Currently have a query that hits AWS Redshift. I have this group by a recipient in order to count the total of the output.
select count(CASE WHEN event_name = 'c' THEN 1 END)
from oe
where owner_id = $1
and rid = $2
and cid = $2
and rbid is not null
group by recipient
having count(CASE WHEN event_name = 'c' THEN 1 END) > 0
and count(CASE WHEN event_name = 'd' THEN 1 END) > 0
The output from that is this
5
4
1
1
I'd like to be able, to sum up those numbers to produce a final number, as well as count the number of rows. How can I go about achieving this?
This should give you the desired result.
select sum(sum_c), count(*) from (
select count(CASE WHEN event_name = 'c' THEN 1 END) sum_c
from oe
where owner_id = $1
and rid = $2
and cid = $2
and rbid is not null
group by recipient
having count(CASE WHEN event_name = 'c' THEN 1 END) > 0
and count(CASE WHEN event_name = 'd' THEN 1 END) > 0) x;
Related
This query pulls data from a VistaDB and produces info on the number of courses started in each month of the year from people in different countries.
Select c.CountryName As Country,
Count (case When Month( ch.CourseStarted ) = 1 Then 1 End) As Jan19,
Count (case when Month(ch.CourseStarted ) = 2 Then 1 End) as Feb19,
Count (case When Month(ch.CourseStarted ) = 3 Then 1 End) as Mar19,
Count (case When Month(ch.CourseStarted ) = 4 Then 1 End) as Apr19,
Count (case When Month(ch.CourseStarted ) = 5 Then 1 End) as May19,
Count (case When Month(ch.CourseStarted ) = 6 Then 1 End) as Jun19,
Count (case When Month(ch.CourseStarted ) = 7 Then 1 End) as Jul19,
Count (case When Month(ch.CourseStarted ) = 8 Then 1 End) as Aug19,
Count (case When Month(ch.CourseStarted ) = 9 Then 1 End) as Sep19,
Count (case When Month(ch.CourseStarted ) = 10 Then 1 End) as Oct19,
Count (case When Month(ch.CourseStarted ) = 11 Then 1 End)as Nov19,
Count (case When Month(ch.CourseStarted ) = 12 Then 1 End) as Dec19
From Country As c
Inner Join CourseHistory As ch On c.Oid = ch.Country
Where (ch.CourseStarted >= '2019-01-01' And
ch.CourseStarted <= '2019-12-31')
Group By c.CountryName
Order by c.CountryName;
My question is would it be possible to make this semi-dynamic so that if I were to make the final date in the where clause '2022-12-31' I could get a rafft of colums for each month of each year?
For some context, I am making an image browser which is connected to an SQLite database. Within the browser, similar images are grouped into an event (EventId) and each image (MicrosoftId) is labelled with a few tags (name).
I have these two queries on the same table (TagsMSCV) but pulling out different information. Ultimately I need to combine the information in my browser so if it was possible to combine these two queries (maybe with a JOIN?) it would be a lot faster and convenient for me. Both results of these queries share the EventId column.
1st Query ():
SELECT EventId as 'event', count(*) as 'size',
SUM(case when tag_count = 1 then 1 else 0 end) as '1',
SUM(case when tag_count = 2 then 1 else 0 end) as '2',
SUM(case when tag_count = 3 then 1 else 0 end) as '3'
FROM (SELECT EventId, MicrosoftId,
SUM(case when name in ('indoor', 'cluttered', 'screen') then 1 else 0 end) as tag_count
FROM TagsMSCV GROUP BY EventId, MicrosoftId) TagsMSCV
GROUP BY EventId ORDER BY 3 DESC, 2 DESC, 1 DESC
2nd Query
SELECT EventId,
SUM(CASE WHEN name = 'indoor' THEN 1 ELSE 0 END) as indoor,
SUM(CASE WHEN name = 'cluttered' THEN 1 ELSE 0 END) as cluttered,
SUM(CASE WHEN name = 'screen' THEN 1 ELSE 0 END) as screen
FROM TagsMSCV WHERE name IN ('indoor', 'cluttered', 'screen')
GROUP BY EventId
As you can see in both queries I am feeding in the tags 'necktie' 'man', 'male' and getting different information back.
