I am looking at different breeds of cattle and their AnimalTypeCode , BreedCateoryID and resultant Growth.
I have the following query
SELECT DATEPART(yyyy,[KillDate])
,[AnimalTypeCode]
,AVG([Growth])
,[BreedCategoryID]
FROM [dbo].[tblAnimal]
WHERE (AnimalTypeCode='C'
or AnimalTypeCode= 'E')
GROUP BY DATEPART(yyyy,[KillDate])
,[AnimalTypeCode]
,[BreedCategoryID]
GO
This query is good and gives me almost what I want, but BreedCategoryID is numbered 1 through 7 and I would like to group them:
(1 = Pure Dairy),
(2 and 3 = Dairy)
(4, 5, 6 and 7 = Beef)
So instead of getting the mean Growthrate for each BreedCategoryID I would like to get the average for Pure Dairy, Dairy, and Beef.
Any help greatly appreciated!
You can assign a new "variable" using cross apply in the from clause:
SELECT YEAR(KillDate]), a.AnimalTypeCode, v.grp,
AVG([Growth])
FROM [dbo].[tblAnimal] a CROSS APPLY
(VALUES (CASE WHEN a.BreedCategoryID IN (1) THEN 'Pure Dairy'
WHEN a.BreedCategoryID IN (2, 3) THEN 'Dairy'
WHEN a.BreedCategoryID IN (4, 5, 6, 7) THEN 'Beef'
END)
) as v(grp)
WHERE a.AnimalTypeCode IN ('C', 'E')
GROUP BY YEAR(KillDate]), a.AnimalTypeCode, v.grp;
Note that I also introduced table aliases and qualified all the column references.
Do the calculations in a derived table (the subquery). GROUP BY its result:
select killyear, [AnimalTypeCode], AVG([Growth]), BreedCat
(
SELECT DATEPART(yyyy,[KillDate]) killyear
,[AnimalTypeCode]
,[Growth]
,case when [BreedCategoryID] = 1 then 'Pure Dairy'
when [BreedCategoryID] in (2, 3) then 'Dairy'
when [BreedCategoryID] in (4, 5, 6, 7) then 'Beef'
end BreedCat
FROM [dbo].[tblAnimal]
WHERE (AnimalTypeCode='C'
or AnimalTypeCode= 'E')
) dt
GROUP BY killyear
,[AnimalTypeCode]
,BreedCat
Related
I need to write a stored procedure or table function to return a new data table as a new data source.
I wish to loop through the original table for every 5 rows base on the invoice ID column (it's possible not start from 1), the first 5 rows add to the left of the new table and the second 5 rows add to the right of the new table, the third 5 rows to the left and so on.
For example, Here is the original table:
Here is the expect table:
Thanks in advance!
declare #rowCount int = 5;
with cte as (
select *,( (IN_InvoiceID-1) / #rowCount ) % 2 group1
,( (IN_InvoiceID-1) / #rowCount ) group2
,IN_InvoiceID % #rowCount group3
from T
)
select * from cte
select T1.INID,T1.IN_InvoiceID,T1.IN_InvoiceAmount,T2.INID,T2.IN_InvoiceID,T2.IN_InvoiceAmount
from CTE T1
left join CTE T2 on T2.group1 = 1 and T1.group2 = T2.group2-1 and T1.group3 = T2.group3
where T1.group1 = 0
Test DDL
CREATE TABLE T
([INID] varchar(38), [IN_InvoiceID] int, [IN_InvoiceAmount] int)
;
INSERT INTO T
([INID], [IN_InvoiceID], [IN_InvoiceAmount])
VALUES
('DB3E17E6-35C5-41:121-93B1-F809BF6B2972', 1, 2999),
('3212F048-8213-4FCC-AB64-121485B77D4E43', 2, 3737),
('E3526373-A204-40F5-801C-7F8302A4E5E2', 3, 3175),
('76CC9C19-BF79-4E8A-8034-A33805AD3390', 4, 391),
('EC7A2FBC-B62D-4865-88DE-A8097975F125', 5, 1206),
('52AD3046-21331-4F0A-BD1D-67F232C54244', 6, 402),
('CA48F132-A9F5-4516-9E58-CDEE6644AAD1', 7, 1996),
('02E10C31-CAB2-4220-B66A-CEE5E67A9378', 8, 3906),
('98F1EEFF-B07A-4B65-87F4-E165264284DD', 9, 2575),
