select from parent table having condition in child table - sql

I have parent table as
pID Name
1 AAA
2 BBB
3 CCC
and a child table as
cID pID Name
1 1 XXX
2 1 YYY
3 2 XXX
4 2 YYY
5 2 ZZZ
6 3 YYY
7 3 ZZZ
now i need to select the parent rows that have at least 2 child rows one of them have the value YYY and the other ZZZ, which should be pID 2 & 3.
is this possible?
thanks in advance everyone

You can try the below -
select p.pid,p.name from c join p on p.pid=c.pid
where c.name in ('YYY','ZZZ')
group by p.pid,p.name
having count(distinct c.name)=2

Related

oracle sub query or union

I have a case table as follows:
caseId
caseType
last_name
first_Name
aCaseStatus
bCaseStatus
created_by
1
P
test
a
0
0
1
2
M
test1
b
1
2
2
3
M
test2
c
1
3
1
aCaseStatus
id
descr
1
aaa
2
bbb
3
ccc
bCaseStatus
id
descr
1
xxx
2
yyy
3
zzz
I have a query like below
select c.case_id caseId, c.last_name lastName, c.first_name firstName,
caseType caseType,
acaseStatus||','||bCaseStatus as caseStatus
from cases c
join aCaseStatus acs
on acs.id = c.aCaseStatus
left outer join bCaseStatus bcs
on bcs.id = c.bCaseStatus
where (c.created_by = 1 ) and ( c.aCaseStatus in (1) or c.bCaseStatus in (0)) and c.caseType='M'
UI has a display like below
caseId
Name
caseStatus
2
b,test1
aaa, yyy
3
c,test2
aaa, zzz
When you look at the UI display caseStatus is a combination of aCaseStatus, bCaseStatus.
Also, the UI table has a search functionality wherein caseStatus is a multi-select dropdown field.
This dropdown has a combination of aCaseStatus and bCaseStatus.
Dropdown is as below:
CaseStatus
aaa
bbb
ccc
xxx
yyy
zzz
Note: aCaseStatus alone is a mandatory field so I have given an inner join, however, bCaseStatus is not so I have given a left outer join.
When the user selects aaa, UI should display:
caseId
Name
caseStatus
2
b,test1
aaa
3
c,test2
aaa
when the user selects aaa, xxx UI should display:
caseId
Name
caseStatus
2
b,test1
aaa, xxx
3
c,test2
aaa
But when I use the above query for aaa selection I get:
caseId
Name
caseStatus
2
b,test1
aaa, xxx
3
c,test2
aaa
I do not want the xxx to be displayed even though caseId has xxx caseStatus. How should I change the query to achieve this? Should I write a union query one for aCaseStatus and the other for bCaseStatus or is there any other way this can be achieved?
Suggestions, please?

identify NULL and update for same key column in oracle

I have a test table having below details:
ID Key_COLUMN final_Value
1 aaa 1234
2 bbb 2345
3 bbb NULL
4 ccc 456
5 ccc 145
Desired Output:
--final_value updated from NULL to 2345 based key_column (bbb)
ID Key_COLUMN final_Value
1 aaa 1234
2 bbb 2345
3 bbb 2345
4 ccc 456
5 ccc 145
Identify KEY column having NULL and value and update NULL with the value.
this update requied on huge amount of data
Please assist.
You can use window functions:
select t.*,
coalesce(final_value, max(final_value) over (partition by key_column)) as imputed_final_value
from t;
If you wanted an update -- to actually change the data -- you can use a correlated subquery:
update t
set final_value = (select t2.final_value
from t t2
where t2.key_column = t.key_column and
t2.final_value is not null and
rownum = 1
)
where final_value is null;

Select rows with specific multiple values from the same column?

I have database where 2 roles can't be associated with each other, and I need to display any users who have conflicting roles.
For example: an (id 2) accountant can't also be a (id 5) trainer
this has to be done without using CTE's
Table a Table b table c
--------------- ------------------- ------------
userID | roleID roleID | conflictID roleID | Role Name
1 2 2 5 1 chef
1 3 2 accountant
1 5 3 driver
2 3 4 barmaid
2 1 5 trainer
3 2
3 3
the result should contain only the userID who has both roles 2 and 5
userID
------
1
Join the b table with the a table twice, to get userID's with conflicting combinations:
select distinct a1.userid
from tableb b
join tablea a1 on b.roleID = a1.roleID
join tablea a2 on b.conflictID = a2.roleID
and a1.userID = a2.userID

