It looks like the output is not as what I expecting. Could it be by design or program bug?
doc = nlp(
"Line 1 50%. "
"Line 2 40% end space and dot ." # try comment
# "Line 2 40% end space and dot." # try comment
"20% at line 3 where Line 2 end with or without space"
)
# Iterate over the tokens in the doc
for token in doc:
# Check if the token resembles a number
if token.like_num:
# Get the next token in the document
next_token = doc[token.i+1]
# Check if the next token's text equals "%"
if next_token.text == "%":
print("Percentage found:", token.text)
Try doc.text and see the reason for what you're getting:
doc.text
'Line 1 50%. Line 2 40% end space and dot .20% at line 3 where Line 2 end with or without space'
Tip: you have all your strings concatenated into one.
To achieve what you want feed your docs as comma separated strings:
docs = nlp.pipe(["Line 1 50%. "
,"Line 2 40% end space and dot ."
,"20% at line 3 where Line 2 end with or without space"])
for doc in docs:
for token in doc:
if token.like_num and doc[token.i+1].text=="%":
print("Percentage found:", token)
Percentage found: 50
Percentage found: 40
Percentage found: 20
Related
Given an input that looks like the following:
123
456
789
42
23
1337
3117
I want to iterate over this file in whitespace-separated chunks in Fortran (any version is fine). For example, let's say I wanted to take the average of each chunk (e.g. mean(123, 456, 789) then mean(42, 23, 1337) then mean(31337)).
I've tried iterating through the file normally (e.g. READ), reading in each line as a string and then converting to an int and doing whatever math I want to do on each chunk. The trouble here is that Fortran "helpfully" ignores blank lines in my text file - so when I try and compare against the empty string to check for the blank line, I never actually get a .True. on that comparison.
I feel like I'm missing something basic here, since this is a typical functionality in every other modern language, I'd be surprised if Fortran didn't somehow have it.
If you're using so-called "list-directed" input (format = '*'), Fortran does special handling to spaces, commas, and blank lines.
To your point, there's a feature which is using the BLANK keyword with read
read(iunit,'(i10)',blank="ZERO",err=1,end=2) array
You can set:
blank="ZERO" will return a valid zero value if a blank is found;
blank="NULL" is the default behavior that skips blank/returns an error depending on the input format.
If all your input values are positive, you could use blank="ZERO" and then use the location of zero values to process your data.
EDIT as #vladimir-f has correctly pointed out, you not only have blanks in between lines, but also after the end of the numbers in most lines, so this strategy will not work.
You can instead load everything into an array, and process it afterwards:
program array_with_blanks
integer :: ierr,num,iunit
integer, allocatable :: array(:)
open(newunit=iunit,file='stackoverflow',form='formatted',iostat=ierr)
allocate(array(0))
do
read(iunit,'(i10)',iostat=ierr) num
if (is_iostat_end(ierr)) then
exit
else
array = [array,num]
endif
end do
close(iunit)
print *, array
end program
Just read each line as a character (but note Francescalus's comment on the format). Then read the character as an internal file.
program stuff
implicit none
integer io, n, value, sum
character (len=1000) line
n = 0
sum = 0
io = 0
open( 42, file="stuff.txt" )
do while( io == 0 )
read( 42, "( a )", iostat = io ) line
if ( io /= 0 .or. line == "" ) then
if ( n > 0 ) print *, ( sum + 0.0 ) / n
n = 0
sum = 0
else
read( line, * ) value
n = n + 1
sum = sum + value
end if
end do
close( 42 )
end program stuff
456.000000
467.333344
3117.00000
How can I configure John the Ripper to generate only mangled (Jumbo) palindromes from a word-list to crack a password hash?
(I've googled it but only found "how to avoid palindromes")
in john/john.conf (for e.g. 9 and 10 letter palindromes) -append the following rules at the end:
# End of john.conf file.
# Keep this comment, and blank line above it, to make sure a john-local.conf
# that does not end with \n is properly loaded.
[List.Rules:palindromes]
f
f D5
then run john with your wordlist plus the newly created "palindromes" rules:
$ john --wordlist=wordlist.lst --rules:palindromes hashfile.hash
rule f simply appends a reflection of itself to the current word from the wordlist, e.g. P4ss! -> P4ss!!ss4P
rule f D5 not only reflects the word but then deletes the 5th character, e.g. P4ss! -> P4ss!ss4P
I haven't found a way to "delete the middle character" so as of now, the rule has to be adjusted to the required length of palindromes, e.g. f D4 for length of 7, f D6 for length of 11 etc.