SQL Fiddle Here: https://www.db-fiddle.com/f/f8WNimjmZAj1XXeCj4PHB8/3
You should do this all in one query:
SELECT EventId as event, count(*) as size,
SUM(case when (indoor + cluttered + screen) = 1 then 1 else 0 end) as tc_1,
SUM(case when (indoor + cluttered + screen) = 2 then 1 else 0 end) as tc_2,
SUM(case when (indoor + cluttered + screen) = 3 then 1 else 0 end) as tc_3,
SUM(indoor) as indoor,
SUM(cluttered) as cluttered,
SUM(screen) as screen
FROM (SELECT EventId, MicrosoftId,
SUM(CASE WHEN name = 'indoor' THEN 1 ELSE 0 END) as indoor,
SUM(CASE WHEN name = 'cluttered' THEN 1 ELSE 0 END) as cluttered,
SUM(CASE WHEN name = 'screen' THEN 1 ELSE 0 END) as screen
FROM TagsMSCV
GROUP BY EventId, MicrosoftId
) TagsMSCV
GROUP BY EventId
ORDER BY 3 DESC, 2 DESC, 1 DESC;
You need two aggregations to get the information about the tag counts. There is no need to add more aggregations and joins to the query.
You could use an Inner join subquery
SELECT TagsMSCV.EventId as 'event', count(*) as 'size',
SUM(case when tag_count = 1 then 1 else 0 end) as '1',
SUM(case when tag_count = 2 then 1 else 0 end) as '2',
SUM(case when tag_count = 3 then 1 else 0 end) as '3',
t.necktie,
t.man,
t.male
FROM (
SELECT EventId, MicrosoftId,
SUM(case when name in ('necktie' 'man', 'male') then 1 else 0 end) as tag_count
FROM TagsMSCV GROUP BY EventId, MicrosoftId
) TagsMSCV
INNER JOIN (
SELECT EventId,
SUM(CASE WHEN name = 'necktie' THEN 1 ELSE 0 END) as necktie,
SUM(CASE WHEN name = 'man' THEN 1 ELSE 0 END) as man,
SUM(CASE WHEN name = 'male' THEN 1 ELSE 0 END) as male
FROM TagsMSCV WHERE name IN ('necktie' 'man', 'male')
GROUP BY EventId
) t on t.EventId = TagsMSCV.EventId
GROUP BY TagsMSCV.EventId
ORDER BY 3 DESC, 2 DESC, 1 DESC
I have a Tickets table in My database , each Ticket have a status_id (1,2,3)
1: Ticket IN PROGRESS
2: Ticket Out Of time
3: Ticket Closed
I want using SQL to calculate the number of tickets for each status .
Calculate the cumulative total for each Status in a specific Date, I have already a column affectation_Date that contains the date where the status of ticket has been changed .
Use conditional aggregation as
SELECT TicketID,
AffectationDate,
SUM(CASE WHEN StatusID = 1 THEN 1 ELSE 0 END) InProgress,
SUM(CASE WHEN StatusID = 2 THEN 1 ELSE 0 END) OuOfTime,
SUM(CASE WHEN StatusID = 3 THEN 1 ELSE 0 END) Closed,
COUNT(1) Total
FROM Tickets
GROUP BY TicketID,
AffectationDate
ORDER BY TicketID,
AffectationDate;
Or if you want to GROUP BY AffectationDate only
SELECT AffectationDate,
SUM(CASE WHEN StatusID = 1 THEN 1 ELSE 0 END) TotalInProgress,
SUM(CASE WHEN StatusID = 2 THEN 1 ELSE 0 END) TotalOutOfTime,
SUM(CASE WHEN StatusID = 3 THEN 1 ELSE 0 END) TotalClosed,
COUNT(1) TotalStatusThisDate
FROM Tickets
GROUP BY AffectationDate
ORDER BY AffectationDate;
Live Demo
Using conditional counts.