('91EBDD8B-B73C-470C-8900-DD66078483DB', 10, 2965),
('6E2490E5-C4DE-4833-877F-1590F7BDC1B8', 11, 1603),
('00985921-AC3C-4E3E-BAE1-7F58302F831A', 12, 1302)
;
Result:
Could you please check article Display Data in Multiple Columns using SQL showing with example case how a database developer can show the list of data rows in a columnar mode using Row_Number() function and mode arithmetic expression
You need to add additional columns from the same row that is different in the sample
Seems as if you want to split the table into 2 tables with alternating 5 rows. An easy way to do this would be:
Take data into a temp table having an extra column (lets say
grouping_id)
Update the grouping id so that each 5 rows have the same id. You can
use in_invoiceId % 5 (the nod function). After this step the first 5
rows will have grouping_id 0, next 5 will have 1, next will have 2
(assuming your invoice id is incremented +1 for all rows).
You can just do a normal select with where clause for odd and even grouping_id
Ideally, you can manage with the 2 tables Master and detail table.
But due to my curiosity, I am able to solve and give the answer as
Declare #table table(id int identity, invoice_id int)
; WITH Numbers AS
(
SELECT n = 1
UNION ALL
SELECT n + 1
FROM Numbers
WHERE n+1 <= 50
)
insert into #table SELECT n
FROM Numbers
Select (a.id )%5 ,* from #table a join #table b on a.id+5 = b.id and a.id != b.id
;WITH Numbers AS
(
SELECT n = 1, o = 5
UNION ALL
SELECT n + 10, o = o+10
FROM Numbers
WHERE n+1 <= 50
)
select a.id ParentId,a.invoice_id ParentInvoiceId, --b.n, b.o,
c.invoice_id childInvoiceID from #table a
join Numbers b on a.id between b.n and b.o
left join #table c on a.id + 5 = c.id
Here is my solution
First i create grps based on whether the in_invoiceid is divisible by 5 or not.(Ignore the remainders)
After that i create a category to indicate between alternative groups(ie by checking if the remainder is 0 or otherise)
Then its a matter of dense_ranking the records on the basis of the category field ordered by in_invoiceid
Lastly a join with category=1 rows with same dense_rank as those records in category=0
create table Invoicetable(IN_ID varchar(100), IN_InvoiceID int)
INSERT INTO Invoicetable (IN_ID, IN_InvoiceID)
VALUES
('2345-BCDE-6645-1DDF', 1),
('2345-BCDE-6645-3DDF', 2),
('2345-BCDE-6645-4DDF', 3),
('2345-BCDE-6645-5DDF', 4),
('2345-BCDE-6645-6DDF', 5),
('2345-BCDE-6645-7DDF', 6),
('2345-BCDE-6645-aDDF', 7),
('2345-BCDE-6645-sDDF', 8),
('2345-BCDE-6645-dDDF', 9),
('2345-BCDE-6645-dDDF', 10),
('2345-BCDE-6645-dDDF', 11),
('2345-BCDE-6645-dDDF', 12);
with data
as (
select *
,(in_invoiceid-1)/5 as grp
,case when ((in_invoiceid-1)/5)%2=0 then '1' else '0' end as category
,dense_rank() over(partition by case when ((in_invoiceid-1)/5)%2=0 then '1' else '0' end
order by in_invoiceid) as rnk
from invoicetable a
)
select *
from data a
left join data b
on a.rnk=b.rnk
and b.category=0
where a.category=1
Here is db fiddle link.
https://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=287f101737c580ca271940764b2536ae
You may try with the following approach. Dividing the table is done with (((ROW_NUMBER() OVER (ORDER BY IN_InvoiceID) - 1) / 5) % 2 = 0) which groups records in left and right groups.
