I have this query
select *
from (
select c.*,p.name as project_name,u.firstname || ' ' || u.lastname as fullname, u.email as owner_email, u.payment_method, u as user, u.id as user_id, u.api_id, u.api_key,
v.name as vendor_name, v.exid as vendor_id, s.number as sim_number, vm.exid as vendor_model_id, vm.name as vendor_model_name, cr.status as is_recording,
cr.storage_duration as cloud_recording_storage_duration, cr.schedule as schedule, cr.frequency as frequency,
(select count(id) as total from camera_shares cs where c.id=cs.camera_id) as total_share
from cameras c
inner JOIN users u on c.owner_id = u.id
left JOIN projects p on c.project_id = p.id
left JOIN sims s on c.id = s.camera_id
left JOIN vendor_models vm on c.model_id = vm.id
left JOIN vendors v on vm.vendor_id = v.id
left JOIN cloud_recordings cr on c.id = cr.camera_id
) c
this gives me all cameras and with all relevant values which I require.
now there is another table, snapshot_extractors and it has a relation with the camera on id and camera_id in extractors table, as one camera can have more than 1 extractors.
In the above query, I want to get all extraction for one camera, I can do it in a separate query, but is it possible to get all extractions in the above query as an array of all extractions for a camera?
You can use another correlated subquery:
(select array_agg(e.extraction)
from snapshot_extractors e
where e.camera_id = c.camera_id
)
Related
I am trying to create one single query that will give me a distinct count for both the ActivityID and the CommentID. My query in MS Access looks like this:
SELECT
tbl_Category.Category, Count(tbl_Activity.ActivityID) AS CountOfActivityID,
Count(tbl_Comments.CommentID) AS CountOfCommentID
FROM tbl_Category LEFT JOIN
(tbl_Activity LEFT JOIN tbl_Comments ON
tbl_Activity.ActivityID = tbl_Comments.ActivityID) ON
tbl_Category.CategoryID = tbl_Activity.CategoryID
WHERE
(((tbl_Activity.UnitID)=5) AND ((tbl_Comments.PeriodID)=1))
GROUP BY
tbl_Category.Category;
I know the answer must somehow include SELECT DISTINCT but am not able to get it to work. Do I need to create multiple subqueries?
This is really painful in MS Access. I think the following does what you want to do:
SELECT ac.Category, ac.num_activities, aco.num_comments
FROM (SELECT ca.category, COUNT(*) as num_activities
FROM (SELECT DISTINCT c.Category, a.ActivityID
FROM (tbl_Category as c INNER JOIN
tbl_Activity as a
ON c.CategoryID = a.CategoryID
) INNER JOIN
tbl_Comments as co
ON a.ActivityID = co.ActivityID
WHERE a.UnitID = 5 AND co.PeriodID = 1
) as caa
GROUP BY ca.category
) as ca LEFT JOIN
(SELECT c.Category, COUNT(*) as num_comments
FROM (SELECT DISTINCT c.Category, co.CommentId
FROM (tbl_Category as c INNER JOIN
tbl_Activity as a
ON c.CategoryID = a.CategoryID
) INNER JOIN
tbl_Comments as co
ON a.ActivityID = co.ActivityID
WHERE a.UnitID = 5 AND co.PeriodID = 1
) as aco
GROUP BY c.Category
) as aco
ON aco.CommentId = ac.CommentId
Note that your LEFT JOINs are superfluous because the WHERE clause turns them into INNER JOINs. This adjusts the logic for that purpose. The filtering is also very tricky, because it uses both tables, requiring that both subqueries have both JOINs.
