Reaching out for help. I've seen plenty of answers on how to use DUPLICATE, but not quite how I need it. Let's say I have the result of query that looks like the following.
query result
Incident_No Open_Approval_Step Approval_ID
------------- -------------------- -------------------
1 3 Tech
1 4 Cust_Serv
2 1 Incident_Recorder
2 2 Estimation
2 3 Tech
3 4 Cust_Serv
3 5 Mgmt
3 6 Closure
And I need one row for each incident number with the smallest numbered approval step. So the result should look like this.
filtered query result
Incident_No Open_Approval_Step Approval_ID
------------- -------------------- -------------------
1 3 Tech
2 1 Incident_Recorder
3 4 Cust_Serv
Edit This is what I came up with in the end
SELECT DISTINCT
MIN(OPEN_APPROVAL_STEP) OVER(PARTITION BY INCIDENT_NO ORDER BY OPEN_APPROVAL_STEP ASC) AS CUR_APP_STEP,
INCIDENT_NO
FROM T
You can use row_number():
select *
from (
select
t.*,
row_number() over(partition by incident_no order by open_approval_step) rn
from mytable t
) t
where rn = 1
With just one extra column appart from the incident number and approval step, another option is aggregation and Oracle's keep syntax:
select
incident_no,
min(open_approval_step) open_approval_step,
min(approval_id) keep(dense_rank first order by open_approval_step) approval_id
from mytable
group by incident_no
If you have just three columns, you can easily use aggregation:
select incident_no, min(open_approval_step),
min(approval_id) keep (dense_rank first order by open_approval_step)
from t
group by incident_no;
Related
How to repeat rows based on column value in snowflake using sql.
I tried a few methods but not working such as dual and connect by.
I have two columns: Id and Quantity.
For each ID, there are different values of Quantity.
So if you have a count, you can use a generator:
with ten_rows as (
select row_number() over (order by null) as rn
from table(generator(ROWCOUNT=>10))
), data(id, count) as (
select * from values
(1,2),
(2,4)
)
SELECT
d.*
,r.rn
from data as d
join ten_rows as r
on d.count >= r.rn
order by 1,3;
ID
COUNT
RN
1
2
1
1
2
2
2
4
1
2
4
2
2
4
3
2
4
4
Ok let's start by generating some data. We will create 10 rows, with a QTY. The QTY will be randomly chosen as 1 or 2.
Next we want to duplicate the rows with a QTY of 2 and leave the QTY =1 as they are.
Obviously you can change all parameters above to suit your needs - this solution works super fast and in my opinion way better than table generation.
Simply stack SPLIT_TO_TABLE(), REPEAT() with a LATERAL() join and voila.
WITH TEN_ROWS AS (SELECT ROW_NUMBER()OVER(ORDER BY NULL)SOME_ID,UNIFORM(1,2,RANDOM())QTY FROM TABLE(GENERATOR(ROWCOUNT=>10)))
SELECT
TEN_ROWS.*
FROM
TEN_ROWS,LATERAL SPLIT_TO_TABLE(REPEAT('hire me $10/hour',QTY-1),'hire me $10/hour')ALTERNATIVE_APPROACH;
I work in healthcare. In a Postgres database, we have a table member IDs and dates. I'm trying to pull the latest two dates for each member ID.
Simplified sample data:
A 1
B 1
B 2
C 1
C 5
C 7
D 1
D 2
D 3
D 4
Desired result:
A 1
B 1
B 2
C 1
C 5
D 1
D 2
I get a strong feeling this is for a homework assignment and would recommend that you look into partitioning and specifically rank() function by yourself first before looking at my solution.
Moreover, you have not specified how you received the initial result you provided, so I'll have to assume you just did select letter_column, number_column from my_table; to achieve the result.
So, what you actually want here is partition the initial query result into groups by the letter_column and select the first two rows in each. rank() function lets you assign each row a number, counting within groups:
select letter_column,
number_column,
rank() over (partition by letter_column order by number_column) as rank
from my_table;
Since it's a function, you can't use it in a predicate in the same query, so you'll have to build another query around this one, this time filtering the results where rank is over 2:
with ranked_results as (select letter_column,
number_column,
rank() over (partition by letter_column order by number_column asc) as rank
from my_table mt)
select letter_column,
number_column
from ranked_results
where rank < 3;
Here's an SQLFiddle to play around: http://sqlfiddle.com/#!15/e90744/1/0
Hope this helps!
