I'm trying to compare unichar, but my code below doesn't work.
NSString *str = #"some string ^ ^";
NSUInteger len = [str length];
unichar buffer[len+1];
[str getCharacters:buffer range:NSMakeRange(0, len)];
for(int i = 0; i < len; i++) {
if (buffer[i] == '^') NSLog(#"%C", buffer[i]);
}
It doesn't seem to be able to log the ^ even though it exist. Any idea why?
Related
I have an NSString *titleName which changes according to an if statement. So the length (number of characters) in the string changes. I would like to divide titleName into a MutableArray of separate strings consisting of its individual characters. I would then like to use these separate strings as the text in different UILabels. I am not sure as how to go about this.
Through some research I have tried to create the NSMutable array like this
NSMutableArray *letterArray = substringWithRange:((i = 0);i<[titleName2 length];i++));
but this gives me an error Use of undeclared identifier 'substringWithRange.
Can someone help me.
I decided to use componentsSeparatedByString instead and just created my various strings with a , between each letter. Thanks for anybody's thoughts though.
The code you pasted is not valid objective-C.
To keep the same algorithm you should write something like :
NSMutableArray *letterArray = [NSMutableArray array];
NSUInteger length = [titleName2 length];
for (NSUInteger i = 0; i < length; ++i) {
[letterArray addObject:[titleName2 substringWithRange:NSMakeRange(i, 1)]];
}
It's probably much "cheaper" to hold a C-array of unichar characters that make-up the string. It will also be quicker to create:
NSString *input = #"How now brown cow?";
unichar chars[[input length]];
for (NSInteger i = 0; i < [input length]; i++)
chars[i] = [input characterAtIndex:i];
Alternatively you could use malloc() to create the C-array:
NSString *input = #"How now brown cow?";
unichar *chars = (unichar *)malloc([input length]);
for (NSInteger i = 0; i < [input length]; i++)
chars[i] = [input characterAtIndex:i];
and then use free(), later, to, err, free the memory:
free(chars);
Cheaper still, would be to not split-up the string at all...
Try this below code
NSMutableArray *letterArray = [NSMutableArray array];
for (int i = 0;i<[titleName2 length];i++)
{
[letterArray addObject: [titleName2 substringWithRange:NSMakeRange(i,1)]];
}
DLog(#"%#", letterArray);
Other option to get characters of string
NSMutableArray *letterArray = [NSMutableArray array];
for (int i=0; i < [titleName2 length]; i++)
{
[letterArray addObject:[NSString stringWithFormat:#"%c", [titleName2 characterAtIndex:i]]];
}
DLog(#"characters - %#", letterArray);
I have an Array , if I print that in console it shows
Price Array=(
"$100",
"$300"
)
I need to add add objects at each index and show it in label. Please suggest any idea, in this case how it will show 400 with $ sign?
I tried this in view did load
for (int j=0; j<[cartArray2 count]; j++)
{
itemPrize =[prizelabel.text floatValue];
tempVar=itemPrize;
total=total+tempVar;
NSString *strTotalAmt = [NSString stringWithFormat:#"%f",total];
prizelabel.text=strTotalAmt;
}
NSLog( #"Toatl= %f",total);`
where in interface float itemPrize,tempVar,total
This is what i did
for (int j=0; j<[cartArray2 count]; j++)
{
NSMutableString *cleanedText = [NSMutableString stringWithCapacity:0];
NSString *newRecord = [[cartArray2 objectAtIndex:j] stringByReplacingOccurrencesOfString:#"$" withString:#"" options:NSCaseInsensitiveSearch range:NSMakeRange(0, [[cartArray2 objectAtIndex:j] length])];
[cleanedText appendFormat:#"%#\n", newRecord];
NSLog(#"Cleaned=%#", cleanedText);
itemPrize =[cleanedText intValue];
tempVar=itemPrize;
total=total+tempVar;
NSString *strTotalAmt = [NSString stringWithFormat:#"%d",total];
prizelabel.text=strTotalAmt;
}
NSLog( #"Toatl= %d",total);
To get rid of $ sign you should try: [[itemPrize componentsSeparatedByString:#"$"] objectAtIndex:1];. Then you should use stringWithFormat method to do the string formatting.