You can use DISTINCT:
SELECT
tbl_Category.Category, Count(DISTINCT tbl_Activity.ActivityID) AS CountOfActivityID,
Count(DISTINCT tbl_Comments.CommentID) AS CountOfCommentID
FROM tbl_Category LEFT JOIN
(tbl_Activity LEFT JOIN tbl_Comments ON
tbl_Activity.ActivityID = tbl_Comments.ActivityID) ON
tbl_Category.CategoryID = tbl_Activity.CategoryID
WHERE
(((tbl_Activity.UnitID)=5) AND ((tbl_Comments.PeriodID)=1))
GROUP BY
tbl_Category.Category;
I have this query:
SELECT
a.account_uuid,
a.account_no,
a.account_group_uuid,
a.account_scope_uuid,
a.created_at,
a.deleted_at,
s.service_uuid,
s.status,
st.service_type,
(
SELECT
c.company
FROM companies c
WHERE a.company_owner_uuid = c.company_uuid
)
FROM
accounts a
LEFT JOIN
services s
ON a.account_uuid = s.account_uuid
LEFT JOIN
service_types st
ON s.service_type_uuid = st.service_type_uuid
WHERE
a.deleted_at IS NULL
ORDER BY
a.account_no
And I need to join and select multiple columns from a people table by way of a pivot table accounts_contacts that would have the account_uuid and a person_uuid. There are also is_primary and is_active columns on the accounts_contacts table and there will only be one primary at a time, so the end result would be a single first and last name. This is the idea of the query:
SELECT
p.first_name, p.last_name
FROM
people p
INNER JOIN
accounts_contacts ac
ON ac.account_uuid = a.account_uuid
AND ac.person_uuid = p.person_uuid
WHERE
ac.is_primary = true
AND ac.is_active = true
But not sure how to fit it into the above query. A subquery would only allow for one of the columns.
account_contacts is an "association" or "junction" table. It is not a pivot table.
The basic idea should be joins:
SELECT . . . ,
p.first_name, p.last_name
FROM accounts a LEFT JOIN
services s
ON a.account_uuid = s.account_uuid LEFT JOIN
service_types st
ON s.service_type_uuid = st.service_type_uuid LEFT JOIN
accounts_contacts ac
ON ac.account_uuid = a.account_uuid LEFT JOIN
people p
ON ac.person_uuid = p.person_uuid AND
ac.is_primary = true AND
ac.is_active = true
I am trying to get a list of our users from our database along with the number of people from the same cohort as them - which in this case is defined as being from the same medical school at the same time.
medical_school_id is stored in the doctor_record table
graduation_dt is stored in the doctor_record table as well.
I have managed to write this query out using a subquery which does a select statement counting the number of others for each row but this takes forever. My logic is telling me that I ought to run a simple GROUP BY query once first and then somehow JOIN the medical_school_id on to that.
The group by query is as follows
select count(ca.id) , cdr.medical_school_id, cdr.graduation_dt
from account ca
LEFT JOIN doctor cd on ca.id = cd.account_id
LEFT JOIN doctor_record cdr on cd.gmc_number = cdr.gmc_number
GROUP BY cdr.medical_school_id, cdr.graduation_dt
The long select query is
select a.id, a.email , dr.medical_school_id,
(select count(ba.id) from account ba
LEFT JOIN doctor bd on ba.id = bd.account_id
LEFT JOIN doctor_record bdr on bd.gmc_number = bdr.gmc_number
WHERE bdr.medical_school_id = dr.medical_school_id AND bdr.graduation_dt = dr.graduation_dt) AS med_count,
from account a
LEFT JOIN doctor d on a.id = d.account_id
LEFT JOIN doctor_record dr on d.gmc_number = dr.gmc_number
If you could push me in the right direction that would be amazing
I think you just want window functions:
select a.id, a.email, dr.medical_school_id, dr.graduation_dt,
count(*) over (partition by dr.medical_school_id, dr.graduation_dt) as cohort_size
from account a left join
doctor d
on a.id = d.account_id left join
doctor_record dr
on d.gmc_number = dr.gmc_number;
Using your same code for group by:
SELECT * FROM (
(
SELECT acc.[id]
, acc.[email]
FROM
account acc
LEFT JOIN
doctor doc
ON
acc.id = doc.account_id
LEFT JOIN
doctor_record doc_rec
ON
doc.gmc_number = doc_rec.gmc_number
) label
LEFT JOIN
(
SELECT count(acco.id)
, doc_reco.medical_school_id
, doc_reco.graduation_dt
FROM
account acco
LEFT JOIN
doctor doct
ON
acco.id = doct.account_id
LEFT JOIN
doctor_record doc_reco
ON
doct.gmc_number = doc_reco.gmc_number
GROUP BY
doc_reco.medical_school_id,
doc_reco.graduation_dt
) count
ON
count.[medical_school_id]=label.[medical_school_id]
AND
count.[graduation_dt]=label.[graduation_date]
)
how about something like this?
select a.doctor_id
, count(*) - 1
from doctor_record a
left join doctor_record b on a.medical_school_id = b.medical_school_id
and a.graduation_dt = b.graduation_dt
group by a.doctor_id
Subtract 1 from the count so that you're not counting the doctor in the "other folks in same cohort" number
I'm defining "same cohort" as "same medical school & graduation date".
