Recursively enter Month Year Name between date range - sql

Question

I'm trying to insert the followings columns below into a #table based off a time range.
For example if the query is run in August 2020, I'd need it to insert Months names from Jan - July 2020
Report_Date_Name| Report_Date_Month| DateYrmo| DateYear| DateMonth|
January 2020| January| 202001| 2020| 1|
February 2020| February| 202002| 2020| 2|
March 2020| March| 202003| 2020| 3|
April 2020| April| 202004| 2020| 4|
May 2020| May| 202005| 2020| 5|
June 2020| June| 202006| 2020| 6|
July 2020| July| 202007| 2020| 7|
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Answer 1

A recursive CTE seems like a simple approach:
with dates as (
select datefromparts(year(getdate()), 1, 1) as dte
union all
select dateadd(month, 1, dte)
from dates
where dte < getdate()
)
select concat(convert(char(12), datename(month, dte)), year(dte)) as report_date_name,
datename(month, dte) as report_date_month,
year(dte) * 100 + month(dte) as year_month,
year(dte) as year
from dates;
It is not clear if the last columns are strings or numbers. If strings, just cast them to the type you want.
Here is a db<>fiddle.

Answer 2

Try this:
DECLARE #SomeDate DATE = '2020-08-08';
WITH Dates ([Date]) AS
(
SELECT DATEADD(MONTH, -[number], '2020-08-08')
FROM
(
SELECT [number] + 1
FROM [master].[dbo].[spt_values]
WHERE [type] = 'P'
) n ([number])
WHERE DATEADD(MONTH, -[number], #SomeDate) <= DATEADD(MONTH, -1, #SomeDate)
AND YEAR(DATEADD(MONTH, -[number], #SomeDate)) = YEAR(#SomeDate)
)
SELECT CONCAT(DATENAME(MONTH, [Date]), ' ', YEAR([Date])) AS [Report_Date_Name]
,DATENAME(MONTH, [Date]) AS [Report_Date_Month]
,RIGHT(YEAR([Date]) * 100 + 10000000 + MONTH([Date]), 6) AS [DateYrmo]
,YEAR([Date]) AS [DateYear]
,MONTH([Date]) AS [DateMonth]
FROM Dates
ORDER BY [Date] ASC;
The CTE is used to generated one date from each previous month for the current year. Then we are using built-in functions to format the output.