I have utc epocha in millisecond and I would like my sql return resulting dates in a specific date format.
This works
SELECT to_timestamp(timestamp / 1000) as date
FROM data
This does not work
SELECT to_timestamp(timestamp / 1000, 'YYYY-MM-DD HH:MI:SS') as date
FROM data
Could you tell me what is wrong in my script and how to fix it please? Thanks
to_timestamp() does not format your output. The version where to_timestamp() accepts a format mask is used to convert a string value to a proper timestamp.
You need to format the result of your conversion (which is a proper timestamp) using to_char().
to_char(to_timestamp(timestamp / 1000), 'yyyy-mm-dd hh24:mi:ss') as date
I inserted date and time in database, now when trying to retrieve date and time both from database only getting time part.
I tried insert date using TO_DATE('08/13/2019 09:10:03', 'MM/DD/YYYY HH24:MI:SS') into 'Time' col. Now trying to get date from table using TO_DATE(Time, 'DD/MON/RR HH24:MI:SS'), but only getting date part. My database nls date format is "DD/MON/RR". 'Time' col is date type and I'm using oracle 10g xe.
I can get date and time using TO_CHAR(Time, 'DD/MON/RR HH24:MI:SS') but as I need to use this in comparison operation like below:
select TO_CHAR(Time,'DD/MON/RR HH24:MI:SS') from Table where (TO_CHAR(Time, 'DD/MON/RR HH24:MI:SS') <= TO_DATE('08/07/2019 10:13:52', 'MM/DD/YYYY HH24:MI:SS'))
it gives this error 'ORA-01830: date format picture ends before converting entire input string'. Also tried to use TO_DATE(TO_CHAR(Time, 'DD/MON/RR HH24:MI:SS')), still it gives only time part. Should I use TIMESTAMP datatype for 'Time' col?
I want to get date and time from table where i can use them in comparison operation.
Date need not be converted into date again.
You can simply write your query like this:
SELECT
TIME -- use to_char for formatting the output date
FROM Table
WHERE
TIME <= TO_DATE('08/07/2019 10:13:52', 'MM/DD/YYYY HH24:MI:SS')
Cheers!!
I have the following date in oracle table:
'2017-08-01 00:00:00,000000000'
I want to convert this to date which I am using the following but I don't know how to deal with zeroes?!
.
.
.
T.EXECUTION_LOCAL_DATE_TIME
between to_date('2017-08-01 00:00:00,000000000', 'yyyy-mm-dd hh:mi:ss')
and to_date('2017-08-10 00:00:00,000000000', 'yyyy-mm-dd hh:mi:ss');
Could anyone help me with this?
Oracle dates do not support milliseconds. Assuming your EXECUTION_LOCAL_DATE_TIME column is a date, then the following comparison is the best you can do:
T.EXECUTION_LOCAL_DATE_TIME
BETWEEN TO_DATE('2017-08-01 00:00:00', 'yyyy-mm-dd hh:mi:ss') AND
TO_DATE('2017-08-10 00:00:00', 'yyyy-mm-dd hh:mi:ss');
If you wanted to convert a text string with milliseconds to a timestamp, you could use something like this:
TO_TIMESTAMP ('2017-08-01 00:00:00,000000000', 'yyyy-mm-dd hh:mi:ss,ff')
Generally speaking this values in not a date but a timestamp so I would use following conversion:
select to_timestamp('2017-08-01 00:00:00,000000000', 'yyyy-mm-dd hh24:mi:ss,ff6')
from dual;
Technically you can have non zeros after comma, so If you want to get correct but not truncated value use timestamp date type.
i have a date in oracle with this format DD-MM-YYY and i want to convert it to datetime with this other format DD-MM-YYY HH24:MI how can i proceed?
I've tried this but nothing is working :
to_date(the_date,'DD-MM-YYY HH24:MI')
and also this:
to_date(to_char(date_debut_p),'DD-MM-YYY HH24:MI')
i have a date in oracle with this format DD-MM-YYY and i want to convert it to datetime with this other format DD-MM-YYY HH24:MI
No, you are confused. Oracle does not store dates in the format you see. It is internally stored in 7 bytes with each byte storing different components of the datetime value.
DATE data type always has both date and time elements up to a precision of seconds.
If you want to display, use TO_CHAR with proper FORMAT MODEL.
For example,
SQL> select to_char(sysdate, 'mm/dd/yyyy hh24:mi:ss') from dual;
TO_CHAR(SYSDATE,'MM
-------------------
11/25/2015 22:25:42
Oracle DATE datatype ALWAYS contains (stores) time.
If you want to see it, you can use function TO_CHAR.
If you want to add, for example, 1 hour, you can just use date_debut_p+1/24.
If you want to covert to timestamp, you can do the following:
Select to_timestamp(date_column, 'DD-MM-YYY') from table;
However, if you want in the required format, you can do the following:
Select to_char(to_timestamp(date_column, 'DD-MON-YY'), 'DD-MM-YYY HH24:MI')
from table;
Hope it helps..
