add the column like below.
ALTER TABLE TABLE1 ADD COLUMNS(COLUMN6 STRING);
I have my final table load query like this:
INSERT OVERWRITE table Final table PARTITION(COLUMN4, COLUMN5)
select
stg.Column1,
stg.Column2,
stg.Column3,
stg.Column4(Partition Column),Field Name:Code Sample value - YAHOO.COM
stg.Column5(Partition Column),Field Name:Date Sample Value - 2021-06-25
stg.Column6(New Column) Field Name:reason sample value - Adjustment
from (
select fee.* from (
select
fees.* ,
ROW_NUMBER() OVER (PARTITION BY fees.Column1 ORDER BY fees.Column3 DESC) as RNK
from Stage table fee
) fee
where RNK = 1
) stg
left join (
select Column1 from Final table
where Column5(date) in (select distinct column5(date) from Stage table)
) TGT
on tgt.Column1(id) = stg.Column1(id) where tgt.column1 is null
UNION
select
tgt.column1(id),
tgt.column2,
tgt.column3,
tgt.column4(partiton column),
tgt.column5(partiton column-date),
tgt.column6(New column)
from
Final Table TGT
WHERE TGT.Column5(date) in (select distinct column5(date) from Stage table);"
Now when my job ran today, and when i try to query the final table, i get the below error
Invalid partition value 'Adjustment' for DATE partition key: Code=2021-06-25/date=Adjustment
I can figure out something wrong happend around the partition column but unable to figure out what went wrong..Can someone help?
Partition columns should be the last ones in the select. When you add new column it is being added as the last non-partition column, partition columns remain the last ones, they are not stored in the datafiles, only metadata contains information about partitions. All other columns order also matters, it should match table DDL, check it using DESCRIBE FORMATTED table_name.
INSERT OVERWRITE table Final table PARTITION(COLUMN4, COLUMN5)
select
stg.Column1,
stg.Column2,
stg.Column3,
stg.Column6 (New column) ------------New column
stg.Column4(Partition Column) ---partition columns
stg.Column5(Partition Column)
...
I have many record in one table :
1 dog
2 cat
3 lion
I want to recreate table or sort data with this Alphabetical order :
1 cat
2 dog
3 lion
Table 1
Id int Unchecked
name nvarchar(50) Checked
To create another table from your table :
CREATE TABLE T1
( ID INT IDENTITY PRIMARY KEY NOT NULL,
NAME NVARCHAR(50) NOT NULL
)
GO
INSERT INTO T1 VALUES ('Dog'),('Cat'),('Lion');
SELECT ROW_NUMBER ()OVER (ORDER BY NAME ASC) ID, NAME INTO T2 FROM T1 ORDER BY NAME ASC;
If you just want to sort the table data, use Order by
Select * from table_1 order by Name
If you want to change the Id's as well according to alphabetical order, create a new table and move the records to the new table by order.
SELECT RANK() OVER (ORDER BY name ) AS Id, name
INTO newTable
FROM table_1
In your database, the order of the records as they were inserted into the table does not necessarily dictate the order in which they're returned when queried. Nor does the ordering of a clustered key. There may be situations in which you appear to always get the same ordering of your results, but that is not guaranteed and may change at any time.
If the results of a query must be a specific order, then you must specify that ordering with an ORDER BY clause in your query (ORDER BY [Name] ASC in this particular case).
I understand, based upon your comments above, that you don't want this to be the answer. But this is how SQL Server (and any other relational database) works. If order matters, you specify that upon querying data from the system, not when inserting data into it.
I have a 2 databases that I want to merge with some similiar tables. The source tables have id as bigint and my destination table has int as ID. There aren't that many records in my source table (< 20k) so I want to assign new ids to all records so the ids can fit in an int. How can I do this with sql?
First Option
You can Use Sequence object as follow:
First Create a Sequence object and assign it's Start With value to max Id value in destination table plus 1. For example if max Id in destination table is 100, you need to assign 101 as Start With. You can also obtain the max Id value from destination table using a Max(Id) aggregate function and store it in a variable:
CREATE SEQUENCE SeqId
START WITH [Max value of Id in destination table]
INCREMENT BY 1 ;
GO
Then insert to destination table using following query:
Insert Into tblXXX (Id, ...) Values (NEXT VALUE FOR SeqId, ...)
