I have two tables where main table has 10+ columns and second table has 3 columns with one common field. My problem here is I am not able to get exact count with left outer join as main table. I am seeing more count than actual. It might be due to one of the field I am trying to get is not in main table which is in second table.
Table 1: master_table
Table 2: manager_table
Master_table :
ID,
Column1,
Column2,
...
Column10
manager_table:
ID,
Column2_different,
Column3_different
I am trying to join using Left Join to get same records as present in master table.
Select table1.columns, table2.columns
From table1
Left join table2 on table1.ID = table2.ID
The above is not giving me exact record count as in master table (table1) , it is giving me more count as the table 2 other field is not present in table 1 .
Can someone help me here ?
TIA
I believe that an INNER JOIN would be better than a LEFT JOIN. Need some sample data to be sure, but if you're getting a higher count than you'd expect upon joining the tables this is probably because the LEFT JOIN is returning everything from both tables. An INNER JOIN will only return data that appears in both tables.
I need to select all data from 2 tables in an sql database.
I searched the site and dried numerous ways but no sucess.
One table has no data but the other is full of it.
If i select each one individually i get good results, but if i use for instance:
select * from relatorio cross join temp
or
select * from relatorio r,temp t
or even:
select t.*, r.* from temp t inner join relatorio r on 1=1
The join works, but none of them shows data.
Can anyone help?
Thanks in advance.
All three select statements in the questions are cross joins.
A cross joins returns data only if both tables have at least one row.
It returns a cartesian product of both tables, meaning that every row in one table will be joined to every row in the other table.
One table has no data but the other is full of it.
Since one of your tables is empty, it will return no results at all. You can think about it as multipling by 0.
Now you have two options: one is to use a full join and the other one is to use left join, in this case both will return the same results, since one table is empty:
select *
from relatorio
left join temp on <join condition> -- assuming temp is the empty table
or
select *
from relatorio
full join temp on <join condition> -- in this case, it doesn't matter what table is empty
If you want to return all matched and umatched rows, use Full Outer Join.The FULL OUTER JOIN keyword returns all rows from the left table (table1) and from the right table (table2).
The FULL OUTER JOIN keyword combines the result of both LEFT and RIGHT joins.
In SQL the FULL OUTER JOIN combines the results of both left and right outer joins and returns all (matched or unmatched) rows from the tables on both sides of the join clause.
SQL FULL OUTER JOIN Syntax:
SELECT column_name(s)
FROM table1
FULL OUTER JOIN table2
ON table1.column_name=table2.column_name;
The SQL CROSS JOIN produces a result set which is the number of rows in the first table multiplied by the number of rows in the second table if no WHERE clause is used along with CROSS JOIN. This kind of result is called as Cartesian Product.
If WHERE clause is used with CROSS JOIN, it functions like an INNER JOIN.
An alternative way of achieving the same result is to use column names separated by commas after SELECT and mentioning the table names involved, after a FROM clause.
CROSS JOIN SYNTAX
SELECT *
FROM table1
CROSS JOIN table2;
I would like to return table entries from an inner join which do not have any matching entries in the second column.
Lets consider the following two tables:
Table one:
Name Number
A 1
A 2
A 4
Table two:
Name ID
A 3
The query should return Name=A ID=3. If ID would be 4, the query should not return anything. Is this even possible in SQL? Thanks for any hints!
Edit:
the joined table would look like this:
Name Number ID
A 1 3
A 2 3
A 4 3
So if I do this query I get no entries in the result set:
SELECT * FROM TABLE_ONE INNER JOIN TABLE_TWO ON TABLE_ONE.NAME=TABLE_TWO.NAME WHERE NUMBER=ID
Exactly in this situation I would like to get the Name returned!
Yes, instead of using an INNER join, use a LEFT or a FULL OUTER join. This will allow null values from the other table to appear when you have a value in one of your tables.
The FULL OUTER JOIN keyword returns all rows from the left table (table1) and from the right table (table2).
The LEFT JOIN keyword returns all rows from the left table (table1), with the matching rows in the right table (table2). The result is NULL in the right side when there is no match. (There is also a RIGHT join, but it does the same thing as the left join, just returning all rows from the RIGHT table instead of the left).
SELECT *
FROM Table2
WHERE NOT EXISTS (
SELECT *
FROM Table1
WHERE Table1.Name = Table2.Name AND Table1.Number = Table2.ID
)
As #rhealitycheck has said, a full outer join would work. I found this blog post helpful in explaining joins. P.S. I can't leave comments (Otherwise I would have).
I have one table that contains lots of data and I want to select everything from this one.
Another table contains different statuscodes ( fields ID and text ), and I want to join this table into the first one so i get something like
All data from first table id1,text2,id2,text2 or id1,id2,text1,text2 from the second table.
USe LEFT OUTER JOIN
Select T1.*,T2.ID,T2.Text
from firstTable t1
LEFT OUTER JOIN SecondTable T2
on T1.<col>=T2.<col>
You can use join like this whether it may be left/right/inner join
SELECT t1.*,t2.id,t2.text
FROM table1 t1
LEFT JOIN table2 t2
ON t2.column_name=t1.column_name
I have a very basic LEFT OUTER JOIN to return all results from the left table and some additional information from a much bigger table. The left table contains 4935 records yet when I LEFT OUTER JOIN it to an additional table the record count is significantly larger.
