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i search for this string abcdefgh in a very large file like this and i don't know at which position the new line begin. My first thought was to remove all \n, but the file is over 3 gb ... I think there is smart way to do this (sed, awk, ...?)
efhashivia
hjasjdjasd
oqkfoflABC
DEFGHqpclq
pasdpapsda
Assuming that your search string cannot expand into more than 2 lines, you can use this awk:
awk -v p="ABCDEFGH" 's $0 ~ p {print NR,s $0} {s=$0}' file
Or you can paste each line with its next one, and grep the result. This way you have to create a file with double size of your large input.
tail -n +2 file | paste -d '' file - > output.txt
> cat output.txt
efhashiviahjasjdjasd
hjasjdjasdoqkfoflABC
oqkfoflABCDEFGHqpclq
DEFGHqpclqpasdpapsda
pasdpapsda
> grep -n ABCDEFGH output.txt
3:oqkfoflABCDEFGHqpclq
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input.txt
hello
cruel
world
I want to print all the lines from the above file such that they have a beginning and ending string added along with a delimiter.
BEGIN='
END='
DELIMITER=|
Expected output:
'hello'|'cruel'|'world'
I would GNU AWK for this task following way, let file.txt content be
hello
cruel
world
then
awk '{printf "%s\047%s\047",(NR>1?"|":""),$0}' file.txt
gives output
'hello'|'cruel'|'world'
Explanation: I use printf with 2 places to fill (denoted to %s) and 2 ' (as they have special meaning we must not use just ' but escaped version, that is \047) and so-called ternany operator (condition?valueiftrue:valueiffalse) to use | for lines after first (NR>1) and empty string for all else to fill 1st place and content of whole line ($0) to fill 2nd place.
(tested in gawk 4.2.1)
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Remove all lines that don't contain a letter from the alphabet (upper or lower case)
Input :
34
76
0hjjAby68xp
H5e
895
Output :
0hjjAby68xp
H5e
With GNU grep:
grep '[[:alpha:]]' file
or GNU sed:
sed '/[[:alpha:]]/!d' file
Output:
0hjjAby68xp
H5e
Using awk:
$ awk '/[[:alpha:]]/' file
0hjjAby68xp
H5e
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I am trying to write a script to grep output from a range based on text, not line numbers.
For instance, in my text file, I want to grep the output starting with $hostname and capture everything in between $endText and then output the data in between those to a file named $hostname.txt.
Since you didn't provide any details, here is the boiler plate.
$ sed -n '/start/,/end/p' file > outputfile
or
$ awk '/start/,/end/' file > outputfile
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n=4;
echo "abcd" awk '{print substr($0,$n,1);}'
I want to get the substring by the usage of variable but I am not getting please help
$ n=4; echo "abcd" | awk -v n="$n" '{print substr($0,n,1);}'
d
Possibly, it is clearer to have two different variable names:
$ n=4; echo "abcd" | awk -v m="$n" '{print substr($0,m,1);}'
d
Here, n is a shell variable and m is an awk variable. The -v option is used to assign the awk variable m to have the value of the shell variable n.
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I have a file with the following format:
AACCCGTAGATCCGAACTTGTG
ACCCGTAGATCCGAACTTGTG
CCGTAGATCCGAACTTGTG
CGTAGATCCGAACTTGT
I want to give a header to each line, using awk, where the header is equal to the line that follows, like this:
>AACCCGTAGATCCGAACTTGTG
AACCCGTAGATCCGAACTTGTG
>ACCCGTAGATCCGAACTTGTG
ACCCGTAGATCCGAACTTGTG
>CCGTAGATCCGAACTTGTG
CCGTAGATCCGAACTTGTG
>CGTAGATCCGAACTTGT
CGTAGATCCGAACTTGT
Simply:
$ awk '{print ">"$0;print}' file
>AACCCGTAGATCCGAACTTGTG
AACCCGTAGATCCGAACTTGTG
>ACCCGTAGATCCGAACTTGTG
ACCCGTAGATCCGAACTTGTG
>CCGTAGATCCGAACTTGTG
CCGTAGATCCGAACTTGTG
>CGTAGATCCGAACTTGT
CGTAGATCCGAACTTGT
Or:
$ awk '{printf ">%s\n%s\n",$0,$0}' file
>AACCCGTAGATCCGAACTTGTG
AACCCGTAGATCCGAACTTGTG
>ACCCGTAGATCCGAACTTGTG
ACCCGTAGATCCGAACTTGTG
>CCGTAGATCCGAACTTGTG
CCGTAGATCCGAACTTGTG
>CGTAGATCCGAACTTGT
CGTAGATCCGAACTTGT
The -v flag allows you to set a variable. Then for each line in the file print that variable followed by the line, and then the line itself.
awk -v c=">" '{ print c $0; print $0; }' <file>