I'm unclear on what GMC number is and how it is related. Is it something to do with cohort?
I want to limit the results in a lateral join, so that it only returns the N most recent matches.
This is my query, but the limit inside the join does not seem to work, as it returns all visitors
select am.id, am.title, ame.event, array_agg(row_to_json(visitors))
from auto_messages am
left join apps a on am.app_id = a.id
left join app_users au on a.id = au.app_id
left join auto_message_events ame on ame.auto_message_id = am.id
left join lateral (
select
id,
name,
avatar,
ame.inserted_at
from visitors v
where v.id = ame.visitor_id
order by ame.inserted_at desc
limit 1
) as visitors on visitors.id = ame.visitor_id
where am.id = '100'
group by am.id, ame.event
I am pretty sure the problem is with ame. That is where the rows are generated. The join to visitors is only picking up additional information.
So, this might solve your problem:
select am.id, am.title, visitors.event, array_agg(row_to_json(visitors))
from auto_messages am left join
apps a
on am.app_id = a.id left join
app_users au
on a.id = au.app_id left join lateral
(select v.id, v.name, v.avatar,
ame.event, ame.inserted_at, ame.auto_message_id
from auto_message_events ame join
visitors v
on v.id = ame.visitor_id
order by ame.inserted_at desc
limit 1
) visitors
on visitors.auto_message_id = am.id
where am.id = '100'
group by am.id, visitors.event;
You also might want to change your select clause, if you only want a subset of columns.
Can someone help me with the rest of my Query.
This query gives me Customer, AdressNr, Date, Employee, Article, ActivityNr
from all the sales in my Company.
SELECT ad.Name + ' ' + ad.Vorname AS Customer,
pa.Kunde AS CustomerNr,
CONVERT(VARCHAR(10),p.datum,126) AS Date,
(SELECT a.name + ' ' + a.Vorname AS Name FROM PRO_Mitarbeiter m LEFT JOIN ADR_Adressen a ON a.AdressNrADR=m.AdressNrADR WHERE m.MitNrPRO = l.MitNrPRO) as Employee,
p.Artikel_1 AS Article,
l.AufgabenNrCRM AS OrderNr
FROM ZUS_Therapie_Positionen p
INNER JOIN CRM_AufgabenLink l ON l.AufgabenNrCRM = p.Id_Aktivitaet
INNER JOIN CRM_Aufgaben ab ON ab.AufgabenNrCRM = p.Id_Aktivitaet
INNER JOIN PRO_Auftraege pa ON pa.AuftragNrPRO = ab.AuftragNrPRO
INNER JOIN ADR_Adressen ad ON ad.AdressNrADR = pa.Kunde
INNER JOIN ADR_GruppenLink gl ON gl.AdressNrADR = ad.AdressNrADR
INNER JOIN ADR_Gruppen g ON g.GruppeADR = gl.GruppeADR
WHERE l.MitNrPRO != 0
GROUP BY l.AufgabenNrCRM,ad.Name,ad.Vorname,pa.Kunde,p.datum,p.Artikel_1,l.MitNrPRO
ORDER BY pa.Kunde,p.datum,l.AufgabenNrCRM
My goal is to filter this so i get only rows back where the customer has bought more then 1 Thing on the same day. It doesn't matter if a customer bought the same Article twice on the same day. I want too see this also.
It's to complicated to write some SQL Fiddle for you but in this Picture you can see what my goal is. I want to take away all rows with an X on the left side and thoose with a Circle i want to Keep.
As I don't speak German, I won't target this specifically to your SQL. But see the following quasi-code for a similar example that you should be able to apply to your own script.