Edit: Possible solution for variable length (not tested yet):
f
Mr[6
M = Memorize current word, r = Reverse the entire word , [ = Delete first character, 6 = Prepend the word saved to memory to current word
With this approach the palindromes could additionally be "turned inside out" (word from wordlist at the end of the resulting palindrome instead of at beginning)
f
Mr[6
Mr]4
M = Memorize current word, r = Reverse the entire word , ] = Delete last character, 4 = Append the word saved to memory to current word
I'm trying to make some changes to my dictionary counter in python. I want make some changes to my current counter, but not making any progress so far. I want my code to show the number of different words.
This is what I have so far:
# import sys module in order to access command line arguments later
import sys
# create an empty dictionary
dicWordCount = {}
# read all words from the file and put them into
#'dicWordCount' one by one,
# then count the occurance of each word
you can use the Count function from collections lib:
from collections import Counter
q = Counter(fileSource.read().split())
total = sum(q.values())
First, your first problem, add a variable for the word count and one for the different words. So wordCount = 0 and differentWords = 0. In the loop for your file reading put wordCount += 1 at the top, and in your first if statement put differentWords += 1. You can print these variables out at the end of the program as well.
The second problem, in your printing, add the if statement, if len(strKey)>4:.
If you want a full example code here it is.
import sys
fileSource = open(sys.argv[1], "rt")
dicWordCount = {}
wordCount = 0
differentWords = 0
for strWord in fileSource.read().split():
wordCount += 1
if strWord not in dicWordCount:
dicWordCount[strWord] = 1
differentWords += 1
else:
dicWordCount[strWord] += 1
for strKey in sorted(dicWordCount, key=dicWordCount.get, reverse=True):
if len(strKey) > 4: # if the words length is greater than four.
print(strKey, dicWordCount[strKey])
print("Total words: %s\nDifferent Words: %s" % (wordCount, differentWords))
For your first qs, you can use set to help you count the number of different words. (Assume there is a space between every two words)
str = 'apple boy cat dog elephant fox'
different_word_count = len(set(str.split(' ')))
For your second qs, using a dictionary to help you record the word_count is ok.
How about this?
#gives unique words count
unique_words = len(dicWordCount)
total_words = 0
for k, v in dicWordCount.items():
total_words += v
#gives total word count
print(total_words)
You don't need a separate variable for counting word counts since you're using dictionary, and to count the total words, you just need to add the values of the keys(which are just counts)
I am trying the ANTLR 4, it gives me the following output for the simple Hello grammar in the book < The Definitive ANTLR 4 Reference >:
[#2,12:11='<EOF>',<-1>,2:0]
According to the book's interpretation, the12:11 notation means <EOF> token starts at position 12 and ends at 11. How could this be possible?
PS. I am working on Windows.
In ANTLR 4, both endpoints are inclusive. The length of a span with inclusive endpoints is the following:
Length = End - Start + 1
The length of the EOF symbol is 0 (it appears at a known location, but it contains no input symbols). If the input is 12 characters long, you get this formula for the end position:
0 = End - 12 + 1
Therefore:
End = 0 + 12 - 1 = 11
OSX v10.6.8 and Gnuplot v4.4
I have a data file with 8 columns. I would like to take the first value from the 6th column and make it the title. Here's what I have so far:
#m1 m2 q taua taue K avgPeriodRatio time
#1 2 3 4 5 6 7 8
K = #read in data here
graph(n) = sprintf("K=%.2e",n)
set term aqua enhanced font "Times-Roman,18"
plot file using 1:3 title graph(K)
And here is what the first few rows of my data file looks like:
1.00e-07 1.00e-07 1.00e+00 1.00e+05 1.00e+04 1.00e+01 1.310 12070.00
1.11e-06 1.00e-07 9.02e-02 1.00e+05 1.00e+04 1.00e+01 1.310 12070.00
2.12e-06 1.00e-07 4.72e-02 1.00e+05 1.00e+04 1.00e+01 1.310 12070.00
3.13e-06 1.00e-07 3.20e-02 1.00e+05 1.00e+04 1.00e+01 1.310 12090.00
I don't know how to correctly read in the data or if this is even the right way to go about this.
EDIT #1
Ok, thanks to mgilson I now have
#m1 m2 q taua taue K avgPeriodRatio time
#1 2 3 4 5 6 7 8
set term aqua enhanced font "Times-Roman,18"
K = "`head -1 datafile | awk '{print $6}'`"
print K+0
graph(n) = sprintf("K=%.2e",n)
plot file using 1:3 title graph(K)
but I get the error: Non-numeric string found where a numeric expression was expected
EDIT #2
file = "testPlot.txt"
K = "`head -1 file | awk '{print $6}'`"
K=K+0 #Cast K to a floating point number #this is line 9
graph(n) = sprintf("K=%.2e",n)
plot file using 1:3 title graph(K)
This gives the error--> head: file: No such file or directory
"testPlot.gnu", line 9: Non-numeric string found where a numeric expression was expected
You have a few options...