Read more about Sequence Object
Second Option
You can make the destination table's Id column as Identity column with seed equal to destination table's Id column max value and Increment equal to 1.
Here is detailed example also Here
You did not provide much details so I can only provide a general guideline:
Note: Example assumes that you want to merge tables A and B into C and you want to generate new IDs. I also assume that these IDs are not referenced by other tables (foreign keys).
First you get record counts from tables A and B:
DECLARE #countA INT
DECLARE #countB INT
SET #countA = ( SELECT COUNT(*) FROM A )
SET #countB = ( SELECT COUNT(*) FROM B )
Next you use a window function to generate new IDs and insert records into table C.
INSERT INTO C
SELECT #countA + ROW_NUMBER() OVER( ORDER BY ID ) AS ID, ....
FROM A
INSERT INTO C
SELECT #countA + #countB + ROW_NUMBER() OVER( ORDER BY ID ) AS ID, ....
FROM B
i want an order info for every row in my table. the following is my table. ID column is identity and its primary key. Order column is computed from id column.
ID -- Name -- Order
1 kiwi 1
2 banana 2
3 apple 3
everything is fine and i have an order column. But i cant switch the orders of rows.
for example i cant say that from now on kiwi's order becomes 2 and banana's order becomes 1
in other words if we would update a computed column then my problem could be solved.
if i dont create order column as computed column then for every new entry i have to compute largest order so that i can write (largest order) + 1 for new entry's order. But i do not calculate largest number for every entry since it is costly.
So what should i do now?
I ve searched and the solutions i found creating trigger function etc. i do not want to do that too.
I might not have understood the question - I don't think its very clear.
but why use a counter to order the set, couldnt you just use a timestamp for each order and use that to dictate which order is more recent?
CREATE TABLE dbo.Test (
ID INT IDENTITY(1,1),
Name varchar(50),
OrderTime Datetime
)
INSERT INTO dbo.TEST (Name,OrderTime)
VALUES ('kiwi',Getdate())
SELECT *
FROM dbo.TEST
ORDER BY OrderTime
if you needed an integer based on the order time you could use a rownumber function to return one;
SELECT *,
ROW_NUMBER() OVER (ORDER BY OrderTime Desc) as OrderInt
FROM dbo.TEST
I have a table in PostgreSQL that has an ID column that is supposed to be unique. However, a large number of the rows (around 3 million) currently have an ID of "1".
What I know:
The total number of rows
The current maximum value for the ID column
The number of rows with an (incorrect) ID of "1"
What I need is a query that will pull all the rows with an ID of "1" and assign them a new ID that increments automatically so that every row in the table will have a unique ID. I'd like it to start at the currentMaxId + 1 and assign each row the subsequent ID.
This is the closest I've gotten with a query:
UPDATE table_name
SET id = (
SELECT max(id) FROM table_name
) + 1
WHERE id = '1'
The problem with this is that the inner SELECT only runs the first time, thus setting the ID of the rows in question to the original max(id) + 1, not the new max(id) + 1 every time, giving me the same problem I'm trying to solve.
Any suggestions on how to tweak this query to achieve my desired result or an alternative method would be greatly appreciated!
You may do it step by step with a temporary sequence.
1) creation
create temporary sequence seq_upd;
2) set it to the proper initial value
select setval('seq_upd', (select max(id) from table_name));
3) update
update table_name set id=nextval('seq_upd') where id=1;
If you are going to work with a SEQUENCE, consider the serial pseudo data type for you id. Then you can just draw nextval() from the "owned" (not temporary) sequence, which will then be up to date automatically.
If you don't want that, you can fall back to using the ctid and row_number() for a one-time numbering:
UPDATE tbl t
SET id = x.max_id + u.rn
FROM (SELECT max(id) AS max_id FROM tbl) x
, (SELECT ctid, row_number() OVER (ORDER BY ctid) AS rn
FROM tbl WHERE id = 1) u
WHERE t.ctid = u.ctid;
Related answer on dba.SE:
numbering rows consecutively for a number of tables