I have a date column in a table stored as MM/DD/YYYY format. I have to select and store the same date in another table in YYYY-MM-DD format i.e. XSD Date Format. But I am not able to do it. I am using this query:
select to_date(date_column,'YYYY-MM-DD') from table;
But still I am not able to do it. Giving me error
ORA-01843 : not a valid month
use
select to_char(date_column,'YYYY-MM-DD') from table;
It sounds like you've got it the wrong way round. If your existing data is in MM/DD/YYYY format, then you want:
select to_date(date_column,'MM/DD/YYYY') from table;
to convert the existing data to DATE values. (I do wonder why they're not stored as dates, to be honest...)
If you want to perform the conversion in one step, you might want:
select to_char(to_date(date_column,'MM/DD/YYYY'), 'YYYY-MM-DD') from table;
In other words, for each row, parse it in MM/DD/YYYY format, then reformat it to YYYY-MM-DD format.
(I'd still suggest trying to keep data in its "natural" type though, rather than storing it as text in the first place.)
I assume that you can use the Oracle SQL Developer, which you can download from here.
You can define the date format which you want to work with:
ALTER SESSION SET nls_date_format='yyyy-mm-dd';
With this, now you can perform a query like this:
SELECT * FROM emp_company WHERE JDate = '2014-02-25'
If you want to be more specific you can define the date format like this:
ALTER SESSION SET nls_date_format='yyyy-mm-dd hh24:mi:ss';
To convert a DATE column to another format, just use TO_CHAR() with the desired format, then convert it back to a DATE type:
SELECT TO_DATE(TO_CHAR(date_column, 'DD-MM-YYYY'), 'DD-MM-YYYY') from my_table
select to_date(to_char(ORDER_DATE,'YYYY/MM/DD'))
from ORDERS;
This might help but, at the end you will get a string not the date. Apparently,
your format problem will get solved for sure .
For military time formatting,
select TO_CHAR(SYSDATE, 'yyyy-mm-dd hh24:mm:ss') from DUAL
--2018-07-10 15:07:15
If you want your date to round DOWN to Month, Day, Hour, Minute, you can try
SELECT TO_CHAR( SYSDATE, 'yyyy-mm-dd hh24:mi:ss') "full-date" --2018-07-11 10:40:26
, TO_CHAR( TRUNC(SYSDATE, 'year'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-year"-- 2018-01-01 00:00:00
, TO_CHAR( TRUNC(SYSDATE, 'month'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-month" -- 2018-07-01 00:00:00
, TO_CHAR( TRUNC(SYSDATE, 'day'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-Sunday" -- 2018-07-08 00:00:00
, TO_CHAR( TRUNC(SYSDATE, 'dd'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-day" -- 2018-07-11 00:00:00
, TO_CHAR( TRUNC(SYSDATE, 'hh'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-hour" -- 2018-07-11 10:00:00
, TO_CHAR( TRUNC(SYSDATE, 'mi'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-minute" -- 2018-07-11 10:40:00
from DUAL
For formats literals, you can find help in
https://docs.oracle.com/cd/B28359_01/server.111/b28286/functions242.htm#SQLRF52037
You can do this simply by :
select to_char(to_date(date_column, 'MM/DD/YYYY'), 'YYYY-MM-DD') from table
According to the comments, the data-type in the datatable is DATE.
So you should simply use:
"select date_column from table;"
Now if you execute the select you will get back a date data-type, which should be what you need for the .xsd.
Culture-dependent formating of the date should be done in the GUI (most languages have convenient ways to do so), not in the select-statement.
Basically , Data in a Date column in Oracle can be stored in any user defined format or kept as default.
It all depends on NLS parameter.
Current format can be seen by : SELECT SYSDATE FROM DUAL;
If you try to insert a record and insert statement is NOT in THIS format then it will give :
ORA-01843 : not a valid month error.
So first change the database date format before insert statements ( I am assuming you have bulk load of insert statements) and then execute insert script.
Format can be changed by :
ALTER SESSION SET nls_date_format = 'mm/dd/yyyy hh24:mi:ss';
Also You can Change NLS settings from SQL Developer GUI , (Tools > preference> database > NLS)
Ref: http://oracle.ittoolbox.com/groups/technical-functional/oracle-sql-l/how-to-view-current-date-format-1992815
This worked for me! You can convert to datatype you want be it a date or string
to_char(TO_DATE(TO_CHAR(end_date),'MM-DD-YYYY'),'YYYY-MM-DD') AS end_date
Late reply but for.databse-date-type the following line works.
SELECT to_date(t.given_date,'DD/MM/RRRR') response_date FROM Table T
given_date's column type is Date
Just to piggy back off of Yahia, if you have a timestamp you can use this function to cast exclusively as date, removing the timestamps.
TO_CHAR(CAST(DateTimeField AS DATE), 'YYYY-MM-DD') AS TrackerKey__C
Or in my case I need the below format
TO_CHAR(CAST(DateTimeField AS DATE), 'YYYYMMDD') AS TrackerKey__C
SELECT TO_DATE(TO_CHAR(date_column,'MM/DD/YYYY'), 'YYYY-MM-DD')
FROM table;
if you need to change your column output date format just use to_char this well get you a string, not a date.
use
SELECT STR_TO_DATE(date_column,'%Y-%m-%d') from table;
also gothrough
http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html