I want to achieve something easy in an while loop but it's too slow to run so I'm sure I can do this with an CTE table but I don't know how..
I have two table with a join one to many and i'm trying to put an order in my detail here's my data:
for each IDRV you have many IDRVOBJET. I want to put an order number 1 to n for each IDRVOBJET in IDRV. I don't know if i'm clear but here's what I should have as result:
Thanks for taking the time to help me!
EDIT
Here's the formated text:
IDRV IDRVOBJET ORDER
12700 76357 1
12700 76358 2
12701 76363 1
12701 76364 2
12701 76365 3
12702 76359 1
12702 76360 2
12703 76120 1
12703 76121 2
12703 76122 3
12705 19375 1
12705 19376 2
12706 19410 1
12707 19408 1
12707 19409 2
12709 22473 1
12709 22474 2
12711 40352 1
12711 40353 1
Just use a window function.
SELECT
IDRV,
IDRVOBJECT,
ROW_NUMBER() OVER (PARTITION BY IDRV ORDER BY IDRVOBJECT) as ORDRE
FROM YourTable
You can use row_number and partition by
select *, Ordr = Row_Number() over (partition by IDRV order by IDRVOBJET) from your table
SELECT IDRV,IDRVOBJECT,Row_Number()Over(Partition by IDRV Order by IDRVOBJECT) AS ORDRE
FROM <yourtable>
I looked at other examples, but I don't know enough about SQL to adapt it to my needs. I have a table that looks like this:
ID Month NAME COUNT First LAST TOTAL
------------------------------------------------------
1 JAN2013 fred 4
2 MAR2013 fred 5
3 APR2014 fred 1
4 JAN2013 Tom 6
5 MAR2014 Tom 1
6 APR2014 Tom 1
This could be in separate queries, but I need 'First' to equal the first month that a particular name is used, so every row with fred would have JAN2013 in the first field for example. I need the 'Last" column to equal the month of the last record of each name, and finally I need the 'total' column to be the sum of all the counts for each name, so in each row that had fred the total would be 10 in this sample data. This is over my head. Can one of you assist?
This is crude but should do the trick. I renamed your fields a bit because you are using a bunch of "RESERVED" sql words and that is bad form.
;WITH cte as
(
Select
[NAME]
,[nmCOUNT]
,ROW_NUMBER() over (partition by NAME order by txtMONTH ASC) as 'FirstMonth'
,ROW_NUMBER() over (partition by NAME order by txtMONTH DESC) as 'LastMonth'
,SUM([nmCOUNT]) as 'TotNameCount'
From Table
Group by NAME, [nmCOUNT]
)
,cteFirst as
(
Select
NAME
,[nmCOUNT]
,[TotNameCount]
,[txtMONTH] as 'ansFirst'
From cte
Where FirstMonth = 1
)
,cteLast as
(
Select
NAME
,[txtMONTH] as 'ansLast'
From cte
Where LastMonth = 1
Select c.NAME, c.nmCount, c.ansFirst, l.ansLast, c.TotNameCount
From cteFirst c
LEFT JOIN cteLast l on c.NAME = l.NAME
I have a query that calculates points based on multiple criteria, and then orders the result set based on those points.
SELECT * FROM (
SELECT
dbo.afunctionthatcalculates(Something, Something) AS Points1
,dbo.anotherone(Something, Something) AS Points2
,dbo.anotherone(Something, Something) AS Points3
,[TotalPoints] = dbo.function(something) + dbo.function(something)
) AS MyData
ORDER BY MyData.TotalPoints
So my first stab at adding placement, rankings.. was this:
SELECT ROW_NUMBER() OVER(MyData.TotalPoints) AS Ranking, * FROM (
SELECT same as above
) AS MyData
ORDER BY MyData.TotalPoints
This adds the Rankings column, but doesn't work when the points are tied.
Rank | TotalPoints
--------------------
1 100
2 90
3 90
4 80
Should be:
Rank | TotalPoints
--------------------
1 100
2 90
2 90
3 80
Not really sure about how to resolve this.
Thank you for your help.
You should use the DENSE_RANK() function which takes the ties into account, as described here: http://msdn.microsoft.com/en-us/library/ms173825.aspx
DENSE_RANK() instead of ROW_NUMBER()