I want to create a find function to use then in a GridView widget My I don't know how to use a subquery.
This is the simple version of the PostgreSQL query that I have:
SELECT color
FROM cars
LEFT JOIN (
SELECT name
FROM companies
)
Here is what I a trying and doesn't work:
$query = Cars::find()
->select([
'color' => '
SELECT name // Problem here.
FROM companies // Problem here.
',
]);
Your expected query is not what you are trying to do. You can add a custom subquery as
$query = Cars::find()
->select([
'(SELECT name FROM companies) AS xxx'
]);
But if you want to add a field from joined table to the grid, then you should have a relation defined and then you can easily add such a column to your grid. See https://www.yiiframework.com/doc/guide/2.0/en/db-active-record#relational-data
You can use instance of ActiveQuery in leftJoin() method like this:
$subQuery = Companies::find()
->select('name', 'id'); //I've added ID to show how to write on condition
$query = Cars::find()
->select('color')
->leftJoin(
['alias' => $subQuery],
'alias.id = cars.company_id'
);
See documentation for more details about leftJoin() and join() methods.
$query = Cars::find()
->select(['cars.color','companies.name'])
->leftJoin('companies', 'cars.company_id = companies.id');
Related
I am working in yii2.
There are employee and company table employee contains company_id.
I have a filter search running properly If I use joinWith()
$query = Employee::find();
$query->joinWith(['company']);
$dataProvider = new ActiveDataProvider([
'query' => $query,
'pagination' => false,
'sort' => false,
]);
if (!($this->load($params) && $this->validate())) {
return $dataProvider;
}
//and below is the filterwhere
$query->andFilterWhere(['like', 'company.name', $this->company_id]);
But issue came when I make a query using with()
$query = Employee::find()->with(['company']);
$dataProvider = new ActiveDataProvider([
'query' => $query,
'pagination' => false,
'sort' => false,
]);
if (!($this->load($params) && $this->validate())) {
return $dataProvider;
}
//when query contain with() then this filter is not working.
$query->andFilterWhere(['like', 'company.name', $this->company_id]);
This gives error when I use with()
Database Exception – yii\db\Exception
SQLSTATE[42S22]: Column not found: 1054 Unknown column 'company.name' in 'where clause'
The SQL being executed was: SELECT COUNT(*) FROM `employee` WHERE `company`.`name` LIKE '%1%'
Here is the relation in employee with company:
public function getCompany(){
return $this->hasOne(Company::className(), ['id'=> 'company_id']);
}
Can anyone help me or guide me how could I filter data properly using with() in a query?
Thanks.
You can't swap joinWith() and with() methods when you need to filter by the column from the related table. That's because these methods does completely different things.
Methods like joinWith() and join() actually modifies the query to add the "JOIN" part to the SQL query. The with in joinWith allows you to specify the joined table by the relation definition in the model. The eager loading in joinWith is only side effect and you can even turn that off by passing false as second parameter.
When you do:
Employee::find()->joinWith(['company'])->all();
The query that is run looks like:
SELECT * FROM employee LEFT JOIN company ON (...)
On the other side the method with() doesn't modify the query itself. It only forces the eager loading of related models. In reality the second query is used for preloading the related records.
When you do:
Employee::find()->with(['company'])->all();
It actually runs queries like these:
SELECT * FROM employee;
SELECT * FROM company WHERE id IN (...company ids selected in first query...);
So when you try to do:
$query = Employee::find()
->with(['company'])
->andFilterWhere(['like', 'company.name', $this->company_id])
->all();
The generated query is
SELECT * FROM employee WHERE company.name LIKE ...