SELECT affectation_Date,
COUNT(CASE WHEN status_id = 1 THEN 1 END) AS TotalInProgress,
COUNT(CASE WHEN status_id = 2 THEN 1 END) AS TotalOutOfTime,
COUNT(CASE WHEN status_id = 3 THEN 1 END) AS TotalClosed
FROM Tickets t
GROUP BY affectation_Date
ORDER BY affectation_Date
you may use the desired filter condition for the date criteria
SELECT COUNT(1), STATUS
FROM tickets
WHERE affectation_Date >= 'someDate'
group by status
Regards
You just need to group by status and count the number of tickets in each group:
select status, count(*) as number
from Tickets
where dt >= '2019-01-01 00:00:00' and dt < '2019-01-02 00:00:00'
group by status
having status >= 1 and status <= 3
This adds the Cumulative Sum to the existing answers:
SELECT AffectationDate,
Sum(CASE WHEN StatusID = 1 THEN 1 ELSE 0 END) AS TotalInProgress,
Sum(CASE WHEN StatusID = 2 THEN 1 ELSE 0 END) AS TotalOutOfTime,
Sum(CASE WHEN StatusID = 3 THEN 1 ELSE 0 END) AS TotalClosed,
Count(*) as TotalStatusThisDate,
Sum(Sum(CASE WHEN StatusID = 1 THEN 1 ELSE 0 END)) Over (ORDER BY AffectationDate) AS cumTotalInProgress,
Sum(Sum(CASE WHEN StatusID = 2 THEN 1 ELSE 0 END)) Over (ORDER BY AffectationDate) AS cumTotalOutOfTime,
Sum(Sum(CASE WHEN StatusID = 3 THEN 1 ELSE 0 END)) Over (ORDER BY AffectationDate) AS cumTotalClosed,
Sum(Count(*)) Over (ORDER BY AffectationDate) AS cumTotalStatusThisDate
FROM Tickets
GROUP BY AffectationDate
ORDER BY AffectationDate;
Sorry if the title sucks.
I would like to basically convert both of these queries into one query with the result having two columns:
select count(columnA) as prev from myTable where set_id = 1530880217;
select count(columnA) as curr from myTable where set_id = 1530901756;
Output:
prev | curr
1000 | 1500
Use conditional aggregation:
select sum(case when set_id = 1530880217 then 1 else 0 end) as prev,
sum(case when set_id = 1530901756 then 1 else 0 end) as curr
from myTable
where set_id in (1530880217, 1530901756);
This assumes that columnA is never NULL. If you really want the NULL check:
select sum(case when set_id = 1530880217 and ColumnA is not null then 1 else 0 end) as prev,
sum(case when set_id = 1530901756 and ColumnA is not null then 1 else 0 end) as curr
from myTable
where set_id in (1530880217, 1530901756);
I have query returning details of customers that are subscribed to channel xyz or all other channels.
To generate this results i am using the following query:
select customerID
,sum(case when channel='xyz' then 1 else 0 end) as 'xyz Count'
,sum(case when channel<>'xyz' then bundle_qty else 0 end) as 'Other'
From temptable
So my Question is, how do i Exclude customers that are subscribed to 2 channels, where one is xyz and one is another channel.
select customerID
,sum(case when channel='xyz' then 1 else 0 end) as 'xyz Count'
,sum(case when channel<>'xyz' then bundle_qty else 0 end) as 'Other'
From temptable
group by customerID
having sum(case when channel= 'xyz' then 1 else 0 end) > 0
and sum(case when channel<>'xyz' then 1 else 0 end) > 0
First, your query is not correct. It needs a group by. Second, you can do what you want using having:
select customerID,
sum(case when channel = 'xyz' then 1 else 0 end) as xyz_Count,
sum(case when channel<>'xyz' then bundle_qty else 0 end) as Other
From temptable
group by customerID
having count(*) = 2 and
sum(case when channel = 'xyz' then 1 else 0 end) = 1;
If customers can subscribe to the same channel multiple times, and you still want only "xyz" and another channel, then:
having count(distinct channel) = 2 and
(min(channel) = 'xyz' or max(channel) = 'xyz')