I have next table
points:
min max level
0 5 1
6 10 2
11 15 3
16 20 4
and I need to extract level according points. If I have 7 points then level will be 2 and query is next:
select level
from points
where 7 > min
AND 7 < max
what I need is get highest level if points are more then 20, for example if I have 35 points level should be 4. How I can do it?
Set max in the last row to null:
| 16 | null | 4
And your query becomes:
SELECT level
FROM points
WHERE :score >= min
AND (:score <= max OR max is null)
Remark: it is better to define your ranges as [min,max[:
min max level
0 6 1
6 11 2
11 16 3
16 4
Then your query becomes:
SELECT level
FROM points
WHERE :score >= min
AND (:score < max OR max is null)
Related
I'm trying to prepare my data to create a burndown visual. As you can see the Rate column isn't simply A - B, as it carries forward the previous value if B is null.
I've tried some case statements using lag and sums but no avail.
Some direction on the case statement or an optimal solution would be ideal.
For example, this is how my data looks:
ID
A
B
1
20
NULL
2
20
3
3
20
NULL
4
20
7
5
20
NULL
6
20
NULL
7
20
NULL
8
20
5
9
20
7
And I want a rate column that looks like this.
ID
A
B
Rate
1
20
NULL
20
2
20
3
17
3
20
NULL
17
4
20
7
10
5
20
NULL
10
6
20
NULL
10
7
20
NULL
10
8
20
5
5
9
20
7
-2
Thanks to #Larnu for the guidance.
Here is the solution when you have your data partitioned by some group ID and ordered by some data or row ID.
SELECT
GROUP_ID,
ROW_ID,
COL_A,
COL_B,
COL_A - (SUM(ISNULL(COL_B,0)) OVER (PARTITION BY GROUP_ID ORDER BY ROW_ID ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW))
FROM table
Using Sql Server Mgmt Studio. My data set is as below.
ID Days Value Threshold
A 1 10 30
A 2 20 30
A 3 34 30
A 4 25 30
A 5 20 30
B 1 5 15
B 2 10 15
B 3 12 15
B 4 17 15
B 5 20 15
I want to run a query so only rows after the threshold has been reached are selected for each ID. Also, I want to create a new days column starting at 1 from where the rows are selected. The expected output for the above dataset will look like
ID Days Value Threshold NewDayColumn
A 3 34 30 1
A 4 25 30 2
A 5 20 30 3
B 4 17 15 1
B 5 20 15 2
It doesn't matter if the data goes below the threshold for the latter rows, I want to take the first row when threshold is crossed as 1 and continue counting rows for the ID.
Thank you!
You can use window functions for this. Here is one method:
select t.*, row_number() over (partition by id order by days) as newDayColumn
from (select t.*,
min(case when value > threshold then days end) over (partition by id) as threshold_days
from t
) t
where days >= threshold_days;
From a given table I want to be able to sum values having the same number (should be easy, right?)
Problem: A given value can be assigned from 2 to n consecutive numbers.
For some reasons this information is stored in a single row describing the value, the starting number and the ending number as below.
TABLE A
id | starting_number | ending_number | value
----+-----------------+---------------+-------
1 2 5 8
2 0 3 5
3 4 6 6
4 7 8 10
For instance the first row means:
value '8' is assigned to numbers: 2, 3 and 4 (5 is excluded)
So, I would like the following intermediairy result table
TABLE B
id | number | value
----+--------+-------
1 2 8
1 3 8
1 4 8
2 0 5
2 1 5
2 2 5
3 4 6
3 5 6
4 7 10
So I can sum 'value' for elements having identical 'number'
SELECT number, sum(value)
FROM B
GROUP BY number
TABLE C
number | sum(value)
--------+------------
2 13
3 8
4 14
0 5
1 5
5 6
7 10
I don't know how to do this and didn't find any answer on the web (maybe not looking with appropriate key words...)
Any idea?
You can do what you want with generate_series(). So, TableB is basically:
select id, generate_series(starting_number, ending_number - 1, 1) as n, value
from tableA;
Your aggregation is then:
select n, sum(value)
from (select id, generate_series(starting_number, ending_number - 1, 1) as n, value
from tableA
) a
group by n;
When a column value does not equal, I would like to retrieve the closest lower pay value.
For instance: 10 yearsOfService should equal the value 650.00; 14 yearsOfService would equal the value 840.00 in the below incentive table,
ID Pay yearsOfService
1 125.00 0
2 156.00 2
3 188.00 3
4 206.00 4
5 650.00 6
6 840.00 14
7 585.00 22
8 495.00 23
9 385.00 24
10 250.00 25
I have tried several different approaches; including:
SELECT TOP 1 (pay) as incentivePay
FROM incentive
WHERE yearsOfService = '10'
This works but only for yearsOfService that match.
With 10 yearsOfService:
RESULTSET = [1 650.00]
Any ideas?
Please try:
SELECT TOP 1 (pay) as incentivePay
FROM incentive
WHERE yearsOfService <= '10'
ORDER BY yearsOfService desc
Need your help with a SQL query in Oracle db. I have data that I want to partition into groups when event = "Start". E.g. Row 1-6 is a group, row 7-9 is a group. I want to ignore rows with event = "Ignore". Finally I want to calculate max(Value)-min(Value) for these groups. I dont have any way to group the data.
Can this be achieved? Is it possible to use partition by Event = start. Same data is below:
Row Event Value Required Result is max-min of value
1 Start 10
2 A 11
3 B 12
4 C 13
5 D 14
6 E 15 5
--------------------------------------------
7 Start 16
8 A 18
9 B 20 4
--------------------------------------------
10 Start 27
11 A 30
12 B 33
13 C 34 7
--------------------------------------------
14 Ignore 35
--------------------------------------------
15 Ignore 36
--------------------------------------------
16 Start 33
17 A 34
18 B 35
19 C 36
20 D 37
21 E 38 5
--------------------------------------------
Yes, you can do this in SQL.
The following query first finds the group that a row is in, by finding the largest start before the row id. This version uses a correlated subquery for this calculation.
It then does the grouping on the id and does the calculation.
select groupid, max(value) - min(value)
from (select t.*,
(select max(row) from t t2 where t2.row < t.row and t2.event = start
) as groupid
from t
) t
where event <> 'IGNORE'