As far as I'm aware it is absolute gospel that a LEFT OUTER JOIN will return all records from the left table with matched records from the right table and null values for any rows which cannot be matched, as such it's my understanding that it should be impossible to return more rows than exist in the left table, but it's happening all the same!
SQL Query follows:
SELECT SUSP.Susp_Visits.SuspReason, SUSP.Susp_Visits.SiteID
FROM SUSP.Susp_Visits LEFT OUTER JOIN
DATA.Dim_Member ON SUSP.Susp_Visits.MemID = DATA.Dim_Member.MembershipNum
Perhaps I have made a mistake in the syntax or my understanding of LEFT OUTER JOIN is incomplete, hopefully someone can explain how this could be occurring?
The LEFT OUTER JOIN will return all records from the LEFT table joined with the RIGHT table where possible.
If there are matches though, it will still return all rows that match, therefore, one row in LEFT that matches two rows in RIGHT will return as two ROWS, just like an INNER JOIN.
EDIT:
In response to your edit, I've just had a further look at your query and it looks like you are only returning data from the LEFT table. Therefore, if you only want data from the LEFT table, and you only want one row returned for each row in the LEFT table, then you have no need to perform a JOIN at all and can just do a SELECT directly from the LEFT table.
Table1 Table2
_______ _________
1 2
2 2
3 5
4 6
SELECT Table1.Id,
Table2.Id
FROM Table1
LEFT OUTER JOIN Table2 ON Table1.Id=Table2.Id
Results:
1,null
2,2
2,2
3,null
4,null
It isn't impossible. The number of records in the left table is the minimum number of records it will return. If the right table has two records that match to one record in the left table, it will return two records.
In response to your postscript, that depends on what you would like.
You are getting (possible) multiple rows for each row in your left table because there are multiple matches for the join condition. If you want your total results to have the same number of rows as there is in the left part of the query you need to make sure your join conditions cause a 1-to-1 match.
Alternatively, depending on what you actually want you can use aggregate functions (if for example you just want a string from the right part you could generate a column that is a comma delimited string of the right side results for that left row.
If you are only looking at 1 or 2 columns from the outer join you might consider using a scalar subquery since you will be guaranteed 1 result.
Each record from the left table will be returned as many times as there are matching records on the right table -- at least 1, but could easily be more than 1.
Could it be a one to many relationship between the left and right tables?
LEFT OUTER JOIN just like INNER JOIN (normal join) will return as many results for each row in left table as many matches it finds in the right table. Hence you can have a lot of results - up to N x M, where N is number of rows in left table and M is number of rows in right table.
It's the minimum number of results is always guaranteed in LEFT OUTER JOIN to be at least N.
If you need just any one row from the right side
SELECT SuspReason, SiteID FROM(
SELECT SUSP.Susp_Visits.SuspReason, SUSP.Susp_Visits.SiteID, ROW_NUMBER()
OVER(PARTITION BY SUSP.Susp_Visits.SiteID) AS rn
FROM SUSP.Susp_Visits
LEFT OUTER JOIN DATA.Dim_Member ON SUSP.Susp_Visits.MemID = DATA.Dim_Member.MembershipNum
) AS t
WHERE rn=1
or just
SELECT SUSP.Susp_Visits.SuspReason, SUSP.Susp_Visits.SiteID
FROM SUSP.Susp_Visits WHERE EXISTS(
SELECT DATA.Dim_Member WHERE SUSP.Susp_Visits.MemID = DATA.Dim_Member.MembershipNum
)
Pay attention if you have a where clause on the "right side' table of a query containing a left outer join...
In case you have no record on the right side satisfying the where clause, then the corresponding record of the 'left side' table will not appear in the result of your query....
It seems as though there are multiple rows in the DATA.Dim_Member table per SUSP.Susp_Visits row.
if multiple (x) rows in Dim_Member are associated with a single row in Susp_Visits, there will be x rows in the resul set.
Since the left table contains 4935 records, I suspect you want your results to return 4935 records. Try this:
create table table1
(siteID int,
SuspReason int)
create table table2
(siteID int,
SuspReason int)
insert into table1(siteID, SuspReason) values
(1, 678),
(1, 186),
(1, 723)
insert into table2(siteID, SuspReason) values
(1, 678),
(1, 965)
select distinct t1.siteID, t1.SuspReason
from table1 t1 left join table2 t2 on t1.siteID = t2.siteID and t1.SuspReason = t2.SuspReason
union
select distinct t2.siteID, t2.SuspReason
from table1 t1 right join table2 t2 on t1.siteID = t2.siteID and t1.SuspReason = t2.SuspReason
The only way your query would return more number of rows than the left table ( which is SUSP.Susp_Visits in your case), is that the condition (SUSP.Susp_Visits.MemID = DATA.Dim_Member.MembershipNum) is matching multiple rows in the right table, which is DATA.Dim_Member. So, there are multiple rows in the DATA.Dim_Member where identical values are present for DATA.Dim_Member.MembershipNum. You can verify this by executing the below query:
select DATA.Dim_Member.MembershipNum, count(DATA.Dim_Member.MembershipNum) from DATA.Dim_Member group by DATA.Dim_Member.MembershipNum
Simply, LEFT OUTER JOIN is the Cartesian product within each join key, along with the unmatched rows of the left table
(i.e. for each key_x that has N records in table_L and M records in table_R the result will have N*M records if M>0, or N records if M=0)