CREATE TABLE #InvoiceTable(
IN_ID varchar(24),
IN_InvoiceID int
)
INSERT INTO #InvoiceTable (IN_ID, IN_InvoiceID)
VALUES
('2345-BCDE-6645-1DDF', 1),
('2345-BCDE-6645-3DDF', 2),
('2345-BCDE-6645-4DDF', 3),
('2345-BCDE-6645-5DDF', 4),
('2345-BCDE-6645-6DDF', 5),
('2345-BCDE-6645-7DDF', 6),
('2345-BCDE-6645-aDDF', 7),
('2345-BCDE-6645-sDDF', 8),
('2345-BCDE-6645-dDDF', 9),
('2345-BCDE-6645-dDDF', 10),
('2345-BCDE-6645-dDDF', 11),
('2345-BCDE-6645-dDDF', 12);
WITH cte AS (
SELECT
IN_ID,
IN_InvoiceID,
CASE
WHEN (((ROW_NUMBER() OVER (ORDER BY IN_InvoiceID) - 1) / 5) % 2 = 0) THEN 'L'
ELSE 'R'
END AS IN_Position
FROM #InvoiceTable
),
cteL AS (
SELECT IN_ID, IN_InvoiceID, ROW_NUMBER() OVER (ORDER BY IN_InvoiceID) AS IN_RowNumber
FROM cte
WHERE IN_Position = 'L'
),
cteR AS (
SELECT IN_ID, IN_InvoiceID, ROW_NUMBER() OVER (ORDER BY IN_InvoiceID) AS IN_RowNumber
FROM cte
WHERE IN_Position = 'R'
)
SELECT cteL.IN_ID, cteL.IN_InvoiceID, cteR.IN_ID, cteR.IN_InvoiceID
FROM cteL
LEFT JOIN cteR ON (cteL.IN_RowNumber = cteR.IN_RowNumber)
Output:
IN_ID IN_InvoiceID IN_ID IN_InvoiceID
2345-BCDE-6645-1DDF 1 2345-BCDE-6645-7DDF 6
2345-BCDE-6645-3DDF 2 2345-BCDE-6645-aDDF 7
2345-BCDE-6645-4DDF 3 2345-BCDE-6645-sDDF 8
2345-BCDE-6645-5DDF 4 2345-BCDE-6645-dDDF 9
2345-BCDE-6645-6DDF 5 2345-BCDE-6645-dDDF 10
2345-BCDE-6645-dDDF 11 NULL NULL
2345-BCDE-6645-dDDF 12 NULL NULL
I have a (subquery) table that lists meal preferences for my friends. Each meal can only be taken once, and each person can only eat one meal.
row_number person_id meal_id
1 1 3
2 2 1
3 2 2
4 2 3
5 3 1
6 3 2
7 3 3
The picking order is determined by the original order of the table, so I would like the result to be:
person_id meal_id
1 3
2 1
3 2
Because meal 1 is taken by user 2, user 3 gets meal 2. I think this could be solved by selecting distinct values in both columns based on their original order, but I cannot figure out how to write that query. Any help appreciated.
Update Added row_number to original table.