FIRST OPTION:
use columnheader
plot file using 1:3 title columnheader(6)
I haven't tested it, but this may prevent the first row from actually being plotted.
SECOND OPTION:
use an external utility to get the title:
TITLE="`head -1 datafile | awk '{print $6}'`"
plot 'datafile' using 1:3 title TITLE
If the variable is numeric, and you want to reformat it, in gnuplot, you can cast strings to a numeric type (integer/float) by adding 0 to them (e.g).
print "36.5"+0
Then you can format it with sprintf or gprintf as you're already doing.
It's weird that there is no float function. (int will work if you want to cast to an integer).
EDIT
The script below worked for me (when I pasted your example data into a file called "datafile"):
K = "`head -1 datafile | awk '{print $6}'`"
K=K+0 #Cast K to a floating point number
graph(n) = sprintf("K=%.2e",n)
plot "datafile" using 1:3 title graph(K)
EDIT 2 (addresses comments below)
To expand a variable in backtics, you'll need macros:
set macro
file="mydatafile.txt"
#THE ORDER OF QUOTES (' and ") IS CRUCIAL HERE.
cmd='"`head -1 ' . file . ' | awk ''{print $6}''`"'
# . is string concatenation. (this string has 3 pieces)
# to get a single quote inside a single quoted string
# you need to double. e.g. 'a''b' yields the string a'b
data=#cmd
To address your question 2, it is a good idea to familiarize yourself with shell utilities -- sed and awk can both do it. I'll show a combination of head/tail:
cmd='"`head -2 ' . file . ' | tail -1 | awk ''{print $6}''`"'
should work.
EDIT 3
I recently learned that in gnuplot, system is a function as well as a command. To do the above without all the backtic gymnastics,
data=system("head -1 " . file . " | awk '{print $6}'")
Wow, much better.
This is a very old question, but here's a nice way to get access to a single value anywhere in your data file and save it as a gnuplot-accessible variable:
set term unknown #This terminal will not attempt to plot anything
plot 'myfile.dat' index 0 every 1:1:0:0:0:0 u (var=$1):1
The index number allows you to address a particular dataset (separated by two carriage returns), while every allows you to specify a particular line.
The colon-separated numbers after every should be of the form 1:1:<line_number>:<block_number>:<line_number>:<block_number>, where the line number is the line with the the block (starting from 0), and the block number is the number of the block (separated by a single carriage return, again starting from 0). The first and second numbers say plot every 1 lines and every one data block, and the third and fourth say start from line <line_number> and block <block_number>. The fifth and sixth say where to stop. This allows you to select a single line anywhere in your data file.
The last part of the plot command assigns the value in a particular column (in this case, column 1) to your variable (var). There needs to be two values to a plot command, so I chose column 1 to plot against my variable assignment statement.
Here is a less 'awk'-ward solution which assigns the value from the first row and 6th column of the file 'Data.txt' to the variable x16.
set table
# Syntax: u 0:($0==RowIndex?(VariableName=$ColumnIndex):$ColumnIndex)
# RowIndex starts with 0, ColumnIndex starts with 1
# 'u' is an abbreviation for the 'using' modifier
plot 'Data.txt' u 0:($0==0?(x16=$6):$6)
unset table
A more general example for storing several values is given below:
# Load data from file to variable
# Gnuplot can only access the data via the "plot" command
set table
# Syntax: u 0:($0==RowIndex?(VariableName=$ColumnIndex):$ColumnIndex)
# RowIndex starts with 0, ColumnIndex starts with 1
# 'u' is an abbreviation for the 'using' modifier
# Example: Assign all values according to: xij = Data33[i,j]; i,j = 1,2,3
plot 'Data33.txt' u 0:($0==0?(x11=$1):$1),\
'' u 0:($0==0?(x12=$2):$2),\
'' u 0:($0==0?(x13=$3):$3),\
'' u 0:($0==1?(x21=$1):$1),\
'' u 0:($0==1?(x22=$2):$2),\
'' u 0:($0==1?(x23=$3):$3),\
'' u 0:($0==2?(x31=$1):$1),\
'' u 0:($0==2?(x32=$2):$2),\
'' u 0:($0==2?(x33=$3):$3)
unset table
print x11, x12, x13 # Data from first row
print x21, x22, x23 # Data from second row
print x31, x32, x33 # Data from third row