using https://github.com/invertase/react-native-apple-authentication
import React from 'react';
import { View } from 'react-native';
import { AppleButton } from '#invertase/react-native-apple-authentication';
async function onAppleButtonPress() {
}
function App() {
return (
<View>
<AppleButton
buttonStyle={AppleButton.Style.WHITE}
buttonType={AppleButton.Type.SIGN_IN}
style={{
width: 160, // You must specify a width
height: 45, // You must specify a height
}}
onPress={() => onAppleButtonPress()}
/>
</View>
);
}
Maybe you don't need this answer anymore, but currently this error still happens and the solution I found was:
import {appleAuth} from '#invertase/react-native-apple-authentication';
<View>
{appleAuth.isSupported && (
<Button title="Sign in with Apple" onPress={AppleSignIn} />
)}
</View>
The AppleButton seems to work fine in production:
<AppleButton
buttonStyle={AppleButton.Style.BLACK}
buttonType={AppleButton.Type.SIGN_IN}
style={styles.appleButton}
onPress={AppleSignIn}
/>
It says in the library docs that it is only available in React Native v0.60+.
Related
i have a problem when i want to send data of a URL so when you go to the next page your show the spesific url, im using expo cli not react native cli
website.tsx
import React, { useState } from "react";
import { Dimensions } from "react-native";
import { Div, Text } from "react-native-magnus";
import WebView from "react-native-webview";
const Website = ({YOUR_URL}) => {
return (
<WebView
rautomaticallyAdjustContentInsets={false}
source={{uri: YOUR_URL}}
style={{marginTop: 20, height: "100%", width: "100%"}}
onLoad={console.log("Loaded")}
startInLoadingState={true}
javaScriptEnabled={true}
/>
);
};
export default Website;
and this is my button to send the data
<Button w={wp(40)} h={hp(5.5)} ml={hp(2)}
onPress={() => navigation.navigate('Website', {YOUR_URL:data?.external_link})}
// onPress={() => Linking.openURL(data?.external_link)}
>
<Text allowFontScaling={false} fontSize={16} color="#fff">
Selengkapnya
</Text>
if you can help me, thank you very much
For me it worked by passing it precise values for width and height for Webview component and not percentage values. For managing the different display sizes I think you should use "scale".
I was trying to position a button on the bottom right of the screen like the picture below:
So, basically I had a Scrollview with the button inside like so:
import React, { Component } from 'react'
import { ScrollView, Text, KeyboardAvoidingView,View,TouchableOpacity } from 'react-native'
import { connect } from 'react-redux'
import { Header } from 'react-navigation';
import CreditCardList from '../Components/credit-cards/CreditCardList';
import Icon from 'react-native-vector-icons/Ionicons';
import Button from '../Components/common/Button';
// Styles
import styles from './Styles/CreditCardScreenStyle'
import CreditCardScreenStyle from './Styles/CreditCardScreenStyle';
class CreditCardScreen extends Component {
render () {
return (
<ScrollView style={styles.container}>
<CreditCardList />
<TouchableOpacity style={CreditCardScreenStyle.buttonStyle}>
<Icon name="md-add" size={30} color="#01a699" />
</TouchableOpacity>
</ScrollView>
)
}
}
My styles:
import { StyleSheet } from 'react-native'
import { ApplicationStyles } from '../../Themes/'
export default StyleSheet.create({
...ApplicationStyles.screen,
container:{
marginTop: 50,
flex: 1,
flexDirection: 'column'
},
buttonStyle:{
width: 60,
height: 60,
borderRadius: 30,
alignSelf: 'flex-end',
// backgroundColor: '#ee6e73',
position: 'absolute',
bottom: 0,
// right: 10,
}
})
The problem is that the absolute positioning does not work at all when the button is inside the ScrollView. But...If I change the code to look like this:
import CreditCardScreenStyle from './Styles/CreditCardScreenStyle';
class CreditCardScreen extends Component {
render () {
return (
<View style={styles.container}>
<ScrollView >
<CreditCardList />
</ScrollView>
<TouchableOpacity style={CreditCardScreenStyle.buttonStyle}>
<Icon name="md-add" size={30} color="#01a699" />
</TouchableOpacity>
</View>
)
}
}
Then it works !! Whaat? Why? How? I don't understand why this is happening and I would appreciate any information about it.
This might be inconvenient but is just how RN works.
Basically anything that's inside the ScrollView (in the DOM/tree) will scroll with it. Why? Because <ScrollView> is actually a wrapper over a <View> that implements touch gestures.
When you're using position: absolute on an element inside the ScrollView, it gets absolute positioning relative to its first relative parent (just like on the web). Since we're talking RN, its first relative parent is always its first parent (default positioning is relative in RN). First parent, which in this case is the View that's wrapped inside the ScrollView.