Given a sentence composing of X number of Chinese characters. I want to parse each character out in Objective-C or C++.
I tried:
NSString * nsText = [NSString stringWithFormat:#"你好吗"];
for (int i = 0; i < [nsText length]; i++)
{
char current = [nsText characterAtIndex:i];
printf("%i: %c\n", i, current);
}
But I'm not getting the right characters, I got index 0 = ', index 1 = }, etc. The length is returned correctly, which equals 3. I need UTF8 encoding to display it to the UI.
Any tips will be helpful.
Thank you
Three things wrong. First, characterAtIndex: returns a unichar, which is bigger than the char to which you're assigning. You're losing information there. Second, %c is the format specifier for printing an ASCII value (8 bits). You want %C (uppercase 'C') to print a 16-bit unichar. Finally, printf() doesn't seem to accept %C, so you need to use NSLog() instead. Rewritten, then, we have:
NSString * nsText = [NSString stringWithFormat:#"你好吗"];
for (int i = 0; i < [nsText length]; i++)
{
unichar current = [nsText characterAtIndex:i];
NSLog(#"%i: %C\n", i, current);
}
Can this solve your problem?
NSString * nsText = [NSString stringWithFormat:#"你好吗"];
for (int i = 0; i < [nsText length]; i++) {
NSString *str = [nsText substringToIndex:i+1];
NSString *str2 =[str substringFromIndex:i];
NSLog(#"%#",str2);
}
Am basically new to Objective-C. This is the question that i have.
How to i send in individual characters of string into a for-loop and output each of those characters in the for-loop?
NSString *input = #"input string";
for ( NSInteger i=0; i<[input length]; i++ )
{
unichar c = [input characterAtIndex:i];
NSLog(#"Character at %d: %c == %04x == %d",i,c,(int)c,(int)c);
}
I have this function:
void myFunc(NSString* data) {
NSMutableArray *instrs = [[NSMutableArray alloc] initWithCapacity:[data length]];
for (int i=0; i < [data length]; i++) {
unichar c = [data characterAtIndex:i];
[instrs addObject:c];
}
NSEnumerator *e = [instrs objectEnumerator];
id inst;
while (inst = [e nextObject]) {
NSLog("%i\n", inst);
}
}
I think it fails at [instrs addObject:c]. It's purpose is to iterate through the hexadecimal numbers of an NSString. What causes this code to fail?
A unichar is not an object; it's an integer type.
NSMutableArray can only hold objects.
If you really want to put it into an NSMutableArray, you could wrap the integer value in an NSNumber object: [instrs addObject:[NSNumber numberWithInt:c]];
But, what's the point of stuffing the values into an array in the first place? You know how to iterate through the string and get the characters, why put them into an array just to iterate through them again?
Also note that:
the "%i" NSLog format expects an integer; you can't pass it an object
for hexadecimal output, you want "%x", not "%i"
If the function is only meant to display the characters as hexadecimal values, you could use:
void myFunc(NSString* data)
{
NSUInteger len = [data length];
unichar *buffer = calloc(len, sizeof(unichar));
if (!buffer) return;
[data getCharacters:buffer range:NSMakeRange(0, len)];
for (NSUInteger i = 0; i < len; i++)
NSLog(#"%04x", (unsigned) buffer[i]);
free(buffer);
}
This is just a little bit more efficient than your approach (also, in your approach you never release the instrs array, so it will leak in a non-garbage-collected environment).
If the string contains hexadecimal numbers, then you will want to repeatedly use an NSScanner's scanHexInt: method until it returns NO.
void myFunc(NSString* data)
{
NSScanner *scanner = [[NSScanner alloc] initWithString:data];
unsigned number;
while ([scanner scanHexInt:&number])
NSLog(#"%u", number);
[scanner release];
}