How can I do this SQL in Query builder laravel
select Doctor_id from doctors where Doctor_id NOT IN
(SELECT Doctor_id from report_reviewers WHERE Report_id = 26 )
Try with this
$result = DB::table('doctors')
->whereNotIn('doctor_id', function($q){
$q->from('report_reviewers')
->select('Doctor_id')
->where('Report_id', '=', 26)
})
->select('doctor_id')
->get();
Whenver in doubt, if you know the raw SQL, you can simply do
$query = 'select Doctor_id from doctors ...';
$result = DB::select($query);
Also, all credit goes to this genius How to create a subquery using Laravel Eloquent?
Update
The missing argument comes from the closure you are using
->whereNotIn('doctor_id', function($q,$id){
$q->from('report_reviewers')
->select('Doctor_id')
->where('Report_id',$id);
})
You need to pass the $id variable like this
->whereNotIn('doctor_id', function($q) use ($id) {
$q->from('report_reviewers')
->select('Doctor_id')
->where('Report_id',$id);
})
Try again and see.
I'd like to get value by the following SQL using Eloquent ORM.
- SQL
SELECT COUNT(*) FROM
(SELECT * FROM abc GROUP BY col1) AS a;
Then I considered the following.
- Code
$sql = Abc::from('abc AS a')->groupBy('col1')->toSql();
$num = Abc::from(\DB::raw($sql))->count();
print $num;
I'm looking for a better solution.
Please tell me simplest solution.
In addition to #delmadord's answer and your comments:
Currently there is no method to create subquery in FROM clause, so you need to manually use raw statement, then, if necessary, you will merge all the bindings:
$sub = Abc::where(..)->groupBy(..); // Eloquent Builder instance
$count = DB::table( DB::raw("({$sub->toSql()}) as sub") )
->mergeBindings($sub->getQuery()) // you need to get underlying Query Builder
->count();
Mind that you need to merge bindings in correct order. If you have other bound clauses, you must put them after mergeBindings:
$count = DB::table( DB::raw("({$sub->toSql()}) as sub") )
// ->where(..) wrong
->mergeBindings($sub->getQuery()) // you need to get underlying Query Builder
// ->where(..) correct
->count();
Laravel v5.6.12 (2018-03-14) added fromSub() and fromRaw() methods to query builder (#23476).
The accepted answer is correct but can be simplified into:
DB::query()->fromSub(function ($query) {
$query->from('abc')->groupBy('col1');
}, 'a')->count();
The above snippet produces the following SQL:
select count(*) as aggregate from (select * from `abc` group by `col1`) as `a`
The solution of #JarekTkaczyk it is exactly what I was looking for. The only thing I miss is how to do it when you are using
DB::table() queries. In this case, this is how I do it:
$other = DB::table( DB::raw("({$sub->toSql()}) as sub") )->select(
'something',
DB::raw('sum( qty ) as qty'),
'foo',
'bar'
);
$other->mergeBindings( $sub );
$other->groupBy('something');
$other->groupBy('foo');
$other->groupBy('bar');
print $other->toSql();
$other->get();
Special atention how to make the mergeBindings without using the getQuery() method
From laravel 5.5 there is a dedicated method for subqueries and you can use it like this:
Abc::selectSub(function($q) {
$q->select('*')->groupBy('col1');
}, 'a')->count('a.*');
or
Abc::selectSub(Abc::select('*')->groupBy('col1'), 'a')->count('a.*');
There are many readable ways to do these kinds of queries at the moment (Laravel 8).
// option 1: DB::table(Closure, alias) for subquery
$count = DB::table(function ($sub) {
$sub->from('abc')
->groupBy('col1');
}, 'a')
->count();
// option 2: DB::table(Builder, alias) for subquery
$sub = DB::table('abc')->groupBy('col1');
$count = DB::table($sub, 'a')->count();
// option 3: DB::query()->from(Closure, alias)
$count = DB::query()
->from(function ($sub) {
$sub->from('abc')
->groupBy('col1')
}, 'a')
->count();
// option 4: DB::query()->from(Builder, alias)
$sub = DB::table('abc')->groupBy('col1');
$count = DB::query()->from($sub, 'a')->count();
For such small subqueries, you could even try fitting them in a single line with PHP 7.4's short closures but this approach can be harder to mantain.