If I understand correctly, this is a rather complicated graph walking problem. I should first note that there is no guarantee of an optimal solution -- without lots and lots of work. But you can implement a greedy algorithm using recursive CTEs:
with recursive t as (
select v.*
from (values (1, 1, 3), (2, 2, 1), (3, 2, 2), (4, 2, 3), (5, 3, 1), (6, 3, 2), (7, 3, 3)
) v(row_number, person_id, meal_id)
),
cte (row_number, person_id, meal_id, rows, persons, meals, lev) as (
select row_number, person_id, meal_id, array[row_number], array[person_id], array[meal_id], 1 as lev
from t
where row_number = 1
union all
select t.row_number, t.person_id, t.meal_id,
(case when t.person_id = any(cte.persons) or t.meal_id = any(cte.meals)
then cte.rows
else array_append(cte.rows, t.row_number)
end),
(case when t.person_id = any(cte.persons) or t.meal_id = any(cte.meals)
then cte.persons
else array_append(cte.persons, t.person_id)
end),
(case when t.person_id = any(cte.persons) or t.meal_id = any(cte.meals)
then cte.meals
else array_append(cte.meals, t.meal_id)
end),
cte.lev + 1
from cte join
t
on t.row_number = cte.row_number + 1
)
select t.*
from t cross join
(select rows from cte order by lev desc fetch first 1 row only) as last1
where t.row_number = any (last1.rows);
Here is a db<>fiddle.
I have some sample data like:
INSERT INTO mytable
([FK_ID], [TYPE_ID])
VALUES
(10, 1),
(11, 1), (11, 2),
(12, 1), (12, 2), (12, 3),
(14, 1), (14, 2), (14, 3), (14, 4),
(15, 1), (15, 2), (15, 4)
Now, here I am trying to check if in each group by FK_ID we have exact match of TYPE_ID values for 1, 2 & 3.
So, the expected output is like:
(10, 1) this should fail
As in group FK_ID = 10 we only have one record
(11, 1), (11, 2) this should also fail
As in group FK_ID = 11 we have two records.
(12, 1), (12, 2), (12, 3) this should pass
As in group FK_ID = 12 we have two records.
And all the TYPE_ID are exactly matching 1, 2 & 3 values.
(14, 1), (14, 2), (14, 3), (14, 4) this should also fail
As we have 4 records here.
(15, 1), (15, 2), (15, 4) this should also fail
Even though we have three records, it should fail as the TYPE_ID here (1, 2, 4) are not matching with required match (1, 2, 3).
Here is my attempt:
select * from mytable t1
where exists (select COUNT(t2.TYPE_ID)
from mytable t2 where t2.FK_ID = t1.FK_ID
and t2.TYPE_ID IN (1, 2, 3)
group by t2.FK_ID having COUNT(t2.TYPE_ID) = 3);
This is not working as expected, because it also pass for FK_ID = 14 which has four records.
Demo: SQL Fiddle
Also, how we can make it generic so that if we need to check for 4 or more TYPE_ID values like (1,2,3,4) or (1,2,3,4,5), we can do that easily by updating few values.
The following query will do what you want:
select fk_id
from t
group by fk_id
having sum(case when type_id in (1, 2, 3) then 1 else 0 end) = 3 and
sum(case when type_id not in (1, 2, 3) then 1 else 0 end) = 0;
This assumes that you have no duplicate pairs (although depending on how you want to handle duplicates, it might be as easy as using, from (select distinct * from t) t).
As for "genericness", you need to update the in lists and the 3.
If you want something more generic:
with vals as (
select id
from (values (1), (2), (3)) v(id)
)
select fk_id
from t
group by fk_id
having sum(case when type_id in (select id from vals) then 1 else 0 end) = (select count(*) from vals) and
sum(case when type_id not in (select id from vals) then 1 else 0 end) = 0;
You can use this code:
SELECT y.fk_id FROM
(SELECT x.fk_id, COUNT(x.type_id) AS count, SUM(x.type_id) AS sum
FROM mytable x GROUP BY (x.fk_id)) AS y
WHERE y.count = 3 AND y.sum = 6
For making it generic, you can equal y.count with N and y.sum with N*(N-1)/2, where N is the number you are looking for (1, 2, ..., N).
You can try this query. COUNT and DISTINCT used for eliminate duplicate records.
