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I am trying to do the following in my Bigquery sql:
input: myword1 myword my 3433123 other stuff
output: myword1 myword my
input: myword 23498780000123 more stuff
output: myword
I want the output shown above based on the above input.
I need everything before the numbers.
I tried using ^([\s\w\s]+)(?=[^\d\r\n]+\d+[^\d\r\n]+$) but re2 doesn't like it.
Re2 doesn't like ?= . Hope that helps
It seems like you want everything before the first digit. If so, you can use regexp_replace():
regexp_replace(mycol, '\s*\d.*$', '')
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How to trim only zeroes in a leading position in a string?
I'm writing a DB2 script that removes all leading zeroes from a string that could be only 13 characters long.
What I wrote so far:
ltrim(replace(Field, '00000',''))
That works as follows:
0000012345678111 -> 12345678111
0000012300000174 -> 123174
Now, I need to delete ONLY the five leading zeroes, not the zeroes in the middle and I already tried to convert to decimal, but if I have, for example, only two zeroes leading, I want to leave them in the same position.
For example (converting to decimal) :
001234566890000 -> 1234566890000
I want no Changes in the left string.
How could I solve it?
Thanks
Use LTRIM to get rid of the zeroes. If you want a resulting string length, make it a string of that type again. To have CHAR(13) as result:
CHAR(LTRIM(inputvalue, '0'), 13)
I found the Solution by myself.
I've used nested function:
substr( replace( ltrim( replace(Field,'00000', ' ')), ' ', '0'), 1, 13)
(please, i can't indent properly from My smartphone, could someone do it for me? Thanks)
This solve My question
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Let's say i have the following file:
balloons:
- 2
- 3
Each number above should represents how many times i want to print the string. So for example I would like to process this to output as following:
balloons:
- red
- red
- blue
- blue
- blue
I only have red and blue balloons. The digits will vary from one file to another, so my search string would be a simple regex search sed -e "/[[:digit:]]\+/ perform_my_action"
Try:
awk 'BEGIN{idx[2]="red"; idx[3]="blue"}
/^-[ \t]+[0-9]+/{for(i=1;i<=$2;i++) print idx[$2]; next}
1
' file
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I have a list of product codes grouped in 2 or 3 lines. I need to return the group where codes are not same (or consecutive)
9003103
9003103
9003978
9003979
9003763
9003728
9003543
9003543
9003543
In this case, only the third group should be returned:
9003763
9003728
I would harness GNU AWK for this task following way, let file.txt content be
9003103
9003103
9003978
9003979
9003763
9003728
9003543
9003543
9003543
then
awk 'BEGIN{RS=""}{diff=$NF-$1;diff=diff>0?diff:-diff}diff>NF' file.txt
gives output
9003763
9003728
Explanation: I set RS to empty string to provoke paragraph mode, thus every block is treated as single line, then for each block I compute absolute of difference between first and last field, if difference is bigger than number of field block is printed.
(tested in GNU Awk 5.0.1)
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I have a very big text file (1 GB) and I see that there are few places where the http url field has a space there.
For example in the lines below we have space between "brad pitt" and "[30 wet=]". They should be changed to "bradpitt" and "[30wet=]" but they can occur in any url or trim_url. I am currently finding these places using my program and then manually fixing it vim. Is there a way using awk/sed we can do it?
0.0 q:hello url:http://sapient.com/bapper/30/brad pitt/C345/surf trim_url:http://sapient.com/bapper/30/brad pitt/C345 rating:good
0.0 q:hello url:http://sick.com/bright/[30 wet=]/sound trim_url:http://sick.com/bright/[30 wet=]rating:good
What I tried to do was sed:
sed -i -e 's/*http*[:space:]*/*http*/g' test.txt
Using perl and a proper module to URI encode the URL:
perl -MURI::Escape -pe 's!(https?://)(.*)!$1 . uri_escape($2)!e' file
You even can replace the file in place with -i switch (just like sed) perl -MURI::Escape -i -pe [...]
Output
0.0 q:hello url:http://sapient.com%2Fbapper%2F30%2Fbrad%20pitt%2FC345%2Fsurf%20trim_url%3Ahttp%3A%2F%2Fsapient.com%2Fbapper%2F30%2Fbrad%20pitt%2FC345%20rating%3Agood
0.0 q:hello url:http://sick.com%2Fbright%2F%5B30%20wet%3D%5D%2Fsound%20trim_url%3Ahttp%3A%2F%2Fsick.com%2Fbright%2F%5B30%20wet%3D%5Drating%3Agood
URI::Escape - Percent-encode and percent-decode unsafe characters
Note
As msanford said in comments, spaces in a URL are meaningful. You can't decide to cut them without breaking the link in something that just become not reachable
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I would like to create an input mask which looks like this C-HG__.
But because C represent option character or space in masking (VB.net). It wouldn't let me.
Please assist.
Try using the escape element: \
MSDN has a fairly nice write-up. Here's an excerpt:
\
Escape. Escapes a mask character, turning it into a literal. "\\" is the escape sequence for a backslash.
Possible duplicate with this question and/or this question.