So, the only way of having it "fixed" is taking it outside (in the tree) of the ScrollView, as this is what's actually done in real projects and what I've always done.
Cheers.
i suggest to use "react-native-modal".
you can not use position: 'absolute' to make elements full size in ScrollView
but you can do it by
putting that element in modal wrapper.
below are two examples. first one doesnt work but the second one works perfectly.
first way (doesnt work):
const app = () => {
const [position, setPosition] = useState('relative')
return(
<ScrollView>
<Element style={{position: position}}/>
<Button
title="make element fixed"
onPress={()=> setPosition('absolute')}
/>
</ScrollView>
)
}
second way (works perfectly):
const app = () => {
const [isModalVisible, setIsModalVisible] = useState(false)
return(
<ScrollView>
<Modal isModalVisible={isModalVisible}>
<Element style={{width: '100%', height: '100%'}}/>
</Modal>
<Button
title="make element fixed"
onPress={()=> setIsModalVisible(true)}
/>
</ScrollView>
)
}
for me this worked:
before:
<View>
<VideoSort FromHome={true} />
<StatisticShow style={{position:'absulote'}}/>
</View>
after:
<View>
<ScrollView>
<VideoSort FromHome={false} />
</ScrollView>
<View style={{position:'relative'}}>
<StatisticShow style={{position:'absulote'}}/>
</View>
</View>
// How do you set the image on the top of the screen without losing the aspect ration?
[![import React, { Component } from 'react';
import { AppRegistry, View, Image, StyleSheet } from 'react-native';
export default class DisplayAnImageWithStyle extends Component {
render() {
return (
<View style={{flex:1}}>
<Image
resizeMode="contain"
style={{flex:1}}
source={{uri: 'https://i.pinimg.com/originals/ba/84/1c/ba841cc07934b508458a7faea62141a8.jpg'}}
/>
</View>
);
}
}
// Skip these lines if you are using Create React Native App.
AppRegistry.registerComponent(
'DisplayAnImageWithStyle',
() => DisplayAnImageWithStyle
);][1]][1]
// Here the liked image shows that it is not fitting well... it is not showing from the top... do you have any idea how I can set the image without any padding?
[1]: https://i.stack.imgur.com/LYNKn.png
So you might wanna use resizeMode: 'cover' with a height and width.
<Image
resizeMode="contain"
style={{ width: 200, height:220, resizeMode: 'cover'}}
source={{uri: 'https://i.pinimg.com/originals/ba/84/1c/ba841cc07934b508458a7faea62141a8.jpg'}}
/>
Here's an example https://snack.expo.io/HJTFg9tU4
Let me know if this works for you.
I am working with react native, and I am using a video component from the expo. during this how I can change the value for URI attribute dynamically
(As you mentioned in the comment that you already solved the problem and want to play youtube videos)
You can use WebView to play Youtube video.
Working demo: https://snack.expo.io/Syhzx-VvX
Here is the sample code:
import React, { Component } from 'react';
import { StyleSheet, View, WebView, Platform } from 'react-native';
export default class App extends Component<{}> {
render() {
return (
<View style={{ height: 300 }}>
<WebView
style={ styles.WebViewContainer }
javaScriptEnabled={true}
domStorageEnabled={true}
source={{uri: 'https://www.youtube.com/embed/YE7VzlLtp-4' }}
/>
</View>
);
}
}
const styles = StyleSheet.create({
WebViewContainer: {
marginTop: (Platform.OS == 'android') ? 20 : 0,
}
});
Otherwise if you don't want to use WebView, use a third party package like react-native-youtube
I was following React Native basic tutorial. Then after it ended, I tried to add a button in the code used in TextInput tutorial, following example in Button page
import React, { Component } from 'react';
import { AppRegistry, Text, TextInput, Button, View } from 'react-native';
class AwsumProjek extends Component {
constructor(props) {
super(props);
this.state = {tiText: ''};
}
render() {
return (
<View style={{padding: 10}}>
<TextInput
style={{height: 40}}
placeholder="Type here to translate!"
onChangeText={(tiText) => this.setState({tiText})}
/>
<Text style={{padding: 10, fontSize: 42}}>
{this.state.tiText.split(' ').map((word) => word && 'WA').join(' ')}
</Text>
<Button
title="Press Purple"
color="#841584"
accessibilityLabel="Learn more about purple"
/>
</View>
);
}
}
AppRegistry.registerComponent('AwsumProjek', () => AwsumProjek);
Instead I got this error
Element type is invalid: expected a string (for built-in components)
or a class/function (for composite components) but got: undefined.
Check the render method of 'AwsumProjek'.
What did I do wrong? Seeing other answer, is it something related to importing something?
I'm native android developer trying to learn React Native, and as me now, Javascript is totally unfamiliar for me.
Make sure you are using correct version of React Native. Button component was introduced in React Native version 0.37