SELECT C.CustomerName, O.OrderDate, O.OrderNumber
FROM CUSTOMER C
JOIN ORDERS O ON O.Customer_ID = C.Customer_ID
JOIN
(SELECT Customer_ID, OrderDate
FROM ORDERS
GROUP BY Customer_ID, OrderDate
HAVING COUNT(*) > 1) SRC
ON SRC.Customer_ID = O.Customer_ID AND SRC.OrderDate = O.OrderDate
In the script above, the last query (a subquery) would only return results where a customer had more than one order in a given day. By joining that to your main query, you would effectively produce the result asked in the OP.
Edit 1:
Regarding your comment below, I really recommend just going over your datamodel, trying to understand what's happening here, and fixing it on your own. But there is an easy - albeit hardly optimal solution to this by just using your own script above. Note, while this is not disastrous performance-wise, it's obviously not the cleanest, most effective method either. But it should work:
;WITH CTE AS (SELECT ad.Name + ' ' + ad.Vorname AS Customer,
pa.Kunde AS CustomerNr,
CONVERT(VARCHAR(10),p.datum,126) AS [Date],
(SELECT a.name + ' ' + a.Vorname AS Name FROM PRO_Mitarbeiter m LEFT JOIN ADR_Adressen a ON a.AdressNrADR=m.AdressNrADR WHERE m.MitNrPRO = l.MitNrPRO) as Employee,
p.Artikel_1 AS Article,
l.AufgabenNrCRM AS OrderNr
FROM ZUS_Therapie_Positionen p
INNER JOIN CRM_AufgabenLink l ON l.AufgabenNrCRM = p.Id_Aktivitaet
INNER JOIN CRM_Aufgaben ab ON ab.AufgabenNrCRM = p.Id_Aktivitaet
INNER JOIN PRO_Auftraege pa ON pa.AuftragNrPRO = ab.AuftragNrPRO
INNER JOIN ADR_Adressen ad ON ad.AdressNrADR = pa.Kunde
INNER JOIN ADR_GruppenLink gl ON gl.AdressNrADR = ad.AdressNrADR
INNER JOIN ADR_Gruppen g ON g.GruppeADR = gl.GruppeADR
WHERE l.MitNrPRO != 0
GROUP BY l.AufgabenNrCRM,ad.Name,ad.Vorname,pa.Kunde,p.datum,p.Artikel_1,l.MitNrPRO
ORDER BY pa.Kunde,p.datum,l.AufgabenNrCRM)
SELECT C.*
FROM CTE C
JOIN (Select CustomerNr, [Date]
FROM CTE B
GROUP BY CustomerNr, [Date]
HAVING COUNT(*) > 1) SRC
ON SRC.CustomerNr = C.CustomerNr AND SRC.[Date] = C.[Date]
This should work directly. But as I said, this is an ugly workaround where we're basically all but fetching the whole set twice, as opposed to just limiting the sub query to just the bare minimum of necessary tables. Your choice. :)
Tried that also and it didnt work. I also made a new query trying to Keep it so simple as possible and it doesnt work either. It still give me Single values back..
SELECT p.Datum,a.AufgabenNrCRM,auf.Kunde FROM CRM_Aufgaben a
LEFT JOIN ZUS_Therapie_Positionen p ON p.Id_Aktivitaet = a.AufgabenNrCRM
LEFT JOIN PRO_Auftraege auf ON auf.AuftragNrPRO = a.AuftragNrPRO
LEFT JOIN
(SELECT pa.Datum,au.Kunde FROM CRM_Aufgaben aa
LEFT JOIN ZUS_Therapie_Positionen pa ON pa.Id_Aktivitaet = aa.AufgabenNrCRM
LEFT JOIN PRO_Auftraege au ON au.AuftragNrPRO = aa.AuftragNrPRO
GROUP BY pa.Datum,au.Kunde
HAVING COUNT(*) > 1) SRC
ON SRC.Kunde = auf.Kunde
WHERE p.datum IS NOT NULL
GROUP BY p.Datum,a.AufgabenNrCRM,auf.Kunde
ORDER BY auf.Kunde,p.Datum