SELECT
[FK_ID]
FROM
#mytable T
GROUP BY
[FK_ID]
HAVING
COUNT(DISTINCT CASE WHEN [TYPE_ID] IN (1,2,3) THEN [TYPE_ID] END) = 3
AND COUNT(CASE WHEN [TYPE_ID] NOT IN (1,2,3) THEN [TYPE_ID] END) = 0
Try this:
select FK_ID,count(distinct TYPE_ID) from mytable
where TYPE_ID<=3
group by FK_ID
having count(distinct TYPE_ID)=3
You should use CTE with Dynamic pass Value which you have mentioned in Q.
WITH CTE
AS (
SELECT FK_ID,
COUNT(*) CNT
FROM #mytable
GROUP BY FK_ID
HAVING COUNT(*) = 3) <----- Pass Value here What you want to Display Result,
CTE1
AS (
SELECT T.[ID],
T.[FK_ID],
T.[TYPE_ID],
ROW_NUMBER() OVER(PARTITION BY T.[FK_ID] ORDER BY
(
SELECT NULL
)) RN
FROM #mytable T
INNER JOIN CTE C ON C.FK_ID = T.FK_ID),
CTE2
AS (
SELECT C1.FK_ID
FROM CTE1 C1
GROUP BY C1.FK_ID
HAVING SUM(C1.TYPE_ID) = SUM(C1.RN))
SELECT TT1.*
FROM CTE2 C2
INNER JOIN #mytable TT1 ON TT1.FK_ID = C2.FK_ID;
From above SQL Command which will produce Result (I have passed 3) :
ID FK_ID TYPE_ID
4 12 1
5 12 2
6 12 3
So in this case I want to display every ID where the corresponding value is 1. However, in the case below where the ID is 4, I don't want it to display the 4's where the value is 1, I just want it to not show 4 at all. If I do a WHERE value LIKE '1', it'll show me the two IDs of 4 where the value is 1. Is there a way to not show 4 at all? Thanks in advance.
ID:.......1...2...3...4...4...4...5
Value:....1...1...1...1...2...1...1
(This is on Microsoft SQL Server management studio by the way)
If you just want the ids, then use aggregation:
select id
from t
group by id
having min(value) = 1 and max(value) = 1;
To add on Gordon's answer
I would add a count since it seems your data has multiple 1s in that case if you have two 1s you'd have it as both min and max
select id
from t
group by id
having min(value) = 1 and max(value) = 1 and count(value) = 1;
You could also use
select id from t group by id having sum(value) = 1 and count(value) = 1;
with cte as (
select * from (values
(1, 1),
(2, 1),
(3, 1),
(4, 1),
(4, 2),
(4, 1),
(5, 1)
) as x(ID, Value)
)
select *
from cte
where ID not in (
select ID
from cte
where Value > 1
);
I've been struggling to create an Oracle SQL query that will tell me if my SDO table contains curves or arcs. I know that the sdo_elem_info contains the information I need, but I don't know how to use SQL to separate out the etype and interpretation from the sdo_elem_info.
So far, all I have is: select tbl.shape.sdo_elem_info from my_table tbl
You can use the TABLE function to extract the sdo_elem_info_array elements, then pivot that and aggregate the resulting rows to yield a row per element, with a column for offset, etype and interpretation.
Something like this should give you your query... (warning: untested)
WITH elem_info AS (
SELECT
TRUNC((ROWNUM - 1) / 3, 0) element_no
, MAX(DECODE(MOD(ROWNUM, 3), 1, t.COLUMN_VALUE, NULL)) offset
, MAX(DECODE(MOD(ROWNUM, 3), 2, t.COLUMN_VALUE, NULL)) etype
, MAX(DECODE(MOD(ROWNUM, 3), 0, t.COLUMN_VALUE, NULL)) interpretation
FROM my_table tbl
, TABLE(tbl.shape.sdo_elem_info) t
GROUP BY TRUNC((ROWNUM - 1) / 3, 0)
)
SELECT DECODE(COUNT(*), 0, 'false', 'true')
FROM elem_info ei
WHERE ei.etype IN (1005, 2005)
OR ei.interpretation IN (2, 4)