I don't have the right answer in SQL

List the project numbers (PR_NO) for projects that have only received parts that are stored in (P_CITY) the same city as the project (show output of the query).
Table: EMP
Primary Key: E_NO
E_NO E_NAME E_RATE E_DEPT
1 A $400.00
2 B $200.00 1
3 C $150.00 2
4 D $150.00 3
5 E $120.00 1
6 F $100.00 1
7 G $100.00 2
8 H $50.00 2
9 I $50.00 3
10 J $50.00 3
11 K $150.00 3
Table: PART
Primary Key: P_NO
P_NO P_NAME P_CITY
1 P1 NY
2 P2 NY
3 P3 LA
4 P4 SF
5 P5 LA
6 P6 NY
Table: PROJECT
Primary Key: PR_NO
PR_NO PR_MGR PR_DEPT PR_LOC
1 2 1 NY
2 3 2 LA
3 2 1 NY
Table: SUPPLIER
Primary Key: S_NO
S_NO S_NAME S_LOC
1 S1 NY
2 S2 NY
3 S3 LA
Table: SUPPLY
Primary Key: P_NO + PR_NO + S_NO
Foreign Key: P_NO references PART
Foreign Key: PR_NO references PROJECT
Foreign Key: S_NO references SUPPLIER
P_NO PR_NO S_NO QTY
1 1 1 111
1 1 2 112
1 1 3 113
1 2 1 121
1 2 2 122
1 2 3 123
1 3 1 131
1 3 2 132
1 3 3 133
2 1 1 211
3 1 1 311
4 1 1 411
5 1 1 511
6 1 1 611
Table: WORK
Primary Key: E_NO + PR_NO
Foreign Key: E_NO references EMP
Foreign Key: PR_NO references PROJECT
E_NO PR_NO HRS
2 1 10
3 2 20
5 1 20
5 2 20
5 3 20
6 1 10
6 2 10
select distinct P.PR_NO
from PROJECT P, PART PA
where PA.P_CITY = P.PR_LOC;
The right answer question should be :
PR_NO
3
This is the error:
PR_NO
1
3
2
In order to achieve this task, you also need to use Supply table as follows:
select s.pr_no
from supply s
inner join part p
on p.p_no = s.p_no
group by s.pr_no
having max(p.p_city) = min(p.p_city)
and min(p.p_city) = (select pr_loc
from project
where pr_no = s.pr_no
)
I tested this query with your example data and it returns project #3 as expected:
SELECT DISTINCT S.PR_NO
FROM
SUPPLY S
INNER JOIN PROJECT PR
ON S.PR_NO = PR.PR_NO
INNER JOIN PART P
ON S.P_NO = P.P_NO
WHERE
PR.PR_LOC = P.P_CITY AND
NOT S.PR_NO IN
(
SELECT S2.PR_NO
FROM
SUPPLY S2
INNER JOIN PROJECT PR2
ON S2.PR_NO = PR2.PR_NO
INNER JOIN PART P2
ON S2.P_NO = P2.P_NO
WHERE PR2.PR_LOC <> P2.P_CITY
)
The SUPPLY table creates the link between PART and PROJECT. The main query looks for parts that are stored in the same city as the project. The sub-select in the where clause looks almost the same, except that it looks for parts stored in a different city. Projects with such cities are excluded with NOT S.PR_NO IN (...).
The main issue in your query is that you should correctly join the 2 tables PROJECT and PART before filtering; so in this case you should use the table SUPPLY.
SELECT DISTINCT S.PR_NO
FROM SUPPLY S
INNER JOIN PROJECT PR
ON S.PR_NO = PR.PR_NO
INNER JOIN PART P
ON S.P_NO = P.P_NO
WHERE PR.PR_LOC = P.P_CITY
AND S.PR_NO NOT IN ( SELECT DISTINCT S.PR_NO
FROM SUPPLY S
INNER JOIN PROJECT PR
ON S.PR_NO = PR.PR_NO
INNER JOIN PART P
ON S.P_NO = P.P_NO
WHERE PR.PR_LOC <> P.P_CITY );
Hope this helps!

use group by clause and count() in subquery

Table : Class
class_id ClassName
----------------------
1 AAA
2 BBB
3 CCC
Table : Groups
id class_id GroupName
---------------------------
1 1 A1
2 1 A2
3 2 B1
4 3 C1
5 2 B2
6 1 A3
Expected Output :
class_id ClassName count(*)
-------------------------------
1 AAA 3
2 BBB 2
3 CCC 1
Use Inner Join to get result :
SELECT Class.class_id, Class.ClassName, COUNT(*) AS count
FROM Class INNER JOIN
Groups ON Class.class_id = Groups.class_id
GROUP BY Class.class_id, Class.ClassName