$count = DB::table(fn($sub) => $sub->from('abc')->groupBy('col1'), 'a')->count();
Note that I'm using count() instead of explicitly writing the count(*) statement and using get() or first() for the results (which you can easily do by replacing count() with selectRaw(count(*))->first()).
The reason for this is simple: It returns the number instead of an object with an awkwardly named property (count(*) unless you used an alias in the query)
Which looks better?
// using count() in the builder
echo $count;
// using selectRaw('count(*)')->first() in the builder
echo $count->{'count(*)'};
Correct way described in this answer: https://stackoverflow.com/a/52772444/2519714
Most popular answer at current moment is not totally correct.
This way https://stackoverflow.com/a/24838367/2519714 is not correct in some cases like: sub select has where bindings, then joining table to sub select, then other wheres added to all query. For example query:
select * from (select * from t1 where col1 = ?) join t2 on col1 = col2 and col3 = ? where t2.col4 = ?
To make this query you will write code like:
$subQuery = DB::query()->from('t1')->where('t1.col1', 'val1');
$query = DB::query()->from(DB::raw('('. $subQuery->toSql() . ') AS subquery'))
->mergeBindings($subQuery->getBindings());
$query->join('t2', function(JoinClause $join) {
$join->on('subquery.col1', 't2.col2');
$join->where('t2.col3', 'val3');
})->where('t2.col4', 'val4');
During executing this query, his method $query->getBindings() will return bindings in incorrect order like ['val3', 'val1', 'val4'] in this case instead correct ['val1', 'val3', 'val4'] for raw sql described above.
One more time correct way to do this:
$subQuery = DB::query()->from('t1')->where('t1.col1', 'val1');
$query = DB::query()->fromSub($subQuery, 'subquery');
$query->join('t2', function(JoinClause $join) {
$join->on('subquery.col1', 't2.col2');
$join->where('t2.col3', 'val3');
})->where('t2.col4', 'val4');
Also bindings will be automatically and correctly merged to new query.
I like doing something like this:
Message::select('*')
->from(DB::raw("( SELECT * FROM `messages`
WHERE `to_id` = ".Auth::id()." AND `isseen` = 0
GROUP BY `from_id` asc) as `sub`"))
->count();
It's not very elegant, but it's simple.
This works fine
$q1 = DB::table('tableA')->groupBy('col');
$data = DB::table(DB::raw("({$q1->toSql()}) as sub"))->mergeBindings($q1)->get();
I could not made your code to do the desired query, the AS is an alias only for the table abc, not for the derived table.
Laravel Query Builder does not implicitly support derived table aliases, DB::raw is most likely needed for this.
The most straight solution I could came up with is almost identical to yours, however produces the query as you asked for:
$sql = Abc::groupBy('col1')->toSql();
$count = DB::table(DB::raw("($sql) AS a"))->count();
The produced query is
select count(*) as aggregate from (select * from `abc` group by `col1`) AS a;
->selectRaw('your subquery as somefield')
Deriving off mpskovvang's answer, here is what it would look like using eloquent model. (I tried updating mpskovvang answer to include this, but there's too many edit requests for it.)
$qry = Abc::where('col2', 'value')->groupBy('col1')->selectRaw('1');
$num = Abc::from($qry, 'q1')->count();
print $num;
Produces...
