query all of the same id based on multiple true conditions - sql

Question

I have this table :
id act st_dt end_dt stats
1 a 01/01/20 05/01/20 done
1 b 04/01/20 09/02/20 done
1 c 09/02/20 null not done
1 d 09/02/20 09/02/20 done
2 a 09/03/19 14/05/20 done
2 b 09/02/20 25/06/20 done
2 c 01/03/20 22/03/20 done
2 d 09/02/20 null not done
3 a 11/05/20 13/09/19 done
3 b 09/02/20 04/07/20 done
3 c 01/02/20 30/02/20 done
3 d 11/02/20 24/02/20 done
I want to query all activities 'act' of the same ID having activity a >= 01/01/20 and activity d status is done,
so the result should look like this:
id act st_dt end_dt stats
1 a 01/01/20 05/01/20 done
1 b 04/01/20 09/02/20 done
1 c 09/02/20 null not done
1 d 09/02/20 09/02/20 done
the two conditions are met for this id, i did this :
select * from
(
select
a.* ,
case when (act = 'a' and end_dt > to_date('01/01/20','dd/mm/yy')) and (act = 'd' and status = 'done') then 1 end) flag
from
table a
)
where flag = 1;
but it won't do the required,it'll query only activity 'a' and 'd'

Answer 1

You can use exists:
select a.*
from a
where exists (select 1
from a a2
where a2.id = a.id and a2.act = 'a' and a2.st_dt <= date '2020-01-01'
) and
exists (select 1
from a a2
where a2.id = a.id and a2.act = 'd' and a2.stats = 'done'
) ;

Answer 2

If you like to learn something new:
Creation of your table:
create table tab as
with t (id,act, start_date, end_date, status) as
(
select 1,'a',to_date('01/01/2020','dd/mm/yyyy'), to_date('05/01/2020','dd/mm/yyyy'), 'done' from dual union all
select 1,'b',to_date('04/01/2020','dd/mm/yyyy'), to_date('09/02/2020','dd/mm/yyyy'), 'done' from dual union all
select 1,'c',to_date('09/02/2020','dd/mm/yyyy'), null , 'not done' from dual union all
select 1,'d',to_date('09/02/2020','dd/mm/yyyy'), to_date('09/02/2020','dd/mm/yyyy'), 'done' from dual union all
select 2,'a',to_date('09/03/2019','dd/mm/yyyy'), to_date('14/05/2020','dd/mm/yyyy'), 'done' from dual union all
select 2,'b',to_date('09/02/2020','dd/mm/yyyy'), to_date('25/06/2020','dd/mm/yyyy'), 'done' from dual union all
select 2,'c',to_date('01/03/2020','dd/mm/yyyy'), to_date('22/03/2020','dd/mm/yyyy'), 'done' from dual union all
select 2,'d',to_date('09/02/2020','dd/mm/yyyy'), null , 'not done' from dual union all
select 3,'a',to_date('11/05/2020','dd/mm/yyyy'), to_date('13/09/2019','dd/mm/yyyy'), 'done' from dual union all
select 3,'b',to_date('09/02/2020','dd/mm/yyyy'), to_date('04/07/2020','dd/mm/yyyy'), 'done' from dual union all
select 3,'c',to_date('01/02/2020','dd/mm/yyyy'), to_date('29/02/2020','dd/mm/yyyy'), 'done' from dual union all --End_date is wrong in your input data I changed it to 29
select 3,'d',to_date('11/02/2020','dd/mm/yyyy'), to_date('24/02/2020','dd/mm/yyyy'), 'done' from dual
)
select * from t
Here is the solution that works on 12c and later
select * from tab
match_recognize
(
partition by id
order by start_date
all rows per match
pattern (a random_rows* d)
define a as act = 'a' and a.start_date >= date'2020-01-01',
d as act = 'd' and d.status = 'done'
);

Answer 3

One option would be using aggregated conditionals through an analytic function to determine whether both conditions are satisfied at the same time :
WITH a2 AS
(
SELECT a.*, SUM(CASE WHEN act = 'a' AND end_dt >= date'2020-01-01'
THEN 1
ELSE 0
END)
OVER(PARTITION BY id) *
SUM(CASE WHEN act = 'd' AND stats = 'done'
THEN 1
ELSE 0
END)
OVER(PARTITION BY id) AS satisfies
FROM a
)
SELECT id, act, st_dt, end_dt, stats
FROM a2
WHERE satisfies = 1
Demo

Answer 4

First get in two subqueries the ID of the well started and well done jobs.
INTERSECT the results to get jobs with both conditions and use this IDset in the IN predicate
Query
select *
from tab a
where id in (
select id
from tab a
where (act = 'a' and st_dt >= to_date('01/01/20','dd/mm/yy'))
INTERSECT
select id
from tab a
where (act = 'd' and stats = 'done')
)