Hello I want merge two tables in oracle like below -
I tried below answer from stack overflow but not getting answer like Output table
Combining Two Tables With Oracle SQL
Please try with below query:
select * from (
select id, name, rate,total from table1
union all
select id, name, rate,total from table2
) as t
order by t.id asc
use union all
select id, name, rate,total from table1
union all
select id, name, rate,total from table2
Related
I have a 'unique' column, 'GID_New' that is in multiple tables. Is there a way to check if it's unique across all the tables in the QGIS project in SQL?
Can it be done in one SQL search without merging the tables into one and then running something like
SELECT A.GID_New, count(*), A.TableName
FROM "Water_Merged" as A
Group by A.GID_New
And then checking for a count >1
I would like to know which table the non-unique GID_New's are from as well.
The data is in a geopackage in QGIS so the code needs to work in QGIS SQL implementation.
You can use union all:
select gid_new, count(*) no_matches
from (
select gid_new from table1
union all select gid_new from table2
union all select gid_new from table3
) t
group by gid
having count(*) > 1
If you want to know in which table duplicates exists, then one option is string concatenation. Assuming that your database uses string_agg(), that would look like:
select gid_new, count(*) no_matches, string_agg(which, ',') which_tables
from (
select 'table1' which, gid_new from table1
union all select 'table2', gid_new from table2
union all select 'table3', gid_new from table3
) t
group by gid
having count(*) > 1
I want to select a third column based on two distant columns within the same table.
I could only think of this:
select tl.thirdcolumn
from table1 t1
WHERE
EXISTS
(
Select distinct tl.firstcolumn , t1.secondcolumn
From t1
)
This:
select distinct tl.thirdcolumn
from table t1
won't work as I don't want the distinct thirdrow. I want the thirdrow to be based on the first two rows being distinct.
I guess its a kind of nested sql statment with a select top 1... idk
CATEGORY NAME Query
---------------------------------------------------
STUDENTS NUMBER_OF_CHAPTERS QueryA
STUDENTS NUMBER_OF_STUDENT_MEMBERS QueryB
STUDENTS NUMBER_OF_STUDENT_MEMBERS QueryB
MEMBERS NUMBER_OF_MEMBERS_WORLDWIDE QueryC
MEMBERS NUMBER_OF_MEMBERS_WORLDWIDE QueryC
Your question is rather hard to follow, but I think you might simply want group by:
select tl.firstcolumn , t1.secondcolumn, max(tl.thirdcolumn)
from table1 t1
group by tl.firstcolumn , t1.secondcolumn;
If you want rows where the pair of values only appears once, then add having count(*) = 1:
select tl.firstcolumn , t1.secondcolumn, max(tl.thirdcolumn)
from table1 t1
group by tl.firstcolumn , t1.secondcolumn
having count(*) = 1;
Query -
SELECT
CATEGORY,NAME,QUERY
FROM
(
WITH TAB AS (
SELECT
'STUDENTS' AS CATEGORY,
'NUMBER_OF_CHAPTERS' AS NAME,
'QUERYA' AS QUERY
FROM
DUAL
UNION ALL
SELECT
'STUDENTS' AS CATEGORY,
'NUMBER_OF_STUDENT_MEMBERS' AS NAME,
'QUERYB' AS QUERY
FROM
DUAL
UNION ALL
SELECT
'STUDENTS' AS CATEGORY,
'NUMBER_OF_STUDENT_MEMBERS' AS NAME,
'QUERYB' AS QUERY
FROM
DUAL
UNION ALL
SELECT
'MEMBERS' AS CATEGORY,
'NUMBER_OF_MEMBERS_WORLDWIDE' AS NAME,
'QUERYC' AS QUERY
FROM
DUAL
UNION ALL
SELECT
'MEMBERS' AS CATEGORY,
'NUMBER_OF_MEMBERS_WORLDWIDE' AS NAME,
'QUERYC' AS QUERY
FROM
DUAL
) SELECT
CATEGORY,
NAME,
QUERY,
COUNT(*) OVER(PARTITION BY
CATEGORY,
NAME
ORDER BY
CATEGORY,
NAME,
QUERY
) AS RNK
FROM
TAB
)
WHERE
RNK = 1;
Output -
"CATEGORY","NAME","QUERY"
"STUDENTS","NUMBER_OF_CHAPTERS","QueryA"
This is the query which I am using to get the distinct values:
SELECT DISTINCT
LOGIN_BY,
RECEIVED_BY
FROM SAMPLE
My requirement is I need the distinct values of both the columns as a single output. Is there any way to do that?
try this
(SELECT DISTINCT LOGIN_BY as ID from sample )
union all
(Select Distinct RECEIVED_BY as ID FROM SAMPLE)
Try it like this:
select distinct a from (
select
distinct LOGIN_BY as a
from
SAMPLE
union
select
distinct RECEIVED_BY as a
from
SAMPLE
);
This works for me on an Oracle database.
I have two table containing some information as below
ENRNO, PROGRAM, NAME, ADDRESS, AGE
I want to find data referencing ENRNO which is containing from one of the given table but I don't know which table have the information.
Please suggest.
Malay Barik
If ENRNO is unique in tables u may try use UNION
select * from t1
where ENRNO ='ENRNO1'
UNION select * from t2
where ENRNO ='ENRNO1'
else use DISTINCT and subquery
select DISTINCT * from (
select * from t1
where ENRNO ='ENRNO1'
UNION select * from t2
where ENRNO ='ENRNO1')
But goodest way for solving this is redesign(normalize) you DB.
I need to return the unique records between two tables. Ideally, an UNION would solve my problem but both tables contain an object field which gives me an error(cannot ORDER objects without MAP or ORDER method) when I do UNION/distinct.
So, I was wondering if I can do a UNION ALL(to avoid the error) to get all the records first then do something to return only the unique records from there. I tried analytic function combined with the UNION ALL query but no luck so far.
Select * from Table1
union all
Select * from table2
Any help? Note:I need to return all fields.
I actually solved the problem using analytic function+row_num. The query will choose the first record for each set of duplicates hence returning only the unique records.
select * from
(
select ua.*,row_number() over (partition by p_id order by p_id ) row_num from
(
select * from table1
union all
select * from table2
)ua
) inner
where inner.row_num=1
How about this :
SELECT DISTINCT A.* FROM
(
Select * from Table1
union all
Select * from table2
) A;
(or)
SELECT col1,col2,col3...coln FROM
(
Select col1,col2,col3...coln from Table1
union all
Select col1,col2,col3...coln from table2
) A
GROUP BY A.col1,col2,col3...coln;
UNION ALL will give duplicate values as well .. instead use UNION and see if you are facing the error