SELECT COUNT(*) as aggregate FROM (SELECT 1 FROM Abc WHERE col2='value' GROUP BY col1) as q1
I'm trying to create a dynamic dropdown from my database. i noticed when i query using Yii my it doesn't return an array in this format array(1=>1, 2=>2...) which i need for my CHtml::dropDownList()
so i added a for loop to do so. is this correct or following the framework standards? or am i missing something? sorry pretty new to yii
in my model
public function cDropdown()
{
$sql = "SELECT DISTINCT `code`, `name`
FROM `AB`
GROUP BY `code`
ORDER BY `name` ASC";
$query = Yii::app()->db->createCommand($sql)->queryAll();
$arr = array();
foreach($query AS $name=>$value)
$arr[$value['code']] = $value['name'];
return $arr;
}
You can do it in a very much simpler way by using like this: $form->dropDownList($model, 'attribute', CHtml::listData(ModelName::model()->findAll(), 'id', 'name'));
The id and the name, should be replaced by the fields you want in the dropdown. The id will be the value, and the name will be displayed.
You can also change the findAll() and use another method you want.
Okay? Good luck
I have a grid with paging which displays client data.
Let's say I have a table Client with name, lastName and address in it, a table Phone_Number which has phone numbers for each of the rows in Client and a table Adress which has adresses for each client. So each Client HAS MANY Phone_Numbers and HAS MANY Adresses.
The point is I'm trying to set a limit to the grid's store read.
So let's say I set limit = 2. The grid should display only 2 rows per page (2 clients).
The problem is that if, for example, client1 has two phone numbers, the query will bring two rows, making the grid display only one client. I am aware that setting together=>false in the query will solve this. But I'm getting an unknown column error whenever I set together=>false.
Here's the code I'm using....
Client::model()->with(
'clientPhoneNumbers',
'clientPhoneNumbers'.'PhoneNumber',
'clientAddresses',
'clientAddresses'.'Address'
)->findAll(array(condition=>(('Address.s_street_name LIKE :queryString') OR ('PhoneNumber.n_number LIKE :queryString')), params=>$params, order=>$order, limit=>$limit,together=>false));
If I do this, I get an error like: Column not found: Address.s_street_name . However, if I set together=>true, it works just "fine".
I found a solution to this problem by doing the query like this....
$with = array(
'clientPhoneNumbers',
'clientPhoneNumbers'.'PhoneNumber'=>array(condition=>('PhoneNumber.n_number LIKE :queryString'), params=>array(':queryString'=>$queryString)),
'clientAddresses',
'clientAddresses'.'Address'=>array(condition=>('Address.s_street_name LIKE :queryString'), params=>array(':queryString'=>$queryString))
);
Client::model()->findAll(array(with=>$with, order=>$order, limit=>$limit,together=>false));
The problem is that if I do it like this, the condition is something like this
(('Address.s_street_name LIKE :queryString') AND ('PhoneNumber.n_number LIKE :queryString'))
and I need it to be like this
(('Address.s_street_name LIKE :queryString') OR ('PhoneNumber.n_number LIKE :queryString')).
Any ideas ?
Keep in mind that the names of the relations and tables are not the actual names. The models and relations where created using Gii
Hmm.. this is how I would try it.
<?php
$criteria=new CDbCriteria;
$criteria->with = array('clientPhoneNumbers', 'clientAddresses');
$criteria->together = true;
$criteria->addCondition(array('Address.s_street_name LIKE :queryString', 'PhoneNumber.n_number LIKE :queryString'), 'OR');
$criteria->params = array(':queryString' => $queryString);
$criteria->limit = $limit;
$criteria->order = $order;
$result = Client::model()->findAll($criteria);
?>
Also, I think this describes a case similar to yours. Note that he/she is updating the condition parameter explicitly, but IMO doing it with the addCondition method is more readable.
use criteria with join statement.
public function test()
{
$criteria=new CDbCriteria;
$criteria->alias = 'i';
$criteria->compare('id',$this->id);
.........
.........
$criteria->join= 'JOIN phoneNUmbers d ON (i.id=d.id)';
return new CActiveDataProvider($this, array(
'criteria'=>$criteria,
'sort'=>array(
'defaultOrder'=>'clients ASC',
),
));
}
Alternately use DAO to prepare and execute your own query and return data in the format you wish.
Or you can use CSQLDataProvier. the last 2 